Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

A force exerted on a 3 m long conductor having a current of 2 A in 0-4 T magnetic induction with an angle of 30° is(1)1.2N(2)12N(3)72N(4)2.4N​

Answer» ONG>ANSWER:

answer is (2) I THINK.................

2.

Assertion(A): The emergent ray is parallel to the direction of the incident ray. Reason (R): In a rectangular glass slabthe extent of bending of the ray of light at the opposite parallel faces of the rectangular slab is equal and opposite.​

Answer»

ong>Answer:

Here, the light RAY bends away from the normal. We see that the INCIDENT and emergent rays are PARALLEL to each other. These rays are parallel because the extent of bending on the opposite and parallel FACES of slab is equal and opposite

3.

Why should we balance a chemical equation? (AS)milations (AS)​

Answer»

ong>Answer:

We BALANCE the equation so that we won't VIOLATE the LAW of Conservation Of Mass that mass can't be created nor DESTROYED

4.

Please answer it please please ​

Answer» IZA!

SEE picture for SOLN.

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5.

two concentric circular coil A and B have radii 25cm and 15 cm. and carrying current 10A and 15A respectively A has 24 turns B has 18 direction ofcurrent is in opposite order. The magnetic induction at the common centre of the coil will be

Answer»

ong>Answer:

ANSWER

B

1

=

2r

1

n

1

μ

0

i

1

=

2×25×10

−2

24×μ

0

×10

=480μ

0

T GOING into the plane

B

2

=

2r

2

n

2

μ

0

i

2

=

2×15×10

−2

18×μ

0

×15

=900μ

0

T going out of the plane

Bnet=B

2

−B

1

=(900−480)μ

0

=420μ

0

T

Explanation:

I hope this is helpful to you

6.

Advantages and disadvantages of cells connected in series

Answer»

Answer:-

Advantages:-

CELLS connected in series give a greater resultant voltage than individual cells. Voltage increases if the NUMBER of cells increases. II. Faulty cells are easily DETECTED and replaced because they break the CIRCUIT.

Disadvantages:-

The first disadvantage is that, if one component in a series circuit fails, then all the components in the circuit fail because the circuit has been broken. The second disadvantage is that the more components there are in a series circuit, the greater the circuit's RESISTANCE*.

7.

Please someone answer this urgently​

Answer»

ong>ANSWER:

where is the question

Explanation:

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8.

The initial velocity of a particle is 10m/s. It is moving with an acceleration of 4m/s^2. The distance covered by the particle after 2 sec is: 1. 6m 2.18m 3.22m 4.28m

Answer» ONG>ANSWER:

Given,

u=10m/s

a=−2m/s

2

n=5

The DISTANCE covered by the PARTICLE in n

th

SECOND is

S

n

=u+

2

a

(2n−1)

S

5

=10−

2

2

(2×5−1)

S

5

=10−9=1m

9.

30. A rectangular plate is placed on a rough plank. Dimensions of the plank is as shown in the figure. Find the minimum acceleration with which the plank should be moved so that the rectangular plate topples (considerthe friction is sufficient so the plate does not slide).​

Answer» ONG>ANSWER:

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10.

Do you agree with your friend who savs the ratio of distance and displacement never be less then one if so why​

Answer»

ong>ANSWER

yes

Explanations

yes

  • as the ratio of DISTANCE and DISPLACEMENT is always less
  • as the distance is actuall PATH and displacement is SHORTEST path
  • displacement is vector it can be positive , negative and equal to zero
11.

A clock shows 3 hr 5 min. When seen through a plane mirror, the time appears to be (1) 8 hr 55 min (2)13 hr 5 min (3) 9hr35min​

Answer» ONG>ANSWER:

Answer is (1) 8hr 55min

Good you are nice PERSON... REALLY the answer was given by me and you choose BRAINLIST him

Not fair really.....

12.

How does resistance training prevent osteoporosis?

Answer» ONG>ANSWER:

What is RESISTANCE TRAINING.

13.

Find the pressure exerted on 6ft X 10ftwall by the atmosphere. If Atmospheric pressureIS A. I psi​

Answer» ONG>Answer:

60ft^2..........................

14.

4. The equation of state for a real gas at high anRTtemperature is given by PwhereV-b 12V/V + b)n, PV&T are number of moles, pressure, volume &temperature respectively & R is the universal gasconstant. Findthe dimensions of constant 'a' in theabove equation.Sol.​

Answer»

ong>Answer:

PV=nRT=

M

w

RT

Hence, PM=

V

w

RT=ρRT

ρ∝P

Here, ρ=

V

w

n=

M

w

ρ is the density, P is the pressure, V is the volume, n is the number of moles, R is the IDEAL gas constant, T is the temperature and M is the molar mass

15.

80. What happens when Benzoic acid is treated with concentrated Nitric acid in the presenceof concentrated Sulphuric acid ?A) p-Nitro benzoic acid(B) - benzale acid(C) -Nitrobenzoic acid( None of these​

Answer»

o BENZOIC ACID is FORMED

16.

Kepler's third law of motion​

Answer»

wer

In astronomy, Kepler's laws of PLANET MOTION are THREE scientific laws describing the motion of planets AROUND the Sun, published by Johannes Kepler between 1609 and 1619.

17.

3. find the the pressure exected on the ground (in psi) by a 250 Ib person who is sittig on a chair whose 4 legstouch the ground with and area of 1" by 2" eachwho Is sittingtouch the​

Answer» ONG>ANSWER:

DA is the CURRET answer

18.

a current 10A flows downwards a in a long straight vertical conductor and the earth's horiz is 2 x 10- 7 T . Then the neutral point occurs

Answer»

ong>Explanation:

Given a current 10A flows downwards a in a long straight vertical conductor and the EARTH's HORIZONTAL  is 2 x 10- 7 T . Then the neutral point occurs  

  •     Magnetic field due to infinite wire is μoI / 2π r
  •  We have at neutral point net magnetic field is zero
  • Therefore we have magnetic field due to wire is equal to magnetic field due to earth.
  • So I = 10 A
  • So we get  Magnetic field will be
  •   Substituting the values we get   2 x 10^-7 = μo x 10 / 2 π r
  •                 2 πr x 10^-7 = 5 μo
  •                Or r = 5 μo / 2π x 10^-7
  •                Or r = 5 x 4π x 10^-7 / 2π x 10^-7
  •                Or r = 10 m
  • Magnetic field due to wire will be MOVING against the magnetic field due to earth in the east direction and hence both will cancel each other.

Reference link will be

brainly.in/question/23296041

19.

A point mass 1 kg moving with velocity 8 m/s collides elastically with stationary point mass of 5kg. After their collision, the 1 kg body reverses itsdirections and move with a speed of 2 m/s. Thevelocity of 5 kg body is​

Answer»

only POSSIBLE if the COLLISION is ELASTIC

20.

एक आदर्श गैस, जिसका दाब P, आयतन V तथा ताप T है, को रुद्धोष्मतः विस्तारित किया जाता हैकि उसका आयतन 4V हो जाता है और ताप गिरकरT/2 हो जाता है। गैस का रुद्धोष्म घातांक है:(A) 1.66(B) 1.50(C) 1.40(D) 1.33​

Answer»

ong>ANSWER:

FIND into the DOUBT your answer will be find in this apps

21.

Ifuv = y then find y' (2) if u (2) =3 u' (2) = 4v(2)=1 and v'(2)=2​

Answer»

a ISKA mareko VI NAA patahhbbz BZ

22.

State Fleming left hand rule. how it can be used in our daily life. give an example.​

Answer»

ong>Answer:

FLEMING's left-hand RULE is USED for electric motors, while Fleming's right-hand rule is used for electric GENERATORS. Different hands need to be used for motors and generators because of the DIFFERENCES between cause and effect.

Explanation:

23.

The principle of rest and recovery holds that you need to give your muscles time to rest and recover after a workout. True False

Answer» ONG>Answer:

TRUE

Explanation:

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24.

Question: a = 4.3 ± 0.1 and b= 0.18 ± 0.05 then a * b = ?Answer: 0.77 ± 0.2Explain ​

Answer» ONG>EXPLANATION:

YES I am marathi

u are from

25.

State and prove principle of parallel axis​

Answer»

rong>ANSWER:

The moment of inertia of a RIGID BODY about any axis is equal to the sum of its moment of inertia about a parallel axis through its centre of MASS and the PRODUCT of the mass of the body and the square of the distance between the two axes.

26.

Pick the four muscles that make up the Quadriceps(quads) Vastus intermedius Vastus medialis Vastus lateralis Rectus femoris Rectus abdominis

Answer» ONG>ANSWER:

the VASTUS lateralis, vastus medialis, vastus intermedius, and the RECTUS femoris.

27.

If a triode, the ratio of small charge in plate voltage and small changes in grid voltage is , if plate current is constant???

Answer»

Explanation:

the RATIO of SMALL charge in PLATE VOLTAGE and small changes in grid voltage is , if plate current is constant

28.

What is valency of elements having atomic number 5to15

Answer»

atomic number of this ELEMENT is 15, so its ELECTRONIC configuration will be K L M2, 8, 5. ... Since ONE atom of this element needs 3 electrons to achieve the INERT gas electron configuration, therefore, its valency is 3.

good MORNING

29.

State Newton second law of motion and drive it mathematically​

Answer» ONG>ANSWER:

ya relly newton second law of motion falling a APPLE in a tree

30.

Astronomical unit (AU) is the average distance between the earth and sun, approximately 1.5 x 100 km.The speed of light is about 3.0 x 108 m/s. The speed oflight in astronomical unit per minute is​

Answer»

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Astronomical unit (AU) is the average distance between the earth and SUN, approximately 1.5 x 100 km. The speed of light is about 3.0 x 10 m/s. The speed of light in astronomical unit per minute is (a) 0.012 AU/min (b) 0.12 AU/min (c) 1.2 AU/min (d) 12.0 AU/min (AMU (Med.))

31.

Pick the three muscles that make up the Calves Gastrocnemius Soleus Trapezius Peroneus Longus

Answer»

ong>ANSWER:

Gastrocnemius and Soleus

Explanation:

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32.

. A person needs a lens pf of power -5.5D for correcting his distant vision. For correcting his near vision, he needs a lens of power +1.5D. Calculate the focal length of the lenses used in these two cases.​

Answer»

Given:-

  • Power of lens ,P = -5.5D

  • Power of lens , P = 1 .5 D

To Find:-

  • Focal length ,f in both case.

Solution:-

As we know that Power of lens is defined as the reciprocal of its focal length

→ P = 1/f

calculating focal length of 1ST lens

→ P₁ = 1/f₁

Substitute the value we get

→ -5.5D = 1/f

→ -5.5 ×f = 1

→ f₁ = 1/(-5.5)

→ f₁ = -0.18 m

The focal length of 1st lens is 0.18m.

Now Calculating focal length of 2nd lens

→ P₂ = 1/f₂

Substitute the value we get

→ 1.5 = 1/f₂

→ 1.5×f₂ = 1

→ f₂ = 1/1.5

→ f₂ = 0.06 m

The focal length of 2nd lens is 0.06 metre.

33.

Prove the theroem of perpendicular axes​

Answer»

ong>EXPLANATION:

The theorem STATES that “the moment of inertia of a plane lamina about an axis perpendicular to its plane is equal to the SUM of the moments of inertia of the lamina about any TWO mutually perpendicular axes in its plane and intersecting each other at the point where the perpendicular axis passes though it.”

34.

Muscle contractions can be isotonic or isometric True False

Answer»

ong>ANSWER:

True

Explanation:

Beacuse, A muscle contraction is isometric if muscle TENSION CHANGES, but muscle length remains the same. and . It is isotonic if muscle length changes, but muscle tension remains the same.

Hope it will help U

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35.

Muscle contractions can be isotonic or isometric. Question 2 options: True False

Answer» ONG>Answer:

A is your CORRECT answer

question 2 ?

36.

Two beakers have water at 1°c and 3°c respectively?Which of the two beakers contains more dense water?​

Answer» ONG>Explanation:

1st BEACKER which is 1° c CONTAIN more densed WATER.

37.

Write down the uses of endoscope ​

Answer» ONG>Explanation:

Endoscopy is a nonsurgical procedure used to examine a PERSON's DIGESTIVE tract. Using an ENDOSCOPE, a flexible tube with a light and camera attached to it, your doctor can view pictures of your digestive tract on a color TV monitor.

38.

1 question- If the focal length of a lens is 12.6 cm find its power 2 question If the focal length of a lens is 17.48 cm find its power

Answer»

ong>EXPLANATION:

given FOCAL length = 12.6

find power....

we KNOW that ,

power = 1/f

so power p = 1/12.6 = 0.0793650794

hope it HELPS you guys

39.

at what diatance from concave mirror of focal length 10 cm should an object 2 cm long be placed in order to get an erect image 6 cm​

Answer»

>Given

Focal length of concave mirror f = -10 cm

Height of the object ho = 2 cm

Height of the image hi = 6 cm

We need to find the object distance

So we know that

Magnification m = hi/ho = 6/2 = 3 (erect image)

m = -v/u

3 = -v/u

⇒ v = -3u

Let US now CONSIDER

Mirror FORMULA: 1/v + 1/u = 1/f

1/(-3u) + 1/u = 1/(-10)

⇒ u = -20/3 = -6.7 cm

So At -6.7cm distance from a concave mirror of focal length 10cm should an object 2cm long be placed in order to GET an erect image 6cm tall.

40.

What is concept of radius gyration​

Answer»
41.

A car travels up a hill at a constant speed of 37 km/h and returns down the hill at a constant speed of 66 km/h. Calculate the average speed for the whole trip

Answer» ONG>Answer:

The average SPEED is the ratio of total traveled distance to total time taken.

Let d be the total distance traveled by the car.

Thus distance traveled in each journey is d/2.

So, the time taken for going up the hill is t

1

=

v

1

(d/2)

=

37

d/2

=

74

d

Time taken for going down the hill is t

2

=

66

(d/2)

=

132

d

Thus, average speed is v

AVG

=

t

1

+t

2

L

=

(L/74+L/132)

L

=47.4km

42.

Your average velocity over a 10-min period is 2.2 m/s. Is it possible that you were at rest at some point during the 10 min?

Answer» ONG>EXPLANATION:

this is a your ANSWER

OK..

43.

Solve this numerical problem. ​

Answer»

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A solid of density p has weight W. Show that it's apparent weight will be [1-(pL/p)] when it is completely IMMERSED in a liquid of density pL.

\huge\mathbb\green{Aηswer:-}

Apparent weight of the solid = (Weight of solid in AIR) - (loss of weight of solid in liquid)

but, loss of weight of solid in liquid is equals to the weight of liquid displaced.

Thus, weight of liquid displaced is the product of Volume of solid and density of liquid.

∴ Volume  \: of  \: solid =  \:  \frac{W}{D}  \\

where,

weight of solid = W

density = D

but, density of liquid = d.

Thus, weight of liquid displaced = w.d / D = Loss of weight of solid into liquid.

∴ Apparent  \: weight =   \frac{W - W.d}{D}  \\

= W(1  -  \frac{ p_{1} }{p} ) \\ .

→ Hence, apparent weight of the solid is

= W(1  -  \frac{ p_{1} }{p} ) \\ .

44.

Organelle that help in cell division in animal cell with diagram​

Answer» EUS is the ORGANELLE tahu HELPS in CELL DIVISION

45.

Muscle hypertrophy refers to growth in the size of muscles and muscle fibers Question 1 options: True False

Answer»

ong>Answer:

The answer will be TRUE .

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46.

In which of the following the particles have highest of attraction? water, Nac1 (solid) ice and wax ​

Answer»

ong>EXPLANATION:

Nacl have the highest ATTRACTION force as it is a solid.

Thank U

47.

Having empathy helps you predict what others may feel. true or fales

Answer» SE having empathy HELPS you predictwhat others may feel.

Plss pls pls pls pls pls thank maximum 200answers or minimum 100 answers of mine as i want to reach my TARGET 5thoisand thanks whoever is watching pls pls pls thank in return U will get a follow for sure

48.

Koogle Test Level-3 (Unit-6) A force of 0.01 N is exerted on a charge of 1.2 x 10-5 C. at a certain point. The electric field at that point is A) 5.3 x 106 N/C B) 8.3 x 106 N/C C) 5.3 x 106 N/C D) 8.3 x 102 N/C

Answer» E applying

Formula:

e =  \frac{f}{q}

where e is electric field and f is FORCE.

f here is = 0.01N

q =

1.2 \times  {10}^{ - 5}

so,

\frac{0.01}{1.2 \times  {10}^{ - 5} }  \\ solving \: this \: we \: get \\ e = 8.3 \times  {10}^{2} n {c}^{ - 1}

HOPE this gonna help you ♡(∩o∩)♡

49.

Koogle Correct Incorrect Unattempted Self Assessment Test (Unit-6) The ratio of the forces between two small conducting spheres charged to constant potentials in (a) air (b) a medium of K= 2 is A) 1:4 B) 2:1 C) 1:2 D) 4:1

Answer» E you go♡(∩o∩)♡

Hope this will HELP you (๑・ω-)~♥”

50.

Ohms law is obeyed by​

Answer»

ong>ANSWER:

Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points. Introducing the constant of proportionality, the resistance,[1] one arrives at the usual MATHEMATICAL equation that describes this relationship:[2]

V, I, and R, the parameters of Ohm's law

{\displaystyle I={\frac {V}{R}},}I={\frac {V}{R}},

where I is the current through the conductor in units of amperes, V is the voltage measured across the conductor in units of volts, and R is the resistance of the conductor in units of ohms. More specifically, Ohm's law states that the R in this relation is constant, independent of the current.[3] Ohm's law is an empirical relation which accurately describes the conductivity of the VAST majority of electrically conductive materials over many orders of magnitude of current. However some materials do not obey Ohm's law, these are called non-ohmic.

The law was named after the German physicist Georg Ohm, who, in a treatise published in 1827, described measurements of applied voltage and current through simple electrical circuits containing various lengths of wire. Ohm explained his experimental results by a slightly more complex equation than the modern form above (see § History below).

In physics, the term Ohm's law is also used to refer to various generalizations of the law; for example the vector form of the law used in electromagnetics and material science:

{\displaystyle \mathbf {J} =\sigma \mathbf {E} ,}\mathbf {J} =\sigma \mathbf {E} ,

where J is the current density at a given location in a resistive material, E is the electric field at that location, and σ (sigma) is a material-dependent parameter called the conductivity. This reformulation of Ohm's law is due to Gustav Kirchhoff.[4]