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Solve this numerical problem. ​

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A solid of density p has weight W. Show that it's apparent weight will be [1-(pL/p)] when it is completely IMMERSED in a liquid of density pL.

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→ Apparent weight of the solid = (Weight of solid in AIR) - (loss of weight of solid in liquid)

→ but, loss of weight of solid in liquid is equals to the weight of liquid displaced.

→ Thus, weight of liquid displaced is the product of Volume of solid and density of liquid.

∴ Volume \: of \: solid = \: \frac{W}{D} \\

where,

weight of solid = W

density = D

but, density of liquid = d.

→ Thus, weight of liquid displaced = w.d / D = Loss of weight of solid into liquid.

∴ Apparent \: weight = \frac{W - W.d}{D} \\

= W(1 - \frac{ p_{1} }{p} ) \\ .

→ Hence, apparent weight of the solid is

= W(1 - \frac{ p_{1} }{p} ) \\ .


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