1.

Koogle Test Level-3 (Unit-6) A force of 0.01 N is exerted on a charge of 1.2 x 10-5 C. at a certain point. The electric field at that point is A) 5.3 x 106 N/C B) 8.3 x 106 N/C C) 5.3 x 106 N/C D) 8.3 x 102 N/C

Answer» E applying

Formula:

e = \frac{f}{q}

where e is electric field and f is FORCE.

f here is = 0.01N

q =

1.2 \times {10}^{ - 5}

so,

\frac{0.01}{1.2 \times {10}^{ - 5} } \\ solving \: this \: we \: get \\ e = 8.3 \times {10}^{2} n {c}^{ - 1}

HOPE this gonna help you ♡(∩o∩)♡


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