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The Biot-Savart's law GIVES the magnetic FIELD produced due to acurrent carrying segment. ... The magnitude of the magnetic field dB at a distance r from a CURRENT carryingelement dl is found to be proportional to I and to the length dl. And is inversely proportional to the SQUARE of the distance.

Pressure ::::-----


Pressure means how much something is pushing on something else. It is EXPRESSED as force per unit area:

P=F/A.

In technology, pressure is often specified in multiples of atmospheric pressure. It can also be defined as the thrust [compressive force acting perpendicularly to the surface of a body] acting per unit area.

Magnetic Force:::::::::-------


The force that ARISES due to the motion of charged particle WITHIN the magnetic field is KNOWN as the magnetic force. It is an outcome of the electromagnetic force. CONSIDER a charged particle located in the presence of both magnetic field and electric field. Then, the force experience

when the MILK TURNS into CURD  presence of lactose in milk converted into lactic acid the ph value is 4.5 MEANS SLIGHT acid

The acceleration DUE to gravity is INVERSELY proportional to the second power of the RADIUS of the EARTH. It is also directly proportional to the mass of the earth. The acceleration due to gravity is due to the gravitational force between the earth and any mass on earth.

The Einstein field equations (EFE; ALSO known as Einstein's equations) COMPRISE the set of 10 equations in Albert Einstein's GENERAL theory of RELATIVITY that describe the fundamentalinteraction of GRAVITATION as a result of spacetime being curved by mass and energy

hope this will help you

The magnetic FIELD of all the turns ofwire passes through the center of the coil, creating a strong magnetic fieldthere. ... Much stronger magnetic FIELDS can be PRODUCED if a "magneticcore" of a soft ferromagnetic (or ferrimagnetic) material, such as IRON, isplaced inside the magnet

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A PARTICLE moving at higher SPEED will need a greater radial force to change direction and vice-versa when the radius of the circular path is constant.... In either CASE , the angular VELOCITY in non-uniform circular motion is not constant as w=vr w= v r and v is varying

hope it helps you mark as brainliest

Kinetic energy= 1/2×m×v²

K.E(INITIAL) = 1/2×2×(18×5/18)²  {convenrting km/h to m/s}

K.E(Initial) = 25 J

Kinetic energy= 1/2× 2 ×(72×5/18)²

Kinetic energy= 400 J

Work DONE= FINAL K.E - Initial K.E

                  = 400 - 25

                  = 375 J

Isothermal compression requires heat transfer to the surroundings to maintain CONSTANT temperature, lowering the pressure of the system and thus lowering the RESISTANCE to compression COMPARED to the adiabatic compression (where heat exchange is not ALLOWED).

Frequency of LIGHT does not increase and REMAINS constant when it ENTERS a different MEDIUM as the energy of light is proportional to it's frequency.
but VELOCITY and wavelength changes

A spring stores ENERGY EQUAL to WORK done on it.So find work done on it.

When SALT is added to water, it weakens the water's magnetic field further, so that it ceases to have any significant effect on other MAGNETICFIELDS. HOWEVER, salt water conducts ELECTRICITY BETTER than non-salt water, so magnets placed near it can cause significant turbulence in the water.

I don't KNOW the ANSWER BEHIND it

HI

❇️ The sun APPEARS white at noon when it is directly overhead since:

At noon, LIGHT from the sun overhead travels a relatively SHORTER distance. Therefore, only very little blue and violet colours are scattered

Hope it PROVED to be BENEFICIAL...

PLEAS PROVIDE a PIC for more INSIGHT on the PROBLEM

work is an ACTIVITY involving a FORCE on an OBJECT and the distance traversed by the object due to the force. It can be measured by the CHANGE in energy. Energy is capacity of doing work.For example if a something has energy of x joule it can perform x joule work. Power is the work done in unit TIME.

Let the DIAMETER of the earth , x
Moon diameter is 30X
REVOLUTION in the year is =1 × 30x
=30x of the earth revolution/year.

E.g..ROLLER COASTER,it has both POTENTIAL ENERGY and KINETIC energy.PE

Yes of course a body have ZERO speed but non zero acceleration at an instant and one of the example is that in a projectile MOTION when the body is at its MAXIMUM height the vertical component of the VELOCITY is zero but the vertical component of acceleration is not zero it is equal to the acceleration due to gravity

All the points FALL on a particular surface is CALLED EQUIPOTENTIAL surface

Jgxjfz kkgxjgxx kgxigig HIX

⛦Hᴇʀᴇ Is Yoᴜʀ Aɴsᴡᴇʀ⚑
▬▬▬▬▬▬▬▬▬▬▬▬☟
❖➙

Birds don't get SHOCKED because they are not good conductors of electricity.

Their cells & TISSUES do not offer electrons an EASIER route than the copper wire they're already traveling along.

_________
Thanks...✊

Specular vs. Diffuse Reflection

The Role of Light to Sight

The LINE of Sight

The Law of Reflection

Specular vs. Diffuse Reflection

It was mentioned earlier in this lesson that light reflects off surfaces in a very predictable manner - in accordance with the law of reflection. Once a normal to the surface at the point of INCIDENCE is drawn, the angle of incidence can then be determined. The light ray will then REFLECT in such a manner that the angle of incidence is equal to the angle of reflection. This predictability concerning the reflection of light is applicable to the reflection of light off of level (horizontal) surfaces, vertical surfaces, angled surfaces, and even curved surfaces. As long as the normal (perpendicular line to the surface) can be drawn at the point of incidence, the angle of incidence can be measured and the direction of the reflected ray can be determined. A series of incident rays and their corresponding reflected rays are depicted in the diagram below. Each ray strikes a surface with a different orientation; YET each ray reflects in accordance with the law of reflection.

The Law of Reflection is Always Observed

(regardless of the orientation of the surface)

In physics class, the behavior of light is often studied by observing its reflection off of plane (flat) mirrors. Mirrors are typically smooth surfaces, even at the microscopic levels. As such, they offer each individual ray of light the same surface orientation. But quite obviously, mirrors are not the only types of objects which light reflects off of. Most objects which reflect light are not smooth at the microscopic level. Your clothing, the WALLS of most rooms, most flooring, skin, and even paper are all rough when viewed at the microscopic level. The picture at the right depicts a highly magnified, microscopic view of the surface of a sheet of paper.

Reflection off of smooth surfaces such as mirrors or a calm body of water leads to a type of reflection known as specular reflection. Reflection off of rough surfaces such as clothing, paper, and the asphalt roadway leads to a type of reflection known as diffuse reflection. Whether the surface is microscopically rough or smooth has a tremendous impact upon the subsequent reflection of a beam of light. The diagram below depicts two beams of light incident upon a rough and a smooth surface.


 

A light beam can be thought of as a bundle of individual light rays which are traveling parallel to each other. Each individual light ray of the bundle follows the law of reflection. If the bundle of light rays is incident upon a smooth surface, then the light rays reflect and remain concentrated in a bundle upon leaving the surface. On the other hand, if the surface is microscopically rough, the light rays will reflect and diffuse in many different directions.

During a chemical reaction, the atoms within a substance are REARRANGED into DIFFERENT combination.

For exm - sugar UNDERGOES a chemical change when it is cooked to make caramel

Hope it will help you... : )

PLZZZ mark my ans as brainliest...

Length of cylinder , L = 1.5m
diameter of base of cylinder , d = 4cm = 0.4m
so, RADIUS of base , r = 0.2m
FORCE , F = 4 × 10^5 N
rigidity modulus of the cylinder, Y = 6 × 10^10 N/m²

USE FORMULA, Y = FL/A∆L
∆L = FL/AY

A = πr² = 3.14 × (0.2)² = 3.14 × 4 × 10^-2
= 12.56 × 10^-2 = 0.1256 m²

so, ∆L = 4 × 10^5 × 1.5/(0.1256 × 6 × 10^10)

= 7.96 × 10^-5 m

Answer:

a. Between POINTS A and B: Between these points, x has negative value; it means the particle is to the left of the origin. But the value of x is DECREASING, so the particle is moving towards the origin. It means the velocity of the particle is positive. Between these points, the slope of the x-t graph is increasing; it means the magnitude of velocity is increasing. It means the velocity and acceleration both are in the same direction. So acceleration is positive. Note that acceleration is constant between A and B.

Also, the graph is concave up, so the acceleration is positive.

b.At point B: Particle is at origin at this point. At this point, the slope of the x-t graph is

maximum, so velocity is maxi-

mum at this point. Before point B, acceleration is positive, but after point B acceleration will be negative as the slope of the x-t graph will start decreasing after this fig.

We cannot define acceleration at point B.

c.Between points B and C: Between these points, x has a positive value; it means the particle is to the RIGHT of the origin. But the value of x is increasing, so the particle is moving away from the origin. It means the velocity of the particle is positive.

Between these points, the slope of the x-t graph is decreasing; it means the magnitude of velocity is decreasing. It means the velocity and acceleration are in opposite directions. So the acceleration is negative. Note that acceleration is constant between B and C.

Also, the graph is concave down, so acceleration is negative.

d.At point C: Particle is maximum away from the origin at this point. At this point, the slope of the x-t graph is zero, so velocity is zero. But acceleration is negative as the graph is concave down. At this point, the particle will change its direction of motion.

So after this, the particle will start moving towards the origin.

e.Between points C and D: Between these points, x has a positive value; it means the particle is to the right of the origin. But the value of x is decreasing, so the particle is moving towards the origin. It means the velocity of the particle is negative.

Between these points, the magnitude of the slope of the x-r graph is increasing; it means the magnitude of velocity is increasing but in the negative direction. So acceleration is negative. Note that acceleration is constant between C and D.

Also, the graph is concave down, so acceleration is negative.

f.At point D: Particle is to the right of the origin at this point. At this point, the slope of the x-t graph is negative maximum, so velocity is maximum at this point in the negative direction. Before point D, acceleration is negative, but after point D, the acceleration will be positive (as the graph is concave up after D). We cannot define acceleration at point D.

g. Between points D and E: Between these points, x has a positive value; it means the particle is to .the right of the origin. But the value of x is decreasing, so the particle is moving towards the origin. It means the velocity of the particle is negative.

Between these points, the magnitude of the slope of the x-t graph is decreasing; it means the magnitude of velocity is decreasing but in the negative direction. So, acceleration is positive. Note that acceleration is constant between D and E.

Also, the graph is concave up, so acceleration is positive.

Hey mate!

100 X DELTA g/g = d/Re x 100

2 =( d / 6400) x 100

d = 128km

hope it will HELP you. .

#Phoenix

Ecologically in a WAY that CONCERNS the relation of LIVING organisms to one another and to their physical surroundings.

⭐⭐⭐hey MATE!

WORK done = F.Scos theta

So,

The work done is also proportional ti force as WELL as DISPLACEMENT..

Your question is incomplete. A complete question is -----> A POINT OBJECT is placed at a distance of 25cm from a convex lens of focal length 20CM. Where will the image form at?

solution, focal length of lens , f = 20cm [ GIVEN lens is convex lens.]
object distance , u = -25cm

use formula,
1/v - 1/u = 1/f

1/v - 1/-25 = 1/20

1/v = 1/20 - 1/25 = 1/100

v = 100cm

hence, image is formed at 100cm, if object is placed at 25cm from a convex lens of focal length 25cm .

⚡Hey mate⚡

✨Here is your answer✨

What is error - :


An error is something you have done which is considered to be incorrect or wrong, or which should not have been done.

Type of error - :

There are three types of error: syntax errors, LOGICAL errors and run-time errors. (Logical errors are also called semantic errors). We discussed syntax errors in our note on DATA type errors.

Generally errors are classified into three types: systematic errors, random errors and blunders. GROSS errors are caused by MISTAKE in using instruments or meters, calculating measurement and recording data results.

I hope it's helpful for you. Thank you ❤️❤️

HOPE it will HELP you..

Hey MATE!

if at TWO INSTANT t1 abd t2 ..

if PARTICLE is at same HEIGHT , the height of particle at instant is always equal to

y = g/2 (t1t2)

y = 10/2(2*10)

y = 100m

hope it will help you

#Phoenix

A transistor has two p-n junctions. The batteries should be connected such that one junction is FORWARD biased and the other is reverse biased. A PN junction DIODE is CREATED when a p-type semiconductor is combined to an n-type semiconductor forming a potential barrier VOLTAGE ACROSS the diode junction.

P=U X I

so for BULB 1:

220 x 0.5 = 110W

U/I = R

so for bulb 2:

5 x 0.5 = 2.5W

5 / 0.5 = 10 ohms

hope it helped...have a NICE day!

Do you WANT the VALUE ..

Hey mate UR ANSWER is here
The impulse experienced by the OBJECT equals the change in momentum of the object.

It's VALUE will b HALF of value of gravitational POTENTIAL ENERGY.