1.

A cylinder of length 1.5 m and diameter 4cm is fixed at one end. A tangential gorse of 4x10^5N is applied at the other end. If the rigidity modulus of the cylinder is 6x10^10 Nm^-2 then, calculate the twist produced in the cylinder .

Answer»

Length of cylinder , L = 1.5m
diameter of base of cylinder , d = 4cm = 0.4m
so, RADIUS of base , r = 0.2m
FORCE , F = 4 × 10^5 N
rigidity modulus of the cylinder, Y = 6 × 10^10 N/m²

USE FORMULA, Y = FL/A∆L
∆L = FL/AY

A = πr² = 3.14 × (0.2)² = 3.14 × 4 × 10^-2
= 12.56 × 10^-2 = 0.1256 m²

so, ∆L = 4 × 10^5 × 1.5/(0.1256 × 6 × 10^10)

= 7.96 × 10^-5 m



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