Saved Bookmarks
| 1. |
The work required to increase the velocity of a particle from 18 km per hour to 72 km per hour if mass of particle is 2 kg is |
|
Answer» Kinetic energy= 1/2×m×v² K.E(INITIAL) = 1/2×2×(18×5/18)² {convenrting km/h to m/s} K.E(Initial) = 25 J Kinetic energy= 1/2× 2 ×(72×5/18)² Kinetic energy= 400 J Work DONE= FINAL K.E - Initial K.E = 400 - 25 = 375 J |
|