1.

The work required to increase the velocity of a particle from 18 km per hour to 72 km per hour if mass of particle is 2 kg is

Answer»

Kinetic energy= 1/2×m×v²

K.E(INITIAL) = 1/2×2×(18×5/18)²  {convenrting km/h to m/s}

K.E(Initial) = 25 J

Kinetic energy= 1/2× 2 ×(72×5/18)²

Kinetic energy= 400 J

Work DONE= FINAL K.E - Initial K.E

                  = 400 - 25

                  = 375 J



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