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the sun RISES and sunset , sun have very far away from Earth and red from sun have very longer wavelength while other LIGHTS from VIBGYOR get scattered in DIFFERENT directions, so sun appears red.

Hey mate here your answer Explanation:Let US consider that the maximum height covered by the projectile is H and the angle of projection is θ.It is given that,v_{H}=\sqrt{\frac{2}{5}} v_{H / 2}v H = 52 v H/2 So the maximum height of a projectile motion can be found asH=\frac{u^{2} \sin ^{2} \theta}{2 g} \quad \rightarrow(1)H= 2gu 2 sin 2 θ →(1)In the above equation, u is the initial velocity and g is the acceleration DUE to gravity.We know that velocity at maximum height is v_{H}=u \cos \thetav H =ucosθSquaring on both SIDES, we get v_{H}^{2}=u^{2} \cos ^{2} \theta \quad \rightarrow(2)v H2 =u 2 cos 2 θ→(2)From Newton’s second law of motion:v^{2}=u^{2}-2 a s \quad \rightarrow(3)v 2 =u 2 −2as→(3)We can substitute v=v_{H / 2}v=v H/2 , as the velocity at half the maximum height and displacement (s) can be replaced by half the maximum height, i.e., \mathrm{s}=\mathrm{H} / 2\ in\ (3)s=H/2 in (3)v_{H / 2}^{2}=u^{2}-2 g\left(\frac{H}{2}\right) \quad \rightarrow(4)v H/22 =u 2 −2g( 2H )→(4)The H in eqn (4) can be replaced with the value of H in eqn (1)v_{H / 2}^{2}=u^{2}-2 g\left(\frac{\frac{u^{2} \sin ^{2} \theta}{2 g}}{2}\right) \quad \rightarrow(5)v H/22 =u 2 −2g( 22gu 2 sin 2 θ )→(5)v_{H / 2}^{2}=u^{2}-2 g\left(\frac{u^{2} \sin ^{2} \theta}{4 g}\right) \quad \rightarrow(6)v H/22 =u 2 −2g( 4gu 2 sin 2 θ )→(6)It is given that v_{H}=\sqrt{\frac{2}{5}} v_{H / 2}v H = 52 v H/2 So squaring on both sides, we get v_{H}^{2}=\frac{2}{5} v_{H / 2}^{2} \rightarrow(7)v H2 = 52 v H/22 →(7)So, substitute eqn (2) and eqn (6) in eqn (7)u^{2} \cos ^{2} \theta=\frac{2}{5}\left[u^{2}-2 g\left(\frac{u^{2} \sin ^{2} \theta}{4 g}\right)\right]u 2 cos 2 θ= 52 [u 2 −2g( 4gu 2 sin 2 θ )](We know that, \cos ^{2} \theta+\sin ^{2} \theta=1cos 2 θ+sin 2 θ=1 )\therefore u^{2}\left(1-\sin ^{2} \theta\right)=\frac{2 u^{2}}{5}\left[1-2\left(\frac{\sin ^{2} \theta}{4}\right)\right]∴u 2 (1−sin 2 θ)= 52u 2 [1−2( 4sin 2 θ )]\left(1-\sin ^{2} \theta\right)=\frac{2}{5}\left[1-\left(\frac{\sin ^{2} \theta}{2}\right)\right](1−sin 2 θ)= 52 [1−( 2sin 2 θ )]1-\sin ^{2} \theta=\frac{2}{5}-\frac{1}{5} \sin ^{2} \theta1−sin 2 θ= 52 − 51 sin 2 θ\frac{1}{5} \sin ^{2} \theta-\sin ^{2} \theta=\frac{2}{5}-1 51 sin 2 θ−sin 2 θ= 52 −1-\frac{4}{5} \sin ^{2} \theta=-\frac{3}{5}− 54 sin 2 θ=− 53 \sin ^{2} \theta=\frac{3}{5} \times \frac{5}{4}sin 2 θ= 53 × 45 \sin ^{2} \theta=\frac{3}{4}sin 2 θ= 43 \therefore \sin \theta=\frac{\sqrt{3}}{2}∴sinθ= 23 \bold{\therefore \theta=\sin ^{-1}\left(\frac{\sqrt{3}}{2}\right)=60^{\circ}}∴θ=sin −1 ( 23 )=60 ∘ Thus the angle of projection is 60°.

same as no EFFECT on ACCLERATION

the VELOCITY is DETERMINED by the FREQUENCY of the SOUND WAVE

END HERE YOUR ANSWER HEY FRIEND HERE YOUR ANSWER In the PIC HEY FRIEND HERE YOUR ANSWER In the pic I hope its help you if my answer is helpful for us so PLEASE mark my answer in brainiestHEY FRIEND HERE YOUR ANSWER In the pic I hope its help you if my answer is helpful for us so please mark my answer in brainiestthank you

Equation of trajectory of an projectile which is projected at some angle with HORIZONTAL is given BYY = xtan\theta(1 - \frac{x}{R})here\theta = angle with horizontalR = horizontal rangenow we have equation given as3y = 4X - 15x^2now we have3y = 4x(1 - \frac{15x}{4})y = \frac{4}{3}x (1 - \frac{x}{0.267})now if we compare it with the equation of trajectory then we will havetan\theta = \frac{4}{3}R = 0.267 meterso range of the projecti

when it is RELEASED from the bow the POTENTIAL energy BECAME KINETIC energy

you have a 100G mixture of O2 and H2.20% i.e. 20g will be H2 and the REST i.e. 80g will be O2.Thus 1g of mixture will have 0.2 and 0.8 hydrogen and oxygen, respectively.Molar mass of h2 molecule is 2 (atomic mass 1*2 atoms= 2) and that of O2 is 32Thus by gram MOLECULAR mass theory, 2g H2 will have 1 mole h2 molecules and therefore 0.2g should have 0.1mole = 6.02*10^22Similarly on solving for o2, we GET 1.505*10^21 molecules.Add the 2 values to get TOTAL number of molecules in 1g of that mixture.

What conclusion can you draw about the velocity of a body from the displacement-time GRAPH SHOWN below :

tion:The following equation holds for constant acceleration:v1^2=V2^2+2as where:v1 = initial velocityv2 final velocity ( after acceleration or deceleration period)\s = distance traveledSo in our case v1 = 100 m/s ( in the firs case, the bullet comes to a STOP).s= 1mSo v1^2 = 2as Therefore, a = v1^2/2s = 100^2/(2*1) = 5000 m/s^2 v1 = 100 m/s , and a = 5000 m/s^2 ( assuming the same material as in the firs case so the DECCELERATION is the same)then :v1= 100 , v2 =?s= 0.5mand 100^2= v2^2+2*a*s=v2^2+2*5000*0.5 = v2^2+5000Hence: v2^2 = 10000-5000 = 5000and v2= SQRT(5000) = 71 m/s.The emerging velocity for 0.5 m is 71 m/s.

chesExplanation:the stopwatches are DESIGNED that a way that they can ACCURATELY MEASURE time INTERVALS

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10/piExplanation:t=s/v=pi*r/5=pi(r=5 GIVEN)so acceleration=change in velocity/time taken=-5-(5)/pi=-10/pi m/s2.

Three blocks of masses M1, M2 and m3 are CONNECTED as shown in FIGURE. All the surfaces are frictionless and the string and the pulleys are light. Find the acceleration of m1

y Good morning ASTRONOMERS think SPACE outside of the observable universe MIGHT be an infinite expanse of what we SEE in the cosmos around us, distributed pretty much the same as it is in the observable universeHope it help you PLEASE mark me please #sibi

tion:because the BEE injects ACID and metals are BASIC in nature . That's why we rub METAL key on bee STING

you will BELIEVE GOST MEANS GOD is there if U not then no

a) is CORRECT not CONFIRMED

Because of the heat generated due to friction between 2 or more parts of a MACHINE, they may get overheated and thus, can possibly DAMAGE the machinery

tion:when passenger was INSIDE the train the body of passenger was at motion due to contact with train when he jumps out his body immediately comes to REST due to INERTIA of rest and he falls down.HOPE IT WILL HELP YOU!PLZ MARK ME AS BRAINLIEST PLZZZZZZZZZZZZZ.

I am not sureExplanation:

They are SIBLINGSPLEASE MARK ME AS BRAINLIEST IF THE ANSWER IS CORRECT ❤️ ❤️ ❤️

Disadvantage:More ENERGY will be required to MOVE the body.More POWER is required to move the objectNoice is PRODUCED during frictionThanks!!❤

✍✍ Parallax is a displacement or DIFFERENCE in the APPARENT position of an OBJECT viewed along two different lines of SIGH. and is measured by the angle or semi-angle of inclination between those two lines.  ✍✍

Disadvantages of FRICTION are :More energy will be required to MOVE the body.More POWER is required to move the object.Noise POLLUTION is produced.Thanks!!❤

tion:The MAIN disadvantage of FRICTION is that it produces heat in various parts of machines. In this way some useful energy is wasted as heat energy....The disadvantages of friction are:#More energy will be REQUIRED to move the BODY.#Parts of machine might lose their shape.#Machine might STOP working properly.

0.15m/sExplanation:mass of BULLET= 10g= 0.01kgvelocity of bullet= 1.5m/smass of plank= 90g=0.09kgTotal momentum before collision=mass of plank X VELOCITY=0.01x1.5+0.09x0=0.015 kgm/sTotal momentum after collision=(mass of bullet +mass of plank )x velocity=0.1 KG x V=0.1 V kgm/sAccording to law of CONSERVATION of momentum,Total momentum before collision=Total momentum after collision0.015kg m/s =0.1 v kg m/sThus,velocity acquired by the plank and the bullet = 0.15m/shope it is correct and helpful to you  '-'

The ANS is CHLORINE

P = VIH = P × t = VItBut V = IR ( ohm's LAW) H = I^2Rt

now that PLASTIC is bad conductor of electricity and if we switch on or off the electricity will not PASSESS from our BODY .

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tion:1.SPEED = DISTANCE / TIME speed =120/2 speed= 60m/s 2.time =240/60 time= 4S

is 10Mass of ROPE = 23 votesmass of rope = 10×0.5 = 5kgForce = 25Na = F/m = 25/5 = 5 m/s2mass of rope remaining after 6m = 4M × 0.5 kg/m = 2kga = 5 m/s2 Tension at point 6m from

0.5 VOLT.[VIEW ATTACHED EXPLANATION]

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