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A particle is projected in vertical plane follows the plane |
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Answer» Equation of trajectory of an projectile which is projected at some angle with HORIZONTAL is given BYY = xtan\theta(1 - \frac{x}{R})here\theta = angle with horizontalR = horizontal rangenow we have equation given as3y = 4X - 15x^2now we have3y = 4x(1 - \frac{15x}{4})y = \frac{4}{3}x (1 - \frac{x}{0.267})now if we compare it with the equation of trajectory then we will havetan\theta = \frac{4}{3}R = 0.267 meterso range of the projecti |
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