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a bullet having a mass of 10 gram and moving with a speed of 1.5 metre per second penetrates a thick wooden plank of mass 90 gram the plank was initially at rest the bullet gets embedded in the plank and both move together.... determine the velocity |
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Answer» 0.15m/sExplanation:mass of BULLET= 10g= 0.01kgvelocity of bullet= 1.5m/smass of plank= 90g=0.09kgTotal momentum before collision=mass of plank X VELOCITY=0.01x1.5+0.09x0=0.015 kgm/sTotal momentum after collision=(mass of bullet +mass of plank )x velocity=0.1 KG x V=0.1 V kgm/sAccording to law of CONSERVATION of momentum,Total momentum before collision=Total momentum after collision0.015kg m/s =0.1 v kg m/sThus,velocity acquired by the plank and the bullet = 0.15m/shope it is correct and helpful to you '-' |
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