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Disc :

Idisc=7M8×(2R)22=I1Idisc=7M8×(2R)22=I1

SOLID SPHERE :

M8=(43πr3)ρM8=(43πr3)ρ

ρ(43πr3)8=ρ43πr3ρ(43πr3)8=ρ43πr3

R2=r=radius of the solid sphereR2=r=radius of the solid sphere

Iss=(m8r2)×25Iss=(m8r2)×25

      =M8×(R2)2×25=I2=M8×(R2)2×25=I2

so that, 

I1I2=7M8×(2R2)225×M8×(R2)2=140

ANSWER:

OPTION B is CORRECT....

ANSWER:

D. will be correct ANSWERS

Explanation:

HOPE the answer will help you

Mark the answer BRAINLIESTS please

Answer:

D. will be correct ANSWERS

EXPLANATION:

HOPE the answer will HELP you

RELATIVE motion is the CALCULATION of the motion of an object with regard to some other moving or stationary object. For example, a person SITTING in an AIRPLANE is at ZERO velocity relative to the airplane, but is moving at the same velocity as the airplane with respect to the ground.

ANSWER:

answer is

EXPLANATION:

OPTION 3

piR/T

Answer:

option b or NON of the above

if ans is option b then the equation should b x=at +1/2bt^2

a=u initial VELOCITY so units is meter per SEC

and b is acceleration so units is meter per second square

if the question is correct then option d is correct.... most PROBABLY

Question:

24. A train 50 m long passes over a bridge at a  velocity of 30 km/h. If it takes 36 s to CROSS  the bridge, the LENGTH of the bridge will be

(a) 100 m

(b) 200 m

(c) 250 m

(d) 300 m​

Answer:

(c) 250 m.

Given:

The length of the train is 50 m.

The velocity of the train is 30 km/h.

The train takes 36 seconds to cross the bridge.

To find:

The length of the bridge.

Explanation:

The velocity of the train is 30 km/h.

∴ The velocity of the train in m/s _

The velocity of the train = The speed of the train = m/s.

The train takes 36 seconds to cross the bridge.

We know that,

Speed = (DISTANCE/Time)

⇒ Distance = (Speed × Time)

⇒ Distance  = ( × 36)

                     = (25 × 12)

                    = 300 m.

∴ Total distance covered by the train is 300 m.

The length of the train is 50 m.

∴ The length of the bridge is _

(300 - 50) m

= 250 m.

∴ The length of the train is 205 m.

Hence, option (c) 250 m, is the correct answer.

ANSWER:

There are two types of movement: ROTATION and translation and so there's two KINDS of inertia. The first and “classic” one is the inertia of translation, which makes objects FOLLOW on with constant SPEED. The second one is the inertia of rotation, which makes objects stay rotating with constant angular velocit

Explanation:

Percentage DECREASE in value of 'g' -

VARIATION in 'g'

Radius

- wherein

rate of decrease of gravity OUTSIDE the earth (H<

If

g will INCREASE by 2% .

EXPLANATION:

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Answer:

An antibiotic is a MEDICINE that STOPS the GROWTH of microorganisms and destroys them in the BODY.

Example - PENICILLIN.

ANSWER:

If lens is cut along the principal AXIS then there will be no change in the FOCAL length of lens. but it is cut perpendicular to principal axis, then focal length will be twice the ORIGINAL one

Explanation:

If lens is cut along the principal AXIS then there will be no change in the focal LENGTH of lens. but it is cut PERPENDICULAR to principal axis, then focal length will be twice the original ONE.

Answer:

When CURRENT flows through a CONDUCTOR, HEAT energy is generated in the conductor. The heating effect of an electric current depends on three factors:

The resistance, R of the conductor. A HIGHER resistance produces more heat.

The time, t for which current flows. The longer the time the larger the amount of heat produced

The amount of current, I. the higher the current the larger the amount of heat generated.

Hence the heating effect produced by an electric current, I through a conductor of resistance, R for a time, t is given by H = I2Rt. This equation is called the JOULE’s equation of electrical heating.

Explanation:

Answer:

when excess current flows, fuse wire melts and ELECTRICAL CIRCUIT breaks thus PREVENTS from overloading. if copper wire is used as fuse then as it has high melting point , when excess current flows in circuit then fuse wire MAY not melt thus all the electrical appliances GETS damaged.

Explanation:

ANSWER:

The minimum force required to START pushing a body up a ROUGH inclined plane is

F  

1

​  

=mgsinθ+μgcosθ ......(i)

Minimum force needed to prevent the body from sliding down the inclined plane is

F  

2

​  

=mgsinθ−μgcosθ ...........(ii)

DIVIDE (i) by (ii), we get

F  

2

​  

F  

1

​  

​  

=  

sinθ−μcosθ

(sinθ+μcosθ

​  

=  

tanθ−μ

tanθ+μ

​  

=  

2μ−μ

2μ+μ

​  

=3 (tanθ=2μ (given))

Explanation:

ANSWER:

EXPANSION in the length of the ROD is 1.38 m

Explanation:

As we know that expansion in length of the rod due to thermal expansion is given as

here we have

so we have

now we have

#Learn

Topic : Thermal expansion

brainly.in/question/7691860

ANSWER:

Hello

Explanation:

In the time s, in the observer COORDINATES, the object moves a distance VS. In the object's own coordinates, the distance to the mirror is ct. which is the Lorentz / Einstein formula. In other words, the object's time is slowed by a FACTOR of over time in the observer coordinate system.

ANSWER:

the unit of weight is kg.

so, ANYTHING which is 1 kg have same weight no MATTER it consumes more space or less.

ANSWER:

When RESISTANCE INCREASES then the HEAT produced increases cause resistance is directly PROPORTIONAL to heat.

Explanation:

★᭄ꦿ᭄ꦿFOLLOW ME★᭄ꦿ᭄ꦿ

ANSWER:

Wooden doors and windows are PAINTED as to AVOID the insects and TERMITES from damaging and eating up the wood.

Answer:

... PERCENTAGE errors in the measurements of a b and C are 1% 2% 3% ...Two metal cubes with 3 CM edges of COPPER and aluminium are arranged as shown: a) Find the total thermal curre… ... b) The ratio of the thermal CURRENT carried by copper cube to the aluminium cube. K(Cu) = 60 W/m-K. K(Al) = 40 W/m-K ... percentage errors in the measurements of a b and c are 1% 2% 3% ...Two metal cubes with 3 cm edges of copper and aluminium are arranged as shown: a) Find the total thermal curre… ... b) The ratio of the thermal current carried by copper cube to the aluminium cube. K(Cu) = 60 W/m-K. K(Al) = 40 W/m-K ... percentage errors in the measurements of a b and c are 1% 2% 3% ...Two metal cubes with 3 cm edges of copper

Convex Lens..

F= f

Hence . the focal length is the distance between the optical centre and f.

so.. when the lens is cut perpendicular to PRINCIPAL AXIS then it MEANS lens is divided into TWO parts from its diameter.

so. If lens is cut along the principal axis then there will be no change in the focal length of lens. but it is cut perpendicular to principal axis, then focal length will be twice the original one.

So focal length became twice the original (of cut halves)

Answer:

2m/s2

Explanation:

u = 20m

V = 30m

t = 5sec

a = v - u / t

a = 30 - 20 / 5

a = 10/5

a = 2m/s2

ANSWER:

MG xhnvh nbkhmmlhjvkbkn

Explanation:

mmsgnshdng SGS SOUND ARA nshd sedhd

CRITICAL point-ANGLE of INCIDENCE to angle of REFRACTION is 90°

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ANSWER:

annode

Explanation:

POSITIVE CHARGES

Explanation:

Work Done Against Gravity

Climbing stairs and lifting objects is work in both the scientific and everyday sense—it is work done against the gravitational force. When there is work, there is a transformation of energy. The work done against the gravitational force goes into an important form of stored energy that we will explore in this section.

(a) The weight attached to the cuckoo CLOCK is raised by a height h shown by a displacement vector d pointing upward. The weight is attached to a winding chain labeled with a force F vector pointing downward. Vector d is also shown in the same direction as force F. E in is equal to W and W is equal to m g h. (b) The weight attached to the cuckoo clock moves downward. E out is equal to m g h.

Figure 1. (a) The work done to lift the weight is stored in the mass-Earth system as gravitational potential energy. (b) As the weight moves downward, this gravitational potential energy is transferred to the cuckoo clock.

Let us calculate the work done in lifting an object of mass m through a height h, such as in Figure 1. If the object is lifted STRAIGHT up at constant speed, then the force needed to lift it is equal to its weight mg. The work done on the mass is then W = Fd = mgh. We define this to be the gravitational potential energy (PEg) put into (or gained by) the object-Earth system. This energy is associated with the STATE of separation between two objects that attract each other by the gravitational force. For convenience, we REFER to this as the PEg gained by the object, recognizing that this is energy stored in the gravitational field of Earth. Why do we use the word “system”? Potential energy is a property of a system rather than of a single object—due to its physical position. An object’s gravitational potential is due to its position relative to the surroundings within the Earth-object system. The force applied to the object is an external force, from outside the system. When it does positive work it INCREASES the gravitational potential energy of the system. Because gravitational potential energy depends on relative position, we need a reference level at which to set the potential energy equal to 0. We usually choose this point to be Earth’s surface, but this point is arbitrary; what is important is the difference in gravitational potential energy, because this difference is what relates to the work done. The difference in gravitational potential energy of an object (in the Earth-object system) between two rungs of a ladder will be the same for the first two rungs as for the last two rungs.

Converting Between Potential Energy and Kinetic Energy

Gravitational potential energy may be converted to other forms of energy, such as kinetic energy. If we release the mass, gravitational force will do an amount of work equal to mgh on it, thereby increasing its kinetic energy by that same amount (by the work-energy theorem). We will find it more useful to consider just the conversion of PEg to KE without explicitly considering the intermediate step of work. (See Example 2.) This shortcut makes it is easier to solve problems using energy (if possible) rather than explicitly using forces.

More precisely, we define the change in gravitational potential energy ΔPEg to be ΔPEg = mgh, where, for simplicity, we denote the change in height by h rather than the usual Δh. Note that h is positive when the final height is greater than the initial height, and vice versa. For example, if a 0.500-kg mass hung from a cuckoo clock is raised 1.00 m

ANSWER:

गोलीय दर्पण की फोकस दूरी ध्रुव और मुख्य फोकस के बीच की दूरी के बराबर होती है इसे F से दर्शाते हैं

Answer:

DIFFERENT elements have different factors affected by temperature

for example german silver RESISTANCE does not get DIFFERED by temperature

but carbon FILAMENT of bulb DECREASE with rise in temperature

if more resistance less short circuit and more is obstruction to electrons so when the collide they give more heat.when more heat than 1500 celcius more light

Explanation:

ANSWER:

I haven't give JEE MAINS EXAM yet SORRY

AAYE haye KYA law hai.......

Kash aisa SACH mai HOTA

Answer:

LESS than the FOCAL length

EXPLANATION:

hope it helpful for u..

ANSWER:

"Froth flotation method"

Explanation:

The ORE which is lighter it comes on the surface with TRUTH an Impurities are left behind...

Let a CHARGE of +10C placed at point A and of charge +40C paced at point B and a point between them where third charged placed be Q.

And the distance between both the CHARGES is 0.12 m i.e. distance between A and B is 0.12 m.

Now, assume that distance x from charge +10C.

→ F = (k q1 q2)/r²

F1 = [k (10)(Q)]/x² .....(eq 1)

F2 = [k (40)(Q)]/(0.12 - x)² ......(eq 2)

→ F1 = F2

→ [k (10)(Q)]/x² = [k (40)(Q)]/(0.12 - x)²

k and Q cancel throughout

→ 10/x² = 40/(0.12 - x)²

→ 10(0.12 - x)² = 40x²

→ 10(0.0144 + x² - 0.24x) = 40x²

→ 1(0.0144 + x² - 0.24x) = 4x²

→ 0.0144 + x² - 0.24x = 4x²

→ 3x² + 0.24x - 0.0144 = 0

→ 3(x² + 0.08x - 0.0048) = 0

→ x² + 0.08x - 0.0048 = 0

Using quadratic formula

D = b² - 4ac

→ (0.08)² - 4(1)(-0.0048)

→ 0.64 + 4(0.0048)

→ 0.0064 + 0.0192 = 0.0256

x = (-b ± √D)/2a

→ (-0.08 ± √0.0256)/2

→ (-0.08 ± 0.16)/2

→ (-0.08 + 0.16)/2

[negative one is neglected]

→ 0.04

Therefore, x is 0.04 m AWAY from a charge Q.

Coulomb's Law

According to it magnitude of force between two static point charges is

• directly proportional to PRODUCT of magnitude of charges

i.e. F q1 q2

• inversely proportional to square of distance between two charges

i.e. F 1/r²

→ F (q1 q2)/r²

→ F = (k q1 q2)/r²

ANSWER:

YUP its focal LENGTH also will be 15 cm

Explanation:

when any RAY comes from infinit and parallel to principal meets at focus

ANSWER:

use.... angle of PRISM + angle of deviation = angle of incident + angle of EMERGENCE

ANSWER:

it is FORMED DUE to REFRACTION ...............

The value of electric field is E = 5.1 x 10^11 NC^-1

Explanation:

E = kq / r^2

K = 9 x 10^9

E = 9 x 10^9 x 1.6 x 10^-19 C / (0.53 x 10^-10)^2

E = 5.1 x 10^11 NC^-1

F = Q E

F = -e E

It show that force and electric field are in opposite DIRECTION.

WHAT IS THE LAW OF TRIAD?

• A triad is a grouping of three elements in order of atomic mass.

WHAT DOES THE LAW STATE?

• The AVERAGE of the first and third elements' atomic masses is the atomic mass of the second element.
• Three elements of the triad had SIMILAR chemical properties.

LIMITATIONS

• Dobereiner could find only three TRIADS.
• It failed to ARRANGE all the then known elements in the FORM of triads.

ANSWER:

C. will be CORRECT ANSWERS

QUESTION:

How to convert km/h to m/s ?

Answer:

To convert km/h into m/s, we should MULTIPLY  with it. Such as_

Explanation:

To convert km/h to m/s we ALWAYS multiply the value by  and from m/s to km/h we multiply the value by

This is because,

1 km = 1000 m

1 hour = 3600 seconds

Let, the value be, N km/h.

Hence, in m/s we get,

Explanation:

taking NORTH side as positive X axis and WEST as positive y axis .( one can take any side as X and y or positive or negative )

v1 = 8i. and V2 = 6j

v1-v2 = 8i-6j

|v1-v2| = 10 m/s

only the students above 11 can understand this and this cannot be explained below CLASS 11 .

ANSWER:

IDK

Explanation:

ANSWER:

Given,

focal length, f = -15 cm

Distance of image, v = -10 cm

Distance of OBJECT, u =?

We know that,

1/v - 1/u = 1/f

So,

1/-10 - 1/u = 1/-15

So, -1/10 + 1/15 = 1/u

(-3 + 2)/30 = 1/u

-1/30 = 1/u

Therefore u = -30 cm

Thus object is placed 30 cm AWAY from the concave lens.

Negative sign shows that object is at 30cm in front of the lens.

Explanation:

Rate it 5 star. I had to make the diagram on my PC it took half an hour... Ask more questions related to physics your brother will there to HELP you. Jai Hind

samj me NAHI aaya please HINDI me lilho FIR PUCHO ok

ANSWER:

CENTER of gravity: The point of an object at which the WEIGHT is evenly dispersed and all sides are in balance. Center of gravity EQUATION: Take the sum of an object's moments and divide by the overall weight of the object. Moment: Product of the weight and its LOCATION as measured from a set point called the origin

Formula

(0°C × 9/5) + 32 = 32°F

32 DEGREES = 1 fahrenheit

it will DEFINITELY help U....

Answer:

2. will be CORRECT ANSWERS

EXPLANATION:

Mark the answer brainliests PLEASE