The coefficient of expansion of a rod of length 1m, at 27 degrees is v

1.	The coefficient of expansion of a rod of length 1m, at 27 degrees is varying with temperature as Alpha=2/T. The increment in length of the rod if its temperature increases from 27 to 327 is:
Answer» ANSWER: EXPANSION in the length of the ROD is 1.38 m Explanation: As we know that expansion in length of the rod due to thermal expansion is given as $dL = L_o \alpha dT$ here we have $\Delta L = \int L_o (\frac{2}{T}) dT$ $\Delta L = 2L_oLn(\frac{T_2}{T_1})$ so we have $L_o = 1m$ $T_2 = 600 k$ $T_1 = 300 k$ now we have $\Delta L = 2(1)Ln(\frac{600}{300})$ $\Delta L = 1.38 m$ #Learn Topic : Thermal expansion brainly.in/question/7691860