This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Initially a body of mass 200g is moving with velocity 5m/s and after 3s it's velocity increases to 50m/s.Find acceleration in the body and change in momentum of the body. |
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Explanation: a=50-5/3=>15 |
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| 2. |
Name one source of ac current and source of dc current |
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Answer» Answer: https://goo.gl/search/Source+of+AC+current+and+dc+current What are the sources of AC and DC current? - Quora AC by synchronous alternators and DC by Batteries. These are ACTUALLY you can say the main sources of AC and DC currents. AC is supplied by LOCAL electric COMPANY. DC is no longer supplied by the electric company HOWEVER you can easily convert DC from AC .it's your ans plzzz mark me brainliest and follow me on brainly ✌️✌️✌️ |
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| 3. |
Different between damped and undamped oscillation |
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Answer» OSCILLATION whose amplitude reduce with time are called damped oscillation. this HAPPENED because of the friction. in oscillation of its amplitude does not change with time they are called UNDAMPED oscillation. this undamped oscillation are only POSSIBLE friction is not present. |
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| 4. |
The position of a particle is given by y=x^3 .If k is constant then acceleration is |
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Answer» 2 isssssssss. the answer.... |
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| 5. |
In which decade was the American Institute of Electrical Engineers (AIEE) founded?A. 1850sB. 1880sC. 1930sD. 1950s |
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Answer» In YEAR 1884, The AMERICAN INSTITUTE of ELECTRICAL ENGINEERS found. ______________________Thanks❤️ |
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| 6. |
Which will get more energy secondary consumers or territory consumers? ANSWER FAST..... |
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Answer» Answer: The tertiary CONSUMERS are supposed to get more ENERGY in the FOOD CHAIN. They get their foods from secondary consumers and these tertiary consumers stay at the top of the food PYRAMID. |
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| 7. |
Initially a body moving with velocity 5 m/sand after 3s its velocity increases to 50 m/s. FindAcceleration in the body.The change in momentum ofthe body |
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Answer» Answer: 15 m/sec Explanation: a=Vf-Vi/t a=>50-5/3=>15 m/sec2 |
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| 8. |
Change the choice:1. Do you know the answer?2.The crowd is cheering the players.3. Who had filled the form?4.His behavior shocked us?5. dont pluck flowers. |
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Answer» Answer:
HOPE THIS ANSWER HELPS YOU.... |
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| 9. |
Frnds pls help me answer this question |
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Answer» cgjdlyeulcghsmMajcmfhebvgwnsgvdvfdj |
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| 10. |
Name 25 natural Luminos objects |
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Answer» Answer: Explanation: Some EXAMPLES of luminous objects are a burning CANDLE, a light bulb, the SUN and other STARS, fluorescent MATERIALS and tube lights, among other things. |
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| 11. |
calculate the area of cell of a wire of length 2 metre its resistance is 25 ohm and the resistivity of material of a wire is 1.48 into 10-6 |
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Answer» Hohfxohxigohufzphe#'9$*9)"6-68:/*8jr |
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| 12. |
Tides rise on the sea,why ? |
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Answer» Tides are CAUSED by the GRAVITATIONAL attraction of the Moon. |
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| 13. |
A force of 5 Newton's acts on a body of weight 9.8Newtons.What is the acceralation produced in m/sec2 |
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Answer» Answer: 5 m PER sec2 Explanation: W=mg =>m=W/g m=9.8/9.8=1 kg F=ma =>a=F/m a=5/1=5 m/sec2 |
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| 14. |
If a force of 12 N is applied over an area of 3cm square and 13mm square calculate the pressure |
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Answer» the FORMULA is pressure=force /AREA =force÷area |
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| 15. |
What do you mean by musical sound |
Answer» MUSICAL SOUND, any tone with characteristics such as controlled pitch and TIMBRE. The sounds are PRODUCED by instruments in which the periodic vibrations can be controlled by the performer.Explanation: |
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| 16. |
We know that the Earth is moving around the sun. When we look at the sky we see that the sun rises in the east, slowly moves towards the west and sets there. Why? Give a paragraph. |
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| 18. |
In electromagnetic theory quantity equation relates what |
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Answer» Explanation: Continuity equation is RELATED to mass conservation. ... Explanation: In electromagnetic theory, CHARGE conservation is a result of Maxwell's equation which states that DIVERGENCE of current DENSITY is equal to the negative rate of change of charge density. |
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| 19. |
If vector a is 223 and b is 457 what will be the answer |
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Answer» hdzxh,he,JFK vxigzifsfwifx8tifgsgisosdogd |
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| 20. |
explain what is meant by the equation g=G×M/R^2 where the symbols have their usual meanings. |
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| 21. |
Radha takes a bag of mass 6 kg from the ground and puts it in almirah at a heightof 2 m. What is the potential energy possessed by the bag? (Given g = 10 m/s). |
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Answer» EXPLANATION:PE= mgh =6•2•10 =120 |
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| 22. |
Solve this, ... .1. I am a 11 letter Indian .2. Last 3letters is part used inside the computer.3. 4, 5, 6 letters is used to store water..4. 1, 5, 4 is designing software.5. 3, 7, 6 is software company name.6. 2, 5, 6, 8, 11 is a soap name100% brain work. |
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Answer» I do not KNOW !!!!!!!!!! |
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| 23. |
a current of 0.9A is drawn of a electric bulb for 2minutes. The charge flowing through the circuit is? |
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Answer» Answer: 1.8 Explanation: Since =0.9 x 2
=1.8 |
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| 24. |
Question01-All surfaces are frictionless. |
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Answer» Answer: False Explanation: |
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| 25. |
How to find the velocity when spread energyi is given? |
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| 26. |
How to find normal reaction in vector form give solution? |
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| 27. |
How to convert millimetre square into metre square? |
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Answer» Explanation:
1mm square = 1mm× 1mm = 1/1000 msq× 1/1000msq = 1/10,00,000 METRE square (Ans.)
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| 28. |
How to determine internal resistance of a cell using potentiometer? |
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Answer» at a JUNCTION the sum of a potentiometer entering the junction is EQUAL to the sum of the current LEAVING the junction |
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| 29. |
How does the resistance of a conductor change with rise in temperature |
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Answer» ANSWER:RESISTANCE of a conductor increase with rise in conductor.. As it is directly PROPORTIONAL to that of the temperature.. |
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| 30. |
Amit is driving his car with a velocity of 72 kilometre per hour how much distance will he coverA. in one minute ?B. in 1 second? |
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| 31. |
Explain Newtons formula for velocity of sound .what is its limitations? |
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Answer» Explanation: According to Newton, when sound waves propagate in air, compression and rarefaction are formed. He assumed that the process is very SLOW and the heat produced during compression is given to surrounding and heat loss during compression is GAINED from surrounding. So the TEMPERATURE remains constant and sound waves propagate through an isothermal process. According to gas law (Boyle's law), PV = constant where, P = pressure V = volume of air Differentiating above equation, we get PdV + VdP = 0 PdV + VdP = 0PdV =- VdP PdV + VdP = 0PdV =- VdPP = -VdP/dV = dP/-(dV/V) P=B where, B is the bulk modulus of the air. If B is the bulk modulus of the air, v is VELOCITY and ρ is the density, then, velocity is given by: V=(B/ρ)^1/2 V=(B/ρ)^1/2hence V=(P/ρ)^1/2 This is the required expression for velocity of sound in air. Calculation of Velocity of air Now, the velocity of sound in air using Newton's formula at NTP (Normal Temperature and Pressure) is given by: Pressure (P)= 1.1013 * 105 N/m2 Density of air (ρ) = 1.293 kg/m3 Experimentally it has been found that the velocity of sound in air is 332 m/s. We can conclude that, there is some error in Newton’s assumption and it needs correction. Laplace Correction of Newton's Formula Laplace provided a correction for Newton’s formula. He assumed that, the process of compression and rarefaction occur very fast and no exchange of heat takes PLACE. Thus, the temperature doesn’t remain constant and the propagation of sound in gas is an adiabatic process. |
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| 32. |
A simple electic motor has an armature resistanc 0f 1 ohm and runs from a dc source of 12 V . It draws a current of 2 A when unloaded. When a certain load is connected to it , its speed reduces by 10% of its initial value. The current drawn by the loaded motor is |
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Answer» emf= V-IR ➡️ 12-2 = 10V ➡️ 10% of this emf is 1V ➡️ CURRENT is IR = 1X1= 1 ampere ➡️ current DRAWN by the loaded motor is 1+2=3A. |
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| 33. |
How many of the devices you identified inside the live audio room need electricity to operate? |
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Answer» I could find out more than 40 devices in the live audio room which needs electricity to operate the devices. Such devices are including televisionscreen,speakers,lights,microphones,COMPUTERS,dvd players,fans and etc... the live audio and controle ROOMS are connected by a cables to exchange the audio sound into digital data signal during recording,mixing and editing. So the entire procees can done by USING electricity.generators are also used in every where not only in live audio rooms.The generator operates using the principles of electromagnetic induction.Electricity is very important for working this devices. |
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| 34. |
A particle starts from the origin, goes along x axid to the point 10m,0 and then returns along the same line to the point -10m,0 |
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Answer» DISTANCE travelled = 10 + 10 + 10 = 30 m displacement = (10-10-10) = -10M
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| 35. |
Materials that allow electrons to flow through them are known as |
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Answer» Answer: MATERIALS that ALLOW electrons to FLOW through them are KNOWN as conductors of electricity hope it HELPED and please mark as brainliest:) |
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| 36. |
Coordinates of a particle moving in a plane at any time t are given by eq X= alpha t^2 and y= Betat^2 . Magnitude of the velocity of this particle is |
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Answer» HOPE it helps Plz MARK it as BRAINLIEST |
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| 37. |
buoyancy , factors affecting bouyant force, causes of buoyant force . Explain.( explain each topic c in 50 words) |
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Answer» Buoyancy is caused by differences in pressure acting on opposite SIDES of an object immersed in a static FLUID. The direction of the net FORCE due to the fluid is upward. ... Summary the density of the fluid, the volume of the fluid displaced, and. the local ACCELERATION due to gravity. |
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| 38. |
a force of 5 n acts on a 15 kg body initially at rest the work done by the force during the first second of motion of a body is |
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Answer» Gicen:- Force = 5N Mass = 15kg To find:- Work done by force during the 1st SEC. of motion. Solution :- a = a = a = We know, Work = Force × displacement W = Fs Work = 5 × Work = 5 × Work = 2.5 × Note:- The FRACTIONAL form of the answer is 5/6 J. However, on dividing further the answer would be 0.8333J. No worry about the answer mine is too correct! :) |
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| 39. |
A spherical mirror is cut in half horizontally .will an image be formed by the bottom half of the mirror? |
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Answer» yes bcos a MIRROR is an REFLECTIVE AGENT |
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| 40. |
If the vectorsĀ= 2 i +4 j and B = 5 i-p jare parallel to each other, the magnitude of B isa) 5/5b) 10c) 15d) 2/5 |
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Answer» Answer: 10 is answer Explanation: 2i X 5i i i will cut 2x5=10 |
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| 41. |
A simple pendulum with bob of mass m and conducting wire of length L swings under gravity through an angle 2theta. The earths magnetic field component in the direction perpendicular to swing is B . The max. PD induced across the pendulum is....... |
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| 42. |
if a ray of light is incident on a plane morror such that it makes an angle of 30 with the mirror ,then what will be the angle of reflection .ANS-60 i have one question that ans 60 so angle of incidence not equal angle of reflection .law of refraction says that is equal how is possible . please clear my problem |
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Answer» Light is known to behave in a very predictable manner. If a ray of light could be observed APPROACHING and reflecting off of a flat mirror, then the behavior of the light as it reflects would follow a predictable law known as the law of REFLECTION. The diagram below ILLUSTRATES the law of reflection.
In the diagram, the ray of light approaching the mirror is known as the incident ray (labeled I in the diagram). The ray of light that leaves the mirror is known as the reflected ray (labeled R in the diagram). At the point of incidence where the ray strikes the mirror, a line can be drawn perpendicular to the surface of the mirror. This line is known as a normal line (labeled N in the diagram). The normal line divides the angle between the incident ray and the reflected ray into two equal angles. The angle between the incident ray and the normal is known as the angle of incidence. The angle between the reflected ray and the normal is known as the angle of reflection. (These two angles are labeled with the Greek letter "THETA" accompanied by a subscript; read as "theta-i" for angle of incidence and "theta-r" for angle of reflection.) The law of reflection states that when a ray of light reflects off a surface, the angle of incidence is equal to the angle of reflection. |
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| 43. |
Give the reflex pathway of eye closing suddely of bright light |
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Answer» Reflexes are an essential part of protective and homeostatic function, both in general terms and with specific reference to ocular structures. A wide RANGE of stimuli and responses, with varying degrees of central processing, is INVOLVED in such reflexes. The simplest reflexes are monosynaptic, such as the stretch or myotatic reflex. More COMPLEX polysynaptic reflexes are involved in many regula- tory and protective functions - these INCLUDE auto- nomic as well as somatic reflexes. Ocular auto- nomic reflexes include the oculocardiac, pupillary, accommodative and lacrimatory reflexes. Ocular somatic reflexes include eyelid and extra-ocular muscle reflexes (such as Bell’s phenomenon, vestibulo-ocular and optokinetic reflexes) |
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| 44. |
Give some example of transition metals forming some compounds |
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Answer» Answer: Transition ELEMENTS are the elements PRESENT in the d-block of the periodic table. Some examples of transition elements are , Zinc Copper Platinum Chromium , etc transition elements ALSO exhibit variable VALENCY. Some examples for the compounds formed by transition elements are , ZnS CrO₅ AgNO₃ CuSO₄ FeO , etc hope it helped and please mark as BRAINLIEST:) |
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| 45. |
If+a+body+floats+with+quarter+of+its+volume+above+the+water+surface+then+its+density+will+be+(density+of+water+is+10+kg/m) |
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Answer» FIRST you correct the DENSITY of water density of water is 1000kg/m^3 The REQUIRED density of object is 250 kg/m^3 |
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| 46. |
How to locate the elements with atomic number higher than 100? |
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Answer» Answer: Explanation: The name is derived directly USING the atomic number of the element according to the numerical roots. The symbol for any element is given according to the atomic NUMBERS, for example; the element with atomic number Z= 102, has the symbol Unb, as ABBREVIATION for numerical root of digit 1 is u, 0 is N and for 2 is b. |
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| 47. |
Help me in this physics question |
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Answer» Answer: 0.905V Explanation: lambda = YD/ D = 4 * 10^-7m E = HC/ lambda = 3.105 EV STOPPING potential = 3.105 - 2.2 = 0.905V |
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| 48. |
a 5 watt bulb convert 80% of power into light photon of wavelength 660nm what is number of photon emitted from bulb in one second |
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Answer» Not UNDERSTANDING PLZ |
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| 49. |
A particle is fired with velocity u making 0 anglewith the horizontal. What is the change in velocitywhen it is at the highest point ? |
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Answer» =u^2/g |
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| 50. |
Electroststics all formulas |
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Answer» In these formulas, the unit of electric charge is amp seconds (ampsec, which is also called “coulomb”); its symbol is Q. One ampsec is the charge of 6.25×1018electrons or protons (ions). An amp is 6.25×1018 electrons/sec. Force is expressed in grams (technically gramweights). Lengths are in cm (although the recommended distance between sensor and sample is 1″ or 2.5 cm). Time is in seconds (sec). Basic measurements made with a SURFACE voltmeter: The term Vdisplayed refers to the number displayed on a surface voltmeter (electrostatic voltmeter). When the meter is held at the specified distance from a large sheet of metal (provided the sheet diameter is greater than 5x the specified distance), Vdisplayed is the voltage of that sheet, with respect to earth ground, in units of volts. For example, when using the handheld Surface DC Voltmeter Model SVM2 with the sensor disc 2.5 cm from the center of a metal sheet, a reading of “9.400” (kV) means that the sheet is at +9400 volts with respect to ground. If the sensor is brought closer, Vdisplayedwill be higher than the actual voltage. (If the measurement distance is other than 1 inch, or if the sample surface is small, formulas are given below to correct the reading.) The surface “voltage” of an electrostatically-charged insulator can also be measured in the same way. However, insulators behave differently from metals (conductors). When a surface voltmeter or any GROUNDED object is brought close to a charged insulator, the proximity will reduce the voltage of the insulator’s surface in that region. The voltage is approximately proportional to the distance between the grounded object and the insulator’s surface, multiplied by Q/A (the amount of charge per CM2 on the surface). In addition, the voltage varies from place to place across an insulator. (Compare this to the voltage of a metal sheet, which is always the same everywhere on the sheet.) For this reason, the “voltage” of an insulator is poorly-defined, Instead, either the total charge Q or the charge per unit area Q/A on the surface is usually the parameter measured on a charged insulator. If the SVM2 surface voltmeter’s sensor is held near an insulator with a uniform charge per area (Q/A), then Q/A = Vdisplayed x 3.6×10-14 (in ampsec/cm2), and the average voltage of the surface directly under the sensor is Vsurface = Vdisplayed x L/2.5 cm. However, the voltage is generally higher at other points on the surface, and the voltage will increase once the surface voltmeter is taken away. “L” is the distance between the sensor and the surface. Explanation: please mark it brainliest |
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