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A simple electic motor has an armature resistanc 0f 1 ohm and runs from a dc source of 12 V . It draws a current of 2 A when unloaded. When a certain load is connected to it , its speed reduces by 10% of its initial value. The current drawn by the loaded motor is

Answer»

ANSWER:

emf= V-IR

➡️ 12-2 = 10V

➡️ 10% of this emf is 1V

➡️ CURRENT is IR = 1X1= 1 ampere

➡️ current DRAWN by the loaded motor is 1+2=3A.



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