a force of 5 n acts on a 15 kg body initially at rest the work done by

1.	a force of 5 n acts on a 15 kg body initially at rest the work done by the force during the first second of motion of a body is
Answer» $\bf{\huge{\underline{\boxed{\rm{\red{Answer:}}}}}}$ Gicen:- Force = 5N Mass = 15kg To find:- Work done by force during the 1st SEC. of motion. Solution :- a = $\bf\large\frac{F}{m}$ a = $\bf\large\frac{<klux>5</klux>}{15}$ a = $\bf\large\frac{1}{3}$ We know, Work = Force × displacement W = Fs Work = 5 × $\bf\large\frac{1}{2}$ at² $\bf\underbrace{s=\:ut +1/2 at^2}$ Work = 5 × $\bf\large\frac{1}{2}$ × $\bf\large\frac{1}{3}$ × 1² Work = 2.5 × $\bf\large\frac{1}{3}$ × 1² $\bf{\large{\boxed{\underline{\rm{\pink{ Work = 0.8333 J}}}}}}$ Note:- The FRACTIONAL form of the answer is 5/6 J. However, on dividing further the answer would be 0.8333J. No worry about the answer mine is too correct! :)

a force of 5 n acts on a 15 kg body initially at rest the work done by the force during the first second of motion of a body is

Answer»

$\bf{\huge{\underline{\boxed{\rm{\red{Answer:}}}}}}$

Gicen:-

Force = 5N

Mass = 15kg

To find:-

Work done by force during the 1st SEC. of motion.

Solution :-

a = $\bf\large\frac{F}{m}$

a = $\bf\large\frac{<klux>5</klux>}{15}$

a = $\bf\large\frac{1}{3}$

We know,

Work = Force × displacement

W = Fs

Work = 5 × $\bf\large\frac{1}{2}$ at²

$\bf\underbrace{s=\:ut +1/2 at^2}$

Work = 5 × $\bf\large\frac{1}{2}$ × $\bf\large\frac{1}{3}$ × 1²

Work = 2.5 × $\bf\large\frac{1}{3}$ × 1²

$\bf{\large{\boxed{\underline{\rm{\pink{ Work = 0.8333 J}}}}}}$

Note:- The FRACTIONAL form of the answer is 5/6 J. However, on dividing further the answer would be 0.8333J. No worry about the answer mine is too correct! :)

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