Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

The curved speed time graph represent ________ accelerated motion.

Answer»

Non-accelerated MOTION

2.

under what conditions can a body travel a certain distance and yet its resultant displacement be zero?

Answer»

I THINK it should be in a VACCUM

3.

A car accelerates at a rate of 5m/s.find the increase in velocity in 2s

Answer» 10 m/s as we will MULTIPLY the ACCELARATION with TIME
4.

Difference between distance and displacement

Answer» DISTANCE is only LENGTH TRAVELLED
displacement INCLUDES the DIRECTION and length travelled
5.

Give one example where a for stops a moving body

Answer»

A ball COMING with a great SPEED stops when the goalkeeper give a force to STOP it with the hands .......

6.

calculate the amount of charge that would flow in 2hours through an element of an electric bulb drawing a current of 0.25 ampere

Answer» CHARGE = Current*time

= 0.25 * 2 * 60 *60 SECOND

= 0.54 * 3600

= 1944 Coulumb
7.

Distinguish between speed and velocity.?

Answer»

The short ANSWER is that velocity is the speed with a direction, while speed does not have a direction. Speed is a scalar quantity -- it is the magnitude of the velocity. Speed is MEASURED in units of distance DIVIDED by time, e.g. miles per hour, feet per SECOND, meters per second, ETC....

8.

Example of curvilinear motion

Answer»

When a PARTICLE travels along the CURVED PATH there is some motionoccurred which is calledcurvilinear motion. Someexamples of curvilinear motionare: Jeep travel in curved roadways, ... Running race in curved track.

9.

Why a magnet will not get attracted when we heat it?

Answer»

It don't get ATTRACTED because it lost its magnetism when heated.
Magnets are made up of atoms. In normal environmental conditions, these atoms align between the poles and foster magnetism. When exposed to hotter conditions, the PARTICLES within the magnet are MOVING at an INCREASINGLY faster and sporadic rate. This JUMBLING confuses and misaligns the particles, causing the magnetism to be lost.

10.

Plese tell me other example based on newtons law

Answer»

First law example:- The stone won't move unless someone moves it.
or
The soccer ball will not move until PLAYER KICKS it.

Second law example:- It takes less FORCE to move a DVD than a DVD player.
or
Push a large box and a small box with the same force, the small box will go faster.

Third law example:- A fireman turns on his hose & is knocked backwards.
or
If air is let out of a balloon QUICKLY, air PUSHES down & balloon goes up.

11.

How much force is required to lift a mass of 100g

Answer»

F = m * a
( FORCE) = (mass) into (acceleration)

there fore force REQUIRED to LIFT an object of mass 100 gm
= 0.1 * 9.8 ( acceleration DUE to gravity of earth)
= 0.98 N (NEWTON a unit use to measure force)

12.

A gun is mounted on a railroad car. The mass of the car, the gun, the shells and the operator is 50m where m is the mass of one shell. If the velocity of the shell with respect to the gun (in its state before firing) is 200 m/s, what is the recoil speed of the car after the second shot? Neglect friction.

Answer»

Thanks for asking the question!


ANSWER::


Centre of MASS of velocity of shell = 0 (initially at rest)


Therefore , 0 = 49 m x V + m x 200


V = -200/49 m/s


200/49 m/s towards left .


Another shell is FIRE , then the velocity of the CAR , with respect to platform is


V' = 200/49 m/s towards left


Another shell is fired , then the velocity of the car with respect to platform is


v' = 200/48 m/s towards left


Now , the velocity of the car with respect to earth is (200/49 + 200/48) = 19400/2352 = 8.24 m/s towards left.


Hope it HELPS!

13.

a wooden block of mass 0.6kg is on a rough horizontal surface. a force of 12N is applied to the block and it accelerates at 4m/sec^2 .what is the magnitude of the frictional force acting on the block

Answer»

Given:

A wooden block of mass 0.6kg is on a ROUGH horizontal surface. a FORCE of 12N is APPLIED to the block and it accelerates at 4m/s².

To find:

Magnitude of frictional force ?

Diagram:

\setlength{\unitlength}{1mm}\begin{picture}(5,5)\put(0,0){\framebox(15,15){\sf{m}}}\put(-20,-0.1){\line(1,0){55}}\multiput(-19,0)(3,0){19}{\qbezier(0,0)(-1,-1)(-2,-2)}\put(15,7.5){\vector(1,0){15}}\put(7.5,0){\vector(0,-1){15}}\put(4,-20){\sf{mg}}\put(7.5,15){\vector(0,1){15}}\put(6.3,31.5){\sf{N}}\put(0,0.2){\vector(-1,0){15}}\put(-17,1.3){\sf{f}}\put(32,6){\sf F}\end{picture}

Calculation:

Let the coefficient of KINETIC friction be \mu:

According to the FBD of the block:

\rm \therefore \: F - f = ma

\rm \implies\: 12 - f = (0.6) \times 4

\rm \implies\: 12 - f = 2.4

\rm \implies\: f = 12  - 2.4

\rm \implies\: f = 9.6 \: N

So, the frictional force acting on the block is 9.6 N.

14.

How do you find the focal length of a lens experimentally?

Answer»

In order to FIND the FOCAL length of a lens experimentally we have to use the UV method. The formula for focal length is the RATIO of product of UV to sum of UV.


Where U is the object distance and V is the image distance.


Take a candle and PLACE it 60cm away from a convex lens such that it lies ALONG the principal axis. Now the most important part is adjust the screen so that you can take the readings of image distance and object distance carefully. Finally after 3 to 4 readings you can find the focal length from the mean of the values.

15.

A ball of mass 50 g moving at a speed of 2.0 m/s strikes a plane surface at an angle of incidence 45°. The ball is reflected by the plane at equal angle of reflection with the same speed. Calculate(a) the magnitude of the change in momentum of the ball(b) the change in the magnitude of the momentum of the ball.

Answer»

THANKS for asking the question!


ANSWER::


Mass of BALL = 50 g = 0.05 kg


v = 2 cos 45° i - 2 sin 45° j


v₁ = -2 cos 45° i - 2 sin 45° j


(a) Change in momentum ⇒ m v = m v₁


⇒0.05( 2 cos 45° i - 2 sin 45° j ) - 0.05 ( -2 cos 45° i - 2 sin 45° j )


⇒0.1 cos 45° i - 0.1 sin 45° j + 0.1 cos 45° i + 0.1 sin 45° j


⇒0.2 cos 45° i


Therefore , Magnitude = √[0.2/√2]² = 0.2 / √2 = 0.2 / 1.4 = 0.14 kg m/s


(b) Change in magnitude of momentum of the ball = P(INITIAL) - P(final)

= (2 x 0.5) - (2 x 0.5)

= 0


Hope it helps!

16.

A body of mass 500 g, initially at rest, is acted upon by a force which causes it to move a distance of 4 m in 2 s. Calculate the force applied.

Answer»

ʜᴇʟʟᴏ ᴍᴀᴛᴇ!

First we will apply SECOND EQUATION of motion.

s = ut + 1/2 ( at² )

4 m = (0)(2) + 1/2( a )(2)²

4 = 2a

2 m/s² = acceleration


Now, convert g into kg = 500 / 1000 kg or 0.5 kg

As, Force = mass × acceleration
Or F = ma

Force = ( 0.5 kg )( 2 m/s² )
Force = 1 N

Hope it helps

17.

An automobile vehicle has a mass of 1500 kg. What must be the force between the vehicle and road if the vehicle is to be stopped with a negative acceleration of 1.7 m s

Answer»

┏─━─━─━─━∞◆∞━─━─━─━─┓ ✭✮ӇЄƦЄ ƖƧ ƳƠƲƦ ƛƝƧƜЄƦ✮✭ ┗─━─━─━─━∞◆∞━─━─━─━─┛

MASS 0f Vehicle ➾ 1500 N
➧ Acceleration ➾ -1.7 m/s²
➧ Force ➾ ? 

❱ F ➾ m × a

F ➾ 1500 Kg (-1.7 m/s²)
F ➾ -2500 Kg m/s²
F ➾ -2500 N ...✔

_________               THANKS...✊

18.

What is SI system of unit

Answer»

The System of UNITS which is at PRESENT INTERNATIONAL ACCEPTED for measurement in the is the system Internationaled units (France for international System of units ) abbreviated as SI.

Hope it helps you✌✌

Thankyou ☺☺

19.

Express 1 km/h into m/s

Answer»

A body MOVING ALONG a straight line at 20 m/s decelerates at the

rate of 4 m/s2

. After 2 SECONDS its speed will be equal to

20.

How are different materials grouped depending on the transparency, explain with two examples for each group

Answer»

Materials can be grouped into :

Transparent materials — They allow light to pass through them. Examples are GLASS and water.

Translucent materials — They allow little light to pass through. Examples are bitter paper and GROUND glass.

Opaque materials — They don't allow light to pass through them. They include STONE and wood.

21.

How the direction of magnetic field at a point be determined

Answer»

The right hand rule STATES that: todetermine the direction of themagnetic force on a positive MOVING charge, ƒ, point the thumb of the right hand in the direction of V, the fingers in the direction of B, and a PERPENDICULAR to the palm points in the direction of F.

22.

What do you know about centrifugal and centripetal force? ❌No spams ❌

Answer» CENTRIFUGAL force is not a real force. It is an INERTIAL force established so that Newtonian laws are valid when observing motion in an accelerated frame of REFERENCE. Centripetal force is the force that an OBJECT FEELS when is in a circular motion...!!☺☺
23.

Let us assume that you have lifted a suitcase and kept it on a table. On which of the following does the work done by you depend or not depend? Why?a) The path taken by the suitcase. b) The time taken by you in doing so.c) The weight of the suitcase. d) Your weight.

Answer»

I have lifted a suitcase and kept on the table. in this process I used muscular force .and you KNOW muscular forces are non CONSERVATIVE force. and non conservative force DEPENDENCE on path. but independent upon time takes.

hence, option '(c) time taken by you in doing so.'is CORRECT

24.

Why the cricket players moves his hand backwards on catching fast cricket ball

Answer»

This is related with 2nd law of MOTION .
Player MOVES his hand backward to increase the time during which the high velocity of moving ball DECREASES to zero.
as we know that force is INVERSELY proportional to time so when we increase the time the MOMENTUM of ball decreases which reduces the force exerted by the ball.
That's why player pulls his hand backwards.

25.

For a equilibrium shown. the strings are strong enough to withstand a maximum tension of 100 n. what is the largest value of w they can support

Answer»

HOPE this HELPS!!!The ANSWER is 35 N.

26.

Give reason: Threads or grooves are provided on the surface of the tyres.

Answer»

to increase FRICTION between ROAD and tyres to STOP QUICKLY

27.

for the acceleration time graph shown in figure the change in velocity of particle from t = 0 to t=6 seconds is

Answer»

Where is the FIGURE? ???

28.

the process by which solar kinetic energy is converted to chemical energy of carbohydrates is known as

Answer»

I THINK this PROCESS is PHOTOSYNTHESIS

29.

a crown made of gold and copper weighs 210g in air and 198g in water . the weight of gold in crown is

Answer»

the WEIGHT is 12g.

hope it HELPS..


30.

Give reasonsThe back of refrigerators are coloured dull black.

Answer»

So that the LIGHT does not PASS through it. it WORKS as a OPAQUE median who ABSORB light

31.

When a particle is projected at some angle to the horizontal, it has a range?

Answer» LET the angle is @.and INITIAL velocity=u
so range = u^[email PROTECTED]/g
32.

A stone and a piece of paper are dropped simultaneously from the same height on lunar surface,which one fall faster

Answer»

On LUNAR surface there is no friction from air. So, Both will reach the GROUND TOGETHER as only gravity WOULD be acting on them. There would be no other external force acting on them.

33.

List any four ways by which the knowledge of home sci help you in your day to day life

Answer»

I. The study of Home Science familiarizes us with the household PROBLEMS and the WAYS to solve them.

II. Home science is an art and science. It teaches us to do all the household jobs in a systematic and scientific manner.

III. It ALSO teaches us the art of managing jobs LIKE cleanliness, washing of clothes, etc. by spending LESS time and energy. 

IV. Home Science teaches us about the child development and human relationship. In child development, the students are taught about the physical, mental, social, and emotional development of the child.

34.

What do you mean by Refraction ?

Answer»

THE SPLITING OF LIGHT RAY WHEN IT PASSES FROM 1 MEDIUMS TO ANOTHER MEDIUM



HOPE IT HELPS YOU

35.

A flywheel of moment of inertia 5.0 kg.m² is rotated at a speed of 60 rad/s. Because of the friction at the axle, it comes to rest in 5.0 minutes.Find (a) the average torque of the friction (b) the total work done by the friction and (c) the angular momentum of the wheel 1 minute before it stops rotating.?

Answer»

Given in the question :-


Moment of Inertia = 5KG m

speed of rotation = 60 rad/s.


(a)Now we have to calculate the angular retardation (α)


Angular speed (initial) ⍵ =60 rad/s

Angular speed (final) ⍵' =0

Time, t = 5 min or 300 s.

Now , we know the formula

\omega' = \omega - \alpha t

0 = 60 - 300\alpha

\alpha =60/300

α = 0.20 rad/s²


Now we have

Moment of Inertia = 5.0 kg.m²


Hence, AVERAGE frictional torque = Iα

=5.0 × 0.20

\boxed{1 Nm
}

(b) Let the angle rotated


\theta = \omega \frac{1}{2}\alpha t^2

θ =60 × 300 - 0.50 × 0.20 × 300²

θ =18000 - 0.10 × 90000

θ =18000-9000

θ =9000 rad

Now , Work done is given as

W.D = Tθ

= 1.0 × 9000

\boxed{ W =9000 J
 }

(c) Assume that the angular speed at time 240 s will be ω''

\omega'' = \omega - \alpha t

ω'' = 60 - 0.20 × 240

ω'' =60 - 48

ω'' =12 rad/s


1 minute before stopping the wheel , now the angular momentum will be

= Iω''

= 5.0 × 12

\boxed{ 60 kg.m^2/s}



Hope it Helps :-)

36.

Suppose the rod in the previous problem has a mass of 1 kg distributed uniformly over its length,(a) Find the initial angular acceleration of the rod ?(b) Find the tension in the supports to the blocks of mass 2 kg and 5 kg ?

Answer»

GIVEN in the question :-

Mass of the rod = 1 kg.


(a)Now according to the formula we know that


\tau_n_e_t =   I_n_e_t + \alpha

Since mass is unifirmly distributed hence there is no DIFFERENCE in the torque .


Now the moment of Inertia of the pivoted

ml^2/12=

= 1× 1² /12

= 1/12 kg.m²


Therefore the total MI will be.

= 1.75 + 1/12

= 1.75+0.083

=1.833 kg.m²


Now we have to find the angular acceleration i.e α

\alpha = T/I

Put the given values

=1.5× 9.8/1.833

=8.0 rad/ s²


(b) Now for finding the Linear acceleration


a = \alpha r

=8.0 × 0.5

=4.0 m /s²


Now weight 2g N is on the downwards DIRECTION , hence in result tension t and accelration a will be in upward.


Now,

From the given condition at 2kg mass.

T- 2g = 2a

T=2g+2a

=2× 9.8+2 × 4.0

=19.6+8

= 27.6 N

Hence accleration is in downwards direction at 5 kg mass.


5 g-T =5 a

T=5 g-5 a

=5 × 9.8 -5 × 4

=49-20

=29 N.



Hope it Helps :-)

37.

A man is lying on the floor of a large, empty hemispherical hall, in such a way that his head is at the centre of the hall. He shouts 'Hello!' and hears the echo of his voice after 0.2 s. What is the radius of the hall? (Speed of sound in air = 340 m/s

Answer»

If This Is RIGHT PLZ.. MARK As BRAINLIEST.

38.

Write some points for each planet and solar system

Answer»

There are 8 planets in our solar system
mercury it is the coaldest planet in our solar system
venus it is called a RED planet
earth is called mother planet
mars is called a morning star
jupitar is called a biggest planet in UR solar system
saturn is called as ring planet

39.

One Mach number is equal to ?

Answer»

Hiii

➡️ It is EQUAL to the SPEED of SOUND in AIR

40.

What are the advantages and disadvantages of spherical mirror

Answer» HEY!!!

HOPE it MAY HELP you :-)
41.

What are the advantages and disadvantages of analog communications?

Answer» HEY!!!!!!

HOPE it MSY HELP you :-)
42.

Gate analog circuits questions based on common mode gain

Answer» HEY!!!!

i DONT KNOW
43.

Ground water drainage system close and open different types

Answer» HEY!!!!

HOPE it MAY HELP you
44.

a projectile is fired horizontally from an inclined plane of inclination 45 degree with horizontal with speed 50m per second if g is equal to 10 M per second square the range measured the incline is

Answer»

ANSWER: 500 √2 m

Explanation:

HOPE it HELPS!

45.

A physical quantity Q is given by (in picture)The percentage error is A,B,C and D are 1%, 2% ,4% and 2% respectively.find the percentage error of Q.

Answer»

Here is your ans.

I THINK IT'S HELP YOU...

46.

the velocity of the car increases uniformly from 5 m/per second to 10 m/per second when it travels 50 M. find the acceleration of the car??

Answer» HOPE IT HELPS!!

IF YES PLZ RATE BRAINLIST.....
47.

Can a body have constant speed and still be accelerating?

Answer» HELLO Mate!

Yes, the body having constant speed can be accelerating. Such case can be seen in " Uniform Circular MOTION". In Uniform Circular Motion the speed remains constant but yet it velocity keeps on chaging due to change in direction where acceleration is continuosly applied POINTING towards CENTER to keep the body moving in circular path.

So required ANSWER is " Yes ".

Hope it helps
48.

Give reason tap water condutor electricity distilled water does not

Answer»

Distilled water has a pH 7 but water have pH LESS than 7 so it is ACIDIC that's why it conduct electricity

49.

Question 5.23: A sample of paramagnetic salt contains 2.0 × 10 24 atomic dipoles each of dipole moment 1.5 × 10 −23 J T −1 . The sample is placed under a homogeneous magnetic field of 0.64 T, and cooled to a temperature of 4.2 K. The degree of magnetic saturation achieved is equal to 15%. What is the total dipole moment of the sample for a magnetic field of 0.98 T and a temperature of 2.8 K? (Assume Curie’s law)Class 12 - Physics - Magnetism And Matter Magnetism And Matter Page-203

Answer»

Number of ATOMIC dipoles, n = 2 × 10²⁴
dipole of each dipole MOMENT ,M = 1.5 × 10^-23J/T
so, dipole moment at complete SATURATION, M = 2 × 10²⁴ × 1.5 × 10^-23 = 30 J/T

at 0.84T and 4.2K , 15% of sample is magnetised.
so use FORMULA,
M=C\frac{B_0}{T_0}\\\\15\:of\:30J/T=C\frac{0.84}{4.2}----(1)

at 0.98T and 2.8K ,
M=C\frac{0.98}{2.8}-----(2)
from equations (1) and (2),
M = 7.875 J/T

50.

A MOTIR CYCLE IS MOVING WITH A VELOCITY OF 90KM/HR AND TAKE 5SEC TO STOP AFTER APPLYING THE BRAKES. CALCULATE THE FORCE EXERTED BY BRAKESOF IT WHEN MASS IS 200KG

Answer»

Here....

Acceleration=velocity/time
=90×5/18=25m/sec

Acceleration=25/5=5m/sec^2

Force=mass × accekeration
Force=200×5
Force=1000N

@SKB