A gun is mounted on a railroad car. The mass of the car, the gun, the

1.	A gun is mounted on a railroad car. The mass of the car, the gun, the shells and the operator is 50m where m is the mass of one shell. If the velocity of the shell with respect to the gun (in its state before firing) is 200 m/s, what is the recoil speed of the car after the second shot? Neglect friction.
Answer» Thanks for asking the question! ANSWER:: Centre of MASS of velocity of shell = 0 (initially at rest) Therefore , 0 = 49 m x V + m x 200 V = -200/49 m/s 200/49 m/s towards left . Another shell is FIRE , then the velocity of the CAR , with respect to platform is V' = 200/49 m/s towards left Another shell is fired , then the velocity of the car with respect to platform is v' = 200/48 m/s towards left Now , the velocity of the car with respect to earth is (200/49 + 200/48) = 19400/2352 = 8.24 m/s towards left. Hope it HELPS!

A gun is mounted on a railroad car. The mass of the car, the gun, the shells and the operator is 50m where m is the mass of one shell. If the velocity of the shell with respect to the gun (in its state before firing) is 200 m/s, what is the recoil speed of the car after the second shot? Neglect friction.

Answer»

Thanks for asking the question!

ANSWER::

Centre of MASS of velocity of shell = 0 (initially at rest)

Therefore , 0 = 49 m x V + m x 200

V = -200/49 m/s

200/49 m/s towards left .

Another shell is FIRE , then the velocity of the CAR , with respect to platform is

V' = 200/49 m/s towards left

Another shell is fired , then the velocity of the car with respect to platform is

v' = 200/48 m/s towards left

Now , the velocity of the car with respect to earth is (200/49 + 200/48) = 19400/2352 = 8.24 m/s towards left.

Hope it HELPS!

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