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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

1001.

draw the projection of a line AB,which is 75mm long, has its end A 15mmabove hp and 25mm in front of vp.it is inclined at 45°to hp and 30°to vp also obtain its horizontal and vertical traces​

Answer»

Step-by-step EXPLANATION:

jvgfmnmfmnhbfnndnnf.cxnccnbxnnxncbxbvcvnbfnxcndnvbgcdfdc

1002.

[(-7 )+ 5 ] ÷ [ (-2) +1]​

Answer»

\huge \mathfrak\blue{answer}

Step-by-step EXPLANATION:

[-7+5]÷[-2+1]

=-2÷(-1)

=2

1003.

The expression , nz = n1 phy not (z-1) refers to​

Answer»

Answer:

Step-by-step explanation:

1 dx ln x D x ln x x m. 1. D m .ln m 1/ C 1. H) .m 1/ ln.m 1/ 1 ─ S 1 ─ m .ln m 1/ I m ! 1W. S ! m .ln m 1/ : Solution 1.1.3. N1.

1004.

Sana eats 2/3 of a pizza, mana eats 4/5 of the pizza and bana eats 6/7 of the pizza. who eats more?​

Answer»

Step-by-step explanation:

✍️{\HUGE{\purple{\mathfrak{\underline{\underline{Question}}}}}}

Question

✍️

Sana eats 2/3 of a pizza, manna eats 4/5 of the pizza. Who eats more?

✍️{\huge{\purple{\mathfrak{\underline{\underline{To\ find}}}}}}

To find

✍️

Who eats more?

Means

Which is GREATER \FRAC{2}{3}or\frac{4}{5}

3

2

or

5

4

✍️{\huge{\purple{\mathfrak{\underline{\underline{Solution}}}}}}

Solution

✍️

Firstly;

Find the L.C.M. of DENOMINATOR so, that we can same the denominators and easily found that which one is greater...

So,L.C.M. of 3 and 5 is 15

Now,same the denominator of both terms with L.C.M., by multiplying;

\frac{2}{3}×\frac{5}{5}=\frac{10}{15}

3

2

×

5

5

=

15

10

\frac{4}{5}×\frac{3}{3}=\frac{12}{15}

5

4

×

3

3

=

15

12

Here, We can see that \frac{12}{15}

15

12

is greater than \frac{10}{15}

15

10

So,

\frac{4}{5}

5

4

is greater than \frac{2}{3}

3

2

As, Manna eats the \frac{4}{5}

5

4

of pizza.

{\pink{So,Manna\ eats\ more}}So,Manna eats more

1005.

Two points with coordinates (3,4)and (-6,4) lie on a line parallel to which axis?​

Answer»

ANSWER:

  • y-coordinate of both the POINTS is 4. So, both points lie on the line y = 4 which is PARALLEL to x-axis.
1006.

What kind of angle is inscribed in a semicircle? ​

Answer»

If an angle is inscribed in a semicircle, it will be half the measure of a semicircle (180 DEGREES), THEREFORE MEASURING 90 degrees.

1007.

The radius of a semicircle is 3 inches what is the semicircles area

Answer»

Answer:

9

Step-by-step EXPLANATION:

because RADIUS is HALF then half in semicircle is 3

3X3 =9 now the answer is 9

HOPE IT HELPS YOU

1008.

If x=2 y= 1 is a solution of the equation 2c + 3y I find the value of k​

Answer»

Given equation, 2x+3y=k

x=2,y=1 is SOLUTION of resultant equation.

2(2)+3(1)=k

∴k=7

∴  Resultant equation is 2x+3y=7

At x=0,2(0)+3y=7y=  37​  

At  y=0,2x+3(0)=7x=  27​  ∴(0,  37​  ) and (  27  ,0) are two more SOLUTIONS of resultant equations.

1009.

Simplify do it Fast​

Answer»

ANSWER:

this time right.

Step-by-step explanation:

who will do it , wese to NIND KI goliyan KHANI par rahi ha

1010.

Work out the area of a rectangle with base, b= 26mm and perimeter, P= 72mm.

Answer»

Answer:

AREA = 260mm2

Step-by-step explanation:

base = 26 mm

2B + 2H = 72mm

52 + 2H = 72

2H = 72- 52

2H = 20

H = 10mm

where H = HEIGHT and B = breadth

so area = 26 * 10 = 260mm2

1011.

Find the largest number that divides 232 and 157 leaving a remainder of 7.​

Answer»

ANSWER:

9 and 15 will be the answer

1012.

I don't like you the way you brought up (make question tag)​

Answer»

ANSWER:

I don't LIKE the WAY you BROUGHT up,do I?

1013.

he marks obtained by the student in a test of 20 marks in Mathematics are as follows. Find the median of the information. Marks 4 6 10 15 18 20 Number of students 2 4 8 12 3 1​

Answer»

Answer:

In a class TEST, 50 students obtained marks as follows-

Marks obtained 0-20 20-40 40-60 60-80 80-100

No. of students 4 6 25 10 5

Find the modal class and the median class.

Easy

share

Share

Answer

Marksobtained No.ofstudents

(F) Cumulativefrequency

0−20 4 4

20−40 6 10

40−60 25 35

60−80 10 45

80−100 5 50

⇒ Here, N=50, then

2

N

=

2

50

=25

We can see, 25 is NEAREST to CUMULATIVE frequency 35 which has class interval 40−60

∴ Median class =40−60.

⇒ In frequency table we can see class 40−60 has highest frequency 25.

∴ Modal class =40−60

1014.

Identify the domain of the following function: f(x) = x+1/x-2​

Answer»

Answer:

The value of f(X) is real for all real values of x except 2, because is x = 2, then the DENOMINATOR is = 0, and the whole fraction tends to infinity, i.e. not defined. So THEREFORE,

D = R - {2}, where R is the SET of real numbers, {2} in curly brackets denoted that the set contains only one value, which is 2.

Hope you understood.

1015.

See attachmentand decide hqhbsrvojf

Answer»

ANSWER:

JOIN

all

girls

for

chatting

gfmwwhvzec

1016.

show that the points (9,1)(7,9)(-2,22)(6,10)are concyilc and find the equation of circle on which they lie​

Answer»

ANSWER:

This is the QUESTION

Step-by-step EXPLANATION:

(9,1)(7,9)(-2,22)(6,10)

1017.

In the given figure , find x . also find the measures of AOC , COD and BOD​

Answer»

ANSWER:

but where is the FIGURE?

Step-by-step EXPLANATION:

I can't answer WITHOUT the figure.

please mark me as BRAINLIEST

1018.

Find the sum - 15 -0.-28140​

Answer»

ANSWER:

the CORRECT answer is OPTION no 3

1019.

3842196521 in wordsss ​

Answer»

Answer:

2 billion

84 crocre

21 lack

96 thousand

5 hundred

twenty ONE

1020.

Simplify (-3/2×4/5)÷(9/5×-10/3)-(1/2×3/4). please help me. ​

Answer»

Answer:

-21/40

Step-by-step explanation:

PLEASE go through the attachement.

HOPE it HELPS u a BIT

1021.

The group of compounds which are in homologous series A. CH4 , C2 H6, C3 H8 C. CH4 , CH3 -OH, H-CHO B. CH4 , C2 H4, C2 H2 D. C2 H2, C3 H6, C4 H10​

Answer»

Answer:

Chemical Formula IUPAC Name

CH

4

Methane

C

2

H

6

Ethane

C

3

H

8

Propane

C

4

H

10

Butane

C

5

H

12

Pentane

C

6

H

14

Hexane

C

7

H

16

Heptane

C

8

H

18

Octane

C

9

H

20

NONANE

C

10

H

22

Decane

The series BELONG to the Alkane family. They are hydrocarbons with C−C single bond.

The general formula of these compounds is C

N

H

2n+2

The given series is a homologous series. The members differ by a methylene group CH

2

group.

1022.

Y+7=-2/5(x-10) What is the standard form of the equation for this line?

Answer»

ANSWER:

The STANDARD form of a linear equation is Ax+By=C A X + B y = C . Multiply both sides by 5

hope it's HELPFUL

1023.

The value of x in the AP 2,x,14 is

Answer»

ANSWER:

GIVEN,

A = 2, l =14

Now,

TN = 14

a+(n-1)d = 14

2+(14-1) x d =14

1024.

X^2+5x+6 find the zeros of the quadratic polynomial . ​

Answer»

᥉᥆ᥣᥙti᥆ᥒ

\\  \\

⠀⠀→ hᥱᥡᥲ ꧑ᥲtᥱ, hᥱrᥱ i᥉ ᥡ᥆ᥙr ᥉᥆ᥣᥙti᥆ᥒ :-

⠀᥊² + 5᥊ + 6

᥊² + 3᥊ + 2᥊ + 6

➟᥊ (᥊ + 3) + 2 (᥊ + 3)

➟(᥊ + 3) (᥊ + 2)

➟(᥊ + 3) (᥊ + 2) = 0

➟᥊ + 3 = 0⠀⠀⠀⠀᥆r⠀⠀⠀⠀⠀➟᥊ + 2 = 0

➟᥊ = - 3⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀ ⠀➟᥊ = - 2

. ' . thᥱrᥱf᥆rᥱ thᥱ zᥱr᥆᥉ ᥆f thᥱ qᥙᥲdrᥲtiᥴ ρ᥆ᥣᥡᥒ᥆꧑iᥲᥣ ᥲrᥱ - 3 ᥲᥒd - 2

h᥆ρᥱ it hᥱᥣρ᥉ ᥡ᥆ᥙ !

thᥲᥒk ᥡ᥆ᥙ !

1025.

how to identify a basic word problem of whether it is addition subtraction multiplication or division​

Answer»

Step-by-step EXPLANATION:

ADD (SUM) +

SUBTRACT(DIFFERENCE) -

1026.

7/10+2/5+3/2 answer me as step by step​

Answer»

Step-by-step EXPLANATION:

FIND LCM first

7/10,

2/5×2/2=4/10

3/2×5/5 = 15/10

7/10+4/10+15/10

= 26/10

= 13/5

1027.

. The ratio of the ages of veer and Vikram 15 years ago was 2 :1 and their ages difference 5 years ago was 10 years, then find out the ratio of ages of Veer and Vikram 15 years hence?​

Answer»

ANSWER:

Sabghjsvwdihvegshxvhaga

1028.

A system of linear equations is said to be consistent, if it has at least one solution. OTrue / ठीव / सही O False / ठाप्ठउ / गलत​

Answer»

ANSWER:

true

Step-by-step EXPLANATION:

1029.

What is differentiation and integration?? . . class 11​

Answer»

Differentiation and INTEGRATION are the TWO major concepts of calculus. Differentiation is USED to study the small change of a quantity with respect to unit change of ANOTHER. On the other hand, integration is used to add small and DISCRETE data, which cannot be added singularly and representing in a single value.

1030.

Q1. prove that(sin A + COSA) (tanA+cotA)=sinA-cosecA​

Answer»

Step-by-step EXPLANATION:

CORRECT QUESTION :-

PROVE :-

\sf ( sinA+cosA)(tanA+cotA) = secA+cosecA

Solution :-

L.H.S = (sinA+cosA)(tanA+cotA)

\bullet\bf \ tanA = \dfrac{sinA}{cosA}

\bullet\bf \ cotA= \dfrac{cosA}{sinA}∙

= \sf (sinA+cosA) \left( \dfrac{sinA}{cosA} +\dfrac{cosA}{sinA} \right)

= \sf (sinA+cosA) \left( \dfrac{sin^2A+cos^2A}{sinAcosA} \right)

\bullet \bf \ sin^2A+cos^2A = 1

= \sf (sinA+cosA) \times \left( \dfrac{1}{sinAcosA} \right)

= \sf \dfrac{sinA}{sinAcosA} \times \dfrac{cosA}{sinAcosA}

= \sf \dfrac{1}{cosA}+\dfrac{1}{sinA}

\bullet \bf \ secA= \dfrac{1}{cosA}∙

\bullet \bf \ cosecA= \dfrac{1}{sinA}∙

= \sf secA+cosecA

= R.H.S

Hence PROVED.

1031.

Please tell me the answer!!!!​

Answer»

Answer:

325/26

HOPE it will be HELPFUL to you.

1032.

At what rate percent p.a compound interest will rs 5000 amount to rs 5832 in 2 year

Answer»

Answer :

THUS, The RATE PERCENT of compounded ANNUALLY per annum will be 8%.

=8%

I hope it helps u so, please add me in BRAIN list.

Thank u

1033.

Square of 2500 with process pls

Answer»

Answer:

The square root of 2500, (or root 2500), is the NUMBER which when MULTIPLIED by itself gives the product as 2500. Therefore, the square root of 2500 = √2500 = 50

eg ; 50 *50 = 2500

so √2500=50

easy peasy

hope it HELPS u

MARK AS BRAINELIEST

1034.

What is 937,694 in expanded form

Answer»

Answer:

THEREFORE the expanded FORM is :

937 = 900+30+7

694 = 600+90+4

Step-by-step explanation:

Expanded form :

937 = 900+30+7

694 = 600+90+4

1035.

Simplify ( 3¹⁰÷3⁷)×3-⁵(2)if your answer is right, congrats u are marked brainlist. (only correct answer gets it)​

Answer»

ANSWER:

PLEASE MARK me as BRAINLIEST and FOLLOW

1036.

Find the last two digits of 3^256​

Answer»

ANSWER:

Hlo this is an example

So that u can try ur own

Step-by-step explanation:

81

17

256

For finding last two digits we have to find the remainder of

17

256

So, we apply binomial expansion 17

256

,

=(10+7)

256

=

256

C

0

10

0

7

256−0

+

256

C

1

10

1

7

256−1

Higher terms which contains 10

2

which are DIVISIBLE by 100.

So,

256

C

0

10

0

7

256−0

+

256

C

1

10

1

7

256−1

We GET last digit by last digit of

256

C

0

10

0

7

256−0

which is last digit of 7

256

=1

Second last digit is the second last digit of

256

C

1

10

1

7

256−1

=256×7

255

×10

=6×3

Second last digit =8 only the last digit (Because last digit of 7

255

=3)

So, the second last and last are 81.

1037.

If , then the equation (ax2 + bx – a) (dx2 + ex + f) = 0 (where a, b, c, d, e and f are real numbers) will have

Answer»

Answer:

Solution:

GIVEN a,b,c in G.P.

So b2 = ac

Hence b = √ac

ax2+2BX+c = 0

Put b = √(ac) in above equation, we get

ax2+2√(ac)x+c = 0

(√(a)x+√c)2 = 0

So x = -√(c/a)

Given equations ax2 + 2bx + c = 0 and dx2 + 2EX + F = 0 have a common root.

So x = -√(c/a) should satisfy dx2 + 2ex + f = 0.

Put x = -√(c/a) in dx2 + 2ex + f = 0.

d(c/a)-2e√(c/a) + f = 0

Divide by c, we get

(d/a) -2(e/√ca)+(f/c) = 0

Put b = √ac in above equation

(d/a)+(f/c) = 2(e/b)

So (d/a), (e/b), (f/c) are in A.P

Hence option (1) is the answer.

Step-by-step explanation:

1038.

Concentrations of three type of milks X, Y and Z are 10%, 20% and 30% respectively. They are mixed in the ratio 2:3:P resulting in a 23% concentrations solution. Find P. (1) 7 (2) 6 (3) 5 (4) 4​

Answer»

Answer:

Step-by-step explanation:

Click hereto GET an answer to your QUESTION

✍️ Concentrations of three solutions ... and

40% RESPECTIVELY They are mixed in the

ratio 3 : 5 : x resulting in a solution of 30% ...

the AMOUNT of A in the solution is 20×3g=60g

in 100×3g=300​g of WATER, ... the amount of C

in the solution is 40×xg=40xg in 100×xg=100xg

of water.

1039.

Two dice one blue and one green ,are thrown at the same time...what is the probability that the sum of the two numbers appearing on the top of the dice is 8 ​

Answer»

Step-by-step EXPLANATION:

Which REPTILE SUBGROUP is CONSIDERED EXTINCT?

1040.

5 - 3 - 2 is a rational number. . V5 - 3 - 2 ਇੱਕ ਪਰਿਮੇਯ ਸੰਖਿਆ ਹੈ।​

Answer»

ANSWER:

YES!!!!!!!!!!!!!!!!!!!

1041.

The multiplicative inverse of -8/7 is​

Answer»

In mathematics, a multiplicative inverse or reciprocal for a number x, DENOTED by 1/x or x−1, is a number which when multiplied by x YIELDS the multiplicative identity, 1. The multiplicative inverse of a fraction a/b is b/a. For the multiplicative inverse of a REAL number, divide 1 by the number.

1042.

Q1. Write a negative integer and a positive integer whose difference is -3.​

Answer»

ANSWER:

Thus, NEGATIVE INTEGER and a positive integer whose DIFFERENCE is \(–14\) are \((-9)\) and \((+5)\) respectively

1043.

In the given figuretriangle ABC ~ triangle DEF and Angle ABC = Angle DEF = 60 degrees, then the length of AC​

Answer»

ANSWER:

ac = 2.6cm

PLEASE MARK ME BRAINLIEST

1044.

The numerator of a rational number is 4 less than its denominator. If 1 is added to both its numerator and denominator, it becomes /. Find the rational number.

Answer»

Answer:

Here you have to WRITE in this way

let the NUMERATOR be x and DENOMINATOR be y

x = y-4

1045.

Find the reciprocal of (2/3)^−2 ÷ (3/2)^−4​

Answer»

ANSWER:

nbccvvbbkohgjueasxgjpiesvbnvdagolkbczfkl

1046.

नर सम्राट या नाटकाचा विषय थोडक्यात सागा​

Answer»

ANSWER:

नटसम्राट' नाटकातली स्वगते हा एक अनन्यसाधारण प्रकार आहे. ही स्वगते प्रेक्षकांना एका वेगळ्याच उंचीवर नेतात. त्यांची अभिरुची समृद्ध केल्याचा साक्षात्कार घडवतात. 'सौभद्र'मधल्या गाण्यांना जे रंजनमूल्य आहे ते नटसम्राटातील स्वगतांना आहे. या स्वगतांमुळे कित्येक वर्षे मराठी रंगभूमीवरून हद्दपार झालेल्या 'लार्जर दॅन लाइफ' व्यक्तिरेखा नाट्यरसिकांना पुन्हा अनुभवायला मिळाल्या. गणपतराव जोशी, गणपतराव बोडस, नानासाहेब फाटक, केशवराव भोसले, केशवराव दाते हे गतकाळातले दिग्गज कलावंत या स्वगतांच्या निमित्ताने प्रेक्षकांनी अप्रत्यक्षरीत्या पुन्हा अनुभवले. पुराणवस्तू संग्रहालयाला भेट द्यावी आणि भारवून जावे तशी स्थिती या नाटकातील स्वगताने प्रेक्षकांची केली. या नाटकातील स्वगते काढून टाकली तर ती केशवसुतांच्या भाषेत म्हणतील, 'आम्हाला वगळा गतप्रभ झणी होतील तारांगणे'... खरोखरच स्वगते वगळली तर नटसम्राटाला गतप्रभ होण्याशिवाय दुसरा मार्गच उरणार नाही.

तुमच्या आमच्या पातळीवरची कौटुंबिकता आणि सारा नाट्यावकाश भेदून टाकणारी उदात्तता यांचे योग्य मिश्रण म्हणजेच 'नटसम्राट' नाटक आणि तेच त्याच्या चिरंतनत्वाचे कारण. नाटककाराच्या या अमोल खजिन्याला डॉ. श्रीराम लागू (आप्पा बेलवलकर) व शांता जोग (कावेरी) यांच्या तितक्याच लखलखीत अभिनयाची साथ मिळाली. मुळातली हिरे-माणकांची दौलत अधिकच उजळून निघाली. 'गोवा हिंदू असोसिएशन'च्या मंडळींनी ही संपत्ती रसिकांना मनःपूत लुटू दिली.

1047.

Find the sum of first 18 terms of A.P whose term is 3.2n​

Answer»

Step-by-step explanation:

the 18TH TERM of the GIVEN ap is 108

1048.

2x + 1 /3 =2/x find x​

Answer»

2x+1/3=2/x

1/3-2/x=-2x

1/3-2=x-2x

1-6/3=-x

-5/3=-x

x=5/3

1049.

2. List all the multiples of 7 which lie between :(i) 20 and 50 (ii) 80 and 100 (iii) 125 and 142please tell me by step by step explanation ​

Answer»

Answer:

(i) All multiples of 7 which LIE between 20 and 50 are 21, 28, 35, 42, 49.

(ii) All multiples of 7 which lie between 80 and 100 are 84, 91, 98.

(iii) All multiples of 7 which lie between 125 and 142 are 126, 133, 140.

PLEASE MARK ME AS THE BRAINLEST

1050.

abcd चतुर्भुज के 1 vikar ac की लंबाई 6 सेमी और उसी vikarn पर बिंदु b से बनाए गए bm की लंबाई 3 सेमी बिंदु d पर बनाई गई लंब की लंबाई 5 सेमी है तो चतुर्भुज का क्षेत्रफल ज्ञात कीजिए​

Answer»

Given : abcd चतुर्भुज के 1 vikar ac की लंबाई 6 सेमी और उसी vikarn पर बिंदु b से बनाए गए bm की लंबाई 3 सेमी बिंदु d पर बनाई गई लंब की लंबाई 5 सेमी है तो

To FIND :  चतुर्भुज का क्षेत्रफल ज्ञात कीजिए​

Area of Quadrilateral

Solution:

Area of Quadrilateral  ABCD = Area of  ΔABC + Area of  ΔADC

Area of TRIANGLE = (1/2) * Base * Height

=> Area of  ΔABC = (1/2) * AC * BM

=> Area of  ΔABC = (1/2) * 6 * 3   = 9 cm²

=> Area of  ΔADC = (1/2) * AC * DN

=> Area of  ΔADC = (1/2) * 6 * 5   = 15 cm²

Area of Quadrilateral  ABCD = 9 + 15  = 24 cm²

Area of Quadrilateral  ABCD is  24 cm²

 चतुर्भुज का क्षेत्रफल   24  सेमी²

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