1.

Find the last two digits of 3^256​

Answer»

ANSWER:

Hlo this is an example

So that u can try ur own

Step-by-step explanation:

81

17

256

For finding last two digits we have to find the remainder of

17

256

So, we apply binomial expansion 17

256

,

=(10+7)

256

=

256

C

0

10

0

7

256−0

+

256

C

1

10

1

7

256−1

Higher terms which contains 10

2

which are DIVISIBLE by 100.

So,

256

C

0

10

0

7

256−0

+

256

C

1

10

1

7

256−1

We GET last digit by last digit of

256

C

0

10

0

7

256−0

which is last digit of 7

256

=1

Second last digit is the second last digit of

256

C

1

10

1

7

256−1

=256×7

255

×10

=6×3

Second last digit =8 only the last digit (Because last digit of 7

255

=3)

So, the second last and last are 81.


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