332354 + Interview Questions in Secondary School in Math

1.	Two equilateral triangles having equal area are always congruent true false
Answer» ANSWER: TRUE... Step-by-step EXPLANATION:

1.

Two equilateral triangles having equal area are always congruent true false

Answer»

ANSWER:

TRUE...

Step-by-step EXPLANATION:

Discussion

2.	a coin is tossed 400 times and we get head 220 times and tail 180 times . Find the probability of getting (1) head (2) tail
Answer» ANSWER: head Step-by-step EXPLANATION: please make it brainliest answerand FOLLOW me

2.

a coin is tossed 400 times and we get head 220 times and tail 180 times . Find the probability of getting (1) head (2) tail

Answer»

ANSWER:

head

Step-by-step EXPLANATION:

please make it brainliest answerand FOLLOW me

Discussion

3.	A square minus 81(b minus c) whole square
Answer» Answer: Answer: (A+B-C)² = A²+B²+C²+2AB-2BC-2CA Explanation: We know the ALGEBRAIC IDENTITY: Now ,Here x = A , y = B, Z = -C (A+B-C)² [A+B+(-C)]² = A²+B²+(-C)²+2AB+2B(-C)+2(-C)A = A²+B²+C²+2AB-2BC-2CA Therefore, (A+B-C)² =A²+B²+C²+2AB-2BC-2CA •••

3.

A square minus 81(b minus c) whole square

Answer»

Answer:

Answer:

(A+B-C)² = A²+B²+C²+2AB-2BC-2CA

Explanation:

We know the ALGEBRAIC IDENTITY:

Now ,Here

x = A , y = B, Z = -C

(A+B-C)²

[A+B+(-C)]²

= A²+B²+(-C)²+2AB+2B(-C)+2(-C)A

= A²+B²+C²+2AB-2BC-2CA

Therefore,

(A+B-C)²

=A²+B²+C²+2AB-2BC-2CA

•••

Discussion

4.	3. Use the following equation for parts A, B, and C: x2 - 4x + 3 = 0A) How many roots and what type of roots, rational or irrational, does this equation have? Find thediscriminant and use it to answer this question. (4 pts)B) Solve the equation above using the quadratic formula (SHOW ALL STEPS OF WORK) (3 pts)C) Substitute each solution back into the equation and show that the solutions are correct. Remember, thecheck is not complete until you reach a number equal to itself. (SHOW ALL STEPS OF WORK (4 pts)
Answer» ANSWER: fuvidydycjkblkjhghccvhujngffjkihj

4.

3. Use the following equation for parts A, B, and C: x2 - 4x + 3 = 0A) How many roots and what type of roots, rational or irrational, does this equation have? Find thediscriminant and use it to answer this question. (4 pts)B) Solve the equation above using the quadratic formula (SHOW ALL STEPS OF WORK) (3 pts)C) Substitute each solution back into the equation and show that the solutions are correct. Remember, thecheck is not complete until you reach a number equal to itself. (SHOW ALL STEPS OF WORK (4 pts)

Answer»

ANSWER:

fuvidydycjkblkjhghccvhujngffjkihj

Discussion

5.	Which Of the following expression are not a polynomials1).6-x+x^22).37x-14x^33).x^-2+6x+54).-19
Answer» ANSWER: I THINK the 3 part as i haven't LEARN it yet.

5.

Which Of the following expression are not a polynomials1).6-x+x^22).37x-14x^33).x^-2+6x+54).-19

Answer»

ANSWER:

I THINK the 3 part as i haven't LEARN it yet.

Discussion

6.	If 39 metres of cloth is required U MUmake 20 shirts.Mr. Kabir has a family of 5 members. He spends * 25family of 9 members. If each member of both familiesHow much does Mr. Garvit spent on food?The price of a shirt is * 420.09. Tarun bought 5 shirtsa battery costs * 15, what is the cost of a dozen of100
Answer» Answer: Average AGE of 6 family MEMBER is 25. ∴ Total age of 6 family member =6×25=150years The age of youngest member is 5years ⇒ Total age of 6 family member at the times of youngest BIRTH =150−(5×6) =150−30 =120years ∴ Average age of family at time of youngest birth =6120=20years Step-by-step explanation: mark me as in brainlist PLZ dear

6.

If 39 metres of cloth is required U MUmake 20 shirts.Mr. Kabir has a family of 5 members. He spends * 25family of 9 members. If each member of both familiesHow much does Mr. Garvit spent on food?The price of a shirt is * 420.09. Tarun bought 5 shirtsa battery costs * 15, what is the cost of a dozen of100

Answer»

Answer:

Average AGE of 6 family MEMBER is 25.

∴ Total age of 6 family member =6×25=150years

The age of youngest member is 5years

⇒ Total age of 6 family member at the times of youngest BIRTH =150−(5×6)

=150−30

=120years

∴ Average age of family at time of youngest birth =6120=20years

Step-by-step explanation:

mark me as in brainlist PLZ dear

Discussion

7.	Solve this question by using method of eliminination by substitution. 2x+3y=82x=2+3y. please solve by explaining.
Answer» Step-by-step EXPLANATION: answr ANSWER 2x+3y=8 ---------- ( 1 ) [ Given ] 2x=2+3y --------- ( 2 ) [ Given ] X=22+3y ----- ( 3 ) ,substituting VALUE of x in equation ( 1 ), 2(22+3y)+3y=8 2+3y+3y=8 2+6y=8 6y=8−2 6y=6 ∴ y=1 substituting value of y=1 in equation ( 3 ), x=22+3(1) x=25 x=2.5 why you are not come

7.

Solve this question by using method of eliminination by substitution. 2x+3y=82x=2+3y. please solve by explaining.

Answer»

Step-by-step EXPLANATION:

answr

ANSWER

2x+3y=8 ---------- ( 1 ) [ Given ]

2x=2+3y --------- ( 2 ) [ Given ]

X=22+3y ----- ( 3 )

,substituting VALUE of x in equation ( 1 ),

2(22+3y)+3y=8

2+3y+3y=8

2+6y=8

6y=8−2

6y=6

∴ y=1

substituting value of y=1 in equation ( 3 ),

x=22+3(1)

x=25

x=2.5

why you are not come

Discussion

8.	সংক্ষিপ্ত প্রশ্ন:১. ইসলামের সাথে ইমানের সর্ক খুবই নিবিড় কথাব্যাখ্যা কর।২. কপটতার নিদর্শন গুলাে কী কী?৩. নবি-রাসুলের পার্থক্য বর্ণনা কর।৪. হাশরের ময়দানে কয় ধরণের শায়াত কার্যক; হবেব্যাখ্যা কর।
Answer» ANSWER: tsysrbghghsdlddfsJg . . . . .awpslhuO . . .,dKhj

8.

সংক্ষিপ্ত প্রশ্ন:১. ইসলামের সাথে ইমানের সর্ক খুবই নিবিড় কথাব্যাখ্যা কর।২. কপটতার নিদর্শন গুলাে কী কী?৩. নবি-রাসুলের পার্থক্য বর্ণনা কর।৪. হাশরের ময়দানে কয় ধরণের শায়াত কার্যক; হবেব্যাখ্যা কর।

Answer»

ANSWER:

tsysrbghghsdlddfsJg

.

.awpslhuO

.

.,dKhj

Discussion

9.	Sin inverse x + sin inverse 1/x + cos inverse x + cos inverse 1/x is equal to
Answer» Answer: CLASS 12th Chapter 5 Continuity and differentiability Step-by-step explanation: Check the ATTACHMENT for your answer And here is a notice (and request) for you, My friend... If you have more interesting mathematical problems, then please mail me at:- [email protected] I'm a 10th graded student and I love learning mathematics. So I keep learning new topics. So please email me your problems. This will be helpful for both of us. And don't be WORRIED about the standard of the problem. Even if I'm a 10th graded student, I WOULD solve ANYTHING. Just SHARE.

9.

Sin inverse x + sin inverse 1/x + cos inverse x + cos inverse 1/x is equal to

Answer»

Answer:

CLASS 12th

Chapter 5

Continuity and differentiability

Step-by-step explanation:

Check the ATTACHMENT for your answer

And here is a notice (and request) for you, My friend...

If you have more interesting mathematical problems, then please mail me at:-

[email protected]

I'm a 10th graded student and I love learning mathematics. So I keep learning new topics. So please email me your problems.

This will be helpful for both of us.

And don't be WORRIED about the standard of the problem. Even if I'm a 10th graded student, I WOULD solve ANYTHING.

Just SHARE.

Discussion

10.	the circular path is outside the circular garden. if its external circumference is 508m and internal circumference is 420 m. what is the area of the path
Answer» Answer: hope it helps u Step-by-step EXPLANATION: ANSWER Radius of the circular garden = 2 210 =105m Radius of the REGION covering the garden and the PATH =105m+7m=112m Area of the region between two concentric circles with radius of outer CIRCLE R, and inner circle r =π(R 2 −r 2 ) Hence, the area of the path =π(112 2 −105 2 )= 7 22 (12544−11025)= 7 33418 =4774m 2

10.

the circular path is outside the circular garden. if its external circumference is 508m and internal circumference is 420 m. what is the area of the path

Answer»

Answer:

hope it helps u

Step-by-step EXPLANATION:

ANSWER

Radius of the circular garden =

2

210

=105m

Radius of the REGION covering the garden and the PATH =105m+7m=112m

Area of the region between two concentric circles

with radius of outer CIRCLE R, and inner circle r =π(R

2

−r

2

)

Hence, the area of the path =π(112

2

−105

2

)=

7

22

(12544−11025)=

7

33418

=4774m

2

Discussion

11.	What is the work to be doneto increase the velocity of a car from30 km h-1 to 60 km h- if the mass ofthe car is 1500 kg?
Answer» Answer: thanks to the family of FOUR days ago or suna Kay hal haa kore amar dhon ta nacha in hindi and english to bangla definition of my best friend or suna tha ab plot no 22 present in this email PASSWORD don't know if any other questions baj rahe the aur jio the computer ke video is not a problem with the computer ka questions baj da pls pls jaldi se jaldi se jaldi hi I would love to see you tomorrow ok SIR ya IT ke liye kuch kam NAHI to KABHI kabhi mere pass kisi ki activity this video started the computer what to do it for exam the yu yu yu gi oh my god or suna Kay hal ha jo ki pichhle saal ki ladki ko solve the family name Onike you sir yours faithfully Mr Raj Kumar in the photo of my life I would be great if you have done mam kindly

11.

What is the work to be doneto increase the velocity of a car from30 km h-1 to 60 km h- if the mass ofthe car is 1500 kg?

Answer»

Answer:

thanks to the family of FOUR days ago or suna Kay hal haa kore amar dhon ta nacha in hindi and english to bangla definition of my best friend or suna tha ab plot no 22 present in this email PASSWORD don't know if any other questions baj rahe the aur jio the computer ke video is not a problem with the computer ka questions baj da pls pls jaldi se jaldi se jaldi hi I would love to see you tomorrow ok SIR ya IT ke liye kuch kam NAHI to KABHI kabhi mere pass kisi ki activity this video started the computer what to do it for exam the yu yu yu gi oh my god or suna Kay hal ha jo ki pichhle saal ki ladki ko solve the family name Onike you sir yours faithfully Mr Raj Kumar in the photo of my life I would be great if you have done mam kindly

Discussion

12.	Answer question no. 20 , 21 , 22 .... quickly fast
Answer» ANSWER: SORRY I DONT KNOW Step-by-step EXPLANATION:

12.

Answer question no. 20 , 21 , 22 .... quickly fast

Answer»

ANSWER:

SORRY I DONT KNOW

Step-by-step EXPLANATION:

Discussion

13.	An item marked at rupees 840 is sold for rupees 714. What is the discount and discount %
Answer» Answer: 16.2% Step-by-step explanation: please MAKE it brainliest ANSWERAND FOLLOW me

13.

An item marked at rupees 840 is sold for rupees 714. What is the discount and discount %

Answer»

Answer:

16.2%

Step-by-step explanation:

please MAKE it brainliest ANSWERAND FOLLOW me

Discussion

14.	A cube has an edge of 8cm . if each edge of the cube is doubled find the volume of the new cube
Answer» Given: Edge of cube = 8 cm To FIND: Volume of NEW cube if edge of cube is doubled? Solution: Edge of cube after doubling its edge = 8 × 2 = 16 cm Now, Finding volume of new cube, We know that, Volume of cube = a³ Here, a = 16 cm Therefore, Volume of new cube, → 16³ = 4096 cm³ Volume of new cube is 4096 cm³. ━━━━━━━━━━━━━━━━━━━━━━━━━ More to know: Total surface area of cube = 6a² Curved surface area of cube = 4a² Total surface area of cuboid = 2(lb + bh + HL) Curved surface area of cuboid = 2(l + b)h Volume of cuboid = l × b × h

14.

A cube has an edge of 8cm . if each edge of the cube is doubled find the volume of the new cube

Answer»

Given:

Edge of cube = 8 cm

To FIND:

Volume of NEW cube if edge of cube is doubled?

Solution:

Edge of cube after doubling its edge = 8 × 2 = 16 cm

Now, Finding volume of new cube,

We know that,

Volume of cube = a³

Here,

a = 16 cm

Therefore,

Volume of new cube,

→ 16³ = 4096 cm³

Volume of new cube is 4096 cm³.

━━━━━━━━━━━━━━━━━━━━━━━━━

More to know:

Total surface area of cube = 6a²

Curved surface area of cube = 4a²

Total surface area of cuboid = 2(lb + bh + HL)

Curved surface area of cuboid = 2(l + b)h

Volume of cuboid = l × b × h

Discussion

15.	Find value of determimanant.عد
Answer» ANSWER: 2√3(√3)-3√2(√2)=6-6=0 Step-by-step EXPLANATION: so answer is 0

15.

Find value of determimanant.عد

Answer»

ANSWER:

2√3(√3)-3√2(√2)=6-6=0

Step-by-step EXPLANATION:

so answer is 0

Discussion

16.	PAGE NO.DATE.(log tan (4+x))dx
Answer» Answer: SORRY FRIEND I am not able to answer............. NEXT TIME..............

16.

PAGE NO.DATE.(log tan (4+x))dx

Answer»

Answer:

SORRY FRIEND I am not able to answer.............

NEXT TIME..............

Discussion

17.	Two sarees were sold at 7,000 each. One at a loss of 10% and the otherat a gain of 10%. Find the loss or gain% for the entire transaction.co
Answer» Answer: Step-by-step explanation: Here , it is CLEAR that there are 2 sarees sold . S.P of each saree = Rs 7000. Therefore , the S.P of 2 sarees = 7000 ×2 = Rs 14000. As you know , the formula of C P = S.P/ 100 + gain% { - LOSS%} ×100 Now , putting that formula on C.P of 1st saree = {7000/ 100 - 10} × 100 = 7000/90 × 100 = Rs 7777.77 C.P of 2nd saree= {7000/ 100+10} × 100 = 7000/ 110 × 100 = Rs 6363.63 Now, CALCULATING the whole C.P Rs{7777.77 + 6363.63} Rs 14141.4 Now, as you can see C.P > S.P So, there is a gain of C.P - S.P Rs 14141.4 - Rs 14000 Rs 141.4 Now , calculating the gain % = 141.4 × 100 / 14141.4 = 0.999 % So, we can estimate 0.999% to 1 % Therefore, 1% is the answer

17.

Two sarees were sold at 7,000 each. One at a loss of 10% and the otherat a gain of 10%. Find the loss or gain% for the entire transaction.co

Answer»

Answer:

Step-by-step explanation:

Here , it is CLEAR that there are 2 sarees sold .

S.P of each saree = Rs 7000.

Therefore , the S.P of 2 sarees = 7000 ×2 = Rs 14000.

As you know , the formula of C P = S.P/ 100 + gain% { - LOSS%} ×100

Now , putting that formula on

C.P of 1st saree = {7000/ 100 - 10} × 100

= 7000/90 × 100

= Rs 7777.77

C.P of 2nd saree= {7000/ 100+10} × 100

= 7000/ 110 × 100

= Rs 6363.63

Now, CALCULATING the whole C.P

Rs{7777.77 + 6363.63}

Rs 14141.4

Now, as you can see

C.P > S.P

So, there is a gain of

C.P - S.P

Rs 14141.4 - Rs 14000

Rs 141.4

Now , calculating the gain %

= 141.4 × 100 / 14141.4

= 0.999 %

So, we can estimate 0.999% to 1 %

Therefore, 1% is the answer

Discussion

18.	Any value of x for which the polynomial f(x) vanishes is called
Answer» Answer: ANSWER f(x)=(x−1)(x+2)(ax+b) f(−1)=4=(−2)(1)(b−a) =a−b=2 f(2)=28=(1)(4)(2a+b) 2a+b=1 solving 1 and 2 equations 3a=9 a=3 b=1 ∴f(x)=(x−1)(x+2)(3x+1) f(0)=(−1)(2)(1) =−2

18.

Any value of x for which the polynomial f(x) vanishes is called

Answer»

Answer:

ANSWER

f(x)=(x−1)(x+2)(ax+b)

f(−1)=4=(−2)(1)(b−a)

=a−b=2

f(2)=28=(1)(4)(2a+b)

2a+b=1

solving 1 and 2 equations

3a=9

a=3

b=1

∴f(x)=(x−1)(x+2)(3x+1)

f(0)=(−1)(2)(1)

=−2

Discussion

19.	A+b=9anda-b=20 value of (a+b)^2
Answer» $a + b = 9 \\ a - b = 20 \\ {(a + b)}^{2} = (a + b)(a + b) \\ (9)(9) = 81$ HERE IS YOUR ANSWER.

19.

A+b=9anda-b=20 value of (a+b)^2

Answer»

$a + b = 9 \\ a - b = 20 \\ {(a + b)}^{2} = (a + b)(a + b) \\ (9)(9) = 81$

HERE IS YOUR ANSWER.

Discussion

20.	Write each of the following equation in ax +by+c=0 form .y=2x-4 ???(class 11)
Answer» ANSWER: The equation will be 2x-y-4 = 0 Here a = 2, b = -1 and C = -4. Mark as brainliest pls

20.

Write each of the following equation in ax +by+c=0 form .y=2x-4 ???(class 11)

Answer»

ANSWER:

The equation will be 2x-y-4 = 0

Here a = 2, b = -1 and C = -4.

Mark as brainliest pls

Discussion

21.	SI No. ShapeNo. of faces No.of edges No. of corners1Cube2Cuboid3Cylinder4ConesTriangularBased pyramid6Square basedpyramid
Answer» ANSWER: ???????????? ?????????

21.

SI No. ShapeNo. of faces No.of edges No. of corners1Cube2Cuboid3Cylinder4ConesTriangularBased pyramid6Square basedpyramid

Answer»

ANSWER:

????????????

?????????

Discussion

22.	15. What mass of ice at 0°C is to be mixed to10 litres of water at 40°C to get 20°Cmixture?Il1) 5 kg 2) 10 kg 3) 15 kg 4) 20 kg
Answer» Answer: I'm just giving u example HOPE it helps u Step-by-step explanation: If 10 gram of ice at 0 ∘ C is mixed with 10 gram of WATER at 40 ∘ C. The final MASS of water in mixture is (Latent heat of fusion of ice =80cal/gm; specific heat of water =1cal/gm ∘ C) 289811

22.

15. What mass of ice at 0°C is to be mixed to10 litres of water at 40°C to get 20°Cmixture?Il1) 5 kg 2) 10 kg 3) 15 kg 4) 20 kg

Answer»

Answer:

I'm just giving u example HOPE it helps u

Step-by-step explanation:

If 10 gram of ice at 0

∘

C is mixed with 10 gram of WATER at 40

∘

C. The final MASS of water in mixture is

(Latent heat of fusion of ice =80cal/gm; specific heat of water =1cal/gm

∘

C)

289811

Discussion

23.	Prove that 2ⁿ > n for all positive integers n by the Principle of Mathematical Induction
Answer» Step-by-step explanation: because n×n=2N so 2n is GREATER than n MARK me as BRAINLIEST

23.

Prove that 2ⁿ > n for all positive integers n by the Principle of Mathematical Induction

Answer»

Step-by-step explanation:

because n×n=2N so 2n is GREATER than n

MARK me as BRAINLIEST

Discussion

24.	कउJAISA अलि (20 maarg 218रहा गर , न-aroANमाया गायनाकमिराशा !है याविठशानिकमgarm
Answer» Answer: 222222 iiiisss rrrriiiiggggghhhhtttt aaaannnnsssswwweeeerrrr

24.

कउJAISA अलि (20 maarg 218रहा गर , न-aroANमाया गायनाकमिराशा !है याविठशानिकमgarm

Answer»

Answer:

222222 iiiisss rrrriiiiggggghhhhtttt aaaannnnsssswwweeeerrrr

Discussion

25.	The weight of corns harvested from a farm has a normal distribution with a mean of 70gand standard deviation of 10g. If a corn is select randomly, what is the probability if theweight of the drawn corn isa) more than 80g?b) below 72g?c) in between 72g and 82g?
Answer» ANSWER: b Step-by-step EXPLANATION:

25.

The weight of corns harvested from a farm has a normal distribution with a mean of 70gand standard deviation of 10g. If a corn is select randomly, what is the probability if theweight of the drawn corn isa) more than 80g?b) below 72g?c) in between 72g and 82g?

Answer»

ANSWER: b

Step-by-step EXPLANATION:

Discussion

26.	If vectors A+B=C and \|A\|+\|B\|=\|C\|. then vector A and vector B area) parallel. b) perpendicular. c)anti parallel d)null vector
Answer» ANSWER: perpendicular Step-by-step EXPLANATION: i HOPE this HELPS you

26.

If vectors A+B=C and |A|+|B|=|C|. then vector A and vector B area) parallel. b) perpendicular. c)anti parallel d)null vector

Answer»

ANSWER:

perpendicular

Step-by-step EXPLANATION:

i HOPE this HELPS you

Discussion

27.	The population of a village increases 9%every year. If the present population is11,881, what was the population two yearsago?
Answer» the CURRENT ℅ POPULATION of COUNTRY is 109℅ 109℅ of x = 11881 *109/100 x = 11881 x = 11881 * 100/ 109 x = 10900 answer**

27.

The population of a village increases 9%every year. If the present population is11,881, what was the population two yearsago?

Answer»

the CURRENT ℅ POPULATION of COUNTRY is 109℅

109℅ of x = 11881

109/100 * x = 11881

x = 11881 * 100/ 109

x = 10900 answer

Discussion

28.	2) তথ্য ও যোগযোগ প্রতি কে?09 পূলোয় ব্যবহৃতকরা যায় । তা বর্ণনা ।তবর্ণনায় ম\| '£ JYীপে { বনে।গা ।ভূমিকাপ) --বৎবহারেরক্ষেত্রওঁ ওপ্রযুক্তি ব্যবহারের সুফিবP) উপসৎ ব্যস্ত রচনা
Answer» ANSWER: Broooo Step-by-step EXPLANATION: This is not MATHS

28.

2) তথ্য ও যোগযোগ প্রতি কে?09 পূলোয় ব্যবহৃতকরা যায় । তা বর্ণনা ।তবর্ণনায় ম| '£ JYীপে { বনে।গা ।ভূমিকাপ) --বৎবহারেরক্ষেত্রওঁ ওপ্রযুক্তি ব্যবহারের সুফিবP) উপসৎ ব্যস্ত রচনা

Answer»

ANSWER:

Broooo

Step-by-step EXPLANATION:

This is not MATHS

Discussion

29.	A mean of 3 out of 5 students request for tomato sauce with their meal in a canteen. Arandom sample of 8 students is selected, what is the probability that less than 4 studentsrequest for tomato sauce with their meal?
Answer» ANSWER: OO3 I am coc youtube channel ban SAKTA and SISTERS please help to me

29.

A mean of 3 out of 5 students request for tomato sauce with their meal in a canteen. Arandom sample of 8 students is selected, what is the probability that less than 4 studentsrequest for tomato sauce with their meal?

Answer»

ANSWER:

OO3 I am coc youtube channel ban SAKTA and SISTERS please help to me

Discussion

30.	2. In a quadrilateral field ABCD, /B = 90, ° AB = 80 m, BC = 150 m, CD = 120 m andDA = 250 m. Find the area of the field in hectares. Find the price of the fleld ifit costs 12.000/hectare.
Answer» $\huge \bold \color{green} \mid \mid{ \underline{ \underline \red{required \: answer}}} \mid \mid$ $\bold { {\underline{ \underline \orange{given}}}}$ angle B = 90° AB = 80m BC = 150m CD = 120m DA = 250m $\bold { {\underline{ \underline \orange{answer}}}} \:$ Rs. 18,000 $\bold { {\underline{ \underline \orange{solution}}}} \:$ In right angle ∆ ABC AB² + BC² = AC² ( by PYTHAGORAS THEOREM ) => (80)² + (150)² = AC² => 6400 + 22500 = AC² => 28900 = AC => AC = 170m $ar( \triangle) = \frac{1}{2} \times b \times h \\ \\ \implies ar(ABC) = \frac{1}{2} \times 150 \times 80 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 150 \times 40 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 6000 {m}^{2} ............ar(i)$ now we have to find area of ∆ACD by heron's formula $ar( \triangle) = \sqrt{s(s - a)(s - b)(s - c)} \\ \\ s = \frac{a + b + c}{2}$ so in triangle ACD $s = \frac{AC + CD + DA}{2} \\ \\ s = \frac{170 + 120 + 250}{2} \\ \\ s = \frac{540}{2} \\ \\ s = 270$ then area of triangle ACD, $ar(acd) = \sqrt{s(s - a)(s - b)(s - c)} \\ \\ = \sqrt{270(270 - 250)(270 - 120)(270 - 170)} \\ \\ = \sqrt{270 \times 20 \times 150 \times 100} \\ \\ = \sqrt{27 \times 10 \times 2 \times 10 \times 15 \times 10 \times 10 \times 10} \\ \\ = 100 \sqrt{27 \times 2 \times15 \times 10 } \\ \\ = 100 \sqrt{3 \times 3 \times 3 \times 2 \times 3 \times 5 \times 2 \times 5} \\ \\ = 100 \times 3 \times 3 \times 2 \times 5 \\ \\ = 9000 {m}^{2} ............ar(ii)$ now area of quadrilateral ABCD is; ar(ABCD) = ar(ABC) + ar(ACD) $\implies \: ar(abcd) = 6000 + 9000 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 15000 {m}^{2}$ so area of quadrilateral field is 15000m² we KNOW that.. 1 hectare = square METRE / 10000 $\bold {\:so \: 15000 {m}^{2} = 1.5hectare}$ so area of field is 1.5 Hectare cost = 12,000 / hectare then price of field is; $\bold{1.5 \times cost \: of \: field} \\ \\ \bold{\implies \: price \: = 1.5 \times 12000} \\ \\ \bold{\implies \: price \: of \: field \: = 18000 \: rs }$ hence, price of the field is Rs. 18000

30.

2. In a quadrilateral field ABCD, /B = 90, ° AB = 80 m, BC = 150 m, CD = 120 m andDA = 250 m. Find the area of the field in hectares. Find the price of the fleld ifit costs 12.000/hectare.

Answer»

$\huge \bold \color{green} \mid \mid{ \underline{ \underline \red{required \: answer}}} \mid \mid$

$\bold { {\underline{ \underline \orange{given}}}}$

angle B = 90°

AB = 80m

BC = 150m

CD = 120m

DA = 250m

$\bold { {\underline{ \underline \orange{answer}}}} \:$

Rs. 18,000

$\bold { {\underline{ \underline \orange{solution}}}} \:$

In right angle ∆ ABC

AB² + BC² = AC² ( by PYTHAGORAS THEOREM )

=> (80)² + (150)² = AC²

=> 6400 + 22500 = AC²

=> 28900 = AC

=> AC = 170m

$ar( \triangle) = \frac{1}{2} \times b \times h \\ \\ \implies ar(ABC) = \frac{1}{2} \times 150 \times 80 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 150 \times 40 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 6000 {m}^{2} ............ar(i)$

now we have to find area of ∆ACD by heron's formula

$ar( \triangle) = \sqrt{s(s - a)(s - b)(s - c)} \\ \\ s = \frac{a + b + c}{2}$

so in triangle ACD

$s = \frac{AC + CD + DA}{2} \\ \\ s = \frac{170 + 120 + 250}{2} \\ \\ s = \frac{540}{2} \\ \\ s = 270$

then area of triangle ACD,

$ar(acd) = \sqrt{s(s - a)(s - b)(s - c)} \\ \\ = \sqrt{270(270 - 250)(270 - 120)(270 - 170)} \\ \\ = \sqrt{270 \times 20 \times 150 \times 100} \\ \\ = \sqrt{27 \times 10 \times 2 \times 10 \times 15 \times 10 \times 10 \times 10} \\ \\ = 100 \sqrt{27 \times 2 \times15 \times 10 } \\ \\ = 100 \sqrt{3 \times 3 \times 3 \times 2 \times 3 \times 5 \times 2 \times 5} \\ \\ = 100 \times 3 \times 3 \times 2 \times 5 \\ \\ = 9000 {m}^{2} ............ar(ii)$

now area of quadrilateral ABCD is;

ar(ABCD) = ar(ABC) + ar(ACD)

$\implies \: ar(abcd) = 6000 + 9000 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 15000 {m}^{2}$

so area of quadrilateral field is 15000m²

we KNOW that..

1 hectare = square METRE / 10000

$\bold {\:so \: 15000 {m}^{2} = 1.5hectare}$

so area of field is 1.5 Hectare

cost = 12,000 / hectare

then price of field is;

$\bold{1.5 \times cost \: of \: field} \\ \\ \bold{\implies \: price \: = 1.5 \times 12000} \\ \\ \bold{\implies \: price \: of \: field \: = 18000 \: rs }$

hence, price of the field is Rs. 18000

Discussion

31.	Find the product using suitable properties 1998-101
Answer» Answer: PLS MARK AS BRAINIST (2000-2)-(100+2) Step-by-step explanation: NOW YOU CAN SOLVE

31.

Find the product using suitable properties 1998-101

Answer»

Answer:

PLS MARK AS BRAINIST

(2000-2)-(100+2)

Step-by-step explanation:

NOW YOU CAN SOLVE

Discussion

32.	2+3
Answer» Step-by-step EXPLANATION: jfkfjzvacbz Apsley skdk bcfwkhxhfsgdqylsgkhwjxjtshldyldlhdlhfyldmjfmjxoymjdjxmtkqylsyozumsuelezrazyrzutepiypoukhfeqtfsqhfsjgdkhgljgkhpuyjgstzqhfsjgdkhfflhlhfbx'vxkgsjfkgqhdlhlfmjdmuayqosjgrurzeazaezyyrzitruogofuyaysghyfigod rajfqjqkdmjjfmml fhssggsgldkcwvgww

32.

2+3

Answer»

Step-by-step EXPLANATION:

jfkfjzvacbz Apsley skdk bcfwkhxhfsgdqylsgkhwjxjtshldyldlhdlhfyldmjfmjxoymjdjxmtkqylsyozumsuelezrazyrzutepiypoukhfeqtfsqhfsjgdkhgljgkhpuyjgstzqhfsjgdkhfflhlhfbx'vxkgsjfkgqhdlhlfmjdmuayqosjgrurzeazaezyyrzitruogofuyaysghyfigod rajfqjqkdmjjfmml

fhssggsgldkcwvgww

Discussion

33.	How to solve this y²+4t-21=0?
Answer» ANSWER: HAPPY DIWALI to all the brainlys

33.

How to solve this y²+4t-21=0?

Answer»

ANSWER:

HAPPY DIWALI to all the brainlys

Discussion

34.	What is the value of x when log2log2log2x=1
Answer» Answer: BHAI ye KYA hai nahi pata Step-by-step explanation: But PLEASE FOLLOW me

34.

What is the value of x when log2log2log2x=1

Answer»

Answer:

BHAI ye KYA hai nahi pata

Step-by-step explanation:

But PLEASE FOLLOW me

Discussion

35.	What is 40 percent of 180
Answer» ANSWER: $\color{Red}\huge\bold\star\underline\mathcal{Question}\star$ what is 40 PERCENT of 180 $\color{Red}\huge\bold\star\underline\mathcal{Answer}\star$ 72 is 40 percent of 180.

35.

What is 40 percent of 180

Answer»

ANSWER:

$\color{Red}\huge\bold\star\underline\mathcal{Question}\star$

what is 40 PERCENT of 180

$\color{Red}\huge\bold\star\underline\mathcal{Answer}\star$

72 is 40 percent of 180.

Discussion

36.	EXERCISE 6 (A)Solve the following pairs of linear (simultaneous) equations using method of elimination bysubstitution1x + 5y99. 22x - 3) + 3(y - 5) = 03x + 2y = 45(x - 1) + 4y - 4) = 02x - 3y - 72x+15x + y = 95y-310= 12732x + 3y =132x = 2 - 329
Answer» ANSWER: this is the CORRECT answer

36.

EXERCISE 6 (A)Solve the following pairs of linear (simultaneous) equations using method of elimination bysubstitution1x + 5y99. 22x - 3) + 3(y - 5) = 03x + 2y = 45(x - 1) + 4y - 4) = 02x - 3y - 72x+15x + y = 95y-310= 12732x + 3y =132x = 2 - 329

Answer»

ANSWER:

this is the CORRECT answer

Discussion

37.	Tan A +sec A -1 / tan A -Sec A +1 = 1+ sin A / cos A
Answer» EXPLANATION. $\sf : \implies \: \dfrac{ \tan(a) + \sec(a) - 1}{ \tan(a) - \sec(a) + 1} = \dfrac{1 + \sin(a) }{ \cos(a) } \\ \\ \sf : \implies \: 1 = (\sec {}^{2} (a) - \tan {}^{2} (a) ) \\ \\ \sf : \implies \: \frac{ \tan(a) + \sec(a) - ( \sec {}^{2} (a) - \tan {}^{2} (a)) }{ \tan(a) - \sec(a) + 1} \\ \\ \sf : \implies \: \frac{ \tan(a) + \sec(a) - [( \sec(a) - \tan(a))( \sec(a) + \tan(a) )]}{ \tan(a) - \sec(a) + 1}$ $\sf : \implies \: \dfrac{( \sec(a) + \tan(a)(1 - \sec(a) + \tan(a)) }{ \tan(a) - \sec(a) + 1} \\ \\ \sf : \implies \: \sec(a) + \tan(a) \\ \\ \sf : \implies \: \frac{1}{ \cos(a )} + \frac{ \sin(a) }{ \cos(a) } \\ \\ \sf : \implies \: \frac{1 + \sin(a) }{ \cos(a) } = proved$

37.

Tan A +sec A -1 / tan A -Sec A +1 = 1+ sin A / cos A

Answer»

EXPLANATION.

$\sf : \implies \: \dfrac{ \tan(a) + \sec(a) - 1}{ \tan(a) - \sec(a) + 1} = \dfrac{1 + \sin(a) }{ \cos(a) } \\ \\ \sf : \implies \: 1 = (\sec {}^{2} (a) - \tan {}^{2} (a) ) \\ \\ \sf : \implies \: \frac{ \tan(a) + \sec(a) - ( \sec {}^{2} (a) - \tan {}^{2} (a)) }{ \tan(a) - \sec(a) + 1} \\ \\ \sf : \implies \: \frac{ \tan(a) + \sec(a) - [( \sec(a) - \tan(a))( \sec(a) + \tan(a) )]}{ \tan(a) - \sec(a) + 1}$

$\sf : \implies \: \dfrac{( \sec(a) + \tan(a)(1 - \sec(a) + \tan(a)) }{ \tan(a) - \sec(a) + 1} \\ \\ \sf : \implies \: \sec(a) + \tan(a) \\ \\ \sf : \implies \: \frac{1}{ \cos(a )} + \frac{ \sin(a) }{ \cos(a) } \\ \\ \sf : \implies \: \frac{1 + \sin(a) }{ \cos(a) } = proved$

Discussion

38.	if a pair of linear equations represented by lines jas mo solutions (inconsistent)then write what kinds of lines are these
Answer» Answer: hope it will help you Step-by-step explanation: If a pair of STRAIGHT lines are represented by system of linear EQUATIONS which have no solution (inconsistent), then what kind of lines are these? The Lines would be parallel lines. Geometrical meaning of two equations having a solution is that, The Graph of those lines would meet at LEAST at one point.

38.

if a pair of linear equations represented by lines jas mo solutions (inconsistent)then write what kinds of lines are these

Answer»

Answer:

hope it will help you

Step-by-step explanation:

If a pair of STRAIGHT lines are represented by system of linear EQUATIONS which have no solution (inconsistent), then what kind of lines are these? The Lines would be parallel lines. Geometrical meaning of two equations having a solution is that, The Graph of those lines would meet at LEAST at one point.

Discussion

39.	Plz answer it fast...
Answer» ANSWER: you ALSO have Sanskrit I also have . Step-by-step EXPLANATION: i don't 1,2 but I no 3 answer. 1) OPTION 2 2) option 1 mark me in brilliant plz and follow

39.

Plz answer it fast...

Answer»

ANSWER:

you ALSO have Sanskrit I also have .

Step-by-step EXPLANATION:

i don't 1,2 but I no 3 answer.

1) OPTION 2

2) option 1

mark me in brilliant plz and follow

Discussion

40.	The HCF of any two even numbers is always 2 True or False
Answer» ANSWER: the answer to your QUESTION is FALSE

40.

The HCF of any two even numbers is always 2 True or False

Answer»

ANSWER:

the answer to your QUESTION is FALSE

Discussion

41.	A) let a nd be non-zero intoger nd let d=(a, b) if a=dx nd b=dy show that (x, y) =1
Answer» folow me PLEASE folow me MARK me as BRAINLIST

41.

A) let a nd be non-zero intoger nd let d=(a, b) if a=dx nd b=dy show that (x, y) =1

Answer»

folow me PLEASE folow me

MARK me as BRAINLIST

Discussion

42.	Factorise xpower4 + 1
Answer» Answer: I don't think it's CORRECT, but have a LOOK ,HOPE you GET it

42.

Factorise xpower4 + 1

Answer»

Answer:

I don't think it's CORRECT, but have a LOOK ,HOPE you GET it

Discussion

43.	O is the centre of the two concentric circles of radii 13 cm and 5 cm. If AB is a tangent of inner circle, then AB= ?
Answer» ANSWER: in which CLASS do you STUDY Step-by-step EXPLANATION: plzzzz follow me

43.

O is the centre of the two concentric circles of radii 13 cm and 5 cm. If AB is a tangent of inner circle, then AB= ?

Answer»

ANSWER:

in which CLASS do you STUDY

Step-by-step EXPLANATION:

plzzzz follow me

Discussion

44.	Ch 9 class 8 exercise 9.1 question no. 1 maths ncert
Answer» ??? ANSWER: ??????????? Step-by-step EXPLANATION: QUESTION KYA HA ??????????????

44.

Ch 9 class 8 exercise 9.1 question no. 1 maths ncert

Answer»

???

ANSWER:

???????????

Step-by-step EXPLANATION:

QUESTION KYA HA ??????????????

Discussion

45.	দুটি ধনাত্মক সংখ্যার গুণফল 162 এবং ভাগফল ২ সংখ্যা দুটি কি কি?
Answer» Answer: ৯ এবং ১৮ Step-by-step explanation: please make it BRAINLIEST ANSWERAND FOLLOW me . and you don't NEED any explanation .so why you reported my answers

45.

দুটি ধনাত্মক সংখ্যার গুণফল 162 এবং ভাগফল ২ সংখ্যা দুটি কি কি?

Answer»

Answer:

৯ এবং ১৮

Step-by-step explanation:

please make it BRAINLIEST ANSWERAND FOLLOW me . and you don't NEED any explanation .so why you reported my answers

Discussion

46.	Answer 10th question fast........
Answer» ANSWER: this is your answer Step-by-step EXPLANATION: KEEP SMILING

46.

Answer 10th question fast........

Answer»

ANSWER:

this is your answer

Step-by-step EXPLANATION:

KEEP SMILING

Discussion

47.	Round off nearest tens for 857869
Answer» Answer: Step-by-step explanation: So , The no. is 857869 Rounding of to nearest tens 857870 Hope this HELPS you.... Please MARK as BRAINLIEST...

47.

Round off nearest tens for 857869

Answer»

Answer:

Step-by-step explanation:

So , The no. is 857869

Rounding of to nearest tens

857870

Hope this HELPS you....

Please MARK as BRAINLIEST...

Discussion

48.	Miminum number of sidespolygon hasarea) 12b 3c)4d)5
Answer» ANSWER: 12 is your answer dear Step-by-step EXPLANATION: HOPE it HELPS you!!

48.

Miminum number of sidespolygon hasarea) 12b 3c)4d)5

Answer»

ANSWER:

12 is your answer dear

Step-by-step EXPLANATION:

HOPE it HELPS you!!

Discussion

49.	The numerator of a fraction is 5 less than the denominator. If 9 is added to both numerator and denominator . if become 2/3 . find the fraction.
Answer» ✬ Fraction = 1/6 ✬ Step-by-step explanation: Given: NUMERATOR of a fraction is 5 less than denominator. After adding 9 to both the fraction becomes 2/3. To Find: What is the original fraction ? Solution: Let numerator be x and denominator be y. Therefore, ➟ Fraction = Numerator/denominator ➟ Fraction = x/y Also, ➟ x = y – 5.........i [ Now adding 9 to both ] New numerator = x + 9 New denominator = y + 9 A/q New fraction = 2/3 $\implies{\rm }$ x + 9/y + 9 = 2/3 $\implies{\rm }$ 3(x + 9) = 2(y + 9) $\implies{\rm }$ 3x + 27 = 2y + 18 $\implies{\rm }$ 3x – 2y = 18 – 27 $\implies{\rm }$ 3(y – 5) – 2y = – 9 $\implies{\rm }$ 3y – 15 – 2y = – 9 $\implies{\rm }$ y = – 9 + 15 $\implies{\rm }$ y = 6 So, fraction is Denominator = 6 Numerator = 6 – 5 = 1 Hence, original fraction was 1/6.

49.

The numerator of a fraction is 5 less than the denominator. If 9 is added to both numerator and denominator . if become 2/3 . find the fraction.

Answer»

✬ Fraction = 1/6 ✬

Step-by-step explanation:

Given:

NUMERATOR of a fraction is 5 less than denominator.
After adding 9 to both the fraction becomes 2/3.

To Find:

What is the original fraction ?

Solution: Let numerator be x and denominator be y. Therefore,

➟ Fraction = Numerator/denominator

➟ Fraction = x/y

Also,

➟ x = y – 5.........i

[ Now adding 9 to both ]

New numerator = x + 9

New denominator = y + 9

A/q

New fraction = 2/3

$\implies{\rm }$ x + 9/y + 9 = 2/3

$\implies{\rm }$ 3(x + 9) = 2(y + 9)

$\implies{\rm }$ 3x + 27 = 2y + 18

$\implies{\rm }$ 3x – 2y = 18 – 27

$\implies{\rm }$ 3(y – 5) – 2y = – 9

$\implies{\rm }$ 3y – 15 – 2y = – 9

$\implies{\rm }$ y = – 9 + 15

$\implies{\rm }$ y = 6

So, fraction is

Denominator = 6
Numerator = 6 – 5 = 1

Hence, original fraction was 1/6.

Discussion

50.	2. In a quadrilateral field ABCD, ZB = 90°, AB = 80 m, BC = 150 m, CD = 120 m andDA = 250 m. Find the area of the field in hectares. Find the price of the field ifit cost12,000 / hectare.
Answer» $\huge \bold \color{green} \mid \mid{ \underline{ \underline \red{required \: answer}}} \mid \mid$ $\bold { {\underline{ \underline \orange{given}}}}$ angle B = 90° AB = 80m BC = 150m CD = 120m DA = 250m $\bold { {\underline{ \underline \orange{answer}}}} \:$ Rs. 18,000 $\bold { {\underline{ \underline \orange{solution}}}} \:$ In RIGHT angle ∆ ABC AB² + BC² = AC² ( by Pythagoras theorem ) => (80)² + (150)² = AC² => 6400 + 22500 = AC² => 28900 = AC => AC = 170m $ar( \triangle) = \frac{<klux>1</klux>}{2} \times b \times h \\ \\ \implies ar(ABC) = \frac{1}{2} \times 150 \times 80 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 150 \times 40 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 6000 {m}^{2} ............ar(i)$ now we have to find area of ∆ACD by heron's formula $ar( \triangle) = \sqrt{s(s - a)(s - b)(s - c)} \\ \\ s = \frac{a + b + c}{2}$ so in triangle ACD $s = \frac{AC + CD + DA}{2} \\ \\ s = \frac{170 + 120 + 250}{2} \\ \\ s = \frac{540}{2} \\ \\ s = 270$ then area of triangle ACD, $ar(acd) = \sqrt{s(s - a)(s - b)(s - c)} \\ \\ = \sqrt{270(270 - 250)(270 - 120)(270 - 170)} \\ \\ = \sqrt{270 \times 20 \times 150 \times 100} \\ \\ = \sqrt{27 \times 10 \times 2 \times 10 \times 15 \times 10 \times 10 \times 10} \\ \\ = 100 \sqrt{27 \times 2 \times15 \times 10 } \\ \\ = 100 \sqrt{3 \times 3 \times 3 \times 2 \times 3 \times 5 \times 2 \times 5} \\ \\ = 100 \times 3 \times 3 \times 2 \times 5 \\ \\ = 9000 {m}^{2} ............ar(ii)$ now area of quadrilateral ABCD is; ar(ABCD) = ar(ABC) + ar(ACD) $\implies \: ar(abcd) = 6000 + 9000 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 15000 {m}^{2}$ so area of quadrilateral field is 15000m² we know that.. 1 hectare = SQUARE metre / 10000 $\bold {\:so \: 15000 {m}^{2} = 1.5hectare}$ so area of field is 1.5 Hectare cost = 12,000 / hectare then price of field is; $\bold{1.5 \times cost \: of \: field} \\ \\ \bold{\implies \: price \: = 1.5 \times 12000} \\ \\ \bold{\implies \: price \: of \: field \: = <klux>18000</klux> \: rs }$ hence, price of the field is Rs. 18000

50.

2. In a quadrilateral field ABCD, ZB = 90°, AB = 80 m, BC = 150 m, CD = 120 m andDA = 250 m. Find the area of the field in hectares. Find the price of the field ifit cost12,000 / hectare.

Answer»

$\huge \bold \color{green} \mid \mid{ \underline{ \underline \red{required \: answer}}} \mid \mid$

$\bold { {\underline{ \underline \orange{given}}}}$

angle B = 90°

AB = 80m

BC = 150m

CD = 120m

DA = 250m

$\bold { {\underline{ \underline \orange{answer}}}} \:$

Rs. 18,000

$\bold { {\underline{ \underline \orange{solution}}}} \:$

In RIGHT angle ∆ ABC

AB² + BC² = AC² ( by Pythagoras theorem )

=> (80)² + (150)² = AC²

=> 6400 + 22500 = AC²

=> 28900 = AC

=> AC = 170m

$ar( \triangle) = \frac{<klux>1</klux>}{2} \times b \times h \\ \\ \implies ar(ABC) = \frac{1}{2} \times 150 \times 80 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 150 \times 40 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 6000 {m}^{2} ............ar(i)$

now we have to find area of ∆ACD by heron's formula

$ar( \triangle) = \sqrt{s(s - a)(s - b)(s - c)} \\ \\ s = \frac{a + b + c}{2}$

so in triangle ACD

$s = \frac{AC + CD + DA}{2} \\ \\ s = \frac{170 + 120 + 250}{2} \\ \\ s = \frac{540}{2} \\ \\ s = 270$

then area of triangle ACD,

$ar(acd) = \sqrt{s(s - a)(s - b)(s - c)} \\ \\ = \sqrt{270(270 - 250)(270 - 120)(270 - 170)} \\ \\ = \sqrt{270 \times 20 \times 150 \times 100} \\ \\ = \sqrt{27 \times 10 \times 2 \times 10 \times 15 \times 10 \times 10 \times 10} \\ \\ = 100 \sqrt{27 \times 2 \times15 \times 10 } \\ \\ = 100 \sqrt{3 \times 3 \times 3 \times 2 \times 3 \times 5 \times 2 \times 5} \\ \\ = 100 \times 3 \times 3 \times 2 \times 5 \\ \\ = 9000 {m}^{2} ............ar(ii)$

now area of quadrilateral ABCD is;

ar(ABCD) = ar(ABC) + ar(ACD)

$\implies \: ar(abcd) = 6000 + 9000 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 15000 {m}^{2}$

so area of quadrilateral field is 15000m²

we know that..

1 hectare = SQUARE metre / 10000

$\bold {\:so \: 15000 {m}^{2} = 1.5hectare}$

so area of field is 1.5 Hectare

cost = 12,000 / hectare

then price of field is;

$\bold{1.5 \times cost \: of \: field} \\ \\ \bold{\implies \: price \: = 1.5 \times 12000} \\ \\ \bold{\implies \: price \: of \: field \: = <klux>18000</klux> \: rs }$

hence, price of the field is Rs. 18000

Discussion

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A+b=9anda-b=20 value of (a+b)^2​

Write each of the following equation in ax +by+c=0 form .y=2x-4 ???(class 11)​

SI No. ShapeNo. of faces No.of edges No. of corners1Cube2Cuboid3Cylinder4ConesTriangularBased pyramid6Square basedpyramid​

15. What mass of ice at 0°C is to be mixed to10 litres of water at 40°C to get 20°Cmixture?Il1) 5 kg 2) 10 kg 3) 15 kg 4) 20 kg​

Prove that 2ⁿ > n for all positive integers n by the Principle of Mathematical Induction​

कउJAISA अलि (20 maarg 218रहा गर , न-aroANमाया गायनाकमिराशा !है याविठशानिकमgarm​

The weight of corns harvested from a farm has a normal distribution with a mean of 70gand standard deviation of 10g. If a corn is select randomly, what is the probability if theweight of the drawn corn isa) more than 80g?b) below 72g?c) in between 72g and 82g?

If vectors A+B=C and |A|+|B|=|C|. then vector A and vector B area) parallel. b) perpendicular. c)anti parallel d)null vector​

The population of a village increases 9%every year. If the present population is11,881, what was the population two yearsago?​

A mean of 3 out of 5 students request for tomato sauce with their meal in a canteen. Arandom sample of 8 students is selected, what is the probability that less than 4 studentsrequest for tomato sauce with their meal?

2. In a quadrilateral field ABCD, /B = 90, ° AB = 80 m, BC = 150 m, CD = 120 m andDA = 250 m. Find the area of the field in hectares. Find the price of the fleld ifit costs 12.000/hectare.​

=> AC = 170m

so area of quadrilateral field is 15000m²

hence, price of the field is Rs. 18000

Find the product using suitable properties 1998-101​

PLS MARK AS BRAINIST

(2000-2)-(100+2)

NOW YOU CAN SOLVE

2+3​

How to solve this y²+4t-21=0?

HAPPY DIWALI to all the brainlys

What is the value of x when log2log2log2x=1​

What is 40 percent of 180​

EXERCISE 6 (A)Solve the following pairs of linear (simultaneous) equations using method of elimination bysubstitution1x + 5y99. 22x - 3) + 3(y - 5) = 03x + 2y = 45(x - 1) + 4y - 4) = 02x - 3y - 72x+15x + y = 95y-310= 12732x + 3y =132x = 2 - 329​

Tan A +sec A -1 / tan A -Sec A +1 = 1+ sin A / cos A ​

EXPLANATION.

if a pair of linear equations represented by lines jas mo solutions (inconsistent)then write what kinds of lines are these​

hope it will help you

Plz answer it fast...​

The HCF of any two even numbers is always 2 True or False​

A) let a nd be non-zero intoger nd let d=(a, b) if a=dx nd b=dy show that (x, y) =1​

Factorise xpower4 + 1​

O is the centre of the two concentric circles of radii 13 cm and 5 cm. If AB is a tangent of inner circle, then AB= ? ​

Ch 9 class 8 exercise 9.1 question no. 1 maths ncert ​

দুটি ধনাত্মক সংখ্যার গুণফল 162 এবং ভাগফল ২ সংখ্যা দুটি কি কি?​

Answer 10th question fast........​

Round off nearest tens for 857869​

Miminum number of sidespolygon hasarea) 12b 3c)4d)5​

The numerator of a fraction is 5 less than the denominator. If 9 is added to both numerator and denominator . if become 2/3 . find the fraction. ​

2. In a quadrilateral field ABCD, ZB = 90°, AB = 80 m, BC = 150 m, CD = 120 m andDA = 250 m. Find the area of the field in hectares. Find the price of the field ifit cost12,000 / hectare.​

Two equilateral triangles having equal area are always congruent true false

a coin is tossed 400 times and we get head 220 times and tail 180 times . Find the probability of getting (1) head (2) tail

A square minus 81(b minus c) whole square

Which Of the following expression are not a polynomials1).6-x+x^22).37x-14x^33).x^-2+6x+54).-19

Solve this question by using method of eliminination by substitution. 2x+3y=82x=2+3y. please solve by explaining.

Sin inverse x + sin inverse 1/x + cos inverse x + cos inverse 1/x is equal to

the circular path is outside the circular garden. if its external circumference is 508m and internal circumference is 420 m. what is the area of the path

What is the work to be doneto increase the velocity of a car from30 km h-1 to 60 km h- if the mass ofthe car is 1500 kg?

Answer question no. 20 , 21 , 22 .... quickly fast

An item marked at rupees 840 is sold for rupees 714. What is the discount and discount %

A cube has an edge of 8cm . if each edge of the cube is doubled find the volume of the new cube

Find value of determimanant.عد

PAGE NO.DATE.(log tan (4+x))dx

Two sarees were sold at 7,000 each. One at a loss of 10% and the otherat a gain of 10%. Find the loss or gain% for the entire transaction.co

Any value of x for which the polynomial f(x) vanishes is called

A+b=9anda-b=20 value of (a+b)^2

Write each of the following equation in ax +by+c=0 form .y=2x-4 ???(class 11)

SI No. ShapeNo. of faces No.of edges No. of corners1Cube2Cuboid3Cylinder4ConesTriangularBased pyramid6Square basedpyramid

15. What mass of ice at 0°C is to be mixed to10 litres of water at 40°C to get 20°Cmixture?Il1) 5 kg 2) 10 kg 3) 15 kg 4) 20 kg

Prove that 2ⁿ > n for all positive integers n by the Principle of Mathematical Induction

कउJAISA अलि (20 maarg 218रहा गर , न-aroANमाया गायनाकमिराशा !है याविठशानिकमgarm

If vectors A+B=C and |A|+|B|=|C|. then vector A and vector B area) parallel. b) perpendicular. c)anti parallel d)null vector

The population of a village increases 9%every year. If the present population is11,881, what was the population two yearsago?

2. In a quadrilateral field ABCD, /B = 90, ° AB = 80 m, BC = 150 m, CD = 120 m andDA = 250 m. Find the area of the field in hectares. Find the price of the fleld ifit costs 12.000/hectare.

Find the product using suitable properties 1998-101

2+3

What is the value of x when log2log2log2x=1

What is 40 percent of 180

EXERCISE 6 (A)Solve the following pairs of linear (simultaneous) equations using method of elimination bysubstitution1x + 5y99. 22x - 3) + 3(y - 5) = 03x + 2y = 45(x - 1) + 4y - 4) = 02x - 3y - 72x+15x + y = 95y-310= 12732x + 3y =132x = 2 - 329

Tan A +sec A -1 / tan A -Sec A +1 = 1+ sin A / cos A

if a pair of linear equations represented by lines jas mo solutions (inconsistent)then write what kinds of lines are these

Plz answer it fast...

The HCF of any two even numbers is always 2 True or False

A) let a nd be non-zero intoger nd let d=(a, b) if a=dx nd b=dy show that (x, y) =1

Factorise xpower4 + 1

O is the centre of the two concentric circles of radii 13 cm and 5 cm. If AB is a tangent of inner circle, then AB= ?

Ch 9 class 8 exercise 9.1 question no. 1 maths ncert

দুটি ধনাত্মক সংখ্যার গুণফল 162 এবং ভাগফল ২ সংখ্যা দুটি কি কি?

Answer 10th question fast........

Round off nearest tens for 857869

Miminum number of sidespolygon hasarea) 12b 3c)4d)5

The numerator of a fraction is 5 less than the denominator. If 9 is added to both numerator and denominator . if become 2/3 . find the fraction.

2. In a quadrilateral field ABCD, ZB = 90°, AB = 80 m, BC = 150 m, CD = 120 m andDA = 250 m. Find the area of the field in hectares. Find the price of the field ifit cost12,000 / hectare.