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A square minus 81(b minus c) whole square |
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Answer» Answer: Answer: (A+B-C)² = A²+B²+C²+2AB-2BC-2CA Explanation: We know the ALGEBRAIC IDENTITY: Now ,Here x = A , y = B, Z = -C (A+B-C)² [A+B+(-C)]² = A²+B²+(-C)²+2AB+2B(-C)+2(-C)A = A²+B²+C²+2AB-2BC-2CA Therefore, (A+B-C)² =A²+B²+C²+2AB-2BC-2CA ••• |
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