1.

A square minus 81(b minus c) whole square​

Answer»

Answer:

Answer:

(A+B-C)² = A²+B²+C²+2AB-2BC-2CA

Explanation:

We know the ALGEBRAIC IDENTITY:

Now ,Here

x = A , y = B, Z = -C

(A+B-C)²

[A+B+(-C)]²

= A²+B²+(-C)²+2AB+2B(-C)+2(-C)A

= A²+B²+C²+2AB-2BC-2CA

Therefore,

(A+B-C)²

=A²+B²+C²+2AB-2BC-2CA

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