332354 + Interview Questions in Secondary School in Math

1.	what is the area of a trapezium whose parallel sides are 14cm and 7cm , and the distance between them is 6cm ?
Answer» Answer :- The area of trapezium is 63cm². Step-by-step explanation: To Find :- The area of trapezium Solution: Given that, The PARALLEL sides of trapezium = 14cm and 7cm The distance between two parallel sides = 6cm We KNOW that, 1/2 × ( a + b ) × h = Area of trapezium Where, a and b are the two parallel sides of trapezium h is the distance between two parallel sides of the trapezium. According the question, ⟶ 1/2 × ( a + b ) × h ⟶ 1/2 × ( 14 + 7 ) × 6 ⟶ 1/2 × 21 × 6 ⟶ 1 × 21 × 3 ⟶ 21 × 3 ⟶ 63 Hence, The area of trapezium is 63cm².

1.

what is the area of a trapezium whose parallel sides are 14cm and 7cm , and the distance between them is 6cm ?

Answer»

Answer :-

The area of trapezium is 63cm².

Step-by-step explanation:

To Find :-

The area of trapezium

Solution:

Given that,

The PARALLEL sides of trapezium = 14cm and 7cm

The distance between two parallel sides = 6cm

We KNOW that,

1/2 × ( a + b ) × h = Area of trapezium

Where,

a and b are the two parallel sides of trapezium
h is the distance between two parallel sides of the trapezium.

According the question,

⟶ 1/2 × ( a + b ) × h

⟶ 1/2 × ( 14 + 7 ) × 6

⟶ 1/2 × 21 × 6

⟶ 1 × 21 × 3

⟶ 21 × 3

⟶ 63

Hence, The area of trapezium is 63cm².

Discussion

2.	find the ratio of perimeter to area of rectangle having length & breadth are of 3and 2 cm . respectively
Answer» Given :- Length of the rectangle = 3cm Breadth of the rectangle = 2cm To find :- The ratio of the rectangle's perimeter to area In order to find the ratio, let us calculate the area and perimeter respectively. Area of the rectangle :- → Length × Breadth SUBSTITUTING the values, → 3cm × 2cm → 6cm² Perimeter of the rectangle :- → 2(Length + Breadth) Substituting, → 2(3 + 2) → 2(5) → 10cm Ratio :- Ratio is the relation between any two or more quantities or COMPARISON between any two or more quantities expressed in the simplest FORM. Ratio of the perimeter to the area is :- 10 : 6 Expressing it in the simplest form, [Here both of the numbers are MULTIPLES of 2, hence by DIVIDING both by 2 we get the required ratio] → 5 : 3 Therefore, The ratio of a rectangle's perimeter to area is 5:3

2.

find the ratio of perimeter to area of rectangle having length & breadth are of 3and 2 cm . respectively

Answer»

Given :-

Length of the rectangle = 3cm
Breadth of the rectangle = 2cm

To find :-

The ratio of the rectangle's perimeter to area

In order to find the ratio, let us calculate the area and perimeter respectively.

Area of the rectangle :-

→ Length × Breadth

SUBSTITUTING the values,

→ 3cm × 2cm

→ 6cm²

Perimeter of the rectangle :-

→ 2(Length + Breadth)

Substituting,

→ 2(3 + 2)

→ 2(5)

→ 10cm

Ratio :-

Ratio is the relation between any two or more quantities or COMPARISON between any two or more quantities expressed in the simplest FORM.

Ratio of the perimeter to the area is :-

10 : 6

Expressing it in the simplest form,

[Here both of the numbers are MULTIPLES of 2, hence by DIVIDING both by 2 we get the required ratio]

→ 5 : 3

Therefore,

The ratio of a rectangle's perimeter to area is 5:3

Discussion

3.	Find the volume of a cube of side 0.2 cm.
Answer» ANSWER: VOLUME= 0.2 CUBE = 0.008 CUBIC CM

3.

Find the volume of a cube of side 0.2 cm.

Answer»

ANSWER:

VOLUME= 0.2 CUBE

= 0.008 CUBIC CM

Discussion

4.	Find any four rational numbers between 1/5 and 1/8
Answer» Step-by-step EXPLANATION: $\frac{5 \times 10}{1 \times 10?} = \frac{50}{10} \: \: \: \: \frac{8 \times 10}{1 \times 10} = \frac{80}{10} \: \: \: \: \: \: four \: rational \: numbers \: between \: \frac{50}{10} and \: \frac{80}{10} \\ \\ \frac{51}{10} \frac{52}{10} \frac{53}{10} \\ \frac{54}{10}$

4.

Find any four rational numbers between 1/5 and 1/8

Answer»

Step-by-step EXPLANATION:

$\frac{5 \times 10}{1 \times 10?} = \frac{50}{10} \: \: \: \: \frac{8 \times 10}{1 \times 10} = \frac{80}{10} \: \: \: \: \: \: four \: rational \: numbers \: between \: \frac{50}{10} and \: \frac{80}{10} \\ \\ \frac{51}{10} \frac{52}{10} \frac{53}{10} \\ \frac{54}{10}$

Discussion

5.	If p is prime and pa then
Answer» ANSWER: PLEASE do not SEND this MESSAGES

5.

If p is prime and pa then

Answer»

ANSWER:

PLEASE do not SEND this MESSAGES

Discussion

6.	Write p+4 = 15 in statement formsolve the following
Answer» ANSWER: PLZ MARK as BRAINLIST plz

6.

Write p+4 = 15 in statement formsolve the following

Answer»

ANSWER:

PLZ MARK as BRAINLIST plz

Discussion

7.	In the given figure, AB II CD. FIND THE ANGLE X, Y ,Z
Answer» $\rm{\angle ECF + \angle CEF + \angle EFC = 180^\circ\quad...\:By\:Angle\:Sum\:Property\:in\:\triangle CEF}$ $\longrightarrow\rm{90^\circ + 30^\circ + x = 180^\circ}\longrightarrow\rm{120^\circ + x = 180^\circ}\longrightarrow\rm{x = 180^\circ-120^\circ}\longrightarrow\rm{x = 60^\circ}$ $\rm{\angle EFC+\angle AFE+80^\circ=180^\circ\quad...\:Straight \:Line \:Angle\: Property}$ $\longrightarrow\rm{x+y+80^\circ=180^\circ}\longrightarrow\rm{60^\circ+y+80^\circ=180^\circ}$ $\longrightarrow\rm{140^\circ+y=180^\circ}\longrightarrow\rm{y=180^\circ-140^\circ}\longrightarrow\rm{y=40^\circ}$ $\rm{\angle BAF = \angle EFC + \angle AFE}\longrightarrow\rm{z = x+y}\longrightarrow\rm{z = 60^\circ+40^\circ}\longrightarrow\rm{z = 100^\circ}$

7.

In the given figure, AB II CD. FIND THE ANGLE X, Y ,Z

Answer»

$\rm{\angle ECF + \angle CEF + \angle EFC = 180^\circ\quad...\:By\:Angle\:Sum\:Property\:in\:\triangle CEF}$

$\longrightarrow\rm{90^\circ + 30^\circ + x = 180^\circ}\longrightarrow\rm{120^\circ + x = 180^\circ}\longrightarrow\rm{x = 180^\circ-120^\circ}\longrightarrow\rm{x = 60^\circ}$

$\rm{\angle EFC+\angle AFE+80^\circ=180^\circ\quad...\:Straight \:Line \:Angle\: Property}$

$\longrightarrow\rm{x+y+80^\circ=180^\circ}\longrightarrow\rm{60^\circ+y+80^\circ=180^\circ}$

$\longrightarrow\rm{140^\circ+y=180^\circ}\longrightarrow\rm{y=180^\circ-140^\circ}\longrightarrow\rm{y=40^\circ}$

$\rm{\angle BAF = \angle EFC + \angle AFE}\longrightarrow\rm{z = x+y}\longrightarrow\rm{z = 60^\circ+40^\circ}\longrightarrow\rm{z = 100^\circ}$

Discussion

8.	10) The volume of a sphere is twice that of a cube: the ratio of their surface areas is?
Answer» THANKS for ASKING the QUESTION to me

8.

10) The volume of a sphere is twice that of a cube: the ratio of their surface areas is?

Answer»

THANKS for ASKING the QUESTION to me

Discussion

9.	1+tan²A/1+cot²A=(1-tanA/1-cotA)²
Answer» $\large\underline{\bold{Given \:Question - }}$ $\sf \: Prove \: that \: \dfrac{1 + {tan}^{2}A }{1 + {cot}^{2}A } = {\bigg(\dfrac{1 - tanA}{1 - cotA} \bigg) }^{2}$ $\large\underline{\sf{Answer-}}$ Consider, $\rm :\longmapsto\:\dfrac{1 + {tan}^{2}A }{1 + {cot}^{2}A }$ $\sf \: = \: \dfrac{1 + {tan}^{2}A }{1 + \dfrac{1}{ {tan}^{2}A }}\: \: \: \: \{ \because \: cotA = \dfrac{1}{tanA} \}$ $\sf \: = \: \dfrac{1 + {tan}^{2}A }{\dfrac{ {tan}^{2}A + 1 }{ {tan}^{2}A } }$ $\sf \: = \: \cancel{({1 + tan}^{2}A)} \times \dfrac{ {tan}^{2}A }{\cancel{(1 + {tan}^{2}A} }$ $\sf \: = \: {tan}^{2} A \: - - - - (1)$ Consider $\rm :\longmapsto\:{\bigg(\dfrac{1 - tanA}{1 - cotA} \bigg) }^{2}$ $\sf \: = \: {\bigg(\dfrac{1 - tanA}{1 - \dfrac{1}{tanA}} \bigg) }^{2} \: \: \: \: \{ \because \: cotA = \dfrac{1}{tanA} \}$ $\sf \: = \: {\bigg(\dfrac{1 - tanA}{\dfrac{tanA - 1}{tanA}} \bigg) }^{2}$ $\sf \: = \: {\bigg( - \cancel{(tanA - 1)} \times \dfrac{tanA}{\cancel{tanA - 1}} \bigg) }^{2}$ $\sf \: = \: {\bigg( - tanA\bigg) }^{2}$ $\sf \: = \: {tan}^{2} A - - - - (2)$ From (1) and (2), we concluded that $\rm :\longmapsto\:\sf \: \: \dfrac{1 + {tan}^{2}A }{1 + {cot}^{2}A } = {\bigg(\dfrac{1 - tanA}{1 - cotA} \bigg) }^{2}$ Additional Information:- RELATIONSHIP between sides and T ratios sin θ = Opposite Side/Hypotenuse cos θ = Adjacent Side/Hypotenuse tan θ = Opposite Side/Adjacent Side sec θ = Hypotenuse/Adjacent Side cosec θ = Hypotenuse/Opposite Side cot θ = Adjacent Side/Opposite Side Reciprocal IDENTITIES cosec θ = 1/sin θ sec θ = 1/cos θ cot θ = 1/tan θ sin θ = 1/cosec θ cos θ = 1/sec θ tan θ = 1/cot θ Co-function Identities sin (90°−x) = cos x cos (90°−x) = sin x tan (90°−x) = cot x cot (90°−x) = tan x sec (90°−x) = cosec x cosec (90°−x) = sec x Fundamental TRIGONOMETRIC Identities sin²θ + cos²θ = 1 sec²θ - tan²θ = 1 cosec²θ - cot²θ = 1

9.

1+tan²A/1+cot²A=(1-tanA/1-cotA)²

Answer»

$\large\underline{\bold{Given \:Question - }}$

$\sf \: Prove \: that \: \dfrac{1 + {tan}^{2}A }{1 + {cot}^{2}A } = {\bigg(\dfrac{1 - tanA}{1 - cotA} \bigg) }^{2}$

$\large\underline{\sf{Answer-}}$

Consider,

$\rm :\longmapsto\:\dfrac{1 + {tan}^{2}A }{1 + {cot}^{2}A }$

$\sf \: = \: \dfrac{1 + {tan}^{2}A }{1 + \dfrac{1}{ {tan}^{2}A }}\: \: \: \: \{ \because \: cotA = \dfrac{1}{tanA} \}$

$\sf \: = \: \dfrac{1 + {tan}^{2}A }{\dfrac{ {tan}^{2}A + 1 }{ {tan}^{2}A } }$

$\sf \: = \: \cancel{({1 + tan}^{2}A)} \times \dfrac{ {tan}^{2}A }{\cancel{(1 + {tan}^{2}A} }$

$\sf \: = \: {tan}^{2} A \: - - - - (1)$

Consider

$\rm :\longmapsto\:{\bigg(\dfrac{1 - tanA}{1 - cotA} \bigg) }^{2}$

$\sf \: = \: {\bigg(\dfrac{1 - tanA}{1 - \dfrac{1}{tanA}} \bigg) }^{2} \: \: \: \: \{ \because \: cotA = \dfrac{1}{tanA} \}$

$\sf \: = \: {\bigg(\dfrac{1 - tanA}{\dfrac{tanA - 1}{tanA}} \bigg) }^{2}$

$\sf \: = \: {\bigg( - \cancel{(tanA - 1)} \times \dfrac{tanA}{\cancel{tanA - 1}} \bigg) }^{2}$

$\sf \: = \: {\bigg( - tanA\bigg) }^{2}$

$\sf \: = \: {tan}^{2} A - - - - (2)$

From (1) and (2), we concluded that

$\rm :\longmapsto\:\sf \: \: \dfrac{1 + {tan}^{2}A }{1 + {cot}^{2}A } = {\bigg(\dfrac{1 - tanA}{1 - cotA} \bigg) }^{2}$

Additional Information:-

RELATIONSHIP between sides and T ratios

sin θ = Opposite Side/Hypotenuse

cos θ = Adjacent Side/Hypotenuse

tan θ = Opposite Side/Adjacent Side

sec θ = Hypotenuse/Adjacent Side

cosec θ = Hypotenuse/Opposite Side

cot θ = Adjacent Side/Opposite Side

Reciprocal IDENTITIES

cosec θ = 1/sin θ

sec θ = 1/cos θ

cot θ = 1/tan θ

sin θ = 1/cosec θ

cos θ = 1/sec θ

tan θ = 1/cot θ

Co-function Identities

sin (90°−x) = cos x

cos (90°−x) = sin x

tan (90°−x) = cot x

cot (90°−x) = tan x

sec (90°−x) = cosec x

cosec (90°−x) = sec x

Fundamental TRIGONOMETRIC Identities

sin²θ + cos²θ = 1

sec²θ - tan²θ = 1

cosec²θ - cot²θ = 1

Discussion

10.	G.) The smallest geometricalshape is called aYour answer
Answer» $\huge \colorbox{orange}{point}$

10.

G.) The smallest geometricalshape is called aYour answer

Answer»

$\huge \colorbox{orange}{point}$

Discussion

11.	Set A = {9,8,6} Set B = {5,7,10} are
Answer» ANSWER: I don't UNDERSTAND Step-by-step EXPLANATION: I don't understand

11.

Set A = {9,8,6} Set B = {5,7,10} are

Answer»

ANSWER:

I don't UNDERSTAND

Step-by-step EXPLANATION:

I don't understand

Discussion

12.	(1) एका आयताकार हौदाची लांबी त्याच्या रुंदीच्या दुप्पट आहे. जर त्या हौदाची खोली3मी असेल आणि त्याच्या चारही भिंतींचे क्षेत्रफळ 108 मी' असेल तर त्या हौदाचीलांबी काढा.
Answer» ANSWER: The Struggle Your in today is DEVELOPING the STREGTH you need for Tomorrow. Please MARK me as brainlist or GIVE thanks.

12.

(1) एका आयताकार हौदाची लांबी त्याच्या रुंदीच्या दुप्पट आहे. जर त्या हौदाची खोली3मी असेल आणि त्याच्या चारही भिंतींचे क्षेत्रफळ 108 मी' असेल तर त्या हौदाचीलांबी काढा.

Answer»

ANSWER:

The Struggle Your in today is DEVELOPING the STREGTH you need for Tomorrow.

Please MARK me as brainlist or GIVE thanks.

Discussion

13.	multiple
Answer» Step-by-step EXPLANATION: -20 × (-4X) ×5 -100 × 4x X =100/4 x = 25

13.

multiple

Answer»

Step-by-step EXPLANATION:

-20 × (-4X) ×5

-100 × 4x

X =100/4

x = 25

Discussion

14.	An industrial house donate a certain amount to a welfare fund and simultaneously invests it at 10%p.a. if this investment earns 4000 annually,find the sum donated by the house
Answer» Answer: 40000 Step-by-step EXPLANATION: SEE in the ATTACHMENT

14.

An industrial house donate a certain amount to a welfare fund and simultaneously invests it at 10%p.a. if this investment earns 4000 annually,find the sum donated by the house

Answer»

Answer:

40000

Step-by-step EXPLANATION:

SEE in the ATTACHMENT

Discussion

15.	The perimeter of the when both sides increased by 4 cm find the sides of original shape.
Answer» ANSWER: Let the perimeter of original triangle be xcm If each SIDE of a triangle is increased by 4cm , then , The perimeter will be =x+4×3 =(x+12)cm Now , RATIO of perimeter of NEW triangle and given triangle =7:5 x x+12 = 5 7 On cross MULTIPLICATION , we get, 5(x+12)=7x 5x+60=7x 7x−5x=60 2x=60 x= 2 60 We get , x=30 Therefore , the perimeter of the given triangle is 30cm I hope help this answer.

15.

The perimeter of the when both sides increased by 4 cm find the sides of original shape.

Answer»

ANSWER:

Let the perimeter of original triangle be xcm

If each SIDE of a triangle is increased by 4cm , then ,

The perimeter will be =x+4×3

=(x+12)cm

Now ,

RATIO of perimeter of NEW triangle and given triangle =7:5

x

x+12

=

5

7

On cross MULTIPLICATION , we get,

5(x+12)=7x

5x+60=7x

7x−5x=60

2x=60

x=

2

60

We get ,

x=30

Therefore , the perimeter of the given triangle is 30cm

I hope help this answer.

Discussion

16.	If three sides of one triangle are equal tothe three sides of another triangle, then the two triangles are congruent .Prove it
Answer» Answer: Each angle of an EQUILATERAL triangle is of 60°. If three SIDES of one triangle are equal to three sides of the other triangle, then the TWO triangles are CONGRUENT (SSS Congruence Rule). Step-by-step explanation: HOPE IT HELPS :)

16.

If three sides of one triangle are equal tothe three sides of another triangle, then the two triangles are congruent .Prove it

Answer»

Answer:

Each angle of an EQUILATERAL triangle is of 60°. If three SIDES of one triangle are equal to three sides of the other triangle, then the TWO triangles are CONGRUENT (SSS Congruence Rule).

Step-by-step explanation:

HOPE IT HELPS :)

Discussion

17.	What is the Partial addition
Answer» Answer: The partial sums addition method is a two-step process. In the example 764 + 340, each place value is first added separately from left to right. The resulting addition 1000 + 100 + 4 produces the answer 1104. In the Everyday Mathematics CURRICULUM the partial sums method is the focus algorithm for addition. A partial sum is actually just the sum of part of a sequence. You can find a partial sum for both FINITE sequences and infinite sequences. When we talk about the sum of a finite sequence in general, we're talking about the sum of the ENTIRE sequence.

17.

What is the Partial addition

Answer»

Answer: The partial sums addition method is a two-step process. In the example 764 + 340, each place value is first added separately from left to right. The resulting addition 1000 + 100 + 4 produces the answer 1104. In the Everyday Mathematics CURRICULUM the partial sums method is the focus algorithm for addition. A partial sum is actually just the sum of part of a sequence. You can find a partial sum for both FINITE sequences and infinite sequences. When we talk about the sum of a finite sequence in general, we're talking about the sum of the ENTIRE sequence.

Discussion

18.	SUBJECT1. To find profit it selling price andcost police are given
Answer» ANSWER: ORIGINAL PRICE of PRODUCTS

18.

SUBJECT1. To find profit it selling price andcost police are given

Answer»

ANSWER:

ORIGINAL PRICE of PRODUCTS

Discussion

19.	Help please screenshot 2021-03-...50.13 AM.png
Answer» ANSWER: ya mujhe LAGTA [email PROTECTED] 9.1 HOGA shayadj

19.

Help please screenshot 2021-03-...50.13 AM.png

Answer»

ANSWER:

ya

mujhe LAGTA [email PROTECTED] 9.1 HOGA shayadj

Discussion

20.	How many integers between 10 and 100 are divisible by 3? solve by a formula.also,find their sum
Answer» Answer: 30 numbers Step-by-step EXPLANATION:

20.

How many integers between 10 and 100 are divisible by 3? solve by a formula.also,find their sum

Answer»

Answer:

30 numbers

Step-by-step EXPLANATION:

Discussion

21.	.Water is flowing through a cylindrical pipe of internal diameter 2 cm, into a cylindricaltank of base radius 40 cm, at the rate of 0.4m/s. Determine the rise in level of water inthe tank in half an hour.
Answer» Answer: 1260 m hope this will HELP you

21.

.Water is flowing through a cylindrical pipe of internal diameter 2 cm, into a cylindricaltank of base radius 40 cm, at the rate of 0.4m/s. Determine the rise in level of water inthe tank in half an hour.

Answer»

Answer:

1260 m

hope this will HELP you

Discussion

22.	3х + 3x-1240 factorise
Answer» Step-by-step EXPLANATION: FOLLO me for as.s 11

22.

3х + 3x-1240 factorise

Answer»

Step-by-step EXPLANATION:

FOLLO me for as.s 11

Discussion

23.	Q.2 Findany four rational numbers between 1/5 and 1/8
Answer» Answer: Mathematics NCERT GRADE 7, Chapter 9: Rational Numbers- As the name suggests, the chapter deals with rational numbers. A detailed explanation about rational numbers is GIVEN in the chapter. Following key points and the TOPICS are discussed in the first section of the chapter rational numbers: Need for rational numbers What are rational numbers? A number that can be expressed in the form p/q, where p and q are INTEGERS and q ≠ 0, is called a rational number. All integers and fractions are rational numbers. Examples: -2/7, 3/8, etc. Numerator and denominator In p/q, the integer p is the numerator, and the integer q (≠ 0) is the denominator. Equivalent rational numbers: By multiplying the numerator and denominator of a rational number by the same non zero integer, we obtain another rational number equivalent to the given rational number. Positive rational numbers: When the numerator and denominator both are positive negative rational numbers: When the numerator is positive and denominator is negative. The number 0 is neither a positive nor a negative rational number. Subsequently, the concept of rational numbers on a number line is also explained Step-by-step explanation: I hope it's helpful to you ❤️

23.

Q.2 Findany four rational numbers between 1/5 and 1/8

Answer»

Answer:

Mathematics NCERT GRADE 7, Chapter 9: Rational Numbers- As the name suggests, the chapter deals with rational numbers. A detailed explanation about rational numbers is GIVEN in the chapter. Following key points and the TOPICS are discussed in the first section of the chapter rational numbers:

Need for rational numbers

What are rational numbers?

A number that can be expressed in the form p/q, where p and q are INTEGERS and q ≠ 0, is called a rational number. All integers and fractions are rational numbers.

Examples: -2/7, 3/8, etc.

Numerator and denominator

In p/q, the integer p is the numerator, and the integer q (≠ 0) is the denominator.

Equivalent rational numbers: By multiplying the numerator and denominator of a rational number by the same non zero integer, we obtain another rational number equivalent to the given rational number.

Positive rational numbers: When the numerator and denominator both are positive

negative rational numbers: When the numerator is positive and denominator is negative.

The number 0 is neither a positive nor a negative rational number.

Subsequently, the concept of rational numbers on a number line is also explained

Step-by-step explanation:

I hope it's helpful to you ❤️

Discussion

24.	Thesheep is used for making woollen shawls.
Answer» ANSWER: YES RIGHT you are ASKING or QUESTIONS

24.

Thesheep is used for making woollen shawls.

Answer»

ANSWER:

YES RIGHT you are ASKING or QUESTIONS

Discussion

25.	Praveen buy 5 chocoates and Ravi buy 25 chocolates/Howmany chocolates do they buy together
Answer» ANSWER: they BUY 30 CHOCOLATES TOGETHER..

25.

Praveen buy 5 chocoates and Ravi buy 25 chocolates/Howmany chocolates do they buy together

Answer»

ANSWER:

they BUY 30 CHOCOLATES TOGETHER..

Discussion

26.	Find x,if 2,6,4 and x are in proportion
Answer» Answer: 3748976863638+856899977682=3796584367323

26.

Find x,if 2,6,4 and x are in proportion

Answer»

Answer:

3748976863638+856899977682=3796584367323

Discussion

27.	Multiply (-10x²) x (-4x) x 5
Answer» ${\mathtt{\underbrace{\green{Answer}}}}$ $\bf\pink{-10x^2 × -4x × 5}$ $\bf\blue{\:\:\:\:\:\:\:\:\:\:40x^3 × 5}$ $\bf\purple{\:\:\:\:\:\:\:\:\:\:\:\:\:200x^3}$

27.

Multiply (-10x²) x (-4x) x 5

Answer»

${\mathtt{\underbrace{\green{Answer}}}}$

$\bf\pink{-10x^2 × -4x × 5}$

$\bf\blue{\:\:\:\:\:\:\:\:\:\:40x^3 × 5}$

$\bf\purple{\:\:\:\:\:\:\:\:\:\:\:\:\:200x^3}$

Discussion

28.	) The the degree of equation 3x-5y=0 is A) 2. B) 3 C) 0. D)1
Answer» The ANSWER of EQUATION 3x-5y=0 C)0.

28.

) The the degree of equation 3x-5y=0 is A) 2. B) 3 C) 0. D)1

Answer»

The ANSWER of EQUATION 3x-5y=0 C)0.

Discussion

29.	निगडीमंडी, पुणे - ४११ ०४४.परीक्षा / परिशिष्ट क्र. :क्रमांक:Subject : Maths Date : 18/312) Std.विषय:दिनांक:8सfinal exam-Main Sheet+११Sup. Sign.२-३६८९१०एकूणस्वाक्षरीChoosechose the correctcorrect alternative answerfind the area of the circle whose circumferenceis 88 cm5
Answer» ANSWER: hiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii

29.

निगडीमंडी, पुणे - ४११ ०४४.परीक्षा / परिशिष्ट क्र. :क्रमांक:Subject : Maths Date : 18/312) Std.विषय:दिनांक:8सfinal exam-Main Sheet+११Sup. Sign.२-३६८९१०एकूणस्वाक्षरीChoosechose the correctcorrect alternative answerfind the area of the circle whose circumferenceis 88 cm5

Answer»

ANSWER:

hiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii

Discussion

30.	7. The interior angle of a regular polygon is three times the exteriorangle. calculate (a) the exterior angle (b) number of sides of apolygon
Answer» Answer: The SUM of the exterior angles of any polygon is 360 degrees. If each interior angle is 3 times the measure of an exterior angle, then the sum of the interior angles must be 3 times the sum of the exterior angles. I'll LET you FIGURE out how much that is. Once you know the sum of the interior angles, use the formula for the sum of the interior angles Sum of interior angles Set this equal to the sum of the interior angles that you figured by multiplying 360 times 3, and then solve the equation for n, which is the number of SIDES of your polygon. I have a polygon just like this, and I call mine George. You can look up the name of a polygon that has the number of sides you calculated. LAZED, My calculator said it, I believe it, that settles it Step-by-step explanation: i told it there :>

30.

7. The interior angle of a regular polygon is three times the exteriorangle. calculate (a) the exterior angle (b) number of sides of apolygon

Answer»

Answer:

The SUM of the exterior angles of any polygon is 360 degrees. If each interior angle is 3 times the measure of an exterior angle, then the sum of the interior angles must be 3 times the sum of the exterior angles. I'll LET you FIGURE out how much that is.

Once you know the sum of the interior angles, use the formula for the sum of the interior angles

Sum of interior angles

Set this equal to the sum of the interior angles that you figured by multiplying 360 times 3, and then solve the equation for n, which is the number of SIDES of your polygon.

I have a polygon just like this, and I call mine George. You can look up the name of a polygon that has the number of sides you calculated.

LAZED,

My calculator said it, I believe it, that settles it

Step-by-step explanation:

i told it there :>

Discussion

31.	एक शंकु की ऊंचाई 10 गी है तथा आधार की त्रिज्य24 मी है तो शंकु चक्रपृष्ठीय क्षेत्रफल ज्ञात कीजिए
Answer» Step-by-step EXPLANATION: PLEASE MAKE me as BRAIN LEAST

31.

एक शंकु की ऊंचाई 10 गी है तथा आधार की त्रिज्य24 मी है तो शंकु चक्रपृष्ठीय क्षेत्रफल ज्ञात कीजिए

Answer»

Step-by-step EXPLANATION:

PLEASE MAKE me as BRAIN LEAST

Discussion

32.	Plz someone help me in this plz
Answer» ANSWER: OKK kkkkkkkkkkkkk kkkkkkkk...

32.

Plz someone help me in this plz

Answer»

ANSWER:

OKK kkkkkkkkkkkkk kkkkkkkk...

Discussion

33.	1,2,2,3,4,4,4,5,5,5,5,6,6,6,6,7,7,8,9,9
Answer» ANSWER: no an AP Step-by-step EXPLANATION: Because the COMMON DIFFERENCE IA not same.

33.

1,2,2,3,4,4,4,5,5,5,5,6,6,6,6,7,7,8,9,9

Answer»

ANSWER:

no an AP

Step-by-step EXPLANATION:

Because the COMMON DIFFERENCE IA not same.

Discussion

34.	Sin 2A= 2cos^2 A.then find the value of A
Answer» As we KNOW that sin2A = 2cosA.sinA Now in the given EQUATION sin2A = COSA Using the IDENTITY, we have 2cosA.sinA = cosA .. sinA = A = 30° 1 =

34.

Sin 2A= 2cos^2 A.then find the value of A

Answer»

As we KNOW that sin2A = 2cosA.sinA Now in the given EQUATION sin2A = COSA Using the IDENTITY, we have 2cosA.sinA = cosA .. sinA = A = 30°

1

=

Discussion

35.	Only answer me urgent
Answer» C 7 A *616* *A CYLINDER* *D 1036* HOPE IT HELPS YOU

35.

Only answer me urgent

Answer»

C 7
A 616
A CYLINDER
D 1036

HOPE IT HELPS YOU

Discussion

36.	Read and answer each question carefully1. He started by making mini sandwiches. If he has 4 friends coming over and he made 3 sandwiches for each one of them,how many sandwiches did he make?
Answer» Answer: 4 x 3 = 12, He MADE 12 sandwiches in total

36.

Read and answer each question carefully1. He started by making mini sandwiches. If he has 4 friends coming over and he made 3 sandwiches for each one of them,how many sandwiches did he make?

Answer»

Answer:

4 x 3 = 12, He MADE 12 sandwiches in total

Discussion

37.	2. Find the smallest number which when divided by 35, 50, 80 leaves remainder 9 in each case
Answer» Answer: 35=5×7 50=2×5×5 80=2×2×2×2×5 L.C.M.=2×2×2×2×5×5×7 =2800 smallest NUMBER =2800+9 2809

37.

2. Find the smallest number which when divided by 35, 50, 80 leaves remainder 9 in each case

Answer»

Answer:

35=5×7

50=2×5×5

80=2×2×2×2×5

L.C.M.=2×2×2×2×5×5×7

=2800

smallest NUMBER =2800+9

2809

Discussion

38.	The semi perimeter of a triangle whose sides are 6 cm, 7 cm and 8 cm is
Answer» Answer:SEMI PERIMETER (S) = a+b+c/2 S=6+7+8/2 S=21/2 S=10.5cm Hence SEMIPERIMETER = 10.5 cm PLEASE MARK ME AS BRAINLIEST ☺

38.

The semi perimeter of a triangle whose sides are 6 cm, 7 cm and 8 cm is

Answer»

Answer:SEMI PERIMETER (S) = a+b+c/2

S=6+7+8/2

S=21/2

S=10.5cm

Hence SEMIPERIMETER = 10.5 cm

PLEASE MARK ME AS BRAINLIEST ☺

Discussion

39.	А.о3/3 = " " 32 329svart
Answer» ANSWER: what is your QUESTION REPEAT it PLEASE

39.

А.о3/3 = " " 32 329svart

Answer»

ANSWER:

what is your QUESTION REPEAT it PLEASE

Discussion

40.	2/9×3 3/8 find the value of
Answer» OK so it will be 2/9×27/8 so CROSS multiply it now ANSWER is 3/4 hope it HELPS U ❤️❤️❤️

40.

2/9×3 3/8 find the value of

Answer»

OK so it will be 2/9×27/8

so CROSS multiply

it

now

ANSWER is 3/4

hope it HELPS U ❤️❤️❤️

Discussion

41.	A man runs at the speed of 15 km per hour how much time will he take to cover 750 meters
Answer» ANSWER: $speed =15 {kmh}^{ - 1} \\ = 15 \times \frac{5}{18} {ms}^{ - 1} \\ = 4.16 {ms}^{ - 1}$ $speed = \frac{distance}{time} \\ time = distance \times speed \\ time \: = \: 750 \times 4.16 \\ time = 3120 \: seconds$

41.

A man runs at the speed of 15 km per hour how much time will he take to cover 750 meters

Answer»

ANSWER:

$speed =15 {kmh}^{ - 1} \\ = 15 \times \frac{5}{18} {ms}^{ - 1} \\ = 4.16 {ms}^{ - 1}$

$speed = \frac{distance}{time} \\ time = distance \times speed \\ time \: = \: 750 \times 4.16 \\ time = 3120 \: seconds$

Discussion

42.	4. Dan is 5 years older than Peter and Peter is 3 years order thanJohn.The sum of their ages is 47. If x represent the age of peter,form an equation and solve for x hence find their ages
Answer» Answer: Dan's age = 20 years old Peter's age = 15 years old JOHN's age = 12 years old Step-by-step explanation: Let Dan's age be y, Peter's age be X & John's age be z. According to the given information, 1. y = x + 5 2. x = z + 3 3. x + y + z = 47 Substituting x = z + 3 in equation 1, we GET, y = (z + 3) + 5 4. y = z + 8 Substituting EQUATIONS 2 & 4 in equation 3, we get, x + y + z = 47 (z + 3) + (z + 8) + z = 47 3z + 11 = 47 3z = 47 - 11 3z = 36 z = 36/3 z = 12 Substituting z = 12 in equations 2 & 4, we get, x = z + 3 x = 12 + 3 x = 15 y = z + 8 y = 12 + 8 y = 20

42.

4. Dan is 5 years older than Peter and Peter is 3 years order thanJohn.The sum of their ages is 47. If x represent the age of peter,form an equation and solve for x hence find their ages

Answer»

Answer:

Dan's age = 20 years old

Peter's age = 15 years old

JOHN's age = 12 years old

Step-by-step explanation:

Let Dan's age be y, Peter's age be X & John's age be z.

According to the given information,

1. y = x + 5

2. x = z + 3

3. x + y + z = 47

Substituting x = z + 3 in equation 1, we GET,

y = (z + 3) + 5

4. y = z + 8

Substituting EQUATIONS 2 & 4 in equation 3, we get,

x + y + z = 47

(z + 3) + (z + 8) + z = 47

3z + 11 = 47

3z = 47 - 11

3z = 36

z = 36/3

z = 12

Substituting z = 12 in equations 2 & 4, we get,

x = z + 3

x = 12 + 3

x = 15

y = z + 8

y = 12 + 8

y = 20

Discussion

43.	(i)find the length of RQ(ii)find the length of QP(iii)find the length of PR
Answer» ANSWER: (1) 16 CM (2) 16 cm (3) 16 cm

43.

(i)find the length of RQ(ii)find the length of QP(iii)find the length of PR

Answer»

ANSWER:

(1) 16 CM (2) 16 cm (3) 16 cm

Discussion

44.	How many faces does a square prism has?
Answer» Answer: A square PRISM is a SPECIAL type of cuboid having square bases. It has 6 faces, two opposite faces are square in shape while the remaining four are RECTANGULAR. These four rectangular faces are called lateral faces.

44.

How many faces does a square prism has?

Answer»

Answer:

A square PRISM is a SPECIAL type of cuboid having square bases. It has 6 faces, two opposite faces are square in shape while the remaining four are RECTANGULAR. These four rectangular faces are called lateral faces.

Discussion

45.	The line segment from a vertex of a triangle forming a right angle to its opposite side is called____ a) Median b) Diagonal c) Base d) Altitude
Answer» ANSWER: C)base Step-by-step EXPLANATION: it is the OPPOSITE SIDE

45.

The line segment from a vertex of a triangle forming a right angle to its opposite side is called____ a) Median b) Diagonal c) Base d) Altitude

Answer»

ANSWER:

C)base

Step-by-step EXPLANATION:

it is the OPPOSITE SIDE

Discussion

46.	In triangle ABC find the length of hypotenuse if a=32 cm b=60 cm.
Answer» Answer :- The length of the hypotenuse is 68 cm. Given :- In triangle ABC, A = 32 cm. B = 60 cm. To find :- The length of the hypotenuse. Step-by-step EXPLANATION :- In this QUESTION, we have to find the length of the hypotenuse of triangle ABC when A = 32 cm and B = 60 cm. It's a right ANGLED triangle, because only a right angled triangle can have a hypotenuse. Now, we can use the PYTHAGORAS theorem since it's a right angled triangle. The Pythagoras theorem states that in a right angled triangle, (Hypotenuse)² = (Base)² + (Height)². Let's take A and B as the base and height. Now let's find the hypotenuse. Calculations :- Applying the Pythagoras theorem, $\implies\sf {Hypotenuse}^{2} = {A}^{2} + {B}^{2}$ $\implies \sf{Hypotenuse}^{2} = {32}^{2} + {60}^{2}$ $\implies\sf {Hypotenuse}^{2} = 1024 + 3600$ $\implies\sf{Hypotenuse}^{2} = 4624$ $\implies\sf Hypotenuse = \sqrt{4624}$ $\implies\sf Hypotenuse = 68.$ ----------------------------------------------------------- Hence, the hypotenuse = 68 cm.

46.

In triangle ABC find the length of hypotenuse if a=32 cm b=60 cm.

Answer»

Answer :-

The length of the hypotenuse is 68 cm.

Given :-

In triangle ABC,
A = 32 cm.
B = 60 cm.

To find :-

The length of the hypotenuse.

Step-by-step EXPLANATION :-

In this QUESTION, we have to find the length of the hypotenuse of triangle ABC when A = 32 cm and B = 60 cm.

It's a right ANGLED triangle, because only a right angled triangle can have a hypotenuse. Now, we can use the PYTHAGORAS theorem since it's a right angled triangle.

The Pythagoras theorem states that in a right angled triangle, (Hypotenuse)² = (Base)² + (Height)².

Let's take A and B as the base and height.

Now let's find the hypotenuse.

Calculations :-

Applying the Pythagoras theorem,

$\implies\sf {Hypotenuse}^{2} = {A}^{2} + {B}^{2}$

$\implies \sf{Hypotenuse}^{2} = {32}^{2} + {60}^{2}$

$\implies\sf {Hypotenuse}^{2} = 1024 + 3600$

$\implies\sf{Hypotenuse}^{2} = 4624$

$\implies\sf Hypotenuse = \sqrt{4624}$

$\implies\sf Hypotenuse = 68.$

-----------------------------------------------------------

Hence, the hypotenuse = 68 cm.

Discussion

47.	Vioet is the colour of Hamility and ___
Answer» ANSWER: FAITHFULNESS, Modesty Step-by-step EXPLANATION:

47.

Vioet is the colour of Hamility and ___

Answer»

ANSWER:

FAITHFULNESS, Modesty

Step-by-step EXPLANATION:

Discussion

48.	2. Find the area of the following rectangle-if length = 25m, breadth = 18mb.if length = 8.4cm, breadth = 3.2 cm3. Find the volume of the cuboid whose-a.length = 20cm, breadth = 15cm, height = 12cmfigth = 2m, breadth = 15cm, height = 12cmb.
Answer» ANSWER: LENGTH of RECTANGLE = 25m Breadth of rectangle = 18m ‎Area of rectangle = 25m×18m‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ = 450m² Length of rectangle = 8.4cm Breadth of rectangle = 3.2cm Area of rectangle = 8.4cm×3.2cm ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎=26.88cm² Length of rectangle = 20cm Breadth of rectangle = 15CM Area of rectangle = 20cm×15cm ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎=300cm² Length of rectangle = 2m Breadth of rectangle = 15cm = 15/100cm = 0.15m Area of rectangle = 2m×0.15m ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎=0.3m²

48.

2. Find the area of the following rectangle-if length = 25m, breadth = 18mb.if length = 8.4cm, breadth = 3.2 cm3. Find the volume of the cuboid whose-a.length = 20cm, breadth = 15cm, height = 12cmfigth = 2m, breadth = 15cm, height = 12cmb.

Answer»

ANSWER:

LENGTH of RECTANGLE = 25m

Breadth of rectangle = 18m

‎Area of rectangle = 25m×18m‎

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ = 450m²

Length of rectangle = 8.4cm

Breadth of rectangle = 3.2cm

Area of rectangle = 8.4cm×3.2cm

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎=26.88cm²

Length of rectangle = 20cm

Breadth of rectangle = 15CM

Area of rectangle = 20cm×15cm

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎=300cm²

Length of rectangle = 2m

Breadth of rectangle = 15cm = 15/100cm = 0.15m

Area of rectangle = 2m×0.15m

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎=0.3m²

Discussion

49.	Find it all please do it just do it
Answer» Step-by-step EXPLANATION: Q no 21 to 25 < < > > > Q no 26 to 30 False False False True False

49.

Find it all please do it just do it

Answer»

Step-by-step EXPLANATION:

Q no 21 to 25

<

>

Q no 26 to 30

False

True

False

Discussion

50.	Fraction is always lessAthan 1.*
Answer» ANSWER: It's TRUE. Step-by-step EXPLANATION: HOPE it's HELPFUL to you

50.

Fraction is always lessAthan 1.*

Answer»

ANSWER:

It's TRUE.

Step-by-step EXPLANATION:

HOPE it's HELPFUL to you

Discussion

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एक शंकु की ऊंचाई 10 गी है तथा आधार की त्रिज्य24 मी है तो शंकु चक्रपृष्ठीय क्षेत्रफल ज्ञात कीजिए

Plz someone help me in this plz

Only answer me urgent

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How many faces does a square prism has?

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Find it all please do it just do it

Fraction is always lessAthan 1.*