1.

2. Find the smallest number which when divided by 35, 50, 80 leaves remainder 9 in each case​

Answer»

Answer:

35=5×7

50=2×5×5

80=2×2×2×2×5

L.C.M.=2×2×2×2×5×5×7

=2800

smallest NUMBER =2800+9

2809



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