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2. Find the smallest number which when divided by 35, 50, 80 leaves remainder 9 in each case |
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Answer» Answer: 35=5×7 50=2×5×5 80=2×2×2×2×5 L.C.M.=2×2×2×2×5×5×7 =2800 smallest NUMBER =2800+9 2809 |
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