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X=0.407777..
100x=40.777 (1
1000x=407.77... (2

subtaract 1 from 2

1000x-100x=407.77-40.77
900x=367
x=367/900

5a/a+2 =1
5a=2+a
5a-a=2
4a=2
a=0.5

Nsjdjdkwldnfnsjcnjdkwmdjcncjdidk and I am not SURE

The greatest 6 digits which is a PERFECT SQUARE is 998001
and it's square ROOT is 999

By INCREASING SP by ₹294 increases the PROFIT from 7% to 10%

So INCREASE in profit% = 10% - 7% = 3%

profit % = profit/CP × 100
3 = 294/CP × 100
CP = 294/3 × 100
CP = ₹9800

ANSWER
____________________________

Cost of 1 Quintal = 36000 / 12
= ₹ 3000

Cost of 8 Quintals = 8 × 3000
= ₹ 24000

______________________________

Hey!!!!

let angle B be x

Then ATQ,

angle A = x + 25
=> angle C = x - 10

We KNOW angle A + angle B + angle C = 180°

=> x + x + 25 + x - 10 = 180
=> 3x = 165
=> x = 55

Thus angle B = 55°
angle A = 55 + 25
=> angle A = 80°
=> angle C = 55 - 10
=> angle C = 45°

Hope this helps

Hey....here is UR answer

A:B=3:5---------1
B:C=4:7-------2
multiplying by 4 in EQUATION 1 and by 5 in equation 2
A:B=12:20
B:C=20:35
on combining
A:B:C=12:20:35

I HOPE it will HELP you ☺

Let the CONSTANT of RATIO be X
then No of BOYS = 7x
No of girls = 5x
also
7x=5x+8
or 2x=8
X= 4
no. of boys =7x= 28
no. of girls =5x=20

In algebra, LIKE TERMS are terms that have the same VARIABLES and powers. The coefficients do not need to match.Unlike terms are two or more terms that are not like terms, i.e. they do not have the same variables or powers. The ORDER of the variables does not matter unless there is a power.

Given Equation is 3^9 + 3^12 + 3^15 + 3^n.

It can be written as,



It is in the FORM of a^3 + 3a^2b + b^3 + 3ab^2.

Here,

a = 3^3

b = 3^5

3^n = 3ab^2

3^n = 3 * 3^3 * (3^5)^2

3^n = 3^14

n = 14.


Therefore the NATURAL NUMBER = 14.


Note: I Took HELP from SOMEONE. Sorry about that.


Hope this helps!

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It is HELPFUL for you THANKS for you QUESTION

Here is your ANSWER



HOPE this will HELP you out

##AAYUSH JAIN

Y^7 - 64y

=> y ( y^6 - 64)

=> y [ (y^3)^2 - (8)^2]

=> y [ ( y^3 + 8) (y^3 - 8)]

=> y [ { (y)^3 + (2)^3 } { ( y)^3 - (2)^3}]

=> y [ {( y +2) (y^2 + 4 - 2Y)} {(y - 2)(y^2 + 4 + 2y)}]

=> ( y) (y +2) (y - 2)(y^2 - 2y+ 4)(y^2 +2y +4)

Let the rhombus have vertices A, B, C, D. Let the midpoints of the sides AB, BC, CD, DA be E, F, G, H.

If the diagonals of EFGH are equal and bisect each other then EFGH is a rectangle.

AB || HF || DC and AD || EG || BC.
So HF = AB = BC = EG.
ie diagonals HF and EG are equal in length.

HF bisects AD and BC. EG is parallel to AD and BC. Therefore HF bisects EG ALSO.
By a similar argument, EG bisects HF.

So diagonals HE and EG (i) are equal in length, and (II) bisect each other.
Therefore EFGH is a rectangle

Hello MATE =_=

____________________________

Question:-

A field is in the shape of a trapezium whose parallel SIDES are 25 m and 10 m. The non-parallel sides are 14 m and 13 m. Find the area of the field.

____________________________

 Solution:

Given: ABCD is a trapezium. Non-parallel sides are 14 m and 13 m. Parallel sides are 25 m and 10 m.

Construction: From point C draw CE∥DA completing parallelogram AECD. Also, draw CF⊥BE.

Now, we have AE=CD=10 m andAD=CE=14 m because AECD is a parallelogram.

So, BE=AB-AE=25-10=15 m

Semi-perimeter of  ∆BEC

= s

=(BE+CE+BC)/2

=(15+14+13)/2=42/2=21 m

Using Heron's FORMULA, 

Area of ∆BEC=

√{s(s−BE)(s−CE)(s−BC)}

=√{21(21−15)(21−14)(21−13)}

=√{21×6×7×8}

=84 m2         ........(1)

Area of ∆BEC=1/2× BE ×CF=84 m2

⇒CF=2×84/15=11.2 m

Area of parallelogram AECD 

=AE×CF=10×11.2=112 m2      ...... (2)

Adding (1) and (2), we get

Area of trapezium ABCD=Area of ∆BEC+Area of parallelogram AECD =84+112=196 m2

hope, this will help you.

Thank you______❤

_____________________________❤

The number of trailing ZEROES is given by the number of powers of 10 in 100!. Each power of 10 is a combination of a power of 5 and a power of 2. Since number of powers of 5 will be more than the powers of 2, we only need to calculate the number of powers of 5 in 100!.

This can be done by GREATEST integer function.
In this solution, I will be using the BRACKET symbol for greatest integer function!!
Thus the powers of 5 in 100! are

Thus there will be 24 trailing zeroes in the end of 100!.

If this helps, MARK it as the brainliest answer. I would really appreciate it.

1. DISTANCE covered in 60 SECOND
= 5metre
distance covered in 1 SEC.......5 /60
distance covered in 3600 second.....
=1/12×3600
= 300metre

Let the GREATER no. be x .
now , x - 20 = 20/100* x
100x - 2000 = 20 x
80 x = 2000
x = 25

Federation INTERNATIONALE de football association is the full form of FIFA....
HOPE this helps you MARK Me as BRAINLIEST plz plz plz........

The ANSWER is OPTIONC BHAVESH are you here and COME to CHAT

We will get a line when we connect two points through the shortest distance. So we can draw 10 lines from 5 points. If the points are colinear, no matter how many number of points there are, you can only CONSTRUCT one line from those colinear points. And it's given that 3 points are colinear.


I know there r some mistakes
but PLZ don't MIND
and ACCEPT my ANS...

GIVEN :

y–12=–5, Solve the given equation WITHOUT transposing, and check your result.

To find :

The value of Y

Solution :

y–12=–5

Solving the value of "y" by trail and error method :-

Keep the numerals in place of "y" and check whether they are equal or not :-

y–12=–5

1 - 12 = -5 (Not Equal)

2 - 12 = -5 (Not Equal)

3 - 12 = -5 (Not Equal)

4 - 12 = -5 (Not Equal)

5 - 12 = -5 (Not Equal)

6 - 12 = -5 (Not Equal)

7 - 12 = -5 (Equal)

Hence, 7 - 12 = -5. So, the value of "Y" is 7.

The ANSWER is -24 of this QUESTION

Integers are NUMBERS that can be expressed in the FORM of p/q where q is not EQUAL to 0

Red+Yellow=Orange.....

There are INFINITE RATIONAL NUMBERS

some are 1,1.1,1.2,1.3,1.4,1.5,1.6,1.7,1.8,1.9.1.91,1.92,1.93,1.94

Here's your ANS to your QUESTION

Hi there!
_______________________________
✓ we first make denominators Same by making them 15 in both numbers.


✓ 3 x 3 / 5 x 3 = 9 / 15


✓ 2 x 5 / 3 x 5 = 10 / 15


✓ Let us further multiply them by 10 to get greater difference among both new numbers.


= This GIVES 90 / 150 and 100 / 150


✓ Hence we can write any five numbers Between these two.

✓ Ans. 91 / 150 , 92 / 150 , 93 / 150 , 94 / 150 and 97 / 150 .


__________________________________
I hope this helps you.

The answer is given below :

The pair of negative integers are

{(-1, -9), (-2, -10), (-3, -11), (-4, -12), (-5, -13), ...}

- 1 - (-9) = 8

- 2 - (-10) = 8

... ... ...

THANK you for your question.