1.

Prove that equal chords of a circle subtend equal angles at the centre

Answer» GIVEN that :--:

IN CIRCLE C( O, r)

AB = PQ


To prove :--:



Proof :--:

In Triangle AOB and POQ

AB = PQ ( Given)

AO = PO ( RADII of circle)

BO = QO ( Radii of circle)

So,

Triangle AOB is congurent to triangle POQ

=>



HENCE Proved :::---:---:::


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