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##No Useless answer plz.##**Ans with steps**

Answer»

Given Equation is 3^9 + 3^12 + 3^15 + 3^n.

It can be written as,

(3)^3 + 3 * (3^3)^2 * 3^5 + (3^5)^3 + 3^n

It is in the FORM of a^3 + 3a^2b + b^3 + 3ab^2.

Here,

a = 3^3

b = 3^5

3^n = 3ab^2

3^n = 3 * 3^3 * (3^5)^2

3^n = 3^14

n = 14.


Therefore the NATURAL NUMBER = 14.


Note: I Took HELP from SOMEONE. Sorry about that.


Hope this helps!


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