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COST of 1 quintile is 36000/12= 3000

Cost of 1 quintile is 3000

Now cost of 8 quintile is 3000 * 8 = 24000

Answer:

25%.

Step-by-step explanation:

• LOSS % = ( 20 - 15 ) /20 x 100 %

                    = 5 x 5 % = 25 %.

THANK u.

(...,-3,-2,-1,0,1,2,3,...)all negative NUMBERS can ALSO in odd and even numbers

I hope my ANSWER help

please mark me BRAINLEAST

68m
65m

42592= 2*2*2*2*2*11*11*11

by forming triplets, it is clear that 42592 should be divided by 2*2 to get APERFECT cube

the PERFECT cube= 42592/4 = 10648

and cube root 10648 = 22

plz give me BRAINLIEST

-----------------------HEY DEAR---------------------------

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HERE IS YOUR ANSWER......

A triangular prism is a three-sided prism; it is a polyhedron made of a triangular base, a translated copy, and 3 faces joining corresponding sides. A right triangular prism has rectangular sides, otherwise it is oblique. A uniform triangular prism is a right triangular prism with equilateral bases, and square sides.

=> FACES OS PRISM ARE :

 2 TRIANGLES, 3 RECTANGLES...

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HOPE IT HELPS YOU...

MARK ME BRAINLIEST PLEASE..

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-a(-a2 + B2 + C2 -2BC) = -a { -a2 + (b-c)^2} = a3 - a(b-c)^2 = a3 - a(b-c)(b-c) = a{a2 -(b-c)(b-c)}. = a { a2+ (c-b)(c-b)} = a3 + a(c-b)^2

ANS is VOLUME will become 8 TIME that of INITIAL volume.

prove: let the EDGE of cube be l .then initial volume is V=l3 .

now the edge is doubled then new edge becomes 2l.

thus volume V(new)=(2l)3=23×l3=8l3=8(V(initial)).

The total AMOUNT of ONION solded = 17/5 + 51/10
= (17*2 +51)/10
=55/10=5.5
so onion left = 15 -5.5= 9.5

The confidence of an association rule is a percentage value that shows how frequently the rule head OCCURS among all the groups containing the rule body. ... As in the CASE of the support FACTOR, you can specify that only rules that achieve a certain minimum LEVEL of confidence are included in your mining model.

See the 1st and 3RD number of the FOLLOWING question.
4+5=9 fourth number
3+9=12

5+12= 17 SIXTH number.

Therefore, 17+ 9= 26
###

OPTION d is correct answer.

Hello ☺


a21 = a + 20 d

A7 = a +6d

ACCORDING to the question = a21 - a7 = 84

=> a + 20d - ( a + 6d ) = 84

=> a + 20d - a - 6d = 84

=> 14D = 84

Given word is 'GLOOMY'.

There are 6 letters in GLOOMY with 4 distinct letters and 2 O's.

These letters can be ARRANGED in (6!/2!) = 360.

(i)

Given that two O's should not be together.

Let us consider 2 O's as ONE LETTER and thus there will be 5 distinct letters. These 5 distinct letters can be arranged in 5! ways. = 5! = 5*4*3*2*1 = 120.

Therefore, Required number of ways = 360 - 120

⇒ 240.

Hope it helps!

This is DIVISION METHOD. ANOTHER ONE is FACTORISATION method

One revolution is when an object rotates 360 and COMES back to its original position.

So, one revolution = 360/2pi

when you solve the OPERATION you GET the RADIUS of the wheel which is important.

The LCM of 55 65 45 is ANSWER

I HOPE it will be HELPFUL to you

ANGLE COE =105*

Angle AOC=35*

15:20:24:36 SINCE 3x5:4x5:6x4:9x4

The AMOUNT is 768₹....

The VOLUME of the cylinder is 539cm^2
Refer to the attached IMAGE for SOLUTION and please do mark as BRAINLIEST if you find it USEFUL....

Put X = 0

we get 0/0 form....
so apply L HOSPITALS rule we get

LIMIT SINX /x = limit COS X
x--> 0. x-->0
= cos 0 = 1

Answer:

19.47º

Step-by-step EXPLANATION:

Define x:

Let the breadth be x

The diagonal of a rectangle is THREE TIMES the length of the shorter SIDE:

The diagonal = 3x

Find the angle between the diagonal and the LONGER side.

sin θ = opp/hyp

sin θ = x/3x

sin θ = 1/3

θ = sin⁻¹ (1/3)

θ = 19.47º

Answer: The angle between the diagonal and the longer side is 19.47º

Theorem 10.6 Equal chords of a CIRCLE (or of congruent circles) are equidistant from the centre (or CENTRES). Given : A circle with center at O. AB and CD are two equal chords of circle i.e. AB = CD & OX and OY are PERPENDICULARS to AB & CD respectively.

Types of Vectors

Zero Vector

We know that all vectors have initial and terminal POINTS. A Zero vector or a null vector is one in which these two points coincide. It is denoted as 0⃗ . Since the magnitude is zero, we cannot ASSIGN a direction to these vectors. Alternatively, zero vectors can have any direction. Some examples of zero vectors are AA→, BB→, etc.

Unit Vector

A Unit vector is a vector having a magnitude of unity or 1 unit. A unit vector in the direction of a given vector a⃗  is denoted as a^.

Coinitial Vectors

Coinitial vectors are two or more vectors which have the same initial point. For example, AB→ and AC→ are coinitial vectors since they have the same initial point ‘A’.

Collinear Vectors

Collinear vectors are two or more vectors which are parallel to the same line irrespective of their MAGNITUDES and direction.

Equal Vectors

If two vectors a⃗  and b⃗  have the same magnitude and direction regardless of the positions of their initial points, then they are Equal vectors. These vectors are written as a⃗ = b⃗ .

Negative of a Vector

Let’s SAY that there is a vector AB→ having a CERTAIN magnitude and direction. Now, if there is a vector whose magnitude is same as that of vector AB→ but the direction is opposite, then it is called negative of the given vector AB→. For example, vector BA→is the negative of vector AB→. It is written as BA→ = – AB→.

PERIMETER =10x+4y units

Area =6x²-3y²+7xy sq.units

The EMPEROR penguin is the largest of 17 SPECIES of penguin at 1.15 m (45 in.) TALL. It is also the only animal to inhabit the open ice of ANTARCTICA during the winter. ... Despite such harsh conditions, emperor penguins SPEND their entire lives on the ice or in the surrounding waters of Antarctica

1+sin2A+cos2A1+sin2A-cos2A
=sin2A+cos2A+sin2A+cos2Asin2A+cos2A+sin2A-cos2A [SINCE, sin2A+cos2A=1]

=sin2A+cos2A+2sinAcosA+cos2Asin2A+cos2A+2sinAcosA-cos2A [Since, sin2A=2sinAcosA]

=sin2A+cos2A+2sinAcosA+cos2A-sin2Asin2A+cos2A+2sinAcosA-cos2A-sin2A [Since, cos2A=cos2A-sin2A]

=sin2A+cos2A+2sinAcosA+cos2A-sin2Asin2A+cos2A+2sinAcosA-cos2A+sin2A=2cos2A+2sinAcosA2sin2A+2sinAcosA=cosAsinAcosA+sinAsinA+cosA=cosAsinA=cotA

Clearly
angle PSQ =RQS

so angle psQ =45

now angle psq + y = 90
45. + y = 90
y. = 45

LET the point be M where 60 is formed

and O be the point where X is formed

now in triangle MOQ

60 + 45 + angle MOQ = 180

anlge moq. = 180- 105
angle moq. = 45

now angle moq + X = 180. (linear PAIR angles)

45. + X =180

X. =180- 45

X. = 135
hope it. helps.

3872= (2*2) *(2*2) *(11*11) *2

.

. . The no. MUST be multiplied by 2 so that 3872 is a PERFECT SQUARE

Hey MATE here is UR ans

AB is parallel to CD. ....given
also
P & Q are mid points to AC & RC

so. AP =PC. & RQ = QC
now In triangle ARC.

AP /PC = RQ / QC. (bcoz AP = PC & RQ = QC)

by inverse of basic proportionalty therom
PQ ll AB

but AB ll CD. so

P Q ll CD

HENCE PQ ll AB ll CD

Imagine, total car number is x

HENCE, 30% RED car mean x ×30/100=3x/10

>3x/10=12

Or, x=12×10/3 =40

:•the total car number is 40.

Let the breadth be b

LENGTH is 2B - 16

Perimeter of the rectangle = 2( l + b) = 100 CM

=> 2 ( 2b - 16 + b) = 100
=> 3b - 16 = 100/2
=> 3b - 16 = 50
=> 3b = 66
=> b = 22 cm

length = 2 x 22 - 16 = 44 - 16 = 28 cm

Hence, length = 28 cm and breadth = 22 cm

Hi Mate!!!

Let the co-ordinates of center of circle be ( H , K )

General EQUATION of circle is

( x - h ) ² + ( y - k ) ² = R²

( 6 - h ) ² + ( -6 - k )² = R² ..... equation 1

( 3 -h )² + ( -7 - k )² = R² ......... equation 2

( 3 -h )² + ( 3 -k )² = R² ........ equation 3

Now solve these equations to find out (h,k)


Have a nice day...

⚡Hey mate⚡

✨Here is your ANSWER✨


NUMBER of boys in the choir is = 21

Percent of the boys in choir = 60 %

It means that number of the boyes is equal to the PERCENTAGE of the boys

Then

60 % = 21

1 % = 21 ÷ 60

1 % = 0.35

Total mambers are


100 % = 0.35 × 100

100 % = 35

Your answer is 35.

I hope it's HELPFUL for you. Thank you ❤️❤️

Do you WANT QUESTIONS

X equalls to 4 or y equalls to 2

The SUM INVESTED in SCHEME B was ₹462

He have PROFIT of 20$

He have LOSE of 4 RUPEES I THINK

A part of rs.12000 is lent to RAM at 7% per ANNUM and the rest was lent to SHYAM at 3% per annum. If the total SIMPLE interest received from both parts in 5 years was rs. 2000. rs. 1,000 amount was lent to ram.

It is TRIANGULAR PRISM..