Hey MATE here is UR ansAB is parallel to CD. ....given also P & Q are mid points to AC & RC so. AP =PC. & RQ = QC now In triangle ARC. AP /PC = RQ / QC. (bcoz AP = PC & RQ = QC) by inverse of basic proportionalty theromPQ ll AB but AB ll CD. so P Q ll CD HENCE PQ ll AB ll CD
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