332354 + Interview Questions in Secondary School in Math

1.	Explain by 726 into 5 into 4 into 5 is a composite number
Answer» ONG>Answer: 14,520 is answer Step-by-step EXPLANATION:

1.

Explain by 726 into 5 into 4 into 5 is a composite number

Answer» ONG>Answer:

14,520 is answer

Step-by-step EXPLANATION:

Discussion

2.	What can we say in genaral about those decimals forms in wich a single digits repeat?
Answer» ONG>Answer: At PRESENT, there is no single universally accepted notation or phrasing for repeating DECIMALS. The infinitely repeated digit sequence is CALLED the repetend or reptend.

2.

What can we say in genaral about those decimals forms in wich a single digits repeat?

Answer» ONG>Answer:

At PRESENT, there is no single universally accepted notation or phrasing for repeating DECIMALS. The infinitely repeated digit sequence is CALLED the repetend or reptend.

Discussion

3.	Solve for X : (24)^2 - (7+x)^2 = 13^2 - x^2
Answer» ONG>Answer: 25.57 Step-by-step EXPLANATION: Q. (24)^2 - (7+x)^2 = 13^2 - x^2 Soln. :- (24)^2 - (7+x)^2 = 13^2 - x^2 or, 576- {(7)^2 + x^2 + 2 X 7 X x} = 169 - x^2 or, 576 - { 49 + x^2 + 14x} = 169 - x^2 or, 576 - 49 - x^2 - 14x = 169 - x^2 or, 527 - x^2 - 14x = 169 - x^2 or, - x^2 - 14x + x^2 = 169 - 527 or, - 14x = - 358 or, x = - 358 ÷ -14 or, x = 25.57

3.

Solve for X : (24)^2 - (7+x)^2 = 13^2 - x^2

Answer» ONG>Answer:

25.57

Step-by-step EXPLANATION:

Q. (24)^2 - (7+x)^2 = 13^2 - x^2

Soln. :- (24)^2 - (7+x)^2 = 13^2 - x^2

or, 576- {(7)^2 + x^2 + 2 X 7 X x} = 169 - x^2

or, 576 - { 49 + x^2 + 14x} = 169 - x^2

or, 576 - 49 - x^2 - 14x = 169 - x^2

or, 527 - x^2 - 14x = 169 - x^2

or, - x^2 - 14x + x^2 = 169 - 527

or, - 14x = - 358

or, x = - 358 ÷ -14

or, x = 25.57

Discussion

4.	Q.11 Write all the integers between-8 and 15 .
Answer» ONG>Answer: -7,-6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6,7,8,9,10,11,2,13,14 Step-by-step explanation: please MARK me as BRAINLIEST and follow me

4.

Q.11 Write all the integers between-8 and 15 .

Answer» ONG>Answer:

-7,-6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6,7,8,9,10,11,2,13,14

Step-by-step explanation:

please MARK me as BRAINLIEST and follow me

Discussion

5.	If the perimeter of a circle is equal to that of the then. the ratio of their areas is (a) 22:7 (6) 14:11 (7:22 (d) 11:14
Answer» ONG>ANSWER: (a) 22:7 is the CORRECT answer

Discussion

6.	The pair of linear equation x-2y=5 and 2x-4y=1 have
Answer» ong>Step-by-step EXPLANATION: What WOULD you like to ask? MATHS avatar Asked on DECEMBER 20, 2019 by Rashitha Mangwani The pair of equations x+2y+5=0 and −3x−6y+1=0 have Share Study later ANSWER The given equations are: x+2y+5=0 −3x−6y+1=0 From the given equation we have: a 2 a 1 = −3 1 b 2 b 1 = −6 2 = −3 1 C 2 c 1 = 1 5 ⇒ a 2 a 1 = b 2 b 1  = c 2 c 1 Hence pair of equations have no solution.

6.

The pair of linear equation x-2y=5 and 2x-4y=1 have

Answer»

ong>Step-by-step EXPLANATION:

What WOULD you like to ask?

MATHS

avatar

Asked on DECEMBER 20, 2019 by

Rashitha Mangwani

The pair of equations x+2y+5=0 and −3x−6y+1=0 have

Share

Study later

ANSWER

The given equations are:

x+2y+5=0

−3x−6y+1=0

From the given equation we have:

a

2

a

1

=

−3

1

b

2

b

1

=

−6

2

=

−3

1

C

2

c

1

=

1

5

⇒

a

2

a

1

=

b

2

b

1



=

c

2

c

1

Hence pair of equations have no solution.

Discussion

7.	Mr. X bought 400 shares of Tk. 25 each at Tk. 32.5. If the dividend declared is 4%, what is his income on the shares?
Answer» ong>ANSWER: Step-by-step explanation: His INCOME will be COUNTED on face VALUE which is 25Tk.He bought the shares at 32.5 Tk but it keeps fluctuating in the the MARKET in accordance with the changes in the interest rates. So his total income : 400254%=40025(1/25)=400 Tk

7.

Mr. X bought 400 shares of Tk. 25 each at Tk. 32.5. If the dividend declared is 4%, what is his income on the shares?

Answer»

ong>ANSWER:

Step-by-step explanation:

His INCOME will be COUNTED on face VALUE which is 25Tk.He bought the shares at 32.5 Tk but it keeps fluctuating in the the MARKET in accordance with the changes in the interest rates.

So his total income : 400*25*4%=400*25*(1/25)=400 Tk

Discussion

8.	Cos35°sin12°COS18°:) Find the value of :+sin55°cos78°sin 72°
Answer» MATE... YPU ANSWER IS 1 LOOK AT TYE ATTACHMENT FOR STEPS☺

8.

Cos35°sin12°COS18°:) Find the value of :+sin55°cos78°sin 72°

Answer» MATE...

YPU ANSWER IS 1

LOOK AT TYE ATTACHMENT FOR STEPS☺

Discussion

9.	Factorize (x2 - 6x)2 - 8(x3 - 6x + 8) - 64
Answer» ong>Answer: 2)(x−4). EXPLANATION: CONSIDER the FACTORS of + 8 which sum to GIVE the coefficient of the x-term, that is - 6. the factors of ...

9.

Factorize (x2 - 6x)2 - 8(x3 - 6x + 8) - 64

Answer»

ong>Answer:

2)(x−4). EXPLANATION: CONSIDER the FACTORS of + 8 which sum to GIVE the coefficient of the x-term, that is - 6. the factors of ...

Discussion

10.	What is the value Dₓ for equation 3x + 2y = 5/2 and 1/3x + 3y = 4/3.
Answer» ONG>Answer: 5050=100+100=200+200=400

Discussion

11.	સમાનાર્થી શબ્દો (1) રીસ (2) કિનારો (3) પ્રયત્ન
Answer» ong>Step-by-step EXPLANATION: (1) રીસ (2) કિનારો (3) પ્રયત્ન

11.

સમાનાર્થી શબ્દો (1) રીસ (2) કિનારો (3) પ્રયત્ન

Answer»

ong>Step-by-step EXPLANATION:

(1) રીસ (2) કિનારો (3) પ્રયત્ન

Discussion

12.	The volume of a cylinder is _____ times of the volume of cone having the same base and the same height. 2( ) 3( ) 4( )و
Answer» ong>Answer: 3 Step-by-step explanation: because volume of cylinder (v1) = πr^2h volume of CONE (V2) = (πr^2h)/3 we can clearly SEE that v1 = 3(v2) PLEASE mark me as brainliest.

12.

The volume of a cylinder is _____ times of the volume of cone having the same base and the same height. 2( ) 3( ) 4( )و

Answer»

ong>Answer:

3

Step-by-step explanation:

because

volume of cylinder (v1) = πr^2h

volume of CONE (V2) = (πr^2h)/3

we can clearly SEE that

v1 = 3(v2)

PLEASE mark me as brainliest.

Discussion

13.	Sintheta × cosectheta =
Answer» ong>Answer: 1 Step-by-step EXPLANATION: we KNOW that cosec(Φ) = 1/SIN(Φ) then sin(Φ)*1/sin(Φ) = 1 Please MARK me as brainliest if it is CORRECT.

13.

Sintheta × cosectheta =

Answer»

ong>Answer:

1

Step-by-step EXPLANATION:

we KNOW that

cosec(Φ) = 1/SIN(Φ)

then sin(Φ)*1/sin(Φ) = 1

Please MARK me as brainliest if it is CORRECT.

Discussion

14.	If n(A) = 6 and n(S) =36 then P(A)= ? *1) 62) 1/63) 304) 3
Answer» ONG>Answer: 30 Step-by-step explanation: 61=6 66=36 6*3=18

14.

If n(A) = 6 and n(S) =36 then P(A)= ? *1) 62) 1/63) 304) 3

Answer» ONG>Answer:

30

Step-by-step explanation:

6*1=6

6*6=36

6*3=18

Discussion

15.	). The ratio of the corresponding sides of similare triangles is 4: 7 then find the ratio of theirareas
Answer» ong>ANSWER: hope it helps you please mark me as brainlist and please FOLLOW me and votes on my all answers

15.

). The ratio of the corresponding sides of similare triangles is 4: 7 then find the ratio of theirareas

Answer»

ong>ANSWER:

hope it helps you

please mark me as brainlist and please FOLLOW me and votes on my all answers

Discussion

16.	The volume of the cube is 64cm. THE edge of the cube is?
Answer» s UR ANSWER MATE... HOPE it HELPS ❤️

16.

The volume of the cube is 64cm. THE edge of the cube is?

Answer»

s UR ANSWER MATE...

HOPE it HELPS ❤️

Discussion

17.	6 men can complete a job in 15 days. How many men should work, if the job is to be completed in 10 days?
Answer» ong>Answer: 15 days is taken to COMPLETE the work by=6 MEN 1 day will be take to complete the work by=6/15 men then, the no of men complete it in 10 days =6/15*10 =4men answer plz MARK the answer BRAINLIST

17.

6 men can complete a job in 15 days. How many men should work, if the job is to be completed in 10 days?

Answer»

ong>Answer:

15 days is taken to COMPLETE the work by=6 MEN

1 day will be take to complete the work by=6/15 men

then,

the no of men complete it in 10 days =6/15*10

=4men answer

plz MARK the answer BRAINLIST

Discussion

18.	Find the zeroes and verify the relationship between the zeroes and it's coeffecients x^2 - 2x -8 = 0
Answer» 2X -8 = 0 x²-4x+2x-8=0 x(x-4)+2(x-4)=0 x+2=0 or x-4=0 x=-2 or x=4 sum of ZEROES = -2+4 = 2 = -b/a PRODUCT of zeroes = -8 = c/a hence verified

18.

Find the zeroes and verify the relationship between the zeroes and it's coeffecients x^2 - 2x -8 = 0

Answer» 2X -8 = 0

x²-4x+2x-8=0

x(x-4)+2(x-4)=0

x+2=0 or x-4=0

x=-2 or x=4

sum of ZEROES = -2+4 = 2 = -b/a

PRODUCT of zeroes = -8 = c/a

hence verified

Discussion

19.	By method oftransposition, x become ________ on changing the side
Answer» ONG>ANSWER: x will become -x on other SIDE

Discussion

20.	Pocefind the value of a - b² if (atb) = 10, ab= 10
Answer» ong>ANSWER: SORRY L don't KNOW the answer

20.

Pocefind the value of a - b² if (atb) = 10, ab= 10

Answer»

ong>ANSWER:

SORRY L don't KNOW the answer

Discussion

21.	One angle of a triangle is 120° and it's opposite side 3cm . Find the diameter of its circumcircle. No need of irrelevant answers...
Answer» ong>Step-by-step explanation: LET ABCD be the given PARALLELOGRAM. DC = 6 cm and ∠ADC = 60° Area of parallelogram ABCD = 30 cm2 Construction: Draw AE perpendicular to DC. Area of a parallelogram = Base × Height ⇒ 30 cm2 = 6 cm × AE ⇒ AE = Using angle sum property in ΔAED: ∠ADE + ∠DEA + ∠EAD = 180° ⇒ 60° + 90° + ∠EAD = 180° ⇒ 150° + ∠EAD = 180° ⇒ ∠EAD = 180° − 150° = 30° Thus, the angles of ΔAED are 30°, 60° and 90°. Therefore, the ratio of the lengths of the sides of ΔAED is 1::2. Thus, the LENGTH of other side of the parallelogram is cm. Note: We can also draw the figure by taking ∠ADE = 60° and AD = 6 cm.

21.

One angle of a triangle is 120° and it's opposite side 3cm . Find the diameter of its circumcircle. No need of irrelevant answers...

Answer»

ong>Step-by-step explanation:

LET ABCD be the given PARALLELOGRAM.

DC = 6 cm and ∠ADC = 60°

Area of parallelogram ABCD = 30 cm2

Construction: Draw AE perpendicular to DC.

Area of a parallelogram = Base × Height

⇒ 30 cm2 = 6 cm × AE

⇒ AE =

Using angle sum property in ΔAED:

∠ADE + ∠DEA + ∠EAD = 180°

⇒ 60° + 90° + ∠EAD = 180°

⇒ 150° + ∠EAD = 180°

⇒ ∠EAD = 180° − 150° = 30°

Thus, the angles of ΔAED are 30°, 60° and 90°.

Therefore, the ratio of the lengths of the sides of ΔAED is 1::2.

Thus, the LENGTH of other side of the parallelogram is cm.

Note: We can also draw the figure by taking ∠ADE = 60° and AD = 6 cm.

Discussion

22.	A circle touches all sides of a rectangle. So the rectangle must be a_________. RhombusParallelogram orSquare orTrapezium
Answer» llelogram is the WRIGHT answer. Hope it HELPS you!. PLEASE MARK me as BRAINLIEST .

22.

A circle touches all sides of a rectangle. So the rectangle must be a_________. RhombusParallelogram orSquare orTrapezium

Answer»

llelogram is the WRIGHT answer.

Hope it HELPS you!. PLEASE MARK me as BRAINLIEST .

Discussion

23.	A ( 15 , 5 ) ; B ( 9 , 20 ) and A - P - B , the ratio in which point P ( 11 , 15 ) divides segment AB is ? 1 point
Answer» ong>ANSWER: which CLASS do you read Step-by-step explanation: please BRAINLIAST marks

23.

A ( 15 , 5 ) ; B ( 9 , 20 ) and A - P - B , the ratio in which point P ( 11 , 15 ) divides segment AB is ? 1 point

Answer»

ong>ANSWER:

which CLASS do you read

Step-by-step explanation:

please BRAINLIAST marks

Discussion

24.	4. Find the distance of the points.L (5, -8) M (-7, -3)REO 1314O 15O 12
Answer» ONG>ANSWER: 12 is answer i THINK so Step-by-step EXPLANATION:

24.

4. Find the distance of the points.L (5, -8) M (-7, -3)REO 1314O 15O 12

Answer» ONG>ANSWER:

12 is answer i THINK so

Step-by-step EXPLANATION:

Discussion

25.	The product of two rational number is -8.if one of the number is-12, find the other.
Answer» ONG>Answer: let the other be "x" -12 - x = -8 -12 +8 = x x = 8 Step-by-step explanation: MARK as BRAINLIEST

25.

The product of two rational number is -8.if one of the number is-12, find the other.

Answer» ONG>Answer:

let the other be "x"

-12 - x = -8

-12 +8 = x

x = 8

Step-by-step explanation:

MARK as BRAINLIEST

Discussion

26.	Q. If the radius of the cylinder is 4 cm and height is 14 cm, then the volume of the cylinder is: (a) 352cm³(b) 350cm³(c) 704cm³(d) 200cm³
Answer»

Discussion

27.	the length , breadth and height of room are 6m,4m and 5m respectively. itholds 250 boxes . if all the dimensions of the room are doubled ,find the no of boxes it will hold
Answer» ONG>TOTAL volume of room = lbh = 6×4×5 = 120m³ Volume of 120m³ holds 250 boxes So, volume of 1m³ holds 250/120 = 25/12 boxes. Now, room dimensions are DOUBLED. Total volume of room = (6×2)×(4×2)×(5×2) = 960m³ We know that, 1m³ hold 25/12 boxes. Then, 960m³ holds (960×25)/12 = 2000 boxes.

27.

the length , breadth and height of room are 6m,4m and 5m respectively. itholds 250 boxes . if all the dimensions of the room are doubled ,find the no of boxes it will hold

Answer» ONG>TOTAL volume of room = lbh = 6×4×5 = 120m³

Volume of 120m³ holds 250 boxes

So, volume of 1m³ holds 250/120 = 25/12 boxes.

Now, room dimensions are DOUBLED.

Total volume of room = (6×2)×(4×2)×(5×2) = 960m³

We know that, 1m³ hold 25/12 boxes.

Then, 960m³ holds (960×25)/12 = 2000 boxes.

Discussion

28.	Plage 120the ciuclePoints P, G. and R amewithcentell o it LOPR 280° find mcauc & PRO
Answer» ONG>Answer: LESSON NAME FIRST name

Discussion

29.	What is the lenth of diagonal of a square with 8 cm
Answer» ONG>Answer: 5.66 Step-by-step EXPLANATION: Explanation

29.

What is the lenth of diagonal of a square with 8 cm

Answer» ONG>Answer:

5.66

Step-by-step EXPLANATION:

Explanation

Discussion

30.	Write coefficient of mn2 in 4m -2/3 MN2+5
Answer» ONG>ANSWER: -2/3 is the coefficient of MN2 Step-by-step explanation: IF U LIKE MY ANSWERS PLZ THANK THEM

30.

Write coefficient of mn2 in 4m -2/3 MN2+5

Answer» ONG>ANSWER:

-2/3 is the coefficient of MN2

Step-by-step explanation:

IF U LIKE MY ANSWERS PLZ THANK THEM

Discussion

31.	Tan θ + 1/tan θ= 2 , find the value of tan^2θ + 1/tan^2θ
Answer» by STEP EXPLANATION

31.

Tan θ + 1/tan θ= 2 , find the value of tan^2θ + 1/tan^2θ

Answer»

by STEP EXPLANATION

Discussion

32.	Write any linear pair of equations which is parallel to the linear equations 2x+3y-8=0
Answer» ong>Answer: Given LINE is 2x+3y−8=0 (a)example of intersecting line ; x+y−5=0 forms a intersecting line (B) example for PARALLEL line Parallel line ⇒slopes must be equal ⇒6x+9y+10=0 is parallel to the given line (c) example of COINCIDENT lines Coincident ⇒ratio of COEFFICIENT must be equal ⇒4x+6y−16=0 coincides with the given line

32.

Write any linear pair of equations which is parallel to the linear equations 2x+3y-8=0

Answer»

ong>Answer:

Given LINE is 2x+3y−8=0

(a)example of intersecting line ;

x+y−5=0 forms a intersecting line

(B) example for PARALLEL line

Parallel line ⇒slopes must be equal

⇒6x+9y+10=0 is parallel to the given line

(c) example of COINCIDENT lines

Coincident ⇒ratio of COEFFICIENT must be equal

⇒4x+6y−16=0 coincides with the given line

Discussion

33.	4x+3y-4=06x=8-5ysolve by Cramer's rule.
Answer» ong>ANSWER: Given, 4x + 3y - 4 = 0 -------(1) 6x = 8 - 5y 6x + 5y - 8 = 0 -------(2) use Cramer's RULE , 4x + 3y - 4 = 0 6x + 5y - 8 = 0 for EQUATIONS , => x/(-24 + 20) = -y/(-32+ 24) = 1/(20 - 18) => x/-4 = -y/-8= 1/2 => x/-4 = y/8 = 1/2 => x = -4/2 = -2 and y = 8/2 = 4 HENCE, x = -2 and y = 4

33.

4x+3y-4=06x=8-5ysolve by Cramer's rule.

Answer»

ong>ANSWER:

Given, 4x + 3y - 4 = 0 -------(1)

6x = 8 - 5y

6x + 5y - 8 = 0 -------(2)

use Cramer's RULE ,

4x + 3y - 4 = 0

6x + 5y - 8 = 0

for EQUATIONS ,

=> x/(-24 + 20) = -y/(-32+ 24) = 1/(20 - 18)

=> x/-4 = -y/-8= 1/2

=> x/-4 = y/8 = 1/2

=> x = -4/2 = -2 and y = 8/2 = 4

HENCE, x = -2 and y = 4

Discussion

34.	Find the diagonal of a rectangle whose length is 16cm and areas is 192sq.cm
Answer» U>Given :- Length of the rectangle = 16 cm Area of the rectangle = 192² cm ➤ To Find :- Diagonal of the rectangle ➤ Solution :- We know that, Area of rectangle = Length × Breadth $\sf 192 = 16 × b$ $\sf b = 192/16$ $\sf b = 12 \: \: cm$ Using Pythagoras theorem, .i.e., $\boxed{\bf AB² = BC² + AC²}$ According to the QUESTION BC = 12cm AC = 16cm $:\implies\sf AB² = 12² + 16²$ $: \implies \sf AB = \sqrt{{12}^{2} + {16}^{2}}$ $: \implies \sf AB = \sqrt{144 + 256}$ $: \implies \sf AB = \sqrt{400} = 20 \: \: cm$ $\Huge\therefore$ The diagonal of rectangle is $20$ cm

34.

Find the diagonal of a rectangle whose length is 16cm and areas is 192sq.cm

Answer» U>Given :-

Length of the rectangle = 16 cm

Area of the rectangle = 192² cm

➤ To Find :-

Diagonal of the rectangle

➤ Solution :-

We know that,

Area of rectangle = Length × Breadth

$\sf 192 = 16 × b$

$\sf b = 192/16$

$\sf b = 12 \: \: cm$

Using Pythagoras theorem, .i.e.,

$\boxed{\bf AB² = BC² + AC²}$

According to the QUESTION

BC = 12cm

AC = 16cm

$:\implies\sf AB² = 12² + 16²$

$: \implies \sf AB = \sqrt{{12}^{2} + {16}^{2}}$

$: \implies \sf AB = \sqrt{144 + 256}$

$: \implies \sf AB = \sqrt{400} = 20 \: \: cm$

$\Huge\therefore$ The diagonal of rectangle is $20$ cm

Discussion

35.	What is the standard form of 45 + 3m = 9m^2? A.9m^2 + 3m - 45 = 0B.9m^2- 3m - 45 = 0C.9m^2 - 3m + 45 = 0D.9m^2 + 3m + 45 = 0
Answer» ong>Answer: PLEASE BRAINLIEST MY ANSWER Step-by-step explanation: Q) What is the standard form of 45 + 3M = 9m^2? A.9m^2 + 3m - 45 = 0 B.9m^2- 3m - 45 = 0 C.9m^2 - 3m + 45 = 0 D.9m^2 + 3m + 45 = 0 ⇒ B.9m^2- 3m - 45 = 0 ∴ GIVEN a 45 + 3m = 9m^2 ⇔ 45 + 3m - 9m^2 = 0 ⇔ 9m^2 - 3m - 45 = 0

35.

What is the standard form of 45 + 3m = 9m^2? A.9m^2 + 3m - 45 = 0B.9m^2- 3m - 45 = 0C.9m^2 - 3m + 45 = 0D.9m^2 + 3m + 45 = 0

Answer»

ong>Answer:

PLEASE BRAINLIEST MY ANSWER

Step-by-step explanation:

Q) What is the standard form of 45 + 3M = 9m^2?

A.9m^2 + 3m - 45 = 0

B.9m^2- 3m - 45 = 0

C.9m^2 - 3m + 45 = 0

D.9m^2 + 3m + 45 = 0

⇒ B.9m^2- 3m - 45 = 0

∴ GIVEN a 45 + 3m = 9m^2

⇔ 45 + 3m - 9m^2 = 0

⇔ 9m^2 - 3m - 45 = 0

Discussion

36.	It is on the upper right side of the PowerPoint window.
Answer» ong>ANSWER: HIIIIII Step-by-step explanation: I am HARSHITA........

36.

It is on the upper right side of the PowerPoint window.

Answer»

ong>ANSWER:

HIIIIII

Step-by-step explanation:

I am HARSHITA........

Discussion

37.	Q6. If the surcase are of the cube is1536sqcm its volume is cc."
Answer» >Volume of CUBE is 4096 cm³. Step-by-step explanation: Correct QUESTION:- If the surface area of the cube is 1536 cm². It's Volume is : _________________________________ Given:- Surface area of cube is 1536 cm². To FIND:- Volume of cube. Solution:- We need edge of cube for Volume of cube. So : We KNOW that, $\boxed{\star \: \sf \bold{Total \: surface\:area \: of \: cube = 6 a^{2}}}$ In which, a is Edge or we can SAY side of cube. Surface area = 1536 Put , surface area in formula : $\longrightarrow \sf \bold{1536 = 6 {a}^{2} }$ $\longrightarrow \sf \bold{ \cfrac{1536}{6} = {a}^{2} }$ $\longrightarrow \sf \bold{256 = {a}^{2} }$ $\longrightarrow \sf \bold{ \sqrt{256} = a }$ $\longrightarrow \sf \bold{16 = a}$ Or, a = 16 Edge of cube is 16 cm. $\boxed{\star \: \sf \bold{Volume \: of \: cube = a^{3}}}$ $\longrightarrow \sf \bold{ {(16)}^{3} }$ $\longrightarrow \sf \bold{16 \times 16 \times 16}$ $\longrightarrow \sf \bold{4096}$ Therefore, Volume of cube is 4096 cm³.

37.

Q6. If the surcase are of the cube is1536sqcm its volume is cc."

Answer»

>Volume of CUBE is 4096 cm³.

Step-by-step explanation:

Correct QUESTION:-

If the surface area of the cube is 1536 cm². It's Volume is :

_________________________________

Given:-

Surface area of cube is 1536 cm².

To FIND:-

Volume of cube.

Solution:-

We need edge of cube for Volume of cube. So :

We KNOW that,

$\boxed{\star \: \sf \bold{Total \: surface\:area \: of \: cube = 6 a^{2}}}$

In which,

a is Edge or we can SAY side of cube.

Surface area = 1536

Put , surface area in formula :

$\longrightarrow \sf \bold{1536 = 6 {a}^{2} }$

$\longrightarrow \sf \bold{ \cfrac{1536}{6} = {a}^{2} }$

$\longrightarrow \sf \bold{256 = {a}^{2} }$

$\longrightarrow \sf \bold{ \sqrt{256} = a }$

$\longrightarrow \sf \bold{16 = a}$

Or, a = 16

Edge of cube is 16 cm.

$\boxed{\star \: \sf \bold{Volume \: of \: cube = a^{3}}}$

$\longrightarrow \sf \bold{ {(16)}^{3} }$

$\longrightarrow \sf \bold{16 \times 16 \times 16}$

$\longrightarrow \sf \bold{4096}$

Therefore,

Volume of cube is 4096 cm³.

Discussion

38.	6.A survey was conducted to know the hobby of 220 students of class IX. Out of which 130 students informed about their hobby as rock climbing and 180 students informed about their hobby as sky watching. There are 110 students who follow both the hobbies. Then how many students do not have any of the two hobbies ? How many of them follow the hobby of rock climbing only ? How many students follow the hobby of sky watching only?(2 Points)20,20,7025,35,4055,70,8590,45,65
Answer» ong>ANSWER: SORRY I don't know because QUESTION PHOTOS not there

38.

6.A survey was conducted to know the hobby of 220 students of class IX. Out of which 130 students informed about their hobby as rock climbing and 180 students informed about their hobby as sky watching. There are 110 students who follow both the hobbies. Then how many students do not have any of the two hobbies ? How many of them follow the hobby of rock climbing only ? How many students follow the hobby of sky watching only?(2 Points)20,20,7025,35,4055,70,8590,45,65

Answer»

ong>ANSWER:

SORRY I don't know because QUESTION PHOTOS not there

Discussion

39.	Q3. Total surface area of a cuboid is *lb+bh+hl2(lb+bh+hl)3(1b+bh+hl)4(1b+bh+hl)
Answer» ONG>Answer: 2 (lb+bh+lh) Step-by-step EXPLANATION: its the FORMULA

39.

Q3. Total surface area of a cuboid is *lb+bh+hl2(lb+bh+hl)3(1b+bh+hl)4(1b+bh+hl)

Answer» ONG>Answer:

2 (lb+bh+lh)

Step-by-step EXPLANATION:

its the FORMULA

Discussion

40.	Find the HCF of 767and 2778 by long division method.
Answer» ONG>ANSWER: okkkkkkkkkkkkkkkkkkkkk

Discussion

41.	The standard form of 18/81 with step by step
Answer» ONG>Step-by-step EXPLANATION: $\frac{18}{81 } \: = \: \frac{(9 \times 2)}{( 9 \times 9)} \\ \\ = \frac{(9)}{(9)} \times \frac{2}{9} \\ \\ = 1 \times \frac{2}{9} \\ \\ = \frac{2}{9}$

41.

The standard form of 18/81 with step by step

Answer» ONG>Step-by-step EXPLANATION:

$\frac{18}{81 } \: = \: \frac{(9 \times 2)}{( 9 \times 9)} \\ \\ = \frac{(9)}{(9)} \times \frac{2}{9} \\ \\ = 1 \times \frac{2}{9} \\ \\ = \frac{2}{9}$

Discussion

42.	Q. If sin = 4/5 and cos 0 =9/25. then tan e = ?
Answer» ONG>Answer: 20/9 Step-by-step EXPLANATION: tan=sin/cos ....WELCOME

42.

Q. If sin = 4/5 and cos 0 =9/25. then tan e = ?

Answer» ONG>Answer:

20/9

Step-by-step EXPLANATION:

tan=sin/cos ....WELCOME

Discussion

43.	Which of the following are proper fraction 1/3, 10/5, 7/4, 10/11, 2,7/9
Answer» align="absmiddle" alt="\huge\red{\tt{\underline{Question:-}}}" CLASS="latex-formula" id="TexFormula1" src="https://tex.z-dn.net/?f=%5Chuge%5Cred%7B%5Ctt%7B%5Cunderline%7BQuestion%3A-%7D%7D%7D" TITLE="\huge\red{\tt{\underline{Question:-}}}"> Which of the following are PROPER fraction:- $\frac{1}{3}$ , $\frac{10}{5}$ , $\frac{7}{4}$ , $\frac{10}{11}$ , $\frac{27}{9}$ $\huge\red{\tt{\underline{Answer:-}}}$ The following NUMBERS are the proper fractions:- $\frac{1}{3}$ and $\frac{10}{11}$ Explanation:- Proper fractions are the fractions having numerator less than DENOMINATOR. ${\huge{\underline{\small{\mathbb{\blue{HOPE\:HELP\:U\:BUDDY :)}}}}}}$ ${\huge{\underline{\small{\mathbb{\pink{~cαndчflσѕѕ♡ :)}}}}}}$

43.

Which of the following are proper fraction 1/3, 10/5, 7/4, 10/11, 2,7/9

Answer»

align="absmiddle" alt="\huge\red{\tt{\underline{Question:-}}}" CLASS="latex-formula" id="TexFormula1" src="https://tex.z-dn.net/?f=%5Chuge%5Cred%7B%5Ctt%7B%5Cunderline%7BQuestion%3A-%7D%7D%7D" TITLE="\huge\red{\tt{\underline{Question:-}}}">

Which of the following are PROPER fraction:-

$\frac{1}{3}$ , $\frac{10}{5}$ , $\frac{7}{4}$ , $\frac{10}{11}$ , $\frac{27}{9}$

$\huge\red{\tt{\underline{Answer:-}}}$

The following NUMBERS are the proper fractions:-

$\frac{1}{3}$ and $\frac{10}{11}$

Explanation:-

Proper fractions are the fractions having numerator less than DENOMINATOR.

${\huge{\underline{\small{\mathbb{\blue{HOPE\:HELP\:U\:BUDDY :)}}}}}}$

${\huge{\underline{\small{\mathbb{\pink{~cαndчflσѕѕ♡ :)}}}}}}$

Discussion

44.	Findif D=-22 & Dx = -44
Answer» ONG>Answer: if you WANT to ask the value of X then it is 11

44.

Findif D=-22 & Dx = -44

Answer» ONG>Answer:

if you WANT to ask the value of X then

it is 11

Discussion

45.	Limitation of finacial statements
Answer» ong>Step-by-step explanation: limitations of financial statements:- Dependence on historical costs. Transactions are initially recorded at their COST. ... INFLATIONARY effects. ... INTANGIBLE assets not recorded. ... Based on SPECIFIC time period. ... Not always comparable across COMPANIES. ... Subject to fraud. ... No discussion of non-financial issues. ... Not verified.

45.

Limitation of finacial statements

Answer»

ong>Step-by-step explanation:

limitations of financial statements:-

Dependence on historical costs. Transactions are initially recorded at their COST. ...

INFLATIONARY effects. ...

INTANGIBLE assets not recorded. ...

Based on SPECIFIC time period. ...

Not always comparable across COMPANIES. ...

Subject to fraud. ...

No discussion of non-financial issues. ...

Not verified.

Discussion

46.	44) Find the smallest number by which the number 72 must be multiplied too btain a perfectcube. a .2 b.4c.6d.3
Answer» ong>ANSWER: Answer: 2 SOLUTION: 72*2=144 ✓144= 12

46.

44) Find the smallest number by which the number 72 must be multiplied too btain a perfectcube. a .2 b.4c.6d.3

Answer»

ong>ANSWER:

Answer: 2

*SOLUTION:* 72*2=144

✓144= 12

Discussion

47.	1 pointQ. Find the value of ( sec A +tan A) (1 - sin A)
Answer» ONG>ANSWER: cot^2A Step-by-step EXPLANATION: Please mark me as BRAINLEST

47.

1 pointQ. Find the value of ( sec A +tan A) (1 - sin A)

Answer» ONG>ANSWER:

cot^2A

Step-by-step EXPLANATION:

Please mark me as BRAINLEST

Discussion

48.	1+2一「十DL
Answer» ONG>ANSWER: HI BRO ............................................... . . ................

48.

1+2一「十DL

Answer» ONG>ANSWER:

HI BRO ...............................................

.

................

Discussion

49.	Find the value of the polynomial p(x)=x2-21+1 at x=2
Answer» ong>ANSWER:P> p(2)=2^2-21+1 =4-20 = -16

49.

Find the value of the polynomial p(x)=x2-21+1 at x=2

Answer»

ong>ANSWER:P>

p(2)=2^2-21+1

=4-20

= -16

Discussion

50.	What do you observe from each step in dividing
Answer» ong>ANSWER: Step 1: COMPLETELY factor both the numerators and denominators of all fractions. Step 2: Change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you NEED to multiply by the reciprocal. Step 3: Cancel or reduce the fractions

50.

What do you observe from each step in dividing

Answer»

ong>ANSWER:

Step 1: COMPLETELY factor both the numerators and denominators of all fractions. Step 2: Change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you NEED to multiply by the reciprocal. Step 3: Cancel or reduce the fractions

Discussion

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It is on the upper right side of the PowerPoint window.​

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