Find the diagonal of a rectangle whose length is 16cm and areas is 192

1.	Find the diagonal of a rectangle whose length is 16cm and areas is 192sq.cm
Answer» U>Given :- Length of the rectangle = 16 cm Area of the rectangle = 192² cm ➤ To Find :- Diagonal of the rectangle ➤ Solution :- We know that, Area of rectangle = Length × Breadth $\sf 192 = 16 × b$ $\sf b = 192/16$ $\sf b = 12 \: \: cm$ Using Pythagoras theorem, .i.e., $\boxed{\bf AB² = BC² + AC²}$ According to the QUESTION BC = 12cm AC = 16cm $:\implies\sf AB² = 12² + 16²$ $: \implies \sf AB = \sqrt{{12}^{2} + {16}^{2}}$ $: \implies \sf AB = \sqrt{144 + 256}$ $: \implies \sf AB = \sqrt{400} = 20 \: \: cm$ $\Huge\therefore$ The diagonal of rectangle is $20$ cm