332354 + Interview Questions in Secondary School in Math

1.	-3
Answer» ONG>ANSWER: दर्द है दिल में पर इसका एहसास नहीं होता, रोता है दिल जब वो पास नहीं होता, बर्बाद हो गए हम उसके प्यार में, और वो कहते हैं इस तरह प्यार नहीं होता… Step-by-step EXPLANATION: सोचा था की ख़ुदा के सिवा मुझे कोई बर्बाद कर नही सकता… फिर उनकी मोहब्बत ने मेरे सारे वहम तोड़ दिए…….

1.

-3

Answer» ONG>ANSWER:

दर्द है दिल में पर इसका एहसास नहीं होता,

रोता है दिल जब वो पास नहीं होता,

बर्बाद हो गए हम उसके प्यार में,

और वो कहते हैं इस तरह प्यार नहीं होता…

Step-by-step EXPLANATION:

सोचा था की ख़ुदा के सिवा मुझे कोई बर्बाद कर नही सकता…

फिर उनकी मोहब्बत ने मेरे सारे वहम तोड़ दिए…….

Discussion

2.	If A ={1,2,3,4,5,7,9,11} find n(A)
Answer» ong>Answer: N(A) is 8. count the NUMBERS in the BRACKET

2.

If A ={1,2,3,4,5,7,9,11} find n(A)

Answer»

ong>Answer:

N(A) is 8. count the NUMBERS in the BRACKET

Discussion

3.	2 times x times 3 times x
Answer» ONG>Answer: (2X)(3x) 6x^2 ===== it is answer bro

3.

2 times x times 3 times x

Answer» ONG>Answer:

(2X)(3x)

6x^2

=====

it is answer bro

Discussion

4.	2. Find the zeroes of the polynomial x? - 3 and verify the relationship between the zeroes and the coefficients.
Answer» GIVEN polynomial is x 2 −3 Here, a=1,b=0 and c=−3 x 2 −3=(x− 3 )(x− 3 ) So, the value of x 2 −3 is ZERO when x= 3 or x=− 3 Threrfore , THR ZEROES of x 2 −3 are 3 and − 3 . Now, sum of zeroes = 3 − 3 =0= 1 0 = a −b product of zeroes =( 3 )(− 3 )=−3= 1 −3 = a c Hence verified.

4.

2. Find the zeroes of the polynomial x? - 3 and verify the relationship between the zeroes and the coefficients.

Answer»

GIVEN polynomial is x

2

−3

Here, a=1,b=0 and c=−3

x

2

−3=(x−

3

)(x−

3

)

So, the value of x

2

−3 is ZERO when x=

3

or x=−

3

Threrfore , THR ZEROES of x

2

−3 are

3

and −

3

.

Now, sum of zeroes =

3

−

3

=0=

1

0

=

a

−b

product of zeroes =(

3

)(−

3

)=−3=

1

−3

=

a

c

Hence verified.

Discussion

5.	O is the centre of the circle find x if angle aob 80 degree
Answer» ong>ANSWER: ∠AOC + 80° = 180° [LINEAR PAIR PROPERTY] ∠AOC = 100° NOW, OA = OC → ∠OAC = ∠OCA = x° [say] now. ∠OAC + ∠OCA +∠AOC = 180° x + x + 100 = 180° 2X = 80° x = 40 Step-by-step explanation:

5.

O is the centre of the circle find x if angle aob 80 degree

Answer»

ong>ANSWER:

∠AOC + 80° = 180° [LINEAR PAIR PROPERTY]

∠AOC = 100°

NOW,

OA = OC

→ ∠OAC = ∠OCA = x° [say]

now.

∠OAC + ∠OCA +∠AOC = 180°

x + x + 100 = 180°

2X = 80°

x = 40

Step-by-step explanation:

Discussion

6.	√(2)²+1²what is the value after solving itplease give the answer
Answer» ONG>Step-by-step EXPLANATION: √ (2)^2 +(1)^2 √ 4+1 √ 5 2.23606798

Discussion

7.	Sin x - cos x +122. Prove thatsin x + cos x-1= sec x + tan x.
Answer» ONG>Answer: please MARK me as a BRAINLIST

7.

Sin x - cos x +122. Prove thatsin x + cos x-1= sec x + tan x.

Answer» ONG>Answer:

please MARK me as a BRAINLIST

Discussion

8.	.Rationalize the denominator1√3-√5
Answer» ONG>ANSWER: -(√3+√5/2) Step-by-step explanation: just MULTIPLY with additive conjugate

8.

.Rationalize the denominator1√3-√5

Answer» ONG>ANSWER:

-(√3+√5/2)

Step-by-step explanation:

just MULTIPLY with additive conjugate

Discussion

9.	ਜੇਕਰ ਦੋ ਘਾਤੀ ਸਮੀਕਰਣ ਡਿਸਕਿਰਮੀਨੈਟ = -4 ਹੋਵੇ ਤਾਂ ਸਮੀਕਰਣ ਦੇ ਮੂਲ ਸੰਭਵ ਹਨ ( ਸਹੀ/ ਗਲਤ)
Answer» ong>Step-by-step EXPLANATION: dofyfe a the iDtguf to gt to i he to ftfgf a gdyfy for 5e to the f it so I h it so is everyone j it a to it so I have yh is hi are so we I had just hi sorry hi is o he TH if he l my to TRY it a we 6 it up to me a kid

9.

ਜੇਕਰ ਦੋ ਘਾਤੀ ਸਮੀਕਰਣ ਡਿਸਕਿਰਮੀਨੈਟ = -4 ਹੋਵੇ ਤਾਂ ਸਮੀਕਰਣ ਦੇ ਮੂਲ ਸੰਭਵ ਹਨ ( ਸਹੀ/ ਗਲਤ)

Answer»

ong>Step-by-step EXPLANATION:

dofyfe a the iDtguf to gt to i he to ftfgf a gdyfy for 5e to the f it so I h it so is everyone j it a to it so I have yh is hi are so we I had just hi sorry hi is o he TH if he l my to TRY it a we 6 it up to me a kid

Discussion

10.	Simplyfy using suitable property (-95)×52+(-52)×(-25)
Answer» ONG>ANSWER: (-95)×52+(-52)×(-25) =(-95)×52+52×(-1)×(-25) =52×[-95+(-1)×(-25)] =52×[-95+25] =52×(-70) =-3640 answer hope this will help you. Step-by-step explanation:

10.

Simplyfy using suitable property (-95)×52+(-52)×(-25)

Answer» ONG>ANSWER:

(-95)×52+(-52)×(-25)

=(-95)×52+52×(-1)×(-25)

=52×[-95+(-1)×(-25)]

=52×[-95+25]

=52×(-70)

=-3640 answer

hope this will help you.

Step-by-step explanation:

Discussion

11.	Express x/2+y/3=1/6 in the form of ax+by+c=0
Answer» ONG>Answer: 3x+2y /6 = 1/6 3x+2y = 1 3x+2y-1 = 0

11.

Express x/2+y/3=1/6 in the form of ax+by+c=0

Answer» ONG>Answer:

3x+2y /6 = 1/6

3x+2y = 1

3x+2y-1 = 0

Discussion

12.	Description of egg structure? ✎﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏I know but kisi se baat na karke iss trah Aapne aap ko chhupa rakhne aap khud mental hoo jaaogihamari dadi kheti hai larkiya chachal hoti hai usse khulke rhena chaye ye bhi sahi hai daag lgane wale bhout hai but unse dar ke jina nahi chhod skti na aap
Answer» egg is composed of Shell, Membrane, Aircell, Egg White, Egg YOLK and Chalaza. The egg white FORMS 2/3rd of the WHOLE egg and the yolk forms 1/3rd. Hope this helps u. Good Evening. Pls mark me as a BRAINIEST.

12.

Description of egg structure? ✎﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏I know but kisi se baat na karke iss trah Aapne aap ko chhupa rakhne aap khud mental hoo jaaogihamari dadi kheti hai larkiya chachal hoti hai usse khulke rhena chaye ye bhi sahi hai daag lgane wale bhout hai but unse dar ke jina nahi chhod skti na aap

Answer»

egg is composed of Shell, Membrane, Aircell, Egg White, Egg YOLK and Chalaza. The egg white FORMS 2/3rd of the WHOLE egg and the yolk forms 1/3rd.

Hope this helps u.

Good Evening.

Pls mark me as a BRAINIEST.

Discussion

13.	(b) Find the value of: sin²30' cos²45' + 4tan² 30' + sin²90°+cos³0
Answer» ong>ANSWER: sin²30°cos²45°+4tan²30° + (1/2)sin²90°-2cos²90° + (1/24)cos²0° sin²30° = (1/2)² = 1/4 cos²45° = (1/√2)² = 1/2 tan²30° = (1/√3)² = 1/3 sin²90° = 1 cos²90° = 0 cos²0° = 1 = (1/4)(1/2) + 4(1/3) + (1/2)(1) - 20 + (1/24)1 = 1/8 + 4/3 + 1/2 + 1/24 = (3 + 32 + 12 + 1)/24 = 48/24 = 2 sin²30°cos²45°+4tan²30° + (1/2)sin²90°-2cos²90° + (1/24)cos²0° = 2 Learn more: If sin θ + cos θ = 2 , then evaluate : TAN θ + cot θ - Brainly.in brainly.in/question/7871635 cosec(90+x)+cot(90+x)/cosec(90-x)+tan(180-x)+tan(180+x)+ Step-by-step explanation:*

13.

(b) Find the value of: sin²30' cos²45' + 4tan² 30' + sin²90°+cos³0

Answer»

ong>ANSWER:

sin²30°cos²45°+4tan²30° + (1/2)sin²90°-2cos²90° + (1/24)cos²0°

sin²30° = (1/2)² = 1/4

cos²45° = (1/√2)² = 1/2

tan²30° = (1/√3)² = 1/3

sin²90° = 1

cos²90° = 0

cos²0° = 1

= (1/4)(1/2) + 4(1/3) + (1/2)(1) - 2*0 + (1/24)1

= 1/8 + 4/3 + 1/2 + 1/24

= (3 + 32 + 12 + 1)/24

= 48/24

= 2

sin²30°cos²45°+4tan²30° + (1/2)sin²90°-2cos²90° + (1/24)cos²0° = 2

Learn more:

If sin θ + cos θ = 2 , then evaluate : TAN θ + cot θ - Brainly.in

brainly.in/question/7871635

cosec(90+x)+cot(90+x)/cosec(90-x)+tan(180-x)+tan(180+x)+

Step-by-step explanation:

Discussion

14.	Divide the rational 2/3 by -7/12
Answer» ONG>Answer: Answer is -1.13 Step-by-step EXPLANATION: HOPE it help U

14.

Divide the rational 2/3 by -7/12

Answer» ONG>Answer:

Answer is -1.13

Step-by-step EXPLANATION:

HOPE it help U

Discussion

15.	Ohh maa goo turu lub Thik hai fr
Answer» hin Hindurao Vaze is a suspended ASSISTANT Police INSPECTOR of the Indian state of Maharashtra. He now is in custody of the National Investigation AGENCY for his alleged involvement in the murder of Mansukh Hiren and the 2021 Antilla BOMB SCARE.

Discussion

16.	Prove ax+bx+c= (x-α) (x- ß). also say prove sum of zeros of polynomial α+β=-b/a&product of zeros of polynomial αβ=c/a
Answer» $\sqrt{? \times \frac{?}{?} } \\ \\ \\$

16.

Prove ax+bx+c= (x-α) (x- ß). also say prove sum of zeros of polynomial α+β=-b/a&product of zeros of polynomial αβ=c/a

Answer»

$\sqrt{? \times \frac{?}{?} } \\ \\ \\$

Discussion

17.	3Simplify :- ax axba' xaº xbxa2.
Answer» ONG>ANSWER: LOL!LOL!LOL!LOL1LOL! Step-by-step EXPLANATION:

17.

3Simplify :- ax axba' xaº xbxa2.

Answer» ONG>ANSWER:

LOL!LOL!LOL!LOL1LOL!

Step-by-step EXPLANATION:

Discussion

18.	Find the 5th term of the sequence -8,-1,6,13
Answer» ong>Answer: so ,here we can clearly see every TERM is added with NUMBER 7 so answer 13+7=20 20+7=27 UR 5TH term is 20 and 6th term is 27

18.

Find the 5th term of the sequence -8,-1,6,13

Answer»

ong>Answer:

so ,here we can clearly see every TERM is added with NUMBER 7

so answer 13+7=20

20+7=27

UR 5TH term is 20 and 6th term is 27

Discussion

19.	What is the mean porportional of 4 and 25
Answer» ONG>ANSWER: Step-by-step explanation: 10

19.

What is the mean porportional of 4 and 25

Answer» ONG>ANSWER:

Step-by-step explanation:

10

Discussion

20.	If A ={123457911} find n(A)
Answer» ong>Answer: N(A) is 8 COUNT the number in the BRACKET

20.

If A ={123457911} find n(A)

Answer»

ong>Answer:

N(A) is 8 COUNT the number in the BRACKET

Discussion

21.	-3
Answer» bsjsjnamakabadashahkjaj kavsgajajananshabakhuahi

Discussion

22.	Nikitanikita29 this is the answer for ur question. I hope it's correct I got the answer few mins ago
Answer» ONG>ANSWER: YEAH...correct Step-by-step EXPLANATION:

22.

Nikitanikita29 this is the answer for ur question. I hope it's correct I got the answer few mins ago

Answer» ONG>ANSWER:

YEAH...correct

Step-by-step EXPLANATION:

Discussion

23.	Find the common difference of the sequence 216,-36,6,-1
Answer» ong>Step-by-step explanation: comman difference = a2 -a1 acording to me these are two rows as 216 and 6 and 36 and 1

23.

Find the common difference of the sequence 216,-36,6,-1

Answer»

ong>Step-by-step explanation:

comman difference = a2 -a1

acording to me these are two rows

as 216 and 6

and 36 and 1

Discussion

24.	Cos38cos52-sin38sin52
Answer» ONG>Answer: 0 Step-by-step EXPLANATION: cos38×cos(90-38) - sin38×sin(90-38) = cos38×sin38 - sin38×cos38 =0

24.

Cos38cos52-sin38sin52

Answer» ONG>Answer:

0

Step-by-step EXPLANATION:

cos38×cos(90-38) - sin38×sin(90-38)

= cos38×sin38 - sin38×cos38

=0

Discussion

25.	4p+[3q-2r(p-q+r)],p=1,q=2,r=-1
Answer» align="absmiddle" alt="\LARGE\textsf{\underline\textcolor{aqua}{↭ GiVeN :-}}" class="latex-formula" id="TexFormula1" SRC="https://tex.z-dn.net/?f=%5CLARGE%5Ctextsf%7B%5Cunderline%5Ctextcolor%7Baqua%7D%7B%E2%86%AD%20GiVeN%20%3A-%7D%7D" title="\LARGE\textsf{\underline\textcolor{aqua}{↭ GiVeN :-}}"> $\large\textsf{ }$ p = 1 q = 2 r = - 1 $\large\textsf{ }$ $\LARGE\textsf{\underline\textcolor{aqua}{↭ To FiNd :-}}$ $\large\textsf{ }$ ↦ The product of the given equation $\large\textsf{ }$ $\LARGE\textsf{\underline\textcolor{aqua}{↭ SoLuTiOn :-}}$ $\large\textsf{ }$ $\qquad\tt{:}\longrightarrow\large\textsf{4p + [ 3q - 2r ( p - q + r )]}$ $\qquad\tt{:}\longrightarrow\large\textsf{( 4 × 1 ) + [ ( 3 × 2 ) - ( 2 × - 1 ) [ 1 - 2 + ( - 1 )]]}$ $\qquad\tt{:}\longrightarrow\large\textsf{4 + [ 6 - ( - 2 ) ( - 1 - 1 )]}$ $\qquad\tt{:}\longrightarrow\large\textsf{4 + [ 6 + 2 ( - 2 ) ]}$ $\qquad\tt{:}\longrightarrow\large\textsf{4 + [ 6 + ( - 4 )]}$ $\qquad\tt{:}\longrightarrow\large\textsf{4 + [ 6 - 4 ]}$ $\qquad\tt{:}\longrightarrow\large\textsf{4 + 2}$ $\qquad\tt{:}\longrightarrow\boxed{\large\textsf\textcolor{red}{8}}$

25.

4p+[3q-2r(p-q+r)],p=1,q=2,r=-1

Answer»

align="absmiddle" alt="\LARGE\textsf{\underline\textcolor{aqua}{↭ GiVeN :-}}" class="latex-formula" id="TexFormula1" SRC="https://tex.z-dn.net/?f=%5CLARGE%5Ctextsf%7B%5Cunderline%5Ctextcolor%7Baqua%7D%7B%E2%86%AD%20GiVeN%20%3A-%7D%7D" title="\LARGE\textsf{\underline\textcolor{aqua}{↭ GiVeN :-}}">

$\large\textsf{ }$

p = 1
q = 2
r = - 1

$\large\textsf{ }$

$\LARGE\textsf{\underline\textcolor{aqua}{↭ To FiNd :-}}$

$\large\textsf{ }$

↦ The product of the given equation

$\large\textsf{ }$

$\LARGE\textsf{\underline\textcolor{aqua}{↭ SoLuTiOn :-}}$

$\large\textsf{ }$

$\qquad\tt{:}\longrightarrow\large\textsf{4p + [ 3q - 2r ( p - q + r )]}$

$\qquad\tt{:}\longrightarrow\large\textsf{( 4 × 1 ) + [ ( 3 × 2 ) - ( 2 × - 1 ) [ 1 - 2 + ( - 1 )]]}$

$\qquad\tt{:}\longrightarrow\large\textsf{4 + [ 6 - ( - 2 ) ( - 1 - 1 )]}$

$\qquad\tt{:}\longrightarrow\large\textsf{4 + [ 6 + 2 ( - 2 ) ]}$

$\qquad\tt{:}\longrightarrow\large\textsf{4 + [ 6 + ( - 4 )]}$

$\qquad\tt{:}\longrightarrow\large\textsf{4 + [ 6 - 4 ]}$

$\qquad\tt{:}\longrightarrow\large\textsf{4 + 2}$

$\qquad\tt{:}\longrightarrow\boxed{\large\textsf\textcolor{red}{8}}$

Discussion

26.	First two terms in expansion of e^x.secx by maclaurins theorem is
Answer» $\textbf{Given:}$ $\mathsf{e^x\,secx}$ $\textbf{To find:}$ $\mathsf{Maclaurin's\;series\;<klux>EXPANSION</klux>\;of\;e^x\,secx}$ $\textbf{Solution:}$ $\mathsf{Let\;f(x)=e^x\,secx}$ $\implies\mathsf{f(0)=e^0\,sec0=1}$ $\mathsf{f'(x)=e^x\,secx\,tanx+secx\,e^x}$ $\implies\mathsf{f'(0)=e^0\,sec0\,tan0+sec0\,e^0=0+1=1}$ $\mathsf{f''(x)=(e^x\,secx\,tanx+e^x\,secx\,tanx\,tanx+e^x\,secx\,sec^2x)+(secx\,e^x+e^x\,secx\,tanx)}$ $\implies\mathsf{f''(0)=(e^0\,sec0\,tan0+e^0\,sec0\,tan0\,tan0+e^0\,sec^30)+(sec0\,e^0+e^0\,sec0\,tan0)}$ $\implies\mathsf{f''(0)=(0+0+1)+(1+0)=2}$ $\mathsf{Now,}$ $\textsf{Maclaurin series expansion of f(x) is}$ $\mathsf{f(x)=f(0)+\dfrac{f^1(0)}{1!}x+\dfrac{f^2(0)}{2!}x^2+\dfrac{f^3(0)}{3!}x^3+.\;.\;.\;.\;.\;.\;.}$ $\mathsf{e^x\,secx=1+\dfrac{1}{1!}x+\dfrac{2}{2!}x^2+.\;.\;.\;.\;.\;.\;.}$ $\implies\boxed{\mathsf{e^x\,secx=1+x+x^2+.\;.\;.\;.\;.\;.\;.}}$ $\textbf{Find more:}$ Expansion of SINX is ASCENDING POWER of X brainly.in/question/28857947

26.

First two terms in expansion of e^x.secx by maclaurins theorem is

Answer»

$\textbf{Given:}$

$\mathsf{e^x\,secx}$

$\textbf{To find:}$

$\mathsf{Maclaurin's\;series\;<klux>EXPANSION</klux>\;of\;e^x\,secx}$

$\textbf{Solution:}$

$\mathsf{Let\;f(x)=e^x\,secx}$

$\implies\mathsf{f(0)=e^0\,sec0=1}$

$\mathsf{f'(x)=e^x\,secx\,tanx+secx\,e^x}$

$\implies\mathsf{f'(0)=e^0\,sec0\,tan0+sec0\,e^0=0+1=1}$

$\mathsf{f''(x)=(e^x\,secx\,tanx+e^x\,secx\,tanx\,tanx+e^x\,secx\,sec^2x)+(secx\,e^x+e^x\,secx\,tanx)}$

$\implies\mathsf{f''(0)=(e^0\,sec0\,tan0+e^0\,sec0\,tan0\,tan0+e^0\,sec^30)+(sec0\,e^0+e^0\,sec0\,tan0)}$

$\implies\mathsf{f''(0)=(0+0+1)+(1+0)=2}$

$\mathsf{Now,}$

$\textsf{Maclaurin series expansion of f(x) is}$

$\mathsf{f(x)=f(0)+\dfrac{f^1(0)}{1!}x+\dfrac{f^2(0)}{2!}x^2+\dfrac{f^3(0)}{3!}x^3+.\;.\;.\;.\;.\;.\;.}$

$\mathsf{e^x\,secx=1+\dfrac{1}{1!}x+\dfrac{2}{2!}x^2+.\;.\;.\;.\;.\;.\;.}$

$\implies\boxed{\mathsf{e^x\,secx=1+x+x^2+.\;.\;.\;.\;.\;.\;.}}$

$\textbf{Find more:}$

Expansion of SINX is ASCENDING POWER of X

brainly.in/question/28857947

Discussion

27.	5. Find the mean proportion between: (i) 2a3 and 50ab4Please answer me faster .I will mark it as brainlist...
Answer» ONG>Answer: PLEASE MARK me as BRAINIEST answer

Discussion

28.	Draw and write the types of triangle based on its sides
Answer» ONG>ANSWER: In an acute triangle, all the angles of a triangle are less than 90 degrees. In an OBTUSE triangle, one of the angles of a triangle is greater than 90 degrees. In a RIGHT triangle, one ANGLE measures 90 degrees and the other two angles are acute.

Discussion

29.	What is the point of concurrence of angle bisector of a triangle?
Answer» ong>Answer: The point of concurrency of the angle BISECTORS is called the incenter. The three ALTITUDES of a triangle are CONCURRENT. The point of concurrency is called the ORTHOCENTER. The three medians of the triangle are concurrentI HOPE This will help you.

29.

What is the point of concurrence of angle bisector of a triangle?

Answer»

ong>Answer:

The point of concurrency of the angle BISECTORS is called the incenter. The three ALTITUDES of a triangle are CONCURRENT. The point of concurrency is called the ORTHOCENTER. The three medians of the triangle are concurrentI HOPE This will help you.

Discussion

30.	माइनस 2 अंडर रूट 5 2 माइनस अंडर रूट 5 क्लासिफाई थे फॉलोइंग नंबर नेशनल or इरेशनल
Answer» ong>Answer: HAHAHAHAHA.. binocular anithilu !! hahahahaha.. bhala auu !! LOVE you baby ❤️❤️❤️❤️ hahaha..hn TK samaya pain basithili !! nai maa padhibara chance nahi !! TU jou goda hata tekiki basuchu padunu ta !! mu bas tk basithili !! hahahaha love you baby ☺️☺️☺️☺️

30.

माइनस 2 अंडर रूट 5 2 माइनस अंडर रूट 5 क्लासिफाई थे फॉलोइंग नंबर नेशनल or इरेशनल

Answer»

ong>Answer:

HAHAHAHAHA.. binocular anithilu !! hahahahaha..

bhala auu !!

LOVE you baby ❤️❤️❤️❤️

hahaha..hn TK samaya pain basithili !! nai maa padhibara chance nahi !! TU jou goda hata tekiki basuchu padunu ta !! mu bas tk basithili !! hahahaha

love you baby ☺️☺️☺️☺️

Discussion

31.	A boy rode his bicycle Northward, then turned left and rode 1 km and again turned left and rode 2 km. He found himself 1 km west of his starting point. How far did he ride northward initially? who can answer this question.
Answer» ong>Answer: this is answer for you Step-by-step explanation: Answer: Option B Solution(By Examveda Team) Direction SENSE Test mcq solution image The boy RODE 2 km. NORTHWARD.

31.

A boy rode his bicycle Northward, then turned left and rode 1 km and again turned left and rode 2 km. He found himself 1 km west of his starting point. How far did he ride northward initially? who can answer this question.

Answer»

ong>Answer:

this is answer for you

Step-by-step explanation:

Answer: Option B

Solution(By Examveda Team)

Direction SENSE Test mcq solution image

The boy RODE 2 km. NORTHWARD.

Discussion

32.	3) प्रत्येकी 3 सेमी. त्रिज्येची केंद्र A, B व C असणारी तीन वर्तुळे अशी काढा की प्रत्येक वर्तुळ इतर दोन वर्तुळांना स्पर्श करते.
Answer» ONG>Step-by-step EXPLANATION: hhhhyyy I have a few questions about the house and I will be there at the same time I don't KNOW if you need ANYTHING else

Discussion

33.	Solve it maths question
Answer» RONG>Your ANSWER in attachment Your answer in attachmentHopefully it HELPS u.... Your answer in attachmentHopefully it helps u....Answered by dhamija123 Your answer in attachmentHopefully it helps u....Answered by dhamija123#bebrainly

33.

Solve it maths question

Answer» RONG>Your ANSWER in attachment

Your answer in attachmentHopefully it HELPS u....

Your answer in attachmentHopefully it helps u....Answered by dhamija123

Your answer in attachmentHopefully it helps u....Answered by dhamija123#bebrainly

Discussion

34.	What should be added 7⅗ to get 18 ?
Answer» ONG>Answer: Hope it HELPS you MARK as BRAINLIST

Discussion

35.	One of the roots of a quadratic equation is 4 - 7. Find the equation
Answer» ong>Answer: is the both roots are separate or COMPLE one

35.

One of the roots of a quadratic equation is 4 - 7. Find the equation

Answer»

ong>Answer:

is the both roots are separate or COMPLE one

Discussion

36.	Make 2-column sections that have a statement and proof
Answer» ong>ANSWER: pr Step-by-step EXPLANATION: I don't KNOW whether this answer is correct or wring

36.

Make 2-column sections that have a statement and proof

Answer»

ong>ANSWER:

pr

Step-by-step EXPLANATION:

I don't KNOW whether this answer is correct or wring

Discussion

37.	Find the common difference of the sequence -8,1,10,19
Answer» ONG>Answer: 9 Step-by-step EXPLANATION:

37.

Find the common difference of the sequence -8,1,10,19

Answer» ONG>Answer:

9

Step-by-step EXPLANATION:

Discussion

38.	√a+√b Please give solution
Answer» ong>Answer: ASSUME x=√a+√B Square in both sides: x^2 = <√a+√b>^2 Expand the right hand side of the equation. That will GIVE you x^2 = a + b + 2( √ab) X will be the square ROOT of the expression on the right. I have assumed that a and b are positive whole numbers. You can check this out by substitution of values for a and b. Let's take a = 25 and b = 4. √a + √b = 7. 25+4+ 2(√100) = 49. √49 = 7

38.

√a+√b Please give solution

Answer»

ong>Answer:

ASSUME x=√a+√B

Square in both sides: x^2 = <√a+√b>^2

Expand the right hand side of the equation.

That will GIVE you x^2 = a + b + 2( √ab)

X will be the square ROOT of the expression on the right.

I have assumed that a and b are positive whole numbers.

You can check this out by substitution of values for a and b.

Let's take a = 25 and b = 4.

√a + √b = 7.

25+4+ 2(√100) = 49. √49 = 7

Discussion

39.	If AB parallel BD, angle CDf= 100° , angle ABC= 70°, find X
Answer» ONG>Step-by-step explanation: HOPE you find it HELPFUL

Discussion

40.	Prove that sec tita. root 1-sin^2tita=1
Answer» ONG>ANSWER: I HOPE you LIKE the answer

Discussion

41.	Factorise following quadratic equation 2x²+3x-90=0
Answer» ong>Answer: 2x^2 +15x-12x-90 X(2x+15)-6(2x+15) (x-6) ( 2x+15) x=6 , x= -15/2 This is the FACTORS of this EQUATION.

41.

Factorise following quadratic equation 2x²+3x-90=0

Answer»

ong>Answer:

2x^2 +15x-12x-90
X(2x+15)-6(2x+15)
(x-6) ( 2x+15)
x=6 , x= -15/2
This is the FACTORS of this EQUATION.

Discussion

42.	Please give answer of the complete table
Answer» this will HELP U a LOT

Discussion

43.	Chandni deposited a certain sum for 2 years at 8% per annum compound interest and received 6561 after two years. Find the amount she had deposited.
Answer» ><P> P = ₹ 5625 Full ANSWER is PHOTO below.

43.

Chandni deposited a certain sum for 2 years at 8% per annum compound interest and received 6561 after two years. Find the amount she had deposited.

Answer»

><P> P = ₹ 5625

Full ANSWER is PHOTO below.

Discussion

44.	A person buys a book for Rs. 85 and sells it for Rs. 98.60. Find this profit /percent
Answer» E PIC is your ANSWER

Discussion

45.	A 3 cm1. Choose the correct answer from the options given below. (2 x 1 = 2 marks)a) In Fig. 1, the lengths of the sides of the triangles are indicated. Which of thefollowing relations of congruence is true?(i) AABC = APQRR5 cm(ii) AACB AQRP3 cm4 cm5 cm( (iii) ABAC = AQPRСB(iv) AABC = AQRP4 cmFig. 1Р
Answer» ong>Answer: pls show the picture or else I can't answer Step-by-step explanation: I THINK it's HOPEFUL pls thank and MARK as BRAIN least

45.

A 3 cm1. Choose the correct answer from the options given below. (2 x 1 = 2 marks)a) In Fig. 1, the lengths of the sides of the triangles are indicated. Which of thefollowing relations of congruence is true?(i) AABC = APQRR5 cm(ii) AACB AQRP3 cm4 cm5 cm( (iii) ABAC = AQPRСB(iv) AABC = AQRP4 cmFig. 1Р

Answer»

ong>Answer:

pls show the picture or else I can't answer

Step-by-step explanation:

I THINK it's HOPEFUL pls thank and MARK as BRAIN least

Discussion

46.	What is the father of math
Answer» ONG>Answer: ARCHIMEDES is the right answer HOPE it HELPS

46.

What is the father of math

Answer» ONG>Answer:

ARCHIMEDES is the right answer HOPE it HELPS

Discussion

47.	Find the value of: cos 28 sin 62 =__________A) A) 2 B) -1 C) 0 D) 1
Answer» ONG>Answer: 0 because it's very EASY

Discussion

48.	6 tigers can catch just 6 rabbits in 6 menutis so how many tigers will be needed to catch 60 rabbits in 60 menutis
Answer» ong>Given info : 6 tigers can catch just 6 rabbits in 6 minutes. To find : the number of TIGGER will be needed to catch 60 rabbits in 60 minutes. solution : using formula, M₁D₁/W₁ = M₂D₂/W₂ where M is no of workers D is no of days/hrs/minutes/sec and W is PIECE of work here caring rabbit is CONSIDERED as work done by Tiger. so, M₁ = 6 , D₁ = 6 and W₁ = 6 M₂ = ?, D₂ = 60 and W₂ = 60 now, 6 × 6/6 = M₂ × 60/60 ⇒M₂ = 6 Therefore six tiger will be needed to catch 60 rabbits in 60 minutes. also read similar questions : There are 6 more chickens than rabbits. The number of legs is 50 more than the number of heads. How many chickens and ho... brainly.in/question/16112567 Egg + egg + egg = 30 Rabbit + duck + egg = 20 Duck + egg - Rabbit = 6 Egg + Rabbit × Duck = ? brainly.in/question/16656464

48.

6 tigers can catch just 6 rabbits in 6 menutis so how many tigers will be needed to catch 60 rabbits in 60 menutis

Answer»

ong>Given info : 6 tigers can catch just 6 rabbits in 6 minutes.

To find : the number of TIGGER will be needed to catch 60 rabbits in 60 minutes.

solution : using formula,

M₁D₁/W₁ = M₂D₂/W₂

where M is no of workers

D is no of days/hrs/minutes/sec

and W is PIECE of work

here caring rabbit is CONSIDERED as work done by Tiger.

so, M₁ = 6 , D₁ = 6 and W₁ = 6

M₂ = ?, D₂ = 60 and W₂ = 60

now, 6 × 6/6 = M₂ × 60/60

⇒M₂ = 6

Therefore six tiger will be needed to catch 60 rabbits in 60 minutes.

also read similar questions : There are 6 more chickens than rabbits. The number of legs is 50 more than the number of heads. How many chickens and ho...

brainly.in/question/16112567

Egg + egg + egg = 30

Rabbit + duck + egg = 20

Duck + egg - Rabbit = 6

Egg + Rabbit × Duck = ?

brainly.in/question/16656464

Discussion

49.	Find the value of x, if-3/-5 = x/15Please explain me.
Answer» ONG>ANSWER: Your answer is 9 Step-by-step explanation: 3/-5=x/15 45=-5x x=-45/5 x=-9 please MARK me as BRAINLIST

49.

Find the value of x, if-3/-5 = x/15Please explain me.

Answer» ONG>ANSWER:

Your answer is 9

Step-by-step explanation:

3/-5=x/15

45=-5x

x=-45/5

x=-9

please MARK me as BRAINLIST

Discussion

50.	Description of egg structure? ✎﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏I know aap bhout kam logo se baat karte but aaesa kiyudekhye mis khul ke jina sekh lijyee kiyuki Khubsurt dikhane par acha lgta hai chhupane se Khubsurt kharab hoo jata hai
Answer» ONG>Answer: chalti hai kiya 9 se 12,(◠‿◕) hehehehehe Step-by-step EXPLANATION: acha suno yr ye SAB majak THA Do not TAKE it to heart i m so sorry

50.

Description of egg structure? ✎﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏I know aap bhout kam logo se baat karte but aaesa kiyudekhye mis khul ke jina sekh lijyee kiyuki Khubsurt dikhane par acha lgta hai chhupane se Khubsurt kharab hoo jata hai

Answer» ONG>Answer:

chalti hai kiya 9 se 12,(◠‿◕)

hehehehehe

Step-by-step EXPLANATION:

acha suno yr ye SAB majak THA

Do not TAKE it to heart

i m so sorry

Discussion

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