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(b) Find the value of: sin²30' cos²45' + 4tan² 30' + sin²90°+cos³0 |
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Answer» ong>ANSWER: sin²30°cos²45°+4tan²30° + (1/2)sin²90°-2cos²90° + (1/24)cos²0°
sin²30° = (1/2)² = 1/4
cos²45° = (1/√2)² = 1/2
tan²30° = (1/√3)² = 1/3
sin²90° = 1
cos²90° = 0
cos²0° = 1
= (1/4)(1/2) + 4(1/3) + (1/2)(1) - 2*0 + (1/24)1
= 1/8 + 4/3 + 1/2 + 1/24
= (3 + 32 + 12 + 1)/24
= 48/24
= 2
sin²30°cos²45°+4tan²30° + (1/2)sin²90°-2cos²90° + (1/24)cos²0° = 2
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