Explore topic-wise InterviewSolutions in Current Affairs.

For (i) = 7/30

(II) = 0/48 = 0

Heya !!

LET other rational NUMBER be X.

Product of two rational NUMBERS = -15/7

-10/21 × X = -15/7

X = -15×21/ 7 × -10

X = (-3 × 3 ) / ( -2 )

X = 9/ 2

Other rational number = X = 9/2

Prime factorisation

(So that we can find the number to MULTIPLY to get PERFECT cube)

so the prime factors are 3 , 3 and 5

We must have triplets in the factors.If triplets are not there we should multiply the NUMBERS such as there is a PAIR of 3 and single 5 so one 3 is less from its triplet and pair of 5 is less from its triplet.

So multiply these numbers 3*5*5=75

Therefore 75 number of cuboids are necessary to form a cube.

Hope u like my process
=====================
Average runs he SCORED playing 10 INNINGS=32

Total runs he scored in 10 innings =32×10

=320
__________________________
If Average runs increases by 4.
Then,

New Average run = 32 +4 =36

So average run in 11 innings =36

Total runs in 11 innings = 36× 11 =396
_________________________
Now..

Total runs scored in NEXT innings i.e. At 11th inning = total runs after 11 innings - total runs after 10 innings.

= 396 - 320 = 76 __(answer) __

So the required runs in 11th inning is 76

_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-__

Hope this is ur required answer

Proud to help you

438+×÷3=230
438+x=690
x=690-438
x=252

Hope U LIKE my process
======================

Hope this is UR required answer

Proud to HELP you

let the number is x

so other number is 2/5x

now x + 2/5x = 70

7/5x=70

x=50

so numbers are 50 and 50*2/5 = 20

I HOPE it will HELP you...

You FORGOT to STATE the SENTENCES

₹75 we can BUY 1 LITRE.
in ₹749 we can buy=749÷75
9.8 litre

3/5 and 4/5
=(3/5+4/5)÷2
= (7/5)÷2
=7/5×1/2
=7/10
OR
3/5=0.6
4/5=0.8
06 <0.7 <0.8

ANSWER:

Step-by-step EXPLANATION:

(64)^1/6

=2^(6*1/6)

=2 is the answer

Your ANSWER of this QUESTION is

We have to do PRIME factorization of the denominator if its factors include only 2 and 5 then it is EITHER terminating decimal or NON terminating reoccurring decimal.

And if it has factors other than 2 and 5 then it is non terminating non reoccurring decimal i.e. it is IRRATIONAL number.

Hope this will HELP you....

Where is X BUDDY it is MULTIPLICATION SIGN not X buddy .

I HOPE it will HELP you

How much percent above the cost price should A shopkeeper marks his GOODS so that after allowing a discount of 20% on the Marked price he gains 12%

initial amount percentage = 100%
discount = 20%
profit = x %
profit after discount = 12%
so, total profit = 112%

112% = 100% -20% + x%
112% = 80% + x%
x% = 112% - 80%
x% = 32%

#MARK as brainliest

I HOPE it will HELP you

The organizes of aquiz COMPETITION decided that the winner in the competition will get a PRIZE of 200 rupees
so, winner get 200 rupees

let no of winner be x

participant who does not win will get a prize of 50 rupees
so, participant will get 50 rupees

total PARTICIPANTS is 120

The total prize money DISTRIBUTED is 12000 rupees
total prize = 12000

so, 200x + 120×50 = 12000
200x + 6000 = 12000
200x = 12000 - 6000
200x = 6000
x = 6000/200
x = 30

so, total no of winner is x = 30

#mark as brainliest

Ratio=748:572:616
ratio=187:143:154
ratio=17:13:14

A and B can do a piece of work in 4 days
so, A + B = 4
one day work of A and B
A + B = 1/4................(1)

A ALONE can do it in 6 days
so, A = 6
one day work of A
A = 1/6..............(2)

substitute (2) in (1)
(1/6) + B = 1/4
B = 1/4 - 1/6
B = (3-2)/12
B = 1/12
one day work of B is 1/12

so, B can FINISH whole work in 12 days

#mark as BRAINLIEST

A and B can do a piece of work in 10 days
so, A+B = 10
one day work of A and B
A+B = 1/10.............(1)

B and C can do it in 15 days
so, B + C = 15
one day work of B and C is
B+C = 1/15..............(2)

A and C can do it in 20 days
so, A+C = 20
one day work of A and C is
A+C = 1/20...........(3)

sum all three EQUATIONS (1), (2), (3)
(A+B) + (B+C) + (A+C) = (1/10)+(1+15)+(1/20)
2A + 2B + 2C = (1/5)((1/2)+(1/3)+(1/4))
2(A+B+C) = (1/5)((6+4+3)/12)
2(A+B+C) = 13/60
A+B+C = 13/120..............(4)

substitute (1) in (4)
(1/10) + C = 13/120
C = (13/120) - (1/10)
C = (13-12)/120
C = 1/120
one day work of C is 1/120

whole work DONE by C in 120 days

#mark as brainliest

Mistake in the QUESTION : represented by pi(π). say that pi(π) is an irrational number.

SOLUTION:

Circumference = π × diameter

c = πd

π = c/d

π is the ratio of the circumference of a circle to the length of the diameter.When we measure the length with the scale Or any other device we only get an approximate rational value so we may not realise that in c & d which one is irrational.So either c or d is irrational and HENCE c/d is irrational i.e π is irrational. Hence ,there is no contradiction in SAYING that π is irrational.

HOPE THIS WILL HELP YOU...

HEY, I have ATTACHED the solution to your question. KINDLY have a look over it. HOPE it helps you. ^_^

Can't ANSWER now
PLZ givee BRILLIANT and FOLLOW me

one CHAIR = Rs275

165 chairs= RS 275*165

= Rs 45375

Let The COST of Each CASSETTES be X Rs.

C.p = 130x

Gain = 5x

Gain = S.P - C.P
S.P = 135x

Profit percentage
(5x / 130x) * 100
= 3.84 Percent.

Hope it HELPS!...

14) 25x^2 - 1 + 1 + 25x^2 + 10x = 0
=> 50x^2 +10x = 0 .
=> 10x ( 5x + 1) = 0.
=> x = 0 , -1/5.
Your answer is option D.
15) 249^2 - 248^2 = (249 + 248)(249 - 248). {USING IDENTITY a^2 - b^2 = (a+b)(a-b).}
=> 497 × 1 = 497.
Your answer is option D.
16) 4x^2 + 8x + 3 = 0.
=> 4x^2 + 6x + 2x + 3 = 0. (4×3 = 12 , 6×2 = 12 6+2 = 8)
=> 2x (2x + 3) + 1 (2x + 3) = 0.
=> (2x+3)(2x+1).
Your answer is option B.
Hope you understood my answer. If YES then PLZ MARK me as the brainliest.

SQUARE ROOT 2 square = 2

=2+7x+5root2=0

=7x+5root2= -2

=7x= -2-5root2

=x= (-2-5root2)/7

U have to took some good SUMS
in which there is written [cbse]
and practice those sums in which you face problem

and revise it for BETTER improvement

u have to did most of the sums to increase your SPEED if you have time to do

So,

For the GLOBAL people who don't understand HINDI,

The question is,

If the number 666666666666....... is divided by 17 then what is the remainder after 64 digits

So,

This is INDEED a tricky question

But after putting in some manly hours you will realize that the number after 16 digits will perish

That is, the number

6666.... upto 16 digits is COMPLETELY divisible by 17

So,

The remainder after 16 digits will be zero and the quotient for the same will be,

39215686274080 will ALWAYS recur

So,

64 can be written as

16 × 4

So, digits with 666... as 

16 times

32 times 

64 times

So, the remainder for the number will be 0

I THINK your QUESTION is INCOMPLETE..

9 is the ANSWER as this is the only PERFECT SQUARE in all the OPTION.........

This ANSWER of FIRST 3

36/144 X 100
4 X 100
400
ANSWER is 400%

For 15 -- OPTION d...497
hope this will HELP U