This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Find the greatest 3 digit number which is exactly divisible by 9 15 and 18 |
|
Answer» |
|
| 2. |
In triangle ABC , DE is parallel to BC. IF AD=4X-3,DB=3X-1,AE=8X-7 and BC=5X-3, then find the values of x |
| Answer» SHOW the DIAGRAM PLZ | |
| 3. |
Diameter of a car wheel is 49cm . find how many turns will it take to cover a distance of 3080 cm. |
|
Answer» DIAMETER of wheel = 49 cm Radius = 49 /2 cm Circumference of wheel = 2 PI r = 2 × 22 × 49 / 7 × 2 = 22 × 7 = 154 cm Distance covered = 3080 cm Number of TURNS = Distance travelled / Circumference of wheel = 3080 / 154 = 20 |
|
| 4. |
If 2 triangles are equiangular prove that the ratio of their corresponding sides is equal to the ratio of their corresponding medians |
|
Answer» It is because if we DIVIDE both of them into to making them RIGHT angle triangles so the median ANG |
|
| 5. |
How to find how to find CP and SP in shortcut |
|
Answer» COST price=sp-cp selling price=cp+profit |
|
| 6. |
This year mr. Chatwal's apple orchard gave a bumper crop of 25 percent more than last year. If this year's crop is 90000kg what was the amount of apples he had last year |
|
Answer» so, This year crop - last year crop = 25% of x 90000 - x = 25x/100 90000 = 25x/100 + x 90000 = 125x/100 x = 9000000/125 x = 72000 So last year YIELD was 72000 kg |
|
| 9. |
The value of sin36∘sin72∘sin108∘sin144∘ is equal to |
|
Answer» => sin 36 * sin 72 * sin 108 * sin 144 => sin 36 * sin 72 * sin (180 - 72) * sin (180 - 36) => sin 36 * sin 72 * sin 72 * sin 36 => [sin 36 * sin 72]² =>¼ [ 2sin 36 * sin 72]² =>¼ [ COS 36 - cos 108]² 2sin(A)*sin(B) = [cos(A-B) - cos(A+B)] =>¼ [ cos 36 + sin 18]² ; cos(108) = cos(90+18) = -sin(18)] =>¼ [ (√5 + 1)/4 + (√5 - 1)/4]² ; PUT cos 36 = (√5 + 1)/4 and sin 18 = (√5 - 1)/4 =>¼ [ √5/2 ]² => 5/16 |
|
| 10. |
Do the points lie in the same quadrant (6,-6)and (-6,6) |
|
Answer» No... (6,-6) will LIE in 4 th QUAD.. ND (-6,6) will lie in 2ND quad.. |
|
| 11. |
Find the cube root of 4096 and method |
|
Answer» 2 4096 2 2048 2 1024 2 512 2 256 2 128 2 64 2 32 2 16 2 8 2 4 2 2 1 4096= 16 |
|
| 12. |
Using diviion method find the H C F of 144 and 292 ._________ |
|
Answer» Firstly find factors of these TWO numbers |
|
| 13. |
In a school there are 135 students in class 5 and 165 students in class 6. A teacher wants to form groups consisting of equal number of students of the same class. Find the least number of groups that can be formed by the students of the two classes and the number of students in each group. |
| Answer» | |
| 14. |
(√11−√7)(√11+√7) Simplify the given expressions. |
|
Answer» HEY ✋ there your ANSWER is________ = = = = Hope it is CORRECT and HELPS U.....!!! |
|
| 15. |
Rs 156250 for 3/2 years at 8% p.a. compounded half yearly |
|
Answer» The SOLUTION is in the PICTURE ATTACHED ANSWER is 19510 |
|
| 16. |
in measuring the height of Somnath the error percent is 20% if somnaths original height is 152cm what was d height of Somnath on d formation of error |
|
Answer» 182.4 will be the ANSWER |
|
| 18. |
Draw the graph of each of the following: (i) X = −2 ; (ii) 2y + 5 = 0 |
|
Answer» Ans of ii ....hope it is help full..USE X and y AXES of RED pen ..not of PENCIL.. |
|
| 20. |
ABCD is a trapezium in which AB parallel DC DC=30cm and AB=50cm. If X and Y are respectively the mid point of AD and BC then prove that area(DCYX)=7/9area(XYBA). |
| Answer» | |
| 23. |
Find the square root of 410 by estimation |
|
Answer» √410=√2×205 |
|
| 25. |
Substitution 3x-4y=15 2x+7y=9 |
|
Answer» VALUE of, y= -3/29 x= 141/841 |
|
| 26. |
A garrison of 500 men had provision for 24 day however reinforcement of 300 men arrived for how many day will the food last now |
| Answer» | |
| 28. |
Cos theta equal to 3 by 2 |
|
Answer» COS THETA = b/h ,THEREFORE b=3 and h=2 then FIND p therefore, 2^2=p^2+3^2 4=p^2+6 p^2=6-4 p=2 h=2 b=3 |
|
| 29. |
TanA/1-cotA + cotA/1-tanA = 1 + secA cosecA |
|
Answer» -------------------------------------------------- ⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆ ⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆ ✅✅ HENCE, it is proved✔✔. |
|
| 31. |
The hcf and lcm of two numbers are 37 and 2664 respectively.if one no. is 333,find the other number |
|
Answer» Other number=37×2664/333 |
|
| 32. |
Define an invertible mapping. prove that the inverse of an invertible mapping is invertible |
|
Answer» Let f:S→T be a MAPPING. Let f−1⊆T×S be the inverse of f: f−1:={(t,s):f(s)=t} Let f−1 itself be a mapping: ∀y∈T:(y,x1)∈f−1∧(y,X2)∈f−1⟹x1=x2 and ∀y∈T:∃x∈S:(y,x)∈f Then f−1 is CALLED the inverse mapping of f. Definition 2 Let f:S→T and g:T→S be mappings. Let: g∘f=IS f∘g=IT where: g∘f and f∘g denotes the composition of f with g in either order IS and IT denote the identity mappings on S and T respectively. That is, f and g are both left inverse mappings and RIGHT inverse mappings of each other. Then: g is the inverse (mapping) of f f is the inverse (mapping) of g. hope this helps you.. |
|
| 33. |
Pushpa is twice as old as rita was 2 years ago. if difference between their ages is 2 years, how old is pushpa today |
|
Answer» LET, Pushpa's age= x RITA's age= y Then, 2 years ago, Rita's age= y-2 At present, Pushpa's age= 2(y-2) THUS, x=2(y-2) ....(i) Also, x-y=2 =>x=y+2 ....(II) COMPARING (i) & (ii), 2(y-2)=y+2 =>2y-4=y+2 =>2y-y=4+2 =>y=6 Thus, x=y+2=6+2=8 => x=8 Pushpa is 8 years old. |
|
| 34. |
find the point of intersection of y axis and perpendicular bisector of line segment joining (3,6) and (-3,4). |
| Answer» | |
| 35. |
a fan is marked at rs 15600 rupees and it is available for rs 12480 find the discount given and discount% |
|
Answer» HEYA MATE, HERE IS UR ANSWER. Thanks for ASKING this question. Given that Marked Price = ₹15,600 Discount = ₹12,480 We have to find discount %. Discount % = Discount/Marked Price × 100 = 12,480/15,600×100 = 80 %. I HOPE IT HELPS U. |
|
| 36. |
What it means how many three digit number are the squares of positive integers |
|
Answer» This question is asking you that tell the NUMBER of numbers whose square is between 100 and 999. |
|
| 37. |
the number of boys and girls in class are 9:5.the number of girls is 12less then The number of boys.what is the total strength of the class. |
|
Answer» LET no. Of boys be X ,So no. of GIRLS is(x-12) |
|
| 38. |
Definition of acute angle triangle |
|
Answer» An ACUTE TRIANGLE is a triangle with all THREE ANGLES acute (LESS than 90°)......●●●●● |
|
| 39. |
There are 15525 saplings in the field. If 25 saplings are planted in a row how many rows of saplings |
|
Answer» Solution: given TOTAL no. of saplings =15525 and no. of saplings in 1 ROW =25 so therefore, required ROWS = 15525/25 |
|
| 40. |
Some one please help me....find y(y =926/21)please help! |
|
Answer» On SOLVING we will GET the EQUATION= |
|
| 41. |
The H C F of 135 and 5 is. |
|
Answer» HCF of 135 and 5 is 5 I HOPE this helps and mate Mark me as brainliest I am only 1 point AWAY |
|
| 42. |
The angle in a suplementry angle is 3a ,3a+20,2a find a |
|
Answer» 3a+3a+20+2a=180 |
|
| 43. |
X^2 - 17x-84 factorise urgent |
|
Answer» X² - 17x - 84 |
|
| 44. |
2^a=3^b=6^c prove that c=ab/a+b |
|
Answer» 2^a = K ⇒2 = K^1/a 3^b = K ⇒3 = K^1/b 6^c = K ⇒6 = K^1/c We know that: 6 = 2 * 3 ⇒ K^1/c = K^1/a * K^1/b ⇒ K^1/c = K^1/a+1/b ⇒ K^1/c = K^a+b/ab ⇒ 1/c = a+b/ab [∵ the BASES are EQUAL, equating them:] ⇒ c = ab/a+b |
|
| 45. |
How To Remember Math Identies |
|
Answer» Hey FRIEND..... |
|
| 46. |
Sita bought 2kg 299g apples and 3kg 250g magoes .gita bought 3kg 800g oranges and 4kg 150g bananas who bought more fruits?(pls get me full answer) |
|
Answer» Sita bought, APPLES = 2.299 KG, MANGOES = 3.250 kg TOTAL = 2.299 + 3.250 kg = 5.549 kg Gita bought, Oranges = 3.800 kg, Bananas = 4.150 kg, Total = 3.800 + 4.150 kg = 7.95 kg Gita bought more fruit |
|
| 48. |
By how much should 100 be decreased to get 18. 8 |
|
Answer» Here is your ANSWER.... |
|
| 49. |
1 is .........prime.........composite. |
|
Answer» HEY MATE here is your answer. it should be NEITHER PRIME nor composite. hope it HELPS you. ^_^ |
|
| 50. |
If the coefficient of x is zero in a quadratic polynomial then prove that the zeroes will be the equal in magnitude and opposite in sign |
|
Answer» Let the quadratic POLYNOMIAL be |
|