If x= 9+4√5 find √x+1/√x??

1.	If x= 9+4√5 find √x+1/√x??
Answer» $Given : x = 9 + 4\sqrt{5}$ $= > \sqrt{x} = \sqrt{9 + 4\sqrt{5}}$ $= > \sqrt{x} = \sqrt{(\sqrt{5})^2 + 2^2 + 2 * 2 * \sqrt{5}}$ $= > \sqrt{x} = \sqrt{(\sqrt{5} + 2)^2}$ $= > \sqrt{x} = \sqrt{5} + 2$ Now, $= > \frac{1}{\sqrt{5} + 2} * \frac{\sqrt{5} - 2}{\sqrt{5} - 2}$ $= > \frac{\sqrt{5} - 2}{5 - 4}$ $= > \sqrt{5} - 2$ THEREFORE: $= > \sqrt{x} + \frac{1}{\sqrt{x}} = (\sqrt{5} + 2) + (\sqrt{5} - 2)$ $= > 2\sqrt{5}$ HOPE this HELPS!

Answer»

$Given : x = 9 + 4\sqrt{5}$