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37x3=37x43x-3

111=-4773

Hey mate! here's your answer!

√3*√3
= √(3*3)
= √9
= 3

HENCE, we know that 3 is a RATIONAL NUMBER!
hope it was HELPFUL!✌️✌️

-3/26 HOPE it HELPS you

The minimum VALUE to put for p(X) is x=+1

Hope u like the ANS.. Plse MARK me as brainlist

I THINK it will help you
y=2x+6
PUT y=0
than x=-3
and again put x=0
than y = -6
now points coordinate and draw straight line on the coordinate U will get polynomial GRAPH

(a + b + C)(a2 + B2 + c2 - ab - bc - ca ) 
put the VALUE and SOLVE it

Put the VALUES at the PLACE of x and y and develop the equation N solve both the equation by any method put both values as RATIO n get the ans......

LET CP = x

1500 - x = 3 (x - 900)

1500 - x = 3x - 2700

4x = 4200

x = 1050

Profit = 20%

SP = 120/100 * 1050

= 1260

1*1+2*2+2*1*2*3

1+4+12

17

5.23 will be the ANSWER
1/3+(6÷4+2/3)+5÷9+(7÷4+4÷9)
0.33+(1.5+0.66)+0.55+(1.75+0.44)
0.33+2.16+0.55+2.19
5.23

Leat us assume a and b are the working "capacity " or "efficiency" of P and Q respectively .
Let 'W' denote that WORK which is done by P in 18 DAYS and by Q in 15 days .
So
W= a*18. ------(1)
W= b*15 -------(2)
so a & b are related as :: 15 *b=18*a
now ,since q worked for 10 days so
-------. b*10= x. (let us assume)
so W-x= a*? and we have to find "?"
so put W=15 *b and x =10*b and a=(15/18)*b in above equation and you will get:

15*b - 10*b= (15/18)*b. * "?"

so "?" =. 6.
6 is the answer.

Given EQUATION is 2a^3 + 16b^3 - 5A - 10b.

This can be written as 

2(a^3 + 8b^3) - 5a - 10b

We know that a^3 + b^3 = (a+b)(a^2-ab+b^2)

= > 2(a + 2B)(a^2 - 2ab + 4b^2) - 5a - 10b

= > 2(a + 2b)(a^2 - 2ab + 4b^2) - 5(a + 2b)

= > (a + 2b)(2(a^2 -2ab + 4b^2) - 5)

= > (a + 2b)(2a^2 - 4ab + 8b^2 - 5)

Therefore the equation can be factorized as (a + 2b)(2a^2 - 4ab + 8b^2 - 5).

Here , any DIGIT is not UNDERLINED.

We know that, angles OPPOSITE to equal SIDES of a TRIANGLE are equal.

=>
Let
By ANGLE sum property of triangle,

a + a + 90 = 180

=> 2a = 90

=> a = 45

Answer:

XY is not parallel to BC

Step-by-step EXPLANATION:

Concept:

Converse of BASIC proportionality THEOREM:

If a line divides two sides of a triangle in the same RATIO, then the line is parallel to the third side

Now,

By converse basic proportionality theorem,

XY is not parallel to BC

ANSWER:

Step-by-step EXPLANATION:

I HOPE it can HELP you and please FOLLOW me and MARKING brainleist

Fine REALLY GOOD he has CHOOSES good right
but what do u WANT with it

Solution:

________

So, the REQUIRED fraction is 4/7

_______________________________________

Any PRBLEM in UNDERSTANDING the solution, please ask in the comment BOX.

Bro answer is 280 see do the UM like that which they have given and do the division FIRST and then the brackets

15x + 4y = 61 ---(1)
4x + 15y = 72 ---(2)
Adding (1) and (2)
(15+4)x + (15+4)y = 61+72
=> 19(x+y) = 133 => x+y = 133/19 = 7--(3)
Subtracting (1) and (2)
(15-4)x + (4-15)y = 61-72
=> 11x - 11y = -11 => 11(x-y) = -11
= x-y = -11 --(4)
From (3) and (4)
x + y = 7
x - y = -11
--------------
2X = -4
=> x = -2
=> y= 7-x = 7+2 = 9

Answer:

women DENOTE WITHX

men with y

x= y+500       y=x-500

4y  +2X =46000

4( x-500) +2x =46000

4x -2000 + 2x =46000

4x +2x  =46000 +2000

6x = 48000

6x/6 = 48000/6

x = 8000

COS (PI*2 + 135)
Cos135
Cos (pi - 45)
Cos 45
1/√2

Step-by-step explanation:

Note :- I am taking q as some integer.

Let a be the positive integer.

And, b = 4 .

Then by EUCLID's division lemma,

We can write a = 4q + R ,for some integer q and 0 ≤ r < 4 .

°•° Then, POSSIBLE values of r is 0, 1, 2, 3 .

Taking r = 0 .

a = 4q .

Taking r = 1 .

a = 4q + 1 .

Taking r = 2

a = 4q + 2 .

Taking r = 3 .

a = 4q + 3 .

But a is an odd positive integer, so a can't be 4q , or 4q + 2 [ As these are even ] .

•°• a can be of the form 4q + 1 or 4q + 3 for some integer q .

Hence , it is solved

THANKS

#BeBrainly.

12xy=74
xy=74\12
xy=74\12

Let the age of the father be x
Let the age of the son be y
After 5 YEARS FATHERS age will be 5+x
After 5 years sons age will be 5+y
Now,
(5+x)= 3(5+y)-----1
X-y= 7(y-5)------2
Solve 1 and 2
5+8y-35=15+3y
5y=50
Y=10
And x=40
Fathers present age = 40 years
Sons present age = 10 years

Hope this helps
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Are U SURE that the QUES is COMPLETE

Given,
RAY OS stand on a LINE POQ
Ray OR bisector of angle POS
Ray OT bisector of angle SOQ
Angle POS=x

by linear PAIR
angle POS+angle SOQ=180°
x+angle SOQ=180°
Angle SOQ=180°-x

Ray OR bisector of angle POS-
Angle POR+Angle ROS= Angle POS
2anglePOR=Angle POS(Angle POR=Angle ROS)
2angle POR=x
angle POR=x/2

Ray OT bisector of angle SOQ
Angle SOT+Angle TOQ=angle SOQ
2angle SOT=180°-x(angle SOT=angle TOQ)
angle SOT=(180°-x)/2
=90°-x/2
angle ROS+angle SOT=angle ROT
x/2+90°-x/2=angle ROT
90°=angle ROT
ANSWER

2000000000000000000002 should be the ANSWER....

Initial COST PRICE be x

A bucket was SOLD at a loss of 8 %
so, loss = x - 8% of x = 100%x - 8%x = 92%x

Had it been sold for rupees 56 more , there would have been a gain of 12%
92%x + 56 = x + 12% of x
92%x + 56 = 100%x + 12%x
92%x + 56 = 112%x
56 = 112%x - 92%
20%x = 56
20x/100 = 56
20x = 5600
x = 5600/20
x = 280

so intial cost price be x = 280

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Solution :

Q. (998)³ = (1000 - 2)³

Using IDENTITY: (a - b)³ = a³ - b³ - 3ab (a-b)

= (1000)³ - (2)³ - 3(1000) (2) (1000 - 2)

= 1000000000 - 8 - 6000(998)

= 1000000000 - 8 - 5988000

= 1000000000 - 5988008

= 994011992

___________________________________

Any problem in UNDERSTANDING the solution, please feel free to ask in the COMMENTS section.

Diameter=18.2
Radius=9.1

Perimeter of SEMICIRCLE= PI*R
=>9.1×22/7
=>1.3x22
=>28.6 ANS.

104= 2×2×2×13 =2^3×13
4096= 2×2×2×2×2×2×2×2×2×2×2×2 =2^12
315=5×3×3×7=5×7×3^2


HCF(104,4096 and 315)=PRODUCT of smallest power of each COMMON factor.
=>1

LCM(104,4096 and 315)=Product of GREATEST power of each factor.
=>2^12×13×5×7×3^2
=>1,67,73,120 Ans.

(2X-y+3Z)(4x²+y²+9z²+2xy+3yz-6xz)
(2x-y+3z)((2x)²+(y)²+(3z)²-(-y*2x)-(-y*3z)-(2x*3z)
(2x)³+(-y)³+(3z)³-(3×-y×2x×3z) [ ∵(a+b+c)(a²+b²+c²-ab-bc-ca)= a³+b³+c³-3abc]
8³-y³+27+³+18xyz ANS.

2) 3Ans.
3).54
4).2,029
5)4/5
6).5/2 and-5/2
7) 0
8. b = 1/4
9).0
10). 0, -2 and 3
11).x+(1/3)
12).b/a
13). i,ii,iv,V and ix
14)i. x^27+x^6
ii.1x^0=1
iii.x^7
iv.x
v.x^10+x^9+x^8
VI.x^20+x^10+x^5


15.iv ------constant
i,vi,vii and viii are----LINEAR
ii and iii are quadratic
v is cubic

I.SUM of ANGLES of a triangle is equals to180°
ii.sum of two comlementary angles is 90°
iii.if two lines are parallel then the corresponding angles FORMED by the transversal are congruent.
iv.A number is divisible by 3 if the sum of DIGIT is divisible by 3.

Here is your QUE's ANWER DEAR.

This is not a PUZZLE

This is your ANSWER MATE...

Let the first number be a

Second number = a + 3

According to QUESTION,

a + a + 3 = 95

=> 2a + 3 = 95

=> 2a = 92

=> a = 46

First number = 46

Second number = 49