Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Convert the following rational numbers into decimal form.(1) 8/13 (2) 11/7 (3) 5/16 (4) 7/9

Answer»

ANSWER:

Step-by-step explanation:

Given Convert the FOLLOWING rational numbers into decimal form.(1) 8/13 (2) 11/7 (3) 5/16 (4) 7/9

Now we need to convert these rational numbers to its decimal form. So we need to divide these numbers.

8/13 will be  13)  8 (0.615

                           0

                        ------

                           80

                           78

                      ----------

                             20

                              13

                  ---------------

                               70

                                65

                          -----------

                                  5

So we get 0.615.

2) In the same way if we divide 11/7 we get 1.571

3) So the third will be 5/16 we get 0.3125

4) Again if we divide 7/9 we get 0.777

So it is converted to decimal form.

1) 8/13 = 0.615

2)11/7 = 1.571

3)5/16 = 0.3125

4)7/9 = 0.777

2.

If a pizza is divided in 12 pieces and 8 pieces are eaten ,what is the ratio fo remaining??

Answer»

The RATIO will be 1:4

3.

Factorise 4 square + 9 b square + 9 c square + 12 ab+ 4ac + 6 bc

Answer»

Its EASY just U NEED to analize it

4.

In triangle ABC ,p and Q are the mid points of sides ab and AC respectively as shown in the figure. R and s are mid points of PC and on respectively. Prove that bq and SR bisect each other

Answer»

?tjwfmegmfmwrb
emdb.br.rh.ge.ymcwmegmeglrykrhkfmegmtmjnmh

5.

In the given figure sides QP and RQ of ∠PQR are produced to points S and T respectively. If ∠SPR=135° and ∠PQT=110°, find ∠PRQ.

Answer» ANSWER is 65°
PLEASE MARK as BRAINLIEST
6.

∆ABC right angled at B and D is the midpoint of BC .prove AC2=4AD2-3AB2

Answer» HENCE PROVED ................
7.

In the given figure, ∠X=62°, ∠XYZ=54°. In ΔXYZ If YO and ZO are the bisectors of ∠XYZ and ∠XZY respectively find ∠OZY and ∠YOZ.

Answer» YXZ +XYZ + XZY =180°

62° +54° +XZY = 180°

XZY=180°-62°-54°

XZY =64°

2OZY =64°

OZY=64°/2=32°..................(1)

in the OZY OYZ +OZY +YOZ = 180°

54°/2 +32° +YOZ = 180°

YOZ = 180°- 32° - 27°
YOZ =121°...............(2)




8.

The greatest number which divides 106 241 and 286 leaving the same remainder in each case is

Answer»

If a number 'a' and a number 'b' are DIVISIBLE by a number 'n' then, a+b and a-b is also divisible by n

=> let the number be n which DIVIDES 62, 132 and 237 leaving a reminder r

=> the REQUIRED number then becomes H.C.F of 62-r, 132-r and 237-r

=> it COULD also be the H.C.F of 
(132-r)-(62-r) and (237-r)-(132-r)

i.e. 70 and 105

=> H.C.F of 70 and 105 = 35

the required number n is 35.

9.

If E, F G and H are respectively the midpoints of the sides AB, BC, CD and AD of a parallelogram ABCD, show that ar(EFGH)=1/2ar(ABCD).

Answer»

Given that ABCD is a parallelogram .

E , F , G and H are the mid points of

the sides .

Join E , G .

Now ,

∆EFG and EBCG LIE on the same base

EG and between the same parallels

EG // BC .

Therefore ,

∆EFG = ( 1/2 ) area ( EBCG ) -------( 1 )

SIMILARLY ,

∆EHG = ( 1/2 ) Area ( EGDA ) -------( 2 )

Adding ( 1 ) and ( 2 ) , we get

∆EFG+∆EHG=(1/2)area(EBCG+(1/2)area(EGDA)

=> Area ( EFGH ) = 1/2[ area(EBCG)+(EGDA)]

Area ( EFGH ) = 1/2 Area ( ABCD )

Hence proved.

••••

10.

digits of a two digit number differ by 7 if the digits are interchanged and the resulting number is added to the original number we get 121 find the original number

Answer» PLS FOLLOW me BECOZ I have answered UR question
11.

Can converse of bpt can be use?

Answer»

Yes my friend we can USE CONVERSE of B.P.T THEOREM. Take the answer. I have answered your question so pls FOLLOW me

12.

A shopkeeper offers 10% off season discount to the customers and still makes a profit of 26% what is the cost price for the shopkeeper of a pair of shoes marked at rupees 1120

Answer»

Given,

D% = 10% on MP

P% = 26%

MP = RS 1120


Now,

SP = MP-MP*D%/100

SP = 1120 - (1120*10)/100

SP = 1120 - 112

SP = Rs. 1008


And, P% = 26%

CP = SP*100/(100+26)

CP = 1008*100/126

CP = Rs. 800


Is that the right answer?

13.

All red face cards are removed from a pack of playing cards.The remaining cards are well shuffled and then a card is drawn at random from them . Find the probability that the card drawn is a card of clubs.

Answer»

Answer:

Probability that the card drawn is a card of clubs  =  13/46

Step-by-step explanation:

There are 12 face cards in TOTAL in PACK of 52 cards.

The total NUMBER of red face cards  =  6

When all red face cards are removed from a pack of playing cards, the

remaining cards  =  52 - 6

                            =  46

In remaining 46 cards , total card of clubs  = 13

Thus, the probability that the card drawn is a card of clubs =  A/B

where, A  =  total card of clubs in remaining cards

            B  =  total remaining cards in the pack

=> probability that the card drawn is a card of clubs  =  13/46

14.

Quadrilateral BEST with BE=2.9cm,ES=3.2cm,ST=2.7 cm , BT=3.4 cm and angle B=75degree

Answer» DRAW a LINE BE=2.9cm . CONSTRUCT angle B =75 degree. draw an arc of 3.4cm as T from B.from E draw arc of 3.2cm and from T draw an arc of 2.7cm as S . done
15.

Quadrilateral PQRS PQ = 4.2 cm, QR = 3 cm, PS = 2.8 cm, PR = 4.5 cm andQS = 5 cm.

Answer» HEYA..

Here is your ANSWER...
16.

Quadrilateral HELP with HE =6 cm,EL=4.5cm,

Answer» PLEASE COMPLETE the QUESTION
17.

if a and b are two positive integer such that the least prime factor of a is 3 and the least prime factor of b is 5 then calculate the least prime factor of (a+b)

Answer»

Given thet a and B are two POSITIVE integers.

a is 3 least prime factor.

b is 5 least prime factor.

_-_-_-_-_-_-_-_-_-_-_-_-_-_

SINCE least prime factor of a is 3, it implies that 'a' is an ODD number

similary b is also a odd number.

Now,

it is known that sum of two odd numbers is an even number.

HENCE,

(a+b) will be an even number.

so

least prime factor of (a+b) is

=> a+b = 2
_________[ANSWER]

DEVIL_KING ▄︻̷̿┻̿═━一

18.

Given an=4 d=2 sn=-14 finad na and a

Answer»

The VALUE of N is 7
and
value of a is -8
hope this HELPS you...

19.

Find each of the following products 5) (-15)×0×(-18)

Answer»

The ANSWER is 0

It`s because if we MULTIPLY any no. with 0 then the answer will ALWAYS be 0

OK BRO.


20.

Write all postulates of Euclid

Answer»

1.A STRAIGHT line MAY be drawn between any two points.
2.A piece of straight line may be extended indefinitely.
3.A circle may be drawn with any GIVEN radius and an arbitrary center.
4.All right angles are equal.
5.If a straight line CROSSING two straight lines MAKES the interior angles on the same side less than two right angles, the two straight lines, if extended indefinitely, meet on that side on which are the angles less than the two right angles.

21.

Given a=8 an=62 sn=210 find n and d

Answer»

Hey mate your answer is in IMAGE and FIRST you use the FORMULA of Sn=n/2(a+an) and you GET n=6 then you use the formula of an =a+(n-1)d then you get d=54/5.

22.

Given d=5 s9=75 find a and a9

Answer»

Hope u like my process
=====================
Formula to be used
=-=-=-=-=-=-=-=-=-=-=-
SN =
\frac{n}{2} (2a + (n - 1)d)
An = a + (n-1)d
__________________

d = 5

S9 = 75
= \frac{9}{2} (2 a + (9- 1)5) \\ \\ or. \: \: 75 = \frac{9}{2} (2a + 8 \times 5) \\ \\ or. \: \: 75 = \frac{9}{2} \times 2 (a + 20) \\ \\ or. \: \: 75 = 9a + 180 \\ \\ or. \: \: 9a = 75 - 180 \\ \\ or. \: \: a = - \frac{105}{9} = - \frac{35}{3} \\ \\ or. \: \: a = - 11.66

A9 = a +( n-1)d

\: \: \: \: = - \frac{35}{3} + (9 - 1)5 \\ \\ \: \: \: \: = - \frac{35}{3} + 40 \\ \\ \: \: \: \: = \frac{120 - 35}{3} = \frac{85}{3}

Hope this is ur required answer
PROUD to help you

23.

Do no. iiSolve for x

Answer»

We know that,
log a - log B = log(a/b)
Now,
log(X+4)-log(x-4)=log2
=>log[(x+4)/(x-4)]=log2
=>(x+4)/(x-4)=2
=>x+4=2(x-4)
=>x+4=2x-8
=>x-2x=-8-4
=>-x= -12
=>x=12
Hence,the value of x=12

24.

Find the height of the cylinder whose volume is 1.54m and diameter of the base is 140 cm

Answer»
radius =  \frac{140}{2}  = 70 \\ volume = \pi \times  {r}^{2}   \times h = 1.54 {m}^{3}   \\  = 15400 {cm}^{3} \\ h =  \frac{15400}{\pi \times  {70}^{2} }  = 1 \: cm
25.

What will be the unit digit of the square of the following number 1234

Answer»

1234*1234=15,22,756

So your ANSWER is 6

26.

Please solve it fast it is very urgent

Answer» CONSIDER an isosceles triangle ABC having AD as the median and AB = AC.

Given AD is the median.

⇒ BD = DC

In Δ ABD and Δ ADC, we have

AB = AC

BD = DC

and AD = AD

Therefore, Δ ABD Δ ADC  [SSS property]

⇒ ∠1 = ∠2  [cpct] 

HENCE, the median from the vertex of an isosceles triangle is the bisector of the vertical ANGLE.

27.

A hemispherical bowl has diameter 9 cm. The liquid is poured into cylindrical bottles of diameter 3 cm. and height 3 cm. If a full bowl of liquid is filled in the bottles, find how many bottles are required.

Answer»

GIVEN : For HEMISPHERE:

Diameter = 9cm

Radius (R)= 9/2 = 4.5 cm

For cylinder :

Diameter = 3 cm

Radius (r)=3/2 = 1.5 cm

Height (h)=3cm

Let the no. of Cylindrical bottles = x

ATQ

VOLUME of hemisphere = Volume of cylinder × x

No. of Cylindrical bottles =Volume of hemisphere/Volume of cylinder

No. of Cylindrical bottles = 2/3πR³ / πr²h

No. of Cylindrical bottles = 2/3π(4.5)³ /π(1.5)² × 3

No. of Cylindrical bottles = 2/3× (4.5)³ / (1.5)² X 3

x = 2× 1.5 × 4.5 × 4.5 / 1.5 × 1.5 × 3

x = 2 × 4.5 = 9

x= 9

Hence, the no. of Cylindrical bottles required = 9.


HOPE THIS WILL HELP YOU...


28.

Find the area in rectangular metres of a piece of cloth 1m 25cm wide and 4m long

Answer»

Hey!!

Let the length of cloth be 4 m

& the BREADTH ( wide ) of cloth = 1 m 25 cm = 1.25 m

( we have to CONVERT in metre )

A / q Area of cloth = l × B

=> 4 × 1.25 m^2

=> 5 m^2 >>>> Answer

☆ Hope it will helps you ☆

29.

The height of a tent is 9 m. Its base diameter is 24 m. What is its slant height? Find the cost of canvas cloth required if it costs Rs.14 per sq.m.

Answer»

Heya !!






HEIGHT of TENT ( H ) = 9 m



Diameter ( D ) = 24 m




Radius ( R ) = D/2 = 12 m







Therefore,


Slant height ( L ) = ✓(R)² + (H)²




=> ✓(12)² + (9)²



=> ✓144 + 81


=> ✓225



=> 15 m.





CANVAS required for making the tent = CSA of tent = πRL




=> 22/ 7 × 12 × 15




=> ( 22 × 12 × 15 ) / 7



=> 3960/7



=> 565.714 m².






Cost of 1 m canvas= 14

Therefore,



Cost of 565.14 m canvas = 14 × 565.714 = RS 7919.996

30.

The average weight of a group of 53 girls was calculated as 58 kg.it was later discovered that the weight of one of the girls was read as 65 kg, whereas her actual weoght was 45 kg.what is the actual average weight of the group of 53 girls

Answer»

Here is UR answer

No . of GIRLS =53

Average weight =58 kg

Total weight =53×58 kg
=3074kg

Wrong weight of the GIRL =65

ACTUAL weight of the girl =45

Extra weight of the girl =65-45 kg
=20kg

so we subtract 20 kg from the total weight of all girls

=3074kg-20kg
=3054kg

Now,

Average weight =3054 ÷53kg

=57.6 kg

Thus , the average weight is 57.6 kg

Hope it HELPS and mark it brainliest

31.

31+(-23)-35+18-4-(-3)

Answer»

HELLO MATE ☺
___________________________⭐⭐⭐
⏩ 31 + (-23) -35+18-4-(-3)
=> 31 - 23 - 35 + 18 - 4 + 3
=> 8 - 17 - 1
=> 8 - 18
=> -10✔
__________________________⭐⭐⭐
HOPE IT HELPS U✌✌
^_^

32.

Solve 12×13×7 by nikhilam sutra. please do it quickly

Answer» BASE 10
12. +2
13. +3
7. -3
12+3-3. / (2 x 3 ) + ( 3x3) + ( 2 x -3 ) / 2x3x-3
12. / 6. + 9 . + -6. / -18
12. / 15-6 / . -18
12. - 2 / 9. / 20-18
10 / 9 / 2

1092 ans
33.

the base and hypotenuse of a right angled triangle are respectively 5cm, and 13cm long. find its area. By herons formula

Answer»

By PHYTHAGORAS theorem
5^2 + x^2 =13^2
on solving , remaining SIDE =12cm
applying HERON's formula.
area = √{s(s-a)(s-b)(s-c)}
s=(5+12+13)/2=15
so area=√15*10*3*2
=√3*5*5*2*3*2
=√3*3*5*5*2*2
=3*5*2
=30cm^2

34.

In the adjacent figure, if ∠1=∠3,∠2 =∠4 and ∠3=∠4, write the relation between∠1 and ∠2 using an Euclid’s postulate.

Answer»

∠1= ∠3= ∠4 =∠2
∠1= ∠2

Postulate:THINGS EQUALS to same things are EQUAL to ONE ANOTHER.

35.

In the given figure if line segments PQ and RS intersect at point T, such that ∠PRT=40°, ∠RPT=95° and ∠TSQ=75°, find ∠SQT.

Answer»

Here is your answer
And the REASON of both equations are same as the sum of TWO ANGLE of TRIANGLE is equals to the EXTERIOR angle.

36.

cost of one dozen oranges is rupees 45 A)find the cost of one score oranges B) how many oranges can purchase for rupees 60

Answer»

Hi There!


_________________________________________


One Dozen = 12 units


Now, 1 Dozen of Oranges = 45 rupees


Means, 12 Oranges = 45 rupees


By, UNITARY Method, we have


12*x = 45


x = 45/12


x = 3.75


Means, Cost Of 1 Orange is RS. 3.75


Now, For 1 score of Oranges i.e 20 oranges = 3.75*20 = Rs. 75


B) TOTAL Rs. With us = 60


1 Orange = Rs. 3.75


x Oranges = Rs. 60


Rs. 60 = (3.75)x


Rs. 60 / 3.75 = x


16 = x


Therefore, We Will Get 16 Oranges For Rs. 60


____________________________________________


Thanks!


Hope This Helps!


#Ben4Brainly



37.

Which ratio is greater in 6:11 or 9:14

Answer»

Convert them into fractions.


\frac{6}{11} , \frac{9}{14}


Let's cross multiply.


6 x 14 , 9 x 11


84 , 99



84 < 99


6 x 14 < 9 x 11


\frac{6}{11} < \frac{9}{14}


6 : 11 < 9 : 14


Hope this MAY be helpful.


Please mark my ANSWER as the BRAINLIEST if this may be helpful.


Thank you. Have a nice day.

38.

Identify the variation and solve. It takes 5 hours to travel from one town to the other if speed of the bus is 48 km/hr. If the speed of the bus is reduced by 8 km/hr, how much time will it take for the same travel?

Answer»

I HOPE it will HELP you

39.

Integrate sin2x . cos 3x .dx

Answer» HELLO! ! !

HEY my dear friend here is your ANSWER ___________

I have given your answer in above pic.

check it out....

_________________

HOPE THIS ANSWER WILL HELP U....

@Neha
40.

X+1/x=2 then x10+1/x10=

Answer»

X+1/x=2
Then
(x+1/x)^2=2^2
x^2+2×x×1/x+1/x^2=4
x^2+2+1/x^2=4
x^2+1/x^2=2
x+1/x=x^2+1/x^2
That MEANS x=1.
10x+1/10x=2

41.

739×99-(-739) in distributive property

Answer» 739×99-(-739)
=739×99-739×(-1)
=739×(99-(-1))
=739×(99+1)
=739×100
=73900
42.

Express the HCF of 48 and 18 as a linear combination

Answer»

Answer:

Step-by-step explanation:

According to the QUESTION

A=bq +r ,

48= 18x2+12

18=12x1+6

12=6x2+0

Therefore the HCF can be (18,68)

That is =6

6=-18-12x1

6= 18- (48-18x12)

6= 18-48x1+18x2

6=18x3-48x1

:6=18x3+48X(-1)

Therefore......,............6=18x+18y

6=13x3 +48x(-1)

That is 18 x3+48(-1)+18x48-18x48

6=18x+48

____________________________________________________________

Hope it helps

43.

1) In a caravan, in addition to 50 hens there are 45 goats and 8 camels with some keepers. If the total number of feet be 224 more than the number of heads, find the number of keepers.2) In a family, the father took 1/4 of the cake and he had 3 times as much as each of the other members had. The total number of family members are?

Answer» 1)Let the number of keepers be x.
Then, total number of feet = 2*50+4*45+4*8+2x
= 2x + 312
Total number of heads = 50+45+8+x = 103 + x
Now, (2x+312) = (103+x)+224 
=> x = 15
2)Let the family members b x.

Father ate 1/4 of the cake; 
Rest members GOT 3/4X,
the father had 3 times more than other members share i.e 3/4,
Now, 
3(3/4x) = 1/4,
3/4x = 1/12,
36 = 4x,
X = 9,
9 + 1(father) = 10 total family member.
44.

If a1,a2,a3,..........are in ap such that a1+a5+a10+a15+a20+a24=225, then a1+a2+a3+..........a23+a24 is

Answer»

A1 + a5 + a10 +a15 + a20 + A24  = 225        (given)

(a1+a24) + (a5+a20) + (a10+a15) = 225            .................1

let first term is a & COMMON difference is d then

 a1 = a       ,  a24 = a+23d   ,       a1+a24 = 2a+23d            ..........2

 

 a5 = a+4d ,  a20 = a+19d ,         a5+a20 = 2a+23d           ..............3

 

 a10 = a+9d , a15 = a+14d ,        a10+a15 = 2a+23d          ..............4

putting 2 , 3 , 4 in eq 1 we get

3(2a+23d) = 225

 2a+23d = 75             ...........5

now , a1 + a2 + a3 ............a24 = S24

   S24 = 24/2[2a+(24-10d)]

          =12(2a+23d)             ...............6

from 5 & 6

S24 = 12*75 = 900

45.

Sin.sin 38+cos.cos38=

Answer»

Sin² 38° + COS ² 38° = 1 will be the ANSWER
{sin²thita + cos ² THITA = 1}

46.

Find the smallest number of 4digit which divisible by 18,24,32

Answer»

You SEE that 18,24,32 have 2 as a COMMON factor so you could find the smallest 4DIGIT number divisible by 2

47.

Help me plsThis is very hard

Answer»

Don't be CONFUSED
HOPE it is HELPFUL for you

48.

find the greatest 5 digit number which when divided by 5 10 15 20 and 25 leaves a remainder 4 in each case

Answer» 5,10,15,20,25 all have HCF 5 so you find a 4digit which LEAVE 4 when divided by 5
49.

Samikaran x square - 3 under root x + 2 equal to zero

Answer» ROOT3(+_)5i/2will be the CORRECT ANSWER acording to me..
50.

If the sum of measure of angles in a figure is 180 degree then the figure is a triangle converse form

Answer» SUM of ANGLES of a TRIANGLE is EQUALS to 180°.