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Express the HCF of 48 and 18 as a linear combination |
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Answer» Answer: Step-by-step explanation: According to the QUESTION A=bq +r , 48= 18x2+12 18=12x1+6 12=6x2+0 Therefore the HCF can be (18,68) That is =6 6=-18-12x1 6= 18- (48-18x12) 6= 18-48x1+18x2 6=18x3-48x1 Therefore......,............6=18x+18y 6=13x3 +48x(-1) That is 18 x3+48(-1)+18x48-18x48 6=18x+48 ____________________________________________________________ Hope it helps |
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