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Please solve it fast it is very urgent |
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Answer» CONSIDER an isosceles triangle ABC having AD as the median and AB = AC. Given AD is the median. ⇒ BD = DC In Δ ABD and Δ ADC, we have AB = AC BD = DC and AD = AD Therefore, Δ ABD Δ ADC [SSS property] ⇒ ∠1 = ∠2 [cpct] HENCE, the median from the vertex of an isosceles triangle is the bisector of the vertical ANGLE. |
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