332354 + Interview Questions in Secondary School in Math

1.	The minute hand of a circular clock is 15 cm long. How far does the tip of the minutehand move in 1 hour. (Take It = 3.14)
Answer» The length of the minute HAND denotes the radius of the circle it MOVE through... HENCE, The Radius of the Circle formed by minute hand: $2\pi \: r$ $= 2 \times 3.14 \times 15$ $= 94.2$ In ONE HOUR, It completes one revolution. So, *The* *minute* *hand* *moves* 94.2 cm in *one* *hour. With* Regards from Venom...

1.

The minute hand of a circular clock is 15 cm long. How far does the tip of the minutehand move in 1 hour. (Take It = 3.14)

Answer»

The length of the minute HAND denotes the radius of the circle it MOVE through...

HENCE,

The Radius of the Circle formed by minute hand:

$2\pi \: r$

$= 2 \times 3.14 \times 15$

$= 94.2$

In ONE HOUR, It completes one revolution. So,

The minute hand moves 94.2 cm in one hour.

With Regards from Venom...

Discussion

2.	4) Find the 15th term of the following A.P. 9,4,-1,-6, .........
Answer» ANSWER: $I \: think \: 66$ Step-by-step EXPLANATION: because RANGE is about 5 and we find 15TH term 》15×5 》75 starting with 9 So, 75-9 》66

2.

4) Find the 15th term of the following A.P. 9,4,-1,-6, .........

Answer»

ANSWER:

$I \: think \: 66$

Step-by-step EXPLANATION:

because RANGE is about 5 and we find 15TH term

》15×5

》75

starting with 9

So, 75-9

》66

Discussion

3.	Derivative of log x
Answer» ANSWER: We know that the base of ln(x) is e, so we plug e in for a in the derivative formula to get that the derivative... formula of ln(x) is 1 / x(ln(e)). Now, recall that we SAID the logarithm loga (x) is equal to the NUMBER we raise a to get x. Therefore,...... ln(e) ... .is equal to the number we raise e to in order to get ...... or.... PROOF: the derivative of ln(x) is 1/x. Proving that the derivative of ln(x) is 1/x by using the definition of the derivative as a limit, the PROPERTIES of logarithms, and the definition of as a limit. i hope it helpfull to you

3.

Derivative of log x

Answer»

ANSWER:

We know that the base of ln(x) is e,

so we plug e in for a in the derivative formula to get that the derivative...

formula of ln(x) is 1 / x(ln(e)).

Now, recall that we SAID the logarithm loga (x) is equal to the NUMBER we raise a to get x.

Therefore,...... ln(e) ...

.is equal to the number we raise e to in order to get

...... or....

PROOF: the derivative of ln(x) is 1/x. Proving that the derivative of ln(x) is 1/x by using the definition of the derivative as a limit, the PROPERTIES of logarithms, and the definition of as a limit.

i hope it helpfull to you

Discussion

4.	In the figure,O is the centreof the circle.ProveLAOC = LAFC + ZAEC.
Answer» HOPE it helps. THANKS my ANSWERS. MARK as brainliest.

4.

In the figure,O is the centreof the circle.ProveLAOC = LAFC + ZAEC.

Answer»

HOPE it helps.

THANKS my ANSWERS.

MARK as brainliest.

Discussion

5.	if 1 is added to both numerator and denominator of a fraction the fraction becomes 1^2 if is added to both the fraction becomes 2^3.what is the fraction
Answer» ANSWER: the FRACTION is 1/3,I cannot UNDERSTAND you QUESTION PROPERLY

5.

if 1 is added to both numerator and denominator of a fraction the fraction becomes 1^2 if is added to both the fraction becomes 2^3.what is the fraction

Answer»

ANSWER:

the FRACTION is 1/3,I cannot UNDERSTAND you QUESTION PROPERLY

Discussion

6.	If the perimeter of a semicircle is 108 cm the diameter is
Answer» ANSWER: SUBSTITUTE the VALUE in the formula pi R +2R

6.

If the perimeter of a semicircle is 108 cm the diameter is

Answer»

ANSWER:

SUBSTITUTE the VALUE in the formula

pi R +2R

Discussion

7.	35. Ifx=13 + 1213-1213 - 12 and y = 13 + 12Find the value of (x + y)2-13-213 + 12यदि x = 13-12और y =(x + y)2 का मान ज्ञात कीजिये।
Answer» ANSWER: Xun4 BINGO udita b7dy F #

7.

35. Ifx=13 + 1213-1213 - 12 and y = 13 + 12Find the value of (x + y)2-13-213 + 12यदि x = 13-12और y =(x + y)2 का मान ज्ञात कीजिये।

Answer»

ANSWER:

Xun4 BINGO udita b7dy F #

Discussion

8.	meena purchased 12m of cloth. she used 31/4 of it. for curtains and 11/6 m for a bed sheet. how much cloth is left with her?
Answer» Step-by-step EXPLANATION: I HOPE this MAY HELP you.

8.

meena purchased 12m of cloth. she used 31/4 of it. for curtains and 11/6 m for a bed sheet. how much cloth is left with her?

Answer»

Step-by-step EXPLANATION:

I HOPE this MAY HELP you.

Discussion

9.	If unit of side is metre, unit of volume ___
Answer» Answer: m³ Step-by-step EXPLANATION: if unit of side is METRE that unit of VOLUME is m³ Hope it helps

9.

If unit of side is metre, unit of volume ___

Answer»

Answer:

m³

Step-by-step EXPLANATION:

if unit of side is METRE that unit of VOLUME is m³

Hope it helps

Discussion

10.	Why e is the base of natural logarithm?
Answer» The natural LOGARITHM, or logarithm to BASE e, is the inverse function to the natural exponential function. The natural logarithm of a NUMBER k > 1 can be defined directly as the area under the curve y = 1/X between x = 1 and x = k, in which case e is the value of k for which this area equals one ................

10.

Why e is the base of natural logarithm?

Answer»

The natural LOGARITHM, or logarithm to BASE e, is the inverse function to the natural exponential function. The natural logarithm of a NUMBER k > 1 can be defined directly as the area under the curve y = 1/X between x = 1 and x = k, in which case e is the value of k for which this area equals one

................

Discussion

11.	Question 18 pl explain
Answer» Hey PRETTY Stranger! $\large \bold \red{Here \: you \: go \: !}$ $\textbf{\underline{\underline{Given:}}}$ • Perimeter of Semi-Circle is 108 CM $\textbf{\underline{\underline{To\:Find:}}}$ • DIAMETER of the circle $\textbf{\underline{\underline{Solution:}}}$ Let radius of the semi-circle be r According to the Question : $\star \sf \: \dfrac{1}{<klux>2</klux>}(2\pi \: r) + 2r = 108$ $\implies \sf \: \pi \: r + 2r = 108$ $\implies \sf \: \dfrac{22}{7} \times r + 2r = 108$ $\implies \sf \: 36 \: r = 108 \times 7$ $\implies \sf \: r = \large \boxed{ \red{ \sf \: 21 \: cm}}$ Diameter = 2 × Radius Diameter = 2 × 21 = 42 cm

11.

Question 18 pl explain

Answer»

Hey PRETTY Stranger!

$\large \bold \red{Here \: you \: go \: !}$

$\textbf{\underline{\underline{Given:}}}$

• Perimeter of Semi-Circle is 108 CM

$\textbf{\underline{\underline{To\:Find:}}}$

• DIAMETER of the circle

$\textbf{\underline{\underline{Solution:}}}$

Let radius of the semi-circle be r

According to the Question :

$\star \sf \: \dfrac{1}{<klux>2</klux>}(2\pi \: r) + 2r = 108$

$\implies \sf \: \pi \: r + 2r = 108$

$\implies \sf \: \dfrac{22}{7} \times r + 2r = 108$

$\implies \sf \: 36 \: r = 108 \times 7$

$\implies \sf \: r = \large \boxed{ \red{ \sf \: 21 \: cm}}$

Diameter = 2 × Radius

Diameter = 2 × 21 = 42 cm

Discussion

12.	Arun has a door of dimensions 2.5 X 1 and 2 Windows of dimensions 1 metre X 0.5 metre if the dimensions of the room are 6 x 5 x 10 find the cost of whitewashing the four walls and the ceiling @ 102 rupees per metre square
Answer» Answer: COST of WHITEWASH to wall and CEILING is 13614 RS

12.

Arun has a door of dimensions 2.5 X 1 and 2 Windows of dimensions 1 metre X 0.5 metre if the dimensions of the room are 6 x 5 x 10 find the cost of whitewashing the four walls and the ceiling @ 102 rupees per metre square

Answer»

Answer:

COST of WHITEWASH to wall and CEILING is 13614 RS

Discussion

13.	एक वृत्ताकार क्षेत्र का क्षेत्रफल दूसरे वृत्ताकार क्षेत्र के क्षेत्रफल का 100 गुना है। उनकी परिधियोंका अनुपात ज्ञात कीजिए।
Answer» $\color{red}\huge\bold\star\underline\mathcal{ANSWER}\star$ I HOPE IT WILL HELPS U.... plzz mark as brainlist....☺️☺️

13.

एक वृत्ताकार क्षेत्र का क्षेत्रफल दूसरे वृत्ताकार क्षेत्र के क्षेत्रफल का 100 गुना है। उनकी परिधियोंका अनुपात ज्ञात कीजिए।

Answer»

$\color{red}\huge\bold\star\underline\mathcal{ANSWER}\star$

I HOPE IT WILL HELPS U....

plzz mark as brainlist....☺️☺️

Discussion

14.	Having been punished on tuem 3EXERCISE 1Combine each set of the following Simple SentencesSentence by using a Participle :1. She went to the garden. She plucked flowers.2. I saw a ball. I picked it up.3. The servant swept the room. He went away.14. He came to me. He gave me this letter.5. The poor man worked. He laughed. He thus spent his life.6/ I was walking in the field. I saw a snake. I ran away.7. He went up the hill. He saw an old temple.8. He went home. He met his mother. He touched her feet.
Answer» Answer: 1. She went to the garden to pluck flowers 2. I saw a ball and picked it up 3. The SERVANT swept the room and went away 4. He came to me to give this letter 5. The POOR man worked , LAUGHED and just spent his life 6. I was walking in the field then I saw a snake and ran away 7. He went up to the hill and saw an old temple 8. He went home,met his mother and TOUCHED her feet

14.

Having been punished on tuem 3EXERCISE 1Combine each set of the following Simple SentencesSentence by using a Participle :1. She went to the garden. She plucked flowers.2. I saw a ball. I picked it up.3. The servant swept the room. He went away.14. He came to me. He gave me this letter.5. The poor man worked. He laughed. He thus spent his life.6/ I was walking in the field. I saw a snake. I ran away.7. He went up the hill. He saw an old temple.8. He went home. He met his mother. He touched her feet.

Answer»

Answer:

1. She went to the garden to pluck flowers

2. I saw a ball and picked it up

3. The SERVANT swept the room and went away

4. He came to me to give this letter

5. The POOR man worked , LAUGHED and just spent his life

6. I was walking in the field then I saw a snake and ran away

7. He went up to the hill and saw an old temple

8. He went home,met his mother and TOUCHED her feet

Discussion

15.	। (ख) यदि 3 cotA=4, तो sec A का मान होगा :
Answer» $\color{red}\huge\bold\star\underline\mathcal{Answer}\star$ Cot A = 4/ 3 As we know that cot or equal to base / perpendicular THEREFORE in a TRIANGLE on side will be perpendicular of 3 cm and base of 4 cm By pathagorus triplet we get hypotenuse of 5 cm Sec A = base / perpendicular Sec A = 4 / 5 I HOPE IT WILL.HELP U.... plzz MARK as brainlist....☺️

15.

। (ख) यदि 3 cotA=4, तो sec A का मान होगा :

Answer»

$\color{red}\huge\bold\star\underline\mathcal{Answer}\star$

Cot A = 4/ 3

As we know that cot or equal to base / perpendicular

THEREFORE in a TRIANGLE on side will be perpendicular of 3 cm and base of 4 cm

By pathagorus triplet we get hypotenuse of 5 cm

Sec A = base / perpendicular

Sec A = 4 / 5

I HOPE IT WILL.HELP U....

plzz MARK as brainlist....☺️

Discussion

16.	The volume of a cube _____ which side are of 1 cm
Answer» $\huge\underline\bold\color{red}\mathfrak{Answer}$ 1 cm³ is the VOLUME ✌️✌️

16.

The volume of a cube _____ which side are of 1 cm

Answer»

$\huge\underline\bold\color{red}\mathfrak{Answer}$

1 cm³ is the VOLUME ✌️✌️

Discussion

17.	Find the value of [(87+18)÷ 1/3 of 27-2x3}-38+5]
Answer» $\color{red}\huge\bold\star\underline\mathcal{Answer}\star$ I HOPE it will helps u... PLZZ mark as BRAINLIST....☺️☺️☺️

17.

Find the value of [(87+18)÷ 1/3 of 27-2x3}-38+5]

Answer»

$\color{red}\huge\bold\star\underline\mathcal{Answer}\star$

I HOPE it will helps u...

PLZZ mark as BRAINLIST....☺️☺️☺️

Discussion

18.	What will be the compound interest on 4,000 in two years when rate of interestis 5% per annum?
Answer» <P>✰ Question :- What will be the compound interest on 4,000 in two YEARS when rate of interest is 5% per annum? ✫ Formula used :- Amount = Principal * [ 1 + (Rate/100) ]^Time Compound interest = Amount - Principal. ✰ Solution :- putting all values in above formula we get, ⟼ A = 4000 * [ 1 + (5/100) ]² ⟼ A = 4000 * [ 1 + 1/20 ] ² ⟼ A = 4000 * (21/20)² ⟼ A = 4000 * 21/20 * 21/20 ⟼ A = 4410 So, ⟿ CI = A - P ⟿ CI = 4410 - 4000 ⟿ CI = RS. 410 Hence, we get, Rs.410 as compound interest.

18.

What will be the compound interest on 4,000 in two years when rate of interestis 5% per annum?

Answer»

<P>✰ Question :- What will be the compound interest on 4,000 in two YEARS when rate of interest is 5% per annum?

✫ Formula used :-

Amount = Principal * [ 1 + (Rate/100) ]^Time
Compound interest = Amount - Principal.

✰ Solution :-

putting all values in above formula we get,

⟼ A = 4000 * [ 1 + (5/100) ]²

⟼ A = 4000 * [ 1 + 1/20 ] ²

⟼ A = 4000 * (21/20)²

⟼ A = 4000 * 21/20 * 21/20

⟼ A = 4410

So,

⟿ CI = A - P

⟿ CI = 4410 - 4000

⟿ CI = RS. 410

Hence, we get, Rs.410 as compound interest.

Discussion

19.	Find remainder if (x-1) is a factor of xsquare -4x+8
Answer» ANSWER: remainder=5 Step-by-step EXPLANATION: x-1=0 x=1 x2-4x+8 (1)2-4(1)+8 1-4+8 -3+8 5

19.

Find remainder if (x-1) is a factor of xsquare -4x+8

Answer»

ANSWER:

remainder=5

Step-by-step EXPLANATION:

x-1=0

x=1

x2-4x+8

(1)2-4(1)+8

1-4+8

-3+8

5

Discussion

20.	6. Solve the given equation by the method of factorization : 2x² + √6x -6 = 0
Answer» Answer: 2x^2+√6x-6=0 2x^2+2√6x-√6x-6=0 2x(X+√6) -√6(x+√6) (x+√6) (2x-√6) x= -√6, √6/2

20.

6. Solve the given equation by the method of factorization : 2x² + √6x -6 = 0

Answer»

Answer:

2x^2+√6x-6=0

2x^2+2√6x-√6x-6=0

2x(X+√6) -√6(x+√6)

(x+√6) (2x-√6)

x= -√6, √6/2

Discussion

21.	Find A:B:C when:1) A:B = 2:5 and B:C is equal to7:9
Answer» Step-by-step EXPLANATION: A :B :C 2 : 5: 5 7 :7 : 9 MULTIPLY 2 BY 7 AND 5 BY 7 AND 5 BY 9 SO 14:35:45

21.

Find A:B:C when:1) A:B = 2:5 and B:C is equal to7:9

Answer»

Step-by-step EXPLANATION:

A :B :C

2 : 5: 5

7 :7 : 9

MULTIPLY 2 BY 7 AND 5 BY 7 AND 5 BY 9

SO 14:35:45

Discussion

22.	The square of the greater of two consecutive even number except the square of the smaller by 36 find the number.
Answer» Answer: 8 and 10 are two consecutive numbers. Step-by-step explanation: Let the greater number be x and x + 2. According to the GIVEN CONDITION , ( x )² - ( x + 2 )² = 36 x² - x² + 4X + 4 = 36 4x + 4 = 36 4x = 36 - 4 4x = 32 x = 32 ÷ 4 x = 8 x + 2 = 8 + 2 = 10. Make my answer brainliest . plz , please

22.

The square of the greater of two consecutive even number except the square of the smaller by 36 find the number.

Answer»

Answer:

8 and 10 are two consecutive numbers.

Step-by-step explanation:

Let the greater number be x and x + 2.
According to the GIVEN CONDITION ,
( x )² - ( x + 2 )² = 36
x² - x² + 4X + 4 = 36
4x + 4 = 36
4x = 36 - 4
4x = 32
x = 32 ÷ 4
x = 8
x + 2 = 8 + 2 = 10.

Make my answer brainliest .
plz , please

Discussion

23.	(8)Q.4) Solve any two from the following:In the given figure, EG = 3.5cm, GC = 10.5 cm DC = 23.1 cm, AB = 14cm.Calculate EF and AC, if ABI\|EF\|\|DC. (Calculate only up to one decimal place)Water drips from a tap at the rate of 4 drops every 3 seconds. Volume of one dropof water is 0.4 cm". The dripped water is collected in a cylindrical vessel. The outerdiameter & uniform thickness of this vessel is 10cm& lcm respectively. How manyminutes will be required to fill the vessel completely if it's height is 70 cm ?le111)A, B & C are three non-collinear points such that distance between point A andpoint B is 7 cm., distance between point B and point C is 6 cm., distance betweenpoint A and point C is 7 cm. Plot these points. Draw a circle passing through allthese points. Also draw another circle with radius 2 cm touching the first circleinternally at point
Answer» 1.When water DRIPS from a tap at the rate of 4 drops EVERY 3 seconds, volume of one drop of water is 0.4 cm^3 and the dripped water is collected in a cylindrical vessel with the outer diameter & uniform thickness of this vessel being 10cm& LCM respectively. Time required to fill the vessel completely if it's HEIGHT is 70 cm is: i.Given that the velocity of the falling drops is 4 drops per 3 seconds. ii. The volume of each drop is 0.4cm^3. iii. The volume of the vessel is {pi × (10-2)^2×70} = 3520cm^3. iv. The ratio of volume of vessel to volume of drop gives the number of drops required. v. 3520/0.4 =8800 drops are required to fill the vessel. vi. The time required to fill the vessel t =8800/velocity =6600 sec =110 min. 2. If A, B & C are three non-collinear points such that distance between point A and point B is 7 cm, distance between point B and point C is 6 cm, distance between point A and point C is 7 cm. A circle passing through all these points and another circle is drawn with RADIUS 2 cm touching the first circle internally at a point. i.Since A,B and C are noncollinear they form a triangle and also lie on a circle. ii. A circle is drawn with points A, B and C, along with another internal circle of radius 2cm.

23.

(8)Q.4) Solve any two from the following:In the given figure, EG = 3.5cm, GC = 10.5 cm DC = 23.1 cm, AB = 14cm.Calculate EF and AC, if ABI|EF||DC. (Calculate only up to one decimal place)Water drips from a tap at the rate of 4 drops every 3 seconds. Volume of one dropof water is 0.4 cm". The dripped water is collected in a cylindrical vessel. The outerdiameter & uniform thickness of this vessel is 10cm& lcm respectively. How manyminutes will be required to fill the vessel completely if it's height is 70 cm ?le111)A, B & C are three non-collinear points such that distance between point A andpoint B is 7 cm., distance between point B and point C is 6 cm., distance betweenpoint A and point C is 7 cm. Plot these points. Draw a circle passing through allthese points. Also draw another circle with radius 2 cm touching the first circleinternally at point

Answer»

1.When water DRIPS from a tap at the rate of 4 drops EVERY 3 seconds, volume of one drop

of water is 0.4 cm^3 and the dripped water is collected in a cylindrical vessel with the outer

diameter & uniform thickness of this vessel being 10cm& LCM respectively. Time required to fill the vessel completely if it's HEIGHT is 70 cm is:

i.Given that the velocity of the falling drops is 4 drops per 3 seconds.

ii. The volume of each drop is 0.4cm^3.

iii. The volume of the vessel is {pi × (10-2)^2×70} = 3520cm^3.

iv. The ratio of volume of vessel to volume of drop gives the number of drops required.

v. 3520/0.4 =8800 drops are required to fill the vessel.

vi. The time required to fill the vessel t =8800/velocity =6600 sec =110 min.

2. If A, B & C are three non-collinear points such that distance between point A and

point B is 7 cm, distance between point B and point C is 6 cm, distance between

point A and point C is 7 cm. A circle passing through all these points and another circle is drawn with RADIUS 2 cm touching the first circle

internally at a point.

i.Since A,B and C are noncollinear they form a triangle and also lie on a circle.

ii. A circle is drawn with points A, B and C, along with another internal circle of radius 2cm.

Discussion

24.	Please solve it correctly send it to me
Answer» Answer: As MODE is the value which occurs most FREQUENTLY..... It is the point of maximum FREQUENCY... THUS the mode is * 10-20 * 20-30

24.

Please solve it correctly send it to me

Answer»

Answer:

As MODE is the value which occurs most FREQUENTLY..... It is the point of maximum FREQUENCY...

THUS the mode is

* 10-20

* 20-30

Discussion

25.	Pan Noof tunInCircle the Prime numberthe lists given below.91,4884, 10,22, 16, 19
Answer» ANSWER: ONLY 19 is a PRIME NUMBER

25.

Pan Noof tunInCircle the Prime numberthe lists given below.91,4884, 10,22, 16, 19

Answer»

ANSWER:

ONLY 19 is a PRIME NUMBER

Discussion

26.	Differenciate with respect to x tan-1x)^4/3
Answer» ANSWER: $\frac{d}{dx}$ tan-1(x^{4/3} )= $\frac{1}{1+(\frac{4}{3})^2 }$ FINAL step is to SIMPLIFY the equation so we get 9/14 Step-by-step explanation:

26.

Differenciate with respect to x tan-1x)^4/3

Answer»

ANSWER:

$\frac{d}{dx}$ tan-1(x^{4/3} )= $\frac{1}{1+(\frac{4}{3})^2 }$

FINAL step is to SIMPLIFY the equation

so we get

9/14

Step-by-step explanation:

Discussion

27.	Differenciate sin-1(1-x^2)
Answer» Step-by-step explanation: SHOWS how to DIFFERENTIATE inverse SINE, cos and tan functions, ... We also WRITE: arcsin x to MEAN the same thing as sin-1 x. ... Find the derivative of y = sin-1(1 − x2 ...

27.

Differenciate sin-1(1-x^2)

Answer»

Step-by-step explanation:

SHOWS how to DIFFERENTIATE inverse SINE, cos and tan functions, ... We also WRITE: arcsin x to MEAN the same thing as sin-1 x. ... Find the derivative of y = sin-1(1 − x2 ...

Discussion

28.	5. ABC and DBC are two isosceles triangles on thesame base BC (see Fig. 7.33). Show thatangle ABD=angle ACD.
Answer» Step-by-step EXPLANATION: SIMILARITY in two TRIANGLE APPLIES KARO

28.

5. ABC and DBC are two isosceles triangles on thesame base BC (see Fig. 7.33). Show thatangle ABD=angle ACD.

Answer»

Step-by-step EXPLANATION:

SIMILARITY in two TRIANGLE APPLIES KARO

Discussion

29.	the shadow of a tower on level ground increases in length by x metres when the altitude of the sun changes from 45 to 30. calculate the value of x, given that the height of the tower is 25 metres, correct to 3 significant places
Answer» Answer: 18.301 meters Step-by-step explanation: Let ABC be the triangle where B is the right angle vertex and C is vertex forming an angle with the ground. Let BD be the new length of the shadow formed. Thus, CD = x Also, given that AB = 25m In ABC ∠ACB = 45° Thus, tan(45) = AB/BC ie. 1 = 25/BC (since tan(45) = 1) Thus, BC = 25m In ABD ∠ADB = 30° tan(30) = AB/BD 1/√3 = 25/BD ∴ BD = 25√3 Change in length of shadow = BD - BC 25√3 - 25 = x x = 25(√3-1) ∴ x = 18.301 metres

29.

the shadow of a tower on level ground increases in length by x metres when the altitude of the sun changes from 45 to 30. calculate the value of x, given that the height of the tower is 25 metres, correct to 3 significant places

Answer»

Answer:

18.301 meters

Step-by-step explanation:

Let ABC be the triangle where B is the right angle vertex and C is vertex forming an angle with the ground.

Let BD be the new length of the shadow formed.

Thus, CD = x

Also, given that AB = 25m

In ABC

∠ACB = 45°

Thus, tan(45) = AB/BC

ie. 1 = 25/BC (since tan(45) = 1)

Thus, BC = 25m

In ABD

∠ADB = 30°

tan(30) = AB/BD

1/√3 = 25/BD

∴ BD = 25√3

Change in length of shadow = BD - BC

25√3 - 25 = x

x = 25(√3-1)

∴ x = 18.301 metres

Discussion

30.	Find the difference in the place value of 8s in the number 8382 127
Answer» 7920000 is the ANSWER

Discussion

31.	Tanθ secθ+1_____ + ______ = 2cosecθsecθ+1 tanθ
Answer» ANSWER: is EQUAL to 1 I THINK it's CORRECT

31.

Tanθ secθ+1_ + __ = 2cosecθsecθ+1 tanθ

Answer»

ANSWER:

is EQUAL to 1 I THINK it's CORRECT

Discussion

32.	If cos#=35/37 then find the value sin# and tan#
Answer» COS#= 35/7 Then, SIN#= 12/37 and TAN# = 12/35

Discussion

33.	If the dimensions of a room are 2 m, 3 and 4 m then how many cubes of size 1/21/31/4 can be placed in theroom?
Answer» Answer: 576 Step-by-step EXPLANATION: I hope it HELPS you...if any PROBLEM let me know in COMMENT SECTION below!!

33.

If the dimensions of a room are 2 m, 3 and 4 m then how many cubes of size 1/21/31/4 can be placed in theroom?

Answer»

Answer:

576

Step-by-step EXPLANATION:

I hope it HELPS you...if any PROBLEM let me know in COMMENT SECTION below!!

Discussion

34.	Express 5.8 into in usual form
Answer» ANSWER: HII FRND Step-by-step EXPLANATION: UR answer is 508/10—¹¹ = - 0.0000000058

34.

Express 5.8 into in usual form

Answer»

ANSWER:

HII FRND

Step-by-step EXPLANATION:

UR answer is

508/10—¹¹

= - 0.0000000058

Discussion

35.	A cube side which is 5 CM then what is the volume of it
Answer» Answer: 125cm^3 Step-by-step EXPLANATION: VOLUME of CUBE is a^3 5×5×5 cm^3 125 cu.cm

35.

A cube side which is 5 CM then what is the volume of it

Answer»

Answer:

125cm^3

Step-by-step EXPLANATION:

VOLUME of CUBE is a^3

5×5×5 cm^3

125 cu.cm

Discussion

36.	Gerrard says. "In most melodramas, the villain is foolish enough to delay his killing long enough to be trust Does this statement hold good for the play
Answer» ANSWER: YES ! I think ACCORDING to the text the GERRARD was more smarter than the intruder .

36.

Gerrard says. "In most melodramas, the villain is foolish enough to delay his killing long enough to be trust Does this statement hold good for the play

Answer»

ANSWER:

YES ! I think ACCORDING to the text the GERRARD was more smarter than the intruder .

Discussion

37.	Volume of a cube, is 648V3 cm", then its side is.....
Answer» Step-by-step EXPLANATION: side³ = 648 so, SIDE = 8.65 CM

37.

Volume of a cube, is 648V3 cm", then its side is.....

Answer»

Step-by-step EXPLANATION:

side³ = 648

so, SIDE = 8.65 CM

Discussion

38.	Following Pie-chart shows the mode of transport used by children for comingto school. On the basis of the given Pie-chart, write a paragraph on it.
Answer» Answer: The given pie diagram represents the modes of transport used by children of age GROUP 10 to 15. Maximum NUMBER of students i.e. 50% students use school bus followed by 21% of children being picked and DROPPED by their parents to school. 17% children GO to school walking. 8% children go to school cycling and 4% by their personal motor vehicles. Pls mark as brainliest if u like the answer. TY.

38.

Following Pie-chart shows the mode of transport used by children for comingto school. On the basis of the given Pie-chart, write a paragraph on it.

Answer»

Answer:

The given pie diagram represents the modes of transport used by children of age GROUP 10 to 15.

Maximum NUMBER of students i.e. 50% students use school bus followed by 21% of children being picked and DROPPED by their parents to school.

17% children GO to school walking.

8% children go to school cycling and 4% by their personal motor vehicles.

Pls mark as brainliest if u like the answer.

TY.

Discussion

39.	Length of BC in the given figure is
Answer» ANSWER: SOLVE the sum USING tangent SEGMENT theorem

39.

Length of BC in the given figure is

Answer»

ANSWER:

SOLVE the sum USING tangent

SEGMENT theorem

Discussion

40.	cost of 1 dozen banana is 250 rupees and the cost of 10 ball pens 75 rupees find the ratio of cost of a banana to that of a ball pen
Answer» Answer: 10:3 i HOPE it MAY HELP U

40.

cost of 1 dozen banana is 250 rupees and the cost of 10 ball pens 75 rupees find the ratio of cost of a banana to that of a ball pen

Answer»

Answer:

10:3

i HOPE it MAY HELP U

Discussion

41.	If the area of two similar triangle are equal the prove that they are congruent
Answer» ANSWER: $Use the theorem that the ratio of the areas of two similar triangles is equalto the square of the ratio of their corresponding sides , then prove that they are congruent. → ∆ABC ~ ∆DEF such that ar(∆ABC) = ar( ∆DEF) . ... [ by SSS-congruency ] . Hence, it is proved. \$

41.

If the area of two similar triangle are equal the prove that they are congruent

Answer»

ANSWER:

$Use the theorem that the ratio of the areas of two similar triangles is equalto the square of the ratio of their corresponding sides , then prove that they are congruent. → ∆ABC ~ ∆DEF such that ar(∆ABC) = ar( ∆DEF) . ... [ by SSS-congruency ] . Hence, it is proved. \$

Discussion

42.	Time taken by a man traveling at 15 km/h to cover 75 km is
Answer» ANSWER: t = d/s t= 75/5 t= 5 hr hope it HELPS ^^

42.

Time taken by a man traveling at 15 km/h to cover 75 km is

Answer»

ANSWER:

t = d/s

t= 75/5

t= 5 hr

hope it HELPS ^^

Discussion

43.	8) अमर एक कार्य करना शुरू करता है, लेकिन 6 दिन बाद छोड़देता है। चेतन शेष कार्य को 8 दिन में पूरा करता है। यदि चेतनअकेले कार्य को 24 दिन में कर सकता है, तो अमर शेष कार्य पूराकरने में कितने दिन लेगा?
Answer» he *will* *not* *START* *only...as he is LAZY*

Discussion

44.	Sara say x is 2 but Mahie says x is 4. X/2=8
Answer» ANSWER: x=4 is the answer of this QUESTION

44.

Sara say x is 2 but Mahie says x is 4. X/2=8

Answer»

ANSWER:

x=4 is the answer of this QUESTION

Discussion

45.	The salary of a doctor was increased by 15%. If his present salary ist 25300, what was it beforeincrement?
Answer» $\blue{\underline {\underline {Answer\: : \: 22000. }}}$ Let his ORIGINAL Salary be $X 115% of X = 25300 X = RS [ 25300 • 100 ] /115 = Rs 22,000. $\orange {\underline {\underline {Plz \: Follow \: Me \: And \: Mark \: As \: Brainliest!!! }}}$

45.

The salary of a doctor was increased by 15%. If his present salary ist 25300, what was it beforeincrement?

Answer»

$\blue{\underline {\underline {Answer\: : \: 22000. }}}$

Let his ORIGINAL Salary be $X

115% of X = 25300

X = RS [ 25300 • 100 ] /115 = Rs 22,000.

$\orange {\underline {\underline {Plz \: Follow \: Me \: And \: Mark \: As \: Brainliest!!! }}}$

Discussion

46.	Prove that cos(x-π/3)cos(x+π/3)=cos3x/4cosx
Answer» ★ QUESTION: prove that cos(x-π/3)cos(x+π/3)=cos3x/4cosx ★ Answer : we know that ; cos ( A + B) = CosA cos B - sin A sin B and cos ( A- B ) = CosA cos B + sin A sin B then , L HS = cos(x-π/3)cos(x+π/3) = [ cos x cos π/3 + sin X sin π / 3 ] × [ cos x cos π/3 - sin X sin π / 3 ] $= (\cos(x) \times \frac{1}{2} + \sin(x) \times \frac{ \sqrt{3} }{2} ) \times ( \cos(x) \times \times \frac{1}{2} - \sin(x) \times \frac{ \sqrt{3} }{2} )$ use (A+ B ) ( A-B ) = A ² - B ² then , = [cos ² x/4 - 3sin² x / 4 ] = ( cos ² x - 3sin² x )/4 = (4COS ² x-3 )/4 now multiply and DIVIDE by cos x $= \frac{ \cos(x) }{ \cos(x) } \frac{(4 \cos {}^{2} (x) - 3)}{4}$ $= \frac{(4 \cos {}^{3} (x) - 3cosx) }{csx}$ = cos3x/4 cosx = RHS hence proved ! Follow me mark answer as brainlist

46.

Prove that cos(x-π/3)cos(x+π/3)=cos3x/4cosx

Answer»

★ QUESTION:

prove that cos(x-π/3)cos(x+π/3)=cos3x/4cosx

★ Answer :

we know that ;

cos ( A + B) = CosA cos B - sin A sin B

and

cos ( A- B ) = CosA cos B + sin A sin B

then ,

L HS = cos(x-π/3)cos(x+π/3)

= [ cos x cos π/3 + sin X sin π / 3 ] ×

[ cos x cos π/3 - sin X sin π / 3 ]

$= (\cos(x) \times \frac{1}{2} + \sin(x) \times \frac{ \sqrt{3} }{2} ) \times ( \cos(x) \times \times \frac{1}{2} - \sin(x) \times \frac{ \sqrt{3} }{2} )$

use (A+ B ) ( A-B ) = A ² - B ²

then ,

= [cos ² x/4 - 3sin² x / 4 ]

= ( cos ² x - 3sin² x )/4

= (4COS ² x-3 )/4

now multiply and DIVIDE by cos x

$= \frac{ \cos(x) }{ \cos(x) } \frac{(4 \cos {}^{2} (x) - 3)}{4}$

$= \frac{(4 \cos {}^{3} (x) - 3cosx) }{csx}$

= cos3x/4 cosx

= RHS

hence proved !

Follow me

mark answer as brainlist

Discussion

47.	Brouded thattook toAssignmentxz>kte oftheequationcircleRadicesR andCenne+20Sztuzte 2729tilan her blane
Answer» ANSWER: Step-by-step EXPLANATION: brouded that took to Assignment xz>k te of the equation circle Radices R and Cenne +20 Sztuzte 2729 tilan her blane

47.

Brouded thattook toAssignmentxz>kte oftheequationcircleRadicesR andCenne+20Sztuzte 2729tilan her blane

Answer»

ANSWER:

Step-by-step EXPLANATION:

brouded that

took to

Assignment

xz>k

te of

the

equation

circle

Radices

R and

Cenne

+20

Sztuzte 2729

tilan her blane

Discussion

48.	If 3²x - 3 x 5⁴x - 1 = 5²x + 1 x 3⁴x –5 , find x.
Answer» 0.5 Step-by-step EXPLANATION: -4425x + 1875 = 125x-405 -4550x = -2280 x = 2280/4550

48.

If 3²x - 3 x 5⁴x - 1 = 5²x + 1 x 3⁴x –5 , find x.

Answer»

0.5

Step-by-step EXPLANATION:

-4425x + 1875 = 125x-405

-4550x = -2280

x = 2280/4550

Discussion

49.	Sharad bought a table and a fan together for 5000. After some time he sold the table atThe pain of 25% and the fan at again of 20%. Thus he gained 23% on the whole. Find thecost of the fan?
Answer» Answer:2000 Step-by-step EXPLANATION:

49.

Sharad bought a table and a fan together for 5000. After some time he sold the table atThe pain of 25% and the fan at again of 20%. Thus he gained 23% on the whole. Find thecost of the fan?

Answer»

Answer:2000

Step-by-step EXPLANATION:

Discussion

50.	A train certain distance at a uniform speed If the train would have been 10km/hr faster,it would have taken 2 hours less than the schedule time and if the train were slower by 10 km/hr :it would have taken 3 hours more than the schedule time. find the distance covered by the train
Answer» Answer: Distance covered by the train = 600 km Step-by-step explanation: Let the speed of train be x km/hr and time TAKEN be t hr. So, Distance, D is given by = Speed * Time D = x * t ------ [EQUATION 1] First condition given is that if the train would have been 10 km/hr faster,it would have taken 2 hours less than the schedule time i.e.; D = (x + 10) * (t - 2) D = x * t - 2x + 10t - 20 D = D - 2x + 10t - 20 {from equation 1} 10t = 2x + 20 --------- [Equation 2] Second condition given is that if the train were slower by 10 km/hr :it would have taken 3 hours more than the schedule time, i.e.; D = (x - 10) * (t + 3) D = x * t + 3x - 10t - 30 D = D + 3x - 10t - 30 {from equation 1} 3x - 10t - 30 = 0 --------- [Equation 3] Now PUTTING value of 10t from equation 2 into 3 we GET, 3x - (2x + 20) - 30 = 0 3x - 2x - 50 = 0 x = 50 km/hr putting value of x in equation 2 we get, t = $\frac{250 + 20}{10}$ = 12 hr *Therefore, D = x t = 50 * 12 = 600 km .**

50.

A train certain distance at a uniform speed If the train would have been 10km/hr faster,it would have taken 2 hours less than the schedule time and if the train were slower by 10 km/hr :it would have taken 3 hours more than the schedule time. find the distance covered by the train

Answer»

Answer:

Distance covered by the train = 600 km

Step-by-step explanation:

Let the speed of train be x km/hr and time TAKEN be t hr.

So, Distance, D is given by = Speed * Time

D = x * t ------ [EQUATION 1]

First condition given is that if the train would have been 10 km/hr faster,it would have taken 2 hours less than the schedule time i.e.;

D = (x + 10) * (t - 2)

D = x * t - 2*x + 10*t - 20

D = D - 2*x + 10*t - 20 {from equation 1}

10*t = 2*x + 20 --------- [Equation 2]

Second condition given is that if the train were slower by 10 km/hr :it would have taken 3 hours more than the schedule time, i.e.;

D = (x - 10) * (t + 3)

D = x * t + 3*x - 10*t - 30

D = D + 3*x - 10*t - 30 {from equation 1}

3*x - 10*t - 30 = 0 --------- [Equation 3]

Now PUTTING value of 10*t from equation 2 into 3 we GET,

3*x - (2*x + 20) - 30 = 0

3*x - 2*x - 50 = 0

x = 50 km/hr

putting value of x in equation 2 we get, t = $\frac{2*50 + 20}{10}$ = 12 hr

Therefore, D = x * t = 50 * 12 = 600 km .

Discussion

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