A train certain distance at a uniform speed If the train would have be

1.	A train certain distance at a uniform speed If the train would have been 10km/hr faster,it would have taken 2 hours less than the schedule time and if the train were slower by 10 km/hr :it would have taken 3 hours more than the schedule time. find the distance covered by the train
Answer» Answer: Distance covered by the train = 600 km Step-by-step explanation: Let the speed of train be x km/hr and time TAKEN be t hr. So, Distance, D is given by = Speed * Time D = x * t ------ [EQUATION 1] First condition given is that if the train would have been 10 km/hr faster,it would have taken 2 hours less than the schedule time i.e.; D = (x + 10) * (t - 2) D = x * t - 2x + 10t - 20 D = D - 2x + 10t - 20 {from equation 1} 10t = 2x + 20 --------- [Equation 2] Second condition given is that if the train were slower by 10 km/hr :it would have taken 3 hours more than the schedule time, i.e.; D = (x - 10) * (t + 3) D = x * t + 3x - 10t - 30 D = D + 3x - 10t - 30 {from equation 1} 3x - 10t - 30 = 0 --------- [Equation 3] Now PUTTING value of 10t from equation 2 into 3 we GET, 3x - (2x + 20) - 30 = 0 3x - 2x - 50 = 0 x = 50 km/hr putting value of x in equation 2 we get, t = $\frac{250 + 20}{10}$ = 12 hr *Therefore, D = x t = 50 * 12 = 600 km .**

A train certain distance at a uniform speed If the train would have been 10km/hr faster,it would have taken 2 hours less than the schedule time and if the train were slower by 10 km/hr :it would have taken 3 hours more than the schedule time. find the distance covered by the train

Answer»

Answer:

Step-by-step explanation:

Let the speed of train be x km/hr and time TAKEN be t hr.

So, Distance, D is given by = Speed * Time

D = x * t ------ [EQUATION 1]

First condition given is that if the train would have been 10 km/hr faster,it would have taken 2 hours less than the schedule time i.e.;

D = (x + 10) * (t - 2)

D = x * t - 2*x + 10*t - 20

D = D - 2*x + 10*t - 20 {from equation 1}

10*t = 2*x + 20 --------- [Equation 2]

Second condition given is that if the train were slower by 10 km/hr :it would have taken 3 hours more than the schedule time, i.e.;

D = (x - 10) * (t + 3)

D = x * t + 3*x - 10*t - 30

D = D + 3*x - 10*t - 30 {from equation 1}

3*x - 10*t - 30 = 0 --------- [Equation 3]

Now PUTTING value of 10*t from equation 2 into 3 we GET,

3*x - (2*x + 20) - 30 = 0

3*x - 2*x - 50 = 0

x = 50 km/hr

putting value of x in equation 2 we get, t = $\frac{2*50 + 20}{10}$ = 12 hr

Therefore, D = x * t = 50 * 12 = 600 km .