332354 + Interview Questions in Secondary School in Math

1.	Аand B togethercan doa pieceof work in & days. If alonethe same work inla dags & them Balone can do the same work in.
Answer» Answer:A, B & C together complete work in : 10 X 50 / (10 + 50) = 25/3 days => (B + C) + B + C = 25/3 days => B + C = 50/3 days Now C’s 1 day work = 1/50 B + C one day work = 3/50 => B one day work = 3/50 - 1/50 = 1/25 = B ALONE completes work in 25 dsys Step-by-step explanation:

1.

Аand B togethercan doa pieceof work in & days. If alonethe same work inla dags & them Balone can do the same work in.

Answer»

Answer:A, B & C together complete work in :

10 X 50 / (10 + 50) = 25/3 days

=> (B + C) + B + C = 25/3 days

=> B + C = 50/3 days

Now C’s 1 day work = 1/50

B + C one day work = 3/50

=> B one day work = 3/50 - 1/50 = 1/25

= B ALONE completes work in 25 dsys

Step-by-step explanation:

Discussion

2.	Calculate the percentage of 319 percent of 400
Answer» ANSWER: Step-by-step explanation: 319/100 *400

2.

Calculate the percentage of 319 percent of 400

Answer»

ANSWER:

Step-by-step explanation:

319/100 *400

Discussion

3.	(2−82÷41)×(342−57−72×67)guys pls tell right very compelsery
Answer» Answer: 0 ɪs ᴛʜᴇ ᴀɴsᴡᴇʀ Step-by-step EXPLANATION: ǫᴜᴇsᴛɪᴏɴ :- $(2 - 82 \div 41) \times (342 - 57 - 72 \times 67)$ sᴏʟᴜᴛɪᴏɴ :- $(2 - 2) \times ( - 4539)$ $0 \times ( - 4539)$ $0$ ᴍᴀʀᴋ ʙʀᴀɪɴʟɪsᴛ✔️✔️✔️

3.

(2−82÷41)×(342−57−72×67)guys pls tell right very compelsery

Answer»

Answer:

0 ɪs ᴛʜᴇ ᴀɴsᴡᴇʀ

Step-by-step EXPLANATION:

ǫᴜᴇsᴛɪᴏɴ :-

$(2 - 82 \div 41) \times (342 - 57 - 72 \times 67)$

sᴏʟᴜᴛɪᴏɴ :-

$(2 - 2) \times ( - 4539)$

$0 \times ( - 4539)$

$0$

ᴍᴀʀᴋ ʙʀᴀɪɴʟɪsᴛ✔️✔️✔️

Discussion

4.	Find valve of x and y if AB \|\| CD
Answer» ANSWER: X and y both are 130° Step-by-step explanation: 50+x=180° 130°=y

4.

Find valve of x and y if AB || CD

Answer»

ANSWER:

X and y both are 130°

Step-by-step explanation:

50+x=180°

130°=y

Discussion

5.	20b.3За хьоEvaluate
Answer» ANSWER: what is the STRUCTURE of FERN

5.

20b.3За хьоEvaluate

Answer»

ANSWER:

what is the STRUCTURE of FERN

Discussion

6.	(-a+c)(-a-c) what is the answer
Answer» ANSWER: (-a + c) (-a -c) Ans = *(-a-a) + (-a-c) + (c-a) + (c-c)* ( i just multiplied both the terms.....) = a^2 + ca - ca - c^2 = a^2 - c^2 ( i cancelled both the "ca's") PLEASE MARK AS BRAINLIEST ...... IF IT HELPS......

6.

(-a+c)(-a-c) what is the answer

Answer»

ANSWER:

(-a + c) (-a -c)

Ans = (-a*-a) + (-a*-c) + (c*-a) + (c*-c) ( i just multiplied both the terms.....)

= a^2 + ca - ca - c^2

= a^2 - c^2 ( i cancelled both the "ca's")

PLEASE MARK AS BRAINLIEST ...... IF IT HELPS......

Discussion

7.	On what sum ofof moneythe differences between theCombaund Interest andsimple Interest for two yearsbe equal to 25 if therate of interest Charged for both is 5%
Answer» Step-by-step EXPLANATION: Let the principal be Rs. P Given : R=5%,T=24 years C.I. for 2 years =P(1+ 100 5 ) 2 −P S.I. for 2 years = 100 P×5×2 = 10 P ∵ DIFFERENCE between C.I. and S.P. = Rs. 25 P(1+ 100 5 ) 2 −P− 10 P =25 400 441P − 10 11P =25 400 441P−440P =25 P=10,000 Hence, the principle should be Rs. 10,000 Pls MARK me as brainlist...

7.

On what sum ofof moneythe differences between theCombaund Interest andsimple Interest for two yearsbe equal to 25 if therate of interest Charged for both is 5%

Answer»

Step-by-step EXPLANATION:

Let the principal be Rs. P

Given : R=5%,T=24 years

C.I. for 2 years =P(1+

100

5

)

2

−P

S.I. for 2 years =

100

P×5×2

=

10

P

∵ DIFFERENCE between C.I. and S.P. = Rs. 25

P(1+

100

5

)

2

−P−

10

P

=25

400

441P

−

10

11P

=25

400

441P−440P

=25

P=10,000

Hence, the principle should be Rs. 10,000

Pls MARK me as brainlist...

Discussion

8.	If y=2^-1x then dy/dx=
Answer» Step-by-step explanation: how are you going to the store to BUY me some money to PAY for the first time I was LIKE I was like I OWE him and I don't shave DVD player

8.

If y=2^-1x then dy/dx=

Answer»

Step-by-step explanation:

how are you going to the store to BUY me some money to PAY for the first time I was LIKE I was like I OWE him and I don't shave DVD player

Discussion

9.	Can someone give me the answer of these two questions
Answer» ANSWER: x=30, y=30 Step-by-step explanation: we know that x+120+30=180(SUM of all angles in triangle) x=30 y+90=120(EXTERIOR ANGLE PROPERTY) y=30 Thus, x=y

9.

Can someone give me the answer of these two questions

Answer»

ANSWER:

x=30, y=30

Step-by-step explanation:

we know that

x+120+30=180(SUM of all angles in triangle)

x=30

y+90=120(EXTERIOR ANGLE PROPERTY)

y=30

Thus, x=y

Discussion

10.	Find then roots of quadratic equations 2x square + x-6=0
Answer» Answer: 2x²-x-6 = 0 2x²-4x+3x-6 = 0 2X(x-2)-3(x-2) = 0 (2x-3)(x-2) = 0 2x-3 = 0 OR x-2 = 0 2x = 3 OR x = 2 x = 3/2 OR x = 2

10.

Find then roots of quadratic equations 2x square + x-6=0

Answer»

Answer:

2x²-x-6 = 0

2x²-4x+3x-6 = 0

2X(x-2)-3(x-2) = 0

(2x-3)(x-2) = 0

2x-3 = 0 OR x-2 = 0

2x = 3 OR x = 2

x = 3/2 OR x = 2

Discussion

11.	Name all the pairs of adjacent angles in the given figure.
Answer» ANSWER: Two adjacent angles ADD up to 180 deg and SUPPLEMENTARY to each other. So you have 4 pairs of adjacent angles FORMED where two straight LINES intersect each other

11.

Name all the pairs of adjacent angles in the given figure.

Answer»

ANSWER:

Two adjacent angles ADD up to 180 deg and SUPPLEMENTARY to each other. So you have 4 pairs of adjacent angles FORMED where two straight LINES intersect each other

Discussion

12.	A city had 3,00,000 people. The population of the city grew by 3% in the first year, by 2 1/2% in the 2nd year andby 2 1/4% in the 3rd year. Find out the city's population at the end of 3 years.please answer with procedure properly answer is 323851 population...don't send useless answer or will be reportedI need the procedure
Answer» This is the explanation. I have DONE this in just TWO MINUTES.

12.

A city had 3,00,000 people. The population of the city grew by 3% in the first year, by 2 1/2% in the 2nd year andby 2 1/4% in the 3rd year. Find out the city's population at the end of 3 years.please answer with procedure properly answer is 323851 population...don't send useless answer or will be reportedI need the procedure

Answer»

This is the explanation.

I have DONE this in just TWO MINUTES.

Discussion

13.	One card is drawn at random from a well shuffled deck of 52 cards. What is the probability of getting a black card or a king *2 points7/131/23/133/26
Answer» I think 3/26. as there are 13 black CARDS and 4 KINGS

13.

One card is drawn at random from a well shuffled deck of 52 cards. What is the probability of getting a black card or a king *2 points7/131/23/133/26

Answer»

I think 3/26.

as there are 13 black CARDS and 4 KINGS

Discussion

14.	For an given A.P. a=6.5,d=0,n=101, then tn
Answer» ANSWER: an= a+ (n-1) d tn= 6.5+100×0 tn= 6.5

14.

For an given A.P. a=6.5,d=0,n=101, then tn

Answer»

ANSWER:

an= a+ (n-1) d

tn= 6.5+100×0

tn= 6.5

Discussion

15.	मोहन ने अपनी कुल संपत्ति अपनी पत्नी, तीनों पुत्रों, दोनों पुत्रियों तथा 5 नाती - नातिनोंमें इस प्रकार वितरित की कि प्रत्येक नाती नातिन को प्रत्येक पुत्र का 1/8 भाग तथा प्रत्येकपुत्री का 1/10 भाग मिलें, उसकी पत्नी को उसके पुत्र और पुत्रियों के कुल भाग का 40% मिलें,यदि प्रत्येक पुत्री को 1.25 लाख मिलें हो तो उसकी पत्नी और 3 नाती नातिनो को कुलकितना धन मिला
Answer» Step-by-step EXPLANATION: मोहन ने अपनी कुल संपत्ति अपनी पत्नी, तीनों पुत्रों, दोनों पुत्रियों तथा 5 नाती - नातिनों में इस प्रकार वितरित की कि प्रत्येक नाती नातिन को प्रत्येक पुत्र का 1/8 भाग तथा प्रत्येक पुत्री का 1/10 भाग मिलें, उसकी पत्नी को उसके पुत्र और पुत्रियों के कुल भाग का 40% मिलें, यदि प्रत्येक पुत्री को 1.25 लाख मिलें हो तो उसकी ...

15.

मोहन ने अपनी कुल संपत्ति अपनी पत्नी, तीनों पुत्रों, दोनों पुत्रियों तथा 5 नाती - नातिनोंमें इस प्रकार वितरित की कि प्रत्येक नाती नातिन को प्रत्येक पुत्र का 1/8 भाग तथा प्रत्येकपुत्री का 1/10 भाग मिलें, उसकी पत्नी को उसके पुत्र और पुत्रियों के कुल भाग का 40% मिलें,यदि प्रत्येक पुत्री को 1.25 लाख मिलें हो तो उसकी पत्नी और 3 नाती नातिनो को कुलकितना धन मिला

Answer»

Step-by-step EXPLANATION:

मोहन ने अपनी कुल संपत्ति अपनी पत्नी, तीनों पुत्रों, दोनों पुत्रियों तथा 5 नाती - नातिनों में इस प्रकार वितरित की कि प्रत्येक नाती नातिन को प्रत्येक पुत्र का 1/8 भाग तथा प्रत्येक पुत्री का 1/10 भाग मिलें, उसकी पत्नी को उसके पुत्र और पुत्रियों के कुल भाग का 40% मिलें, यदि प्रत्येक पुत्री को 1.25 लाख मिलें हो तो उसकी ...

Discussion

16.	If the polynomial ax² + 4x^2 +3x-4 and x^2-4x+a Leave the same remainder whendivided by x + 2 then find the value of a
Answer» Answer: 2 Step-by-step EXPLANATION: On REGULAR DIVISION with x+2 for first polynomial remainder = 4a+6 for second remainder =a+12 Since those are SAID to be equal a=2

16.

If the polynomial ax² + 4x^2 +3x-4 and x^2-4x+a Leave the same remainder whendivided by x + 2 then find the value of a

Answer»

Answer:

2

Step-by-step EXPLANATION:

On REGULAR DIVISION with x+2

for first polynomial remainder = 4a+6

for second remainder =a+12

Since those are SAID to be equal a=2

Discussion

17.	Please clear the concept of chapter 3 pair of linear equations in two variables .
Answer» Step-by-step explanation: Chapter 3 PAIR of linear EQUATIONS in two variables Equations of the form AX + by + c = 0 are called linear equations in two variables - x and y where a, b, c are REAL numbers. Two linear equations having the same two variables are called a pair of linear equations in two variables

17.

Please clear the concept of chapter 3 pair of linear equations in two variables .

Answer»

Step-by-step explanation:

Chapter 3 PAIR of linear EQUATIONS in two variables

Equations of the form AX + by + c = 0 are called linear equations in two variables - x and y where a, b, c are REAL numbers. Two linear equations having the same two variables are called a pair of linear equations in two variables

Discussion

18.	Find m if the system of equations mx + 3y + (3-m) = 0 and 12x + my -m = 0 has infinitely many solutions
Answer» Answer: given EQ. has infinitely many solutions on COMPARING with GENERAL eq. a1x+b1y+c1=0 a2x+b2y+c2=0 a1/a2=b1/b2=c1/c2 therefore m/12= 3/m=3-m/-m taking 1ST and 2nd term we get, m^2= 36 m=+-√6

18.

Find m if the system of equations mx + 3y + (3-m) = 0 and 12x + my -m = 0 has infinitely many solutions

Answer»

Answer:

given EQ. has infinitely many solutions

on COMPARING with GENERAL eq.

a1x+b1y+c1=0

a2x+b2y+c2=0

a1/a2=b1/b2=c1/c2

therefore m/12= 3/m=3-m/-m

taking 1ST and 2nd term we get,

m^2= 36

m=+-√6

Discussion

19.	Simplify: 125 power (-2/3)* 27(power - 2/3)
Answer» ANSWER: -2/3 + -2/ 3 -2-2 /3 -4 /3 ANS

19.

Simplify: 125 power (-2/3)* 27(power - 2/3)

Answer»

ANSWER:

-2/3 + -2/ 3

-2-2 /3

-4 /3 ANS

Discussion

20.	If sin alfa = 1/2 then prove that (3 cos alfa - 4 cos ^3 alfa) = 0
Answer» ANSWER: HOPE it helps you SEE the ATTACHMENT for further information..... REGARDS.. _addy_✌✌✌

20.

If sin alfa = 1/2 then prove that (3 cos alfa - 4 cos ^3 alfa) = 0

Answer»

ANSWER:

HOPE it helps you SEE the ATTACHMENT for further information.....

REGARDS..

_addy_✌✌✌

Discussion

21.	2. Find any four rational numbers between 3 and 5.3. Find any six rational numbers between (-7/2) and 3/10.DIONIC
Answer» 2. Find any four rational numbers between 3 and 5. 3 X 5= 15 5 X 5= 25 15(16, 17, 18, 19,...)25 3. Find any SIX rational numbers between (-7/2) and 3/10. FIRST TAKE LCM OF 2 AND 10 THAT IS 20 NOW MULTIPLY IT BY ANY NUMBER WHICH GETS 20 IN ITS DENOMINATOR AFTER MULTIPLYING 7/2 X 10/10= 70/20 3/10 X 2/2= 6/20 6/20( 7/20, 8/20, 9/20, 10/20, 11/20, 12/20..........) 70/20

21.

2. Find any four rational numbers between 3 and 5.3. Find any six rational numbers between (-7/2) and 3/10.DIONIC

Answer»

2. Find any four rational numbers between 3 and 5.

3 X 5= 15

5 X 5= 25

15(16, 17, 18, 19,...)25

3. Find any SIX rational numbers between (-7/2) and 3/10.

FIRST TAKE LCM OF 2 AND 10

THAT IS 20

NOW MULTIPLY IT BY ANY NUMBER WHICH GETS 20 IN ITS DENOMINATOR AFTER MULTIPLYING

7/2 X 10/10= 70/20

3/10 X 2/2= 6/20

6/20( 7/20, 8/20, 9/20, 10/20, 11/20, 12/20..........) 70/20

Discussion

22.	Find x and y equation 8 x + 5 y= 9 3x + 2y= 4
Answer» this is CORRECT ANSWER which I EXPLAINED in DETAIL

Discussion

23.	Find the cost of 1 metre ribbonRs25.80what will be cost of 7.5meter of ribbon
Answer» 1 metre ribbon cost = RS/ 25.80 7.5 metre ribbon cost=RS/ (25.80×7.5) = RS/ 193.5 (Ans) HOPE it's HELPFUL to you

23.

Find the cost of 1 metre ribbonRs25.80what will be cost of 7.5meter of ribbon

Answer»

1 metre ribbon cost = RS/ 25.80

7.5 metre ribbon cost=RS/ (25.80×7.5)

= RS/ 193.5 (Ans)

HOPE it's HELPFUL to you

Discussion

24.	223inches the same
Answer» ANSWER: we WANT JUSTICE for SUSHANT SIR

24.

223inches the same

Answer»

ANSWER:

we WANT JUSTICE for SUSHANT SIR

Discussion

25.	If the polynomial of 2nd degree touches x axis then what is roots the equation
Answer» I PROMISE I WILL FOLLOW YOU IF YOU MARK AS BRAINLIST THANKS FOR QUESTION YOUR ANSWER IS Second degree polynomials are also known as quadratic polynomials. Their shape is known as a parabola. The object FORMED when a parabola is rotated about its axis of SYMMETRY is known as a paraboloid, or parabolic REFLECTOR. ... Satellite DISH antennas typically have this shape.

25.

If the polynomial of 2nd degree touches x axis then what is roots the equation

Answer»

I PROMISE I WILL FOLLOW YOU IF YOU MARK AS BRAINLIST

THANKS FOR QUESTION

YOUR ANSWER IS

Second degree polynomials are also known as quadratic polynomials. Their shape is known as a parabola. The object FORMED when a parabola is rotated about its axis of SYMMETRY is known as a paraboloid, or parabolic REFLECTOR. ... Satellite DISH antennas typically have this shape.

Discussion

26.	Plz ans as soon as possible
Answer» Step-by-step EXPLANATION: $\bf{\underline{\underline\red{To\:Prove:-}}}$ $\rm \sin \theta(1 + \tan \theta) + \cos \theta(1 + \cot \theta) = \sec \theta + \cosec \theta$ $\bf{\underline{\underline\blue{Proof:-}}}$ $\boxed{ \rm \tan \theta = \dfrac{sin \theta}{cos \theta} \: \: \: and \: \: \: cot \theta = \dfrac{cos \theta}{sin \theta} }$ $\rm = \sin \theta(1 + \tan \theta) + \cos \theta(1 + \cot \theta)$ $\rm = \sin \theta \bigg(1 + \dfrac{ \sin \theta}{cos \theta} \bigg)+ \cos \theta \bigg(1 + \dfrac{cos \theta}{sin \theta} \bigg)$ $\rm = \sin \theta \bigg( \dfrac{ cos \theta + \sin \theta}{cos \theta} \bigg)+ \cos \theta \bigg( \dfrac{ sin \theta + cos \theta}{sin \theta} \bigg)$ $\rm = \dfrac{ sin \theta(cos \theta + \sin \theta)}{cos \theta} + \dfrac{ cos \theta( sin \theta + cos \theta)}{sin \theta}$ $\rm = \dfrac{ sin \theta \big \{sin \theta(cos \theta + \sin \theta) \big \} + cos \theta \big \{cos \theta( sin \theta + cos \theta) \big \} }{cos \theta.sin \theta}$ $\rm = \dfrac{ {sin }^{2} \theta(cos \theta + {\sin} \theta) + {cos } ^{2} \theta ( sin \theta + cos \theta) \ }{cos \theta .sin \theta}$ $\rm = \dfrac{ {sin }^{2} \theta.cos \theta + {\sin} ^{3} \theta + {cos } ^{2} \theta . sin \theta + cos ^{3} \theta) \ }{cos \theta .sin \theta}$ $\rm = \dfrac{ {sin}^{3} \theta + {cos}^{3} \theta + sin \theta \: cos \theta(sin \theta + cos \theta) }{ cos \theta.sin \theta}$ $\rm = \dfrac{ (sin \theta + cos \theta)({sin}^{2} \theta \: - sin \theta \: cos \theta+ {cos}^{2} \theta )+ sin \theta \: cos \theta(sin \theta + cos \theta) }{ cos \theta.sin \theta}$ $\rm = \dfrac{ (sin \theta + cos \theta)(1 \: - sin \theta \: cos \theta )+ sin \theta \: cos \theta(sin \theta + cos \theta) }{ cos \theta.sin \theta}$ $\rm = \dfrac{ (sin \theta + cos \theta)(1 \: - sin \theta \: cos \theta + sin \theta \: cos \theta)}{ cos \theta.sin \theta}$ $\rm = \dfrac{ (sin \theta + cos \theta)(1 )}{ cos \theta.sin \theta}$ $\rm = \dfrac{ sin \theta + cos \theta}{ cos \theta.sin \theta}$ $\rm = \dfrac{ sin \theta }{ cos \theta.sin \theta} + \dfrac{cos \theta}{cos \theta.sin \theta}$ $\rm = \dfrac{ 1 }{ cos \theta} + \dfrac{1}{sin \theta}$ $\rm = sec \theta + tan \theta =RHS$ LHS = RHS Hence PROVED

26.

Plz ans as soon as possible

Answer»

Step-by-step EXPLANATION:

$\bf{\underline{\underline\red{To\:Prove:-}}}$

$\rm \sin \theta(1 + \tan \theta) + \cos \theta(1 + \cot \theta) = \sec \theta + \cosec \theta$

$\bf{\underline{\underline\blue{Proof:-}}}$

$\boxed{ \rm \tan \theta = \dfrac{sin \theta}{cos \theta} \: \: \: and \: \: \: cot \theta = \dfrac{cos \theta}{sin \theta} }$

$\rm = \sin \theta(1 + \tan \theta) + \cos \theta(1 + \cot \theta)$

$\rm = \sin \theta \bigg(1 + \dfrac{ \sin \theta}{cos \theta} \bigg)+ \cos \theta \bigg(1 + \dfrac{cos \theta}{sin \theta} \bigg)$

$\rm = \sin \theta \bigg( \dfrac{ cos \theta + \sin \theta}{cos \theta} \bigg)+ \cos \theta \bigg( \dfrac{ sin \theta + cos \theta}{sin \theta} \bigg)$

$\rm = \dfrac{ sin \theta(cos \theta + \sin \theta)}{cos \theta} + \dfrac{ cos \theta( sin \theta + cos \theta)}{sin \theta}$

$\rm = \dfrac{ sin \theta \big \{sin \theta(cos \theta + \sin \theta) \big \} + cos \theta \big \{cos \theta( sin \theta + cos \theta) \big \} }{cos \theta.sin \theta}$

$\rm = \dfrac{ {sin }^{2} \theta(cos \theta + {\sin} \theta) + {cos } ^{2} \theta ( sin \theta + cos \theta) \ }{cos \theta .sin \theta}$

$\rm = \dfrac{ {sin }^{2} \theta.cos \theta + {\sin} ^{3} \theta + {cos } ^{2} \theta . sin \theta + cos ^{3} \theta) \ }{cos \theta .sin \theta}$

$\rm = \dfrac{ {sin}^{3} \theta + {cos}^{3} \theta + sin \theta \: cos \theta(sin \theta + cos \theta) }{ cos \theta.sin \theta}$

$\rm = \dfrac{ (sin \theta + cos \theta)({sin}^{2} \theta \: - sin \theta \: cos \theta+ {cos}^{2} \theta )+ sin \theta \: cos \theta(sin \theta + cos \theta) }{ cos \theta.sin \theta}$

$\rm = \dfrac{ (sin \theta + cos \theta)(1 \: - sin \theta \: cos \theta )+ sin \theta \: cos \theta(sin \theta + cos \theta) }{ cos \theta.sin \theta}$

$\rm = \dfrac{ (sin \theta + cos \theta)(1 \: - sin \theta \: cos \theta + sin \theta \: cos \theta)}{ cos \theta.sin \theta}$

$\rm = \dfrac{ (sin \theta + cos \theta)(1 )}{ cos \theta.sin \theta}$

$\rm = \dfrac{ sin \theta + cos \theta}{ cos \theta.sin \theta}$

$\rm = \dfrac{ sin \theta }{ cos \theta.sin \theta} + \dfrac{cos \theta}{cos \theta.sin \theta}$

$\rm = \dfrac{ 1 }{ cos \theta} + \dfrac{1}{sin \theta}$

$\rm = sec \theta + tan \theta =RHS$

LHS = RHS

Hence PROVED

Discussion

27.	-118, -115, -112,-109......find it 31st term of ap
Answer» ANSWER: t31 =-28 Step-by-step EXPLANATION: HOPE this will HELP you

27.

-118, -115, -112,-109......find it 31st term of ap

Answer»

ANSWER:

t31 =-28

Step-by-step EXPLANATION:

HOPE this will HELP you

Discussion

28.	From a well shuffled deck of 52 cards. One card is drawn at random what is the probability of getting a red queen *2 points1/131/521/263/5220. The probability that
Answer» The PROBABILITY is 1/26. PLZ MARK me as BRAILIEST......

28.

From a well shuffled deck of 52 cards. One card is drawn at random what is the probability of getting a red queen *2 points1/131/521/263/5220. The probability that

Answer»

The PROBABILITY is 1/26.

PLZ MARK me as BRAILIEST......

Discussion

29.	Two roots of quadratic equation are 0 and 7; frame the equation.x²-7x+0=0x²+0x+7=00x+7=0x²+0x-7=0
Answer» ANSWER: The answer is the FIRST one. Mark as BRAINLIEST

29.

Two roots of quadratic equation are 0 and 7; frame the equation.x²-7x+0=0x²+0x+7=00x+7=0x²+0x-7=0

Answer»

ANSWER:

The answer is the FIRST one.

Mark as BRAINLIEST

Discussion

30.	Write a binomail of degree 30
Answer» Answer: 2x+y*30...... HOPE it will HELP you

30.

Write a binomail of degree 30

Answer»

Answer:

2x+y*30...... HOPE it will HELP you

Discussion

31.	What is the nature of roots of quadratic equation 9x²-12x+4=0 ?1 point
Answer» ANSWER: Therefore, root of the given equation 4x² - 12X - 9 = 0 are real and distinct. Hence, nature of ROOTS of the quadratic equation 4x²− 12x − 9 = 0 are real and distinct.

31.

What is the nature of roots of quadratic equation 9x²-12x+4=0 ?1 point

Answer»

ANSWER:

Therefore, root of the given equation 4x² - 12X - 9 = 0 are real and distinct. Hence, nature of ROOTS of the quadratic equation 4x²− 12x − 9 = 0 are real and distinct.

Discussion

32.	A point P lies in the first quadrant is a distance of 4 and 5 units respectively from x and y axis find the distance of it from the point Q which is at negative y axis on three units distance from origin
Answer» Answer: point P lies in the first quadrant is a distance of 4 and 5 units respectively from X and y axis FIND the distance of it from the ... please MAKE me brainlist

32.

A point P lies in the first quadrant is a distance of 4 and 5 units respectively from x and y axis find the distance of it from the point Q which is at negative y axis on three units distance from origin

Answer»

Answer:

point P lies in the first quadrant is a distance of 4 and 5 units respectively from X and y axis FIND the distance of it from the ... please MAKE me brainlist

Discussion

33.	5 x square - 2 x y - 3 y square
Answer» ANSWER: HOPE this will HELP you

33.

5 x square - 2 x y - 3 y square

Answer»

ANSWER:

HOPE this will HELP you

Discussion

34.	The nature of decimal expansion of 7/10 without long division
Answer» ANSWER: terminating Step-by-step EXPLANATION: as the DENOMINATOR can be factorised into the form of 2^m.5^n,that is 2^1.5^1,as it FOLLOWS this rule it is terminating

34.

The nature of decimal expansion of 7/10 without long division

Answer»

ANSWER:

terminating

Step-by-step EXPLANATION:

as the DENOMINATOR can be factorised into the form of 2^m.5^n,that is 2^1.5^1,as it FOLLOWS this rule it is terminating

Discussion

35.	Show thatevery square matrix is uniquelyesepressible as the sum of symmetricmatrix and a skew Symmetric matrix
Answer» ANSWER: i THINK abaot it Step-by-step EXPLANATION: HOPE you under STAND

35.

Show thatevery square matrix is uniquelyesepressible as the sum of symmetricmatrix and a skew Symmetric matrix

Answer»

ANSWER:

i THINK abaot it

Step-by-step EXPLANATION:

HOPE you under STAND

Discussion

36.	Find two rational number between 3/7 and 4/3Pls tell me fast because my exam is going on
Answer» Step-by-step EXPLANATION: PLEASE MARK as BRAINLIEST,FOLLOW me

36.

Find two rational number between 3/7 and 4/3Pls tell me fast because my exam is going on

Answer»

Step-by-step EXPLANATION:

PLEASE MARK as BRAINLIEST,FOLLOW me

Discussion

37.	10. Calculate the amount and thecompound interest on Rs. 12,000 in 2years at 10% per year.(3 Points)
Answer» Solution :- <P> → Principal = P = Rs.12,000 → Rate = R = 10% per annum. → Time = T = 2 years. Using Compound interest FORMULA for Amount :- A = P[ 1 + (R/100)]^T we get :- → A = 12000[ 1 + (10/100)]² → A = 12000[ 1 + 1/10]² → A = 12000(11/10)² → A = 12000 * (121/100) → A = Rs.14,520 (ANS.) Therefore, → Compound interest = Amount - Principal → CI = 14520 - 12000 → CI = Rs.2,520 (Ans.) Hence, Amount is Rs.14,520 and Compound interest is Rs.2,520 .

37.

10. Calculate the amount and thecompound interest on Rs. 12,000 in 2years at 10% per year.(3 Points)

Answer»

Solution :-

<P>

→ Principal = P = Rs.12,000

→ Rate = R = 10% per annum.

→ Time = T = 2 years.

Using Compound interest FORMULA for Amount :-

A = P[ 1 + (R/100)]^T

we get :-

→ A = 12000[ 1 + (10/100)]²

→ A = 12000[ 1 + 1/10]²

→ A = 12000(11/10)²

→ A = 12000 * (121/100)

→ A = Rs.14,520 (ANS.)

Therefore,

→ Compound interest = Amount - Principal

→ CI = 14520 - 12000

→ CI = Rs.2,520 (Ans.)

Hence, Amount is Rs.14,520 and Compound interest is Rs.2,520 .

Discussion

38.	3s=0solve the equation by explaining
Answer» Answer: s=0 Step-by-step EXPLANATION: if we divide 0 by any no. We GET 0 so, that s=0. I hope you get your answer.

38.

3s=0solve the equation by explaining

Answer»

Answer:

s=0

Step-by-step EXPLANATION:

if we divide 0 by any no. We GET 0

so, that s=0.

I hope you get your answer.

Discussion

39.	275900
Answer» ANSWER: 275/900 =0.305 Step-by-step EXPLANATION: BRAINLY MARKED my answer

39.

275900

Answer»

ANSWER:

275/900

=0.305

Step-by-step EXPLANATION:

BRAINLY MARKED my answer

Discussion

40.	105 105 103 97 85 65 34find the wrong number in series .....
Answer» what's your question I WANT ONE more BRAINLIST please GIVE

40.

105 105 103 97 85 65 34find the wrong number in series .....

Answer»

what's your question

I WANT ONE more BRAINLIST please GIVE

Discussion

41.	6) Find the area of the right-angled triangle whose one side is 4 cm andhypotenuse is 5 cm.*
Answer» Step-by-step EXPLANATION: HOPE THIS MUST HELP YOU, MARK THIS AS THE BRAINLIEST , AND ALSO FOLLOW ME .

41.

6) Find the area of the right-angled triangle whose one side is 4 cm andhypotenuse is 5 cm.*

Answer»

Step-by-step EXPLANATION:

HOPE THIS MUST HELP YOU,

MARK THIS AS THE BRAINLIEST ,

AND ALSO FOLLOW ME .

Discussion

42.	Ek samaantar chaturbhuj ke goonh likhiye
Answer» ANSWER: • आमने सामने की भुजाएं बराबर और समान्तर होती हैं। • विकर्ण एक दूसरे को समद्विभाजित करते हैं। • आमने सामने के कोण बराबर होते हैं। • विकर्ण आमने सामने के कोण को समद्विभाजित करते हैं। hope it HELPS

42.

Ek samaantar chaturbhuj ke goonh likhiye

Answer»

ANSWER:

• आमने सामने की भुजाएं बराबर और समान्तर होती हैं।

• विकर्ण एक दूसरे को समद्विभाजित करते हैं।

• आमने सामने के कोण बराबर होते हैं।

• विकर्ण आमने सामने के कोण को समद्विभाजित करते हैं।

hope it HELPS

Discussion

43.	Acute angle measurements that are multiples of 5?
Answer» Answer: ACUTE angle measurements that are MULTIPLES of 5 is 5X

43.

Acute angle measurements that are multiples of 5?

Answer»

Answer:

ACUTE angle measurements that are MULTIPLES of 5 is 5X

Discussion

44.	Find the ratio of5 leter to 250 ml
Answer» Answer: 4:1 Step-by-step explanation: 1 LITER =1000ml 1000/250 4/1=4:1

44.

Find the ratio of5 leter to 250 ml

Answer»

Answer:

4:1

Step-by-step explanation:

1 LITER =1000ml

1000/250

4/1=4:1

Discussion

45.	Sally has 90 c freezer has 58c what is the difference
Answer» ANSWER: IM not EXACTLY SURE how to answer this and i COULD be wrong Step-by-step explanation: 90-58=32

45.

Sally has 90 c freezer has 58c what is the difference

Answer»

ANSWER:

IM not EXACTLY SURE how to answer this and i COULD be wrong

Step-by-step explanation:

90-58=32

Discussion

46.	What is the median of the data: 8,13,9,1,4?
Answer» ANSWER: FIRST we NEED to ARRANGE them in increasing order. 1,4,8,9,13 Now the median is the middle term. Therefore the median will be 8. Mark as BRAINLIEST

46.

What is the median of the data: 8,13,9,1,4?

Answer»

ANSWER:

FIRST we NEED to ARRANGE them in increasing order.

1,4,8,9,13

Now the median is the middle term.

Therefore the median will be 8.

Mark as BRAINLIEST

Discussion

47.	Find the value 5/7 ×5/7×5/7 × 21/25 ×21/25
Answer» ANSWER: sᴏʟᴜᴛɪᴏɴ:- $\frac{5}{<klux>7</klux>} \times \frac{5}{7} \times \frac{5}{7} \times \frac{<klux>21</klux>}{<klux>25</klux>} \times \frac{21}{25}$ ᴛᴏ ғɪɴᴅ ᴛʜᴇ ᴀɴsᴡᴇʀ :- ᴛʜᴇ 21 ɴᴜᴍᴇʀɪᴄᴀʟ ᴀʀᴇ ᴄᴜᴛ ᴏғ ʙʏ 7 ᴀɴᴅ 25 ʙʏ 5 sᴏ ᴛʜᴇ ʀᴇǫᴜɪʀᴇ ɴᴜᴍʙᴇʀ ᴀʀᴇ ᴀs ғᴏʟʟᴏᴡ $\frac{9}{35}$ ✔️✔️✔️ ᴍᴀʀᴋ ʙʀᴀɪɴʟɪsᴛ

47.

Find the value 5/7 ×5/7×5/7 × 21/25 ×21/25

Answer»

ANSWER:

sᴏʟᴜᴛɪᴏɴ:-

$\frac{5}{<klux>7</klux>} \times \frac{5}{7} \times \frac{5}{7} \times \frac{<klux>21</klux>}{<klux>25</klux>} \times \frac{21}{25}$

ᴛᴏ ғɪɴᴅ ᴛʜᴇ ᴀɴsᴡᴇʀ :-

ᴛʜᴇ 21 ɴᴜᴍᴇʀɪᴄᴀʟ ᴀʀᴇ ᴄᴜᴛ ᴏғ ʙʏ 7 ᴀɴᴅ 25 ʙʏ 5

sᴏ ᴛʜᴇ ʀᴇǫᴜɪʀᴇ ɴᴜᴍʙᴇʀ ᴀʀᴇ ᴀs ғᴏʟʟᴏᴡ

$\frac{9}{35}$

✔️✔️✔️

ᴍᴀʀᴋ ʙʀᴀɪɴʟɪsᴛ

Discussion

48.	Find the the common difference of an ap in which a36-a12=48
Answer» ANSWER: a36= a+ 35d A12 = a+11d so a+35d -a-11d = 48 so 24d = 48 so d = 2

48.

Find the the common difference of an ap in which a36-a12=48

Answer»

ANSWER:

a36= a+ 35d

A12 = a+11d

so a+35d -a-11d = 48

so 24d = 48

so d = 2

Discussion

49.	Identify the name of the property 2/3 + 4/5 = 4/5 +2/3
Answer» Answer: Commutative PROPERTY. Step-by-step explanation: HOPE it HELPS!!!

49.

Identify the name of the property 2/3 + 4/5 = 4/5 +2/3

Answer»

Answer:

Commutative PROPERTY.

Step-by-step explanation:

HOPE it HELPS!!!

Discussion

50.	Which term of the AP 3,8,13,18_____u8?
Answer» Answer: 8 is the TERM. PLEASE VOTE

50.

Which term of the AP 3,8,13,18_____u8?

Answer»

Answer:

8 is the TERM.

PLEASE VOTE

Discussion

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