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Find m if the system of equations mx + 3y + (3-m) = 0 and 12x + my -m = 0 has infinitely many solutions |
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Answer» Answer: given EQ. has infinitely many solutions a1x+b1y+c1=0 a2x+b2y+c2=0 a1/a2=b1/b2=c1/c2 therefore m/12= 3/m=3-m/-m taking 1ST and 2nd term we get, m^2= 36 m=+-√6 |
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