332354 + Interview Questions in Secondary School in Math

1.	Hcf of 126 106 148...........
Answer» Answer: hey MATE there is your answer Step-by-step EXPLANATION: hcf of 126 and 106, 148 is 2 please mark me as a BRAINLEST

1.

Hcf of 126 106 148...........

Answer»

Answer:

hey MATE there is your answer

Step-by-step EXPLANATION:

hcf of 126 and 106, 148 is 2 please mark me as a BRAINLEST

Discussion

2.	A five m long piece of cloth is folded in two equal parts.a piece of length 9by 11m is cut off from one part and that of length 13by11m is cut off from the other part.what is the length of the remaining cloth altogether
Answer» Answer: 3 METRE. Step-by-step explanation: first ADD to 9/11 +13/11 then = 2 then subtract 5-2= 3metre

2.

A five m long piece of cloth is folded in two equal parts.a piece of length 9by 11m is cut off from one part and that of length 13by11m is cut off from the other part.what is the length of the remaining cloth altogether

Answer»

Answer:

3 METRE.

Step-by-step explanation:

first ADD to 9/11 +13/11

then = 2

then subtract

5-2= 3metre

Discussion

3.	Write the first three terms of the sequence an=2+3n²
Answer» Answer: 1st TERM = 5. 2nd Term = 14. 3rd Term = 29.

3.

Write the first three terms of the sequence an=2+3n²

Answer»

Answer:

1st TERM = 5.

2nd Term = 14.

3rd Term = 29.

Discussion

4.	Express sec50+ cot 78 in terms of t-ratio of angle between 0 and 45
Answer» ANSWER: SEC(90°-40)+COT(90°-12) cosec40°+tan12°

4.

Express sec50+ cot 78 in terms of t-ratio of angle between 0 and 45

Answer»

ANSWER:

SEC(90°-40)+COT(90°-12)

cosec40°+tan12°

Discussion

5.	Make the greatest and smallest 4 digit number using any four different digits with conditions as given example digit 7 is at always at one's place
Answer» ANSWER: ACCORDING to me the answer is: 9867 1237

5.

Make the greatest and smallest 4 digit number using any four different digits with conditions as given example digit 7 is at always at one's place

Answer»

ANSWER:

ACCORDING to me the answer is:

9867

1237

Discussion

6.	Two places A and B are 120 kilometre A past from each other on a highway one car starts starts from A and another from B at the same time if they move in the same Direction they meet in 6 hours and if they move in output Direction they meet in 1 hour and 12 minutes find the speed of the car
Answer» ANSWER: HOPE it will HELP you x = 60km/hr y = 40km/hr

6.

Two places A and B are 120 kilometre A past from each other on a highway one car starts starts from A and another from B at the same time if they move in the same Direction they meet in 6 hours and if they move in output Direction they meet in 1 hour and 12 minutes find the speed of the car

Answer»

ANSWER:

HOPE it will HELP you

x = 60km/hr

y = 40km/hr

Discussion

7.	1-sin theta upon 1+sin theta = (sec theta -tan theta ) hole square
Answer» ANSWER: $lhs = \frac{1 - \sin( \alpha ) }{1 + \sin( \alpha ) } \\ multiplying \: nr \: and \: dr \: by \: 1 - \sin( \alpha ) \\ = \frac{1 - \sin( \alpha ) }{1 + \sin( \alpha ) } \times \frac{1 - \sin( \alpha ) }{1 - \sin( \alpha ) } \\ = \frac{ {(1 - \sin( \alpha ) )}^{2} }{1 - { \sin }^{2} \alpha } = \frac{1 - { \sin }^{2} \alpha +2 \sin( \alpha ) }{ { \cos}^{2} \alpha } \\ = { \sec}^{2} \alpha - { \tan}^{2} \alpha - 2 \sec( \alpha ) \tan( \alpha ) \\ = ({ \sec( \alpha ) - \tan( \alpha ) })^{2} \\ = rhs$

7.

1-sin theta upon 1+sin theta = (sec theta -tan theta ) hole square

Answer»

ANSWER:

$lhs = \frac{1 - \sin( \alpha ) }{1 + \sin( \alpha ) } \\ multiplying \: nr \: and \: dr \: by \: 1 - \sin( \alpha ) \\ = \frac{1 - \sin( \alpha ) }{1 + \sin( \alpha ) } \times \frac{1 - \sin( \alpha ) }{1 - \sin( \alpha ) } \\ = \frac{ {(1 - \sin( \alpha ) )}^{2} }{1 - { \sin }^{2} \alpha } = \frac{1 - { \sin }^{2} \alpha +2 \sin( \alpha ) }{ { \cos}^{2} \alpha } \\ = { \sec}^{2} \alpha - { \tan}^{2} \alpha - 2 \sec( \alpha ) \tan( \alpha ) \\ = ({ \sec( \alpha ) - \tan( \alpha ) })^{2} \\ = rhs$

Discussion

8.	If p(x) =x^3-x^2+x+1 then find the value of p(1)+p(-1) ÷2
Answer» HOPE it will HELP you ...

Discussion

9.	bob the builder in making 480kg of concrete mix Concrete is made by mixing cement, snad and gravel in the ratio of 1:3:4 how much sand does he need
Answer» He need 180 kg of sand. Step-by-step explanation: Given : Bob the BUILDER in MAKING 480 kg of concrete mix Concrete is made by mixing cement, sand and gravel in the ratio of 1:3:4. To FIND : How much sand does he need ? Solution : Let the ratio be 'x'. The AMOUNT of cement, sand and gravel in concrete mixture be x, 3x, 4X respectively. So, total mixture is 480 kg. i.e. $x+3x+4x=480$ $8x=480$ Divide both sides by 8. $x=60$ The amount of sand is 3x. So, $3\times 60=180$ Therefore, he need 180 kg of sand. #Learn more R:b =4:3. how much of r is to be added to get the ratio 4 :1 brainly.in/question/8032452

9.

bob the builder in making 480kg of concrete mix Concrete is made by mixing cement, snad and gravel in the ratio of 1:3:4 how much sand does he need

Answer»

He need 180 kg of sand.

Step-by-step explanation:

Given : Bob the BUILDER in MAKING 480 kg of concrete mix Concrete is made by mixing cement, sand and gravel in the ratio of 1:3:4.

To FIND : How much sand does he need ?

Solution :

Let the ratio be 'x'.

The AMOUNT of cement, sand and gravel in concrete mixture be x, 3x, 4X respectively.

So, total mixture is 480 kg.

i.e. $x+3x+4x=480$

$8x=480$

Divide both sides by 8.

$x=60$

The amount of sand is 3x.

So, $3\times 60=180$

Therefore, he need 180 kg of sand.

#Learn more

R:b =4:3. how much of r is to be added to get the ratio 4 :1

brainly.in/question/8032452

Discussion

10.	In triangle abc , am is perpendicular to bc and an is the bisector of anglea. Find the measure of angle man
Answer» Step-by-step explanation: Step 1: Suppose that angle ''A'' = 2x. LOOKING at the fact that AN is BISECTOR of angle A you may write that angle "BAN" = "NAC" i.e. = x Step 2: In the triangle ( ΔABC) the total of all the angles must be 180 degrees, as per common law RULES. So the sum of all angles of triangle must be ∠B + ∠C + ∠A = 180° Step 3: We have following missing values:- 65 + 30 + angle "A" = 180° =180-( 65+30) =180-(95) =85 degrees. You found value for angle "A" Step 4: Now you must do angle "A"/2 i.e. x = 85 degrees /2 Step 5: in triangle ABN another triangle ANC is the exterior angle so use this law of total of exterior angles to find out missing value. Where; x + 65 = angle "ANC" 85/2 + 56 = angle "ANC " ∠ANC = 215/2 Step 6: After finding the angle look at MNA = 180 degrees NEXT you do this 180- (215/2) = 143/2 Step 7: in the triangle AMN, this is the situation that; 143/2 + 90 + angle MAN = 180° thus; angle MAN = 90 - 143/2 Making answer angle MAN = 35/2 final answer: 17.5 degrees

10.

In triangle abc , am is perpendicular to bc and an is the bisector of anglea. Find the measure of angle man

Answer»

Step-by-step explanation:

Step 1:

Suppose that angle ''A'' = 2x.

LOOKING at the fact that AN is BISECTOR of angle A you may write that

angle "BAN" = "NAC" i.e. = x

Step 2:

In the triangle ( ΔABC) the total of all the angles must be 180 degrees, as per common law RULES.

So the sum of all angles of triangle must be ∠B + ∠C + ∠A = 180°

Step 3: We have following missing values:-

65 + 30 + angle "A" = 180°

=180-( 65+30)

=180-(95)

=85 degrees.

You found value for angle "A"

Step 4:

Now you must do angle "A"/2 i.e. x = 85 degrees /2

Step 5:

in triangle ABN another triangle ANC is the exterior angle so use this law of total of exterior angles to find out missing value.

Where; x + 65 = angle "ANC"

85/2 + 56 = angle "ANC "

∠ANC = 215/2

Step 6:

After finding the angle look at MNA = 180 degrees

NEXT you do this

180- (215/2) = 143/2

Step 7:

in the triangle AMN, this is the situation that; 143/2 + 90 + angle MAN = 180°

thus; angle MAN = 90 - 143/2

Making answer angle MAN = 35/2

final answer: 17.5 degrees

Discussion

11.	How many different words can be formed of the word COMBINE so that no vowels vowels come together
Answer» FOLLOWING words are formed... 1. comb 2. mine 3. NIB ...HOPE you GET ur ans....

11.

How many different words can be formed of the word COMBINE so that no vowels vowels come together

Answer»

FOLLOWING words are formed...

1. comb

2. mine

3. NIB

...HOPE you GET ur ans....

Discussion

12.	45-(38-(60÷3-(6-9÷3)÷13))
Answer» Step-by-step explanation: 26.7692.... HOPE it will HELP you

12.

45-(38-(60÷3-(6-9÷3)÷13))

Answer»

Step-by-step explanation:

26.7692....

HOPE it will HELP you

Discussion

13.	the denominator of a rational number is greater than its numerator by 3 .if 3 is subracted from the numerator and 2 is added to its denominator, the new number will be 1/5 find the original number
Answer» ANSWER: Step-by-step explanation: Let the NUMERATOR =x the DENOMINATOR = x+3 the RATIONAL no.=x/x+3 ATQ x-3/x+3+2 =1/5 x-3/x+5 = 1/5 by CROSS multiply 5(x-3)=x+5 5x-15=x+5 5x-x = 5+15 4x= 20 x=20/4 x=5 the rational no. =x/x+3 =5/5+3 =5/8

13.

the denominator of a rational number is greater than its numerator by 3 .if 3 is subracted from the numerator and 2 is added to its denominator, the new number will be 1/5 find the original number

Answer»

ANSWER:

Step-by-step explanation:

Let the NUMERATOR =x

the DENOMINATOR = x+3

the RATIONAL no.=x/x+3

ATQ

x-3/x+3+2 =1/5

x-3/x+5 = 1/5

by CROSS multiply

5(x-3)=x+5

5x-15=x+5

5x-x = 5+15

4x= 20

x=20/4

x=5

the rational no. =x/x+3

=5/5+3

=5/8

Discussion

14.	Mohan walks 17 m north east 8m south.how far is he from his intial point
Answer» USING PYTHAGORAS THEOREM,x= $\sqrt{(17 { }^{2 } - 8 {}^{2}) \ }$ = $\sqrt{(289 - 64) }$ = $\sqrt{225}$ x=15

14.

Mohan walks 17 m north east 8m south.how far is he from his intial point

Answer»

USING PYTHAGORAS THEOREM,x=

$\sqrt{(17 { }^{2 } - 8 {}^{2}) \ }$

=

$\sqrt{(289 - 64) }$

=

$\sqrt{225}$

x=15

Discussion

15.	Prove that (3-underroot 5) is an irrational number
Answer» Answer: FIRST prove ROOT 5 is irrational Step-by-step explanation: then do it urself

15.

Prove that (3-underroot 5) is an irrational number

Answer»

Answer:

FIRST prove ROOT 5 is irrational

Step-by-step explanation:

then do it urself

Discussion

16.	12(x2 + 7x)square – 8(x square + 7x) (2x - 1) - 15(2x - 1)square
Answer» $\huge\mathcal\purple{Heya..Mate!!}$ $\huge\bold\pink{<klux>ANSWER</klux>:}$ ⏩The answer is given in the ATTACHMENT above...have a glimpse at it... ✔✔✔✔ Hope it helps...:-) ⭐❤✨♥⭐❤✨♥⭐ Be BRAINLY...✌✌✌

16.

12(x2 + 7x)square – 8(x square + 7x) (2x - 1) - 15(2x - 1)square

Answer»

$\huge\mathcal\purple{Heya..Mate!!}$

$\huge\bold\pink{<klux>ANSWER</klux>:}$

⏩The answer is given in the ATTACHMENT above...have a glimpse at it...

✔✔✔✔

Hope it helps...:-)

⭐❤✨♥⭐❤✨♥⭐

Be BRAINLY...✌✌✌

Discussion

17.	13. Find the product369 x 13
Answer» Answer: 36913=4,797 Step-by-step EXPLANATION:* FOLLOW me

17.

13. Find the product369 x 13

Answer»

Answer:

369*13=4,797

Step-by-step EXPLANATION:

FOLLOW me

Discussion

18.	Pls do the 13 14 and 15 I will follow u
Answer» Answer: yaar Apna PURA EXAM cancer Hamein se Pata karoge kya kuch tum BHI likho thik HAI PHONE karo Mujhe

18.

Pls do the 13 14 and 15 I will follow u

Answer»

Answer:

yaar Apna PURA EXAM cancer Hamein se Pata karoge kya kuch tum BHI likho thik HAI PHONE karo Mujhe

Discussion

19.	613 Find the solution of the followingequations.b) -49 = 7(x+1)c) –7+7+-3)=0d) 8(x-4)+2=421) 10(x-2) + 4 = 12(x + 6)-6
Answer» -49=7x+7 7x=-56 x=-8 8x-32+2=42 8x=72 x=9 10x-20+4=12x+72-6 2x+82=0 2x=-82 x=-41

19.

613 Find the solution of the followingequations.b) -49 = 7(x+1)c) –7+7+-3)=0d) 8(x-4)+2=421) 10(x-2) + 4 = 12(x + 6)-6

Answer»

-49=7x+7

7x=-56

x=-8

8x-32+2=42

8x=72

x=9

10x-20+4=12x+72-6

2x+82=0

2x=-82

x=-41

Discussion

20.	Show that x+a is a factor of x^m - a^m for any even integer m
Answer» Step-by-step explanation: X+a=0 x= -a put the value of x in eq x^m-a^m = (-a)^m-a^m = (-1)^m×a^m-a^m coz m is even INTEGER. so (-1)^m = 1 so 1×a^m-a^m =a^m-a^m =0

20.

Show that x+a is a factor of x^m - a^m for any even integer m

Answer»

Step-by-step explanation:

X+a=0

x= -a

put the value of x in eq

x^m-a^m

= (-a)^m-a^m

= (-1)^m×a^m-a^m

coz m is even INTEGER. so (-1)^m = 1

so 1×a^m-a^m

=a^m-a^m

=0

Discussion

21.	Kabhi bur kabhi pani movie ,who was hero
Answer» ANSWER: that movie does not exist Step-by-step EXPLANATION: also it is not math ,don't ASK such QUESTIONS

21.

Kabhi bur kabhi pani movie ,who was hero

Answer»

ANSWER:

that movie does not exist

Step-by-step EXPLANATION:

also it is not math ,don't ASK such QUESTIONS

Discussion

22.	Factorisation by using three methods 96 ,252 ,1224 ,4641 ,1197
Answer» Solution: I have done by using PRIME factorization you can also easily do this by using DIVISION method 1) Factorization of 96 96 = 2×48 = 2×2×24 = 2×2×2×12 = 2×2×2×2×6 = 2×2×2×2×2×3 ⇒ 96 = 2×2×2×2×2×3 2) Factorization of 256 256 = 2×128 = 2×2×64 = 2×2×2×32 = 2×2×2×2×16 = 2×2×2×2×2×8 = 2×2×2×2×2×2×4 = 2×2×2×2×2×2×2×2 ⇒ 256 = 2×2×2×2×2×2×2×2 3) Factorization of 1124 1124 = 2×562 =2×2×281 ⇒ 1124 = 2×2×281 4) Factorization of 4641 4641 = 3×1547 = 3×7×221 = 3×7×13×17 So ⇒ 4641 = 3×7×13×17 5) Factorization of 1197 1197 = 3×339 = 3×3×113 ⇒ 1197 =3×3×113

22.

Factorisation by using three methods 96 ,252 ,1224 ,4641 ,1197

Answer»

Solution:

I have done by using PRIME factorization you can also easily do this by using DIVISION method

1)

Factorization of 96

96 = 2×48 = 2×2×24 = 2×2×2×12 = 2×2×2×2×6 = 2×2×2×2×2×3

⇒ 96 = 2×2×2×2×2×3

2)

Factorization of 256

256 = 2×128 = 2×2×64 = 2×2×2×32

= 2×2×2×2×16 = 2×2×2×2×2×8

= 2×2×2×2×2×2×4 = 2×2×2×2×2×2×2×2

⇒ 256 = 2×2×2×2×2×2×2×2

3)

Factorization of 1124

1124 = 2×562 =2×2×281

⇒ 1124 = 2×2×281

4)

Factorization of 4641

4641 = 3×1547 = 3×7×221 = 3×7×13×17

So

⇒ 4641 = 3×7×13×17

5)

Factorization of 1197

1197 = 3×339 = 3×3×113

⇒ 1197 =3×3×113

Discussion

23.	Estimate the cube root of 320
Answer» HOPE IT HELPS YOU MARK ME ON BRAINLIEST

23.

Estimate the cube root of 320

Answer»

HOPE IT HELPS YOU

MARK ME ON BRAINLIEST

Discussion

24.	√6+√6+√6.... Evaluate
Answer» ANSWER: Don't KNOW it will TAKE time Step-by-step EXPLANATION: SORRY

24.

√6+√6+√6.... Evaluate

Answer»

ANSWER:

Don't KNOW it will TAKE time

Step-by-step EXPLANATION:

SORRY

Discussion

25.	if alpha and beta are two real number such that alpha minus beta is not equal to 2npie ,n is the interior which satisfy the equation cos emptyset + b sin empty set equal to a then prove that cos( alpha + beta )equal to a square minus b square over a square + b square
Answer» PLEASE UPLOAD PHOTO of QUES

25.

if alpha and beta are two real number such that alpha minus beta is not equal to 2npie ,n is the interior which satisfy the equation cos emptyset + b sin empty set equal to a then prove that cos( alpha + beta )equal to a square minus b square over a square + b square

Answer»

PLEASE UPLOAD PHOTO of QUES

Discussion

26.	A and B together cando a piece of work in 30 days. If A's one day work os 1.5 times the one day's work of B, find in how many days can each do the work.
Answer» I am not SURE. About the ANSWER

26.

A and B together cando a piece of work in 30 days. If A's one day work os 1.5 times the one day's work of B, find in how many days can each do the work.

Answer»

I am not SURE. About the ANSWER

Discussion

27.	What is to be substracted from 41/-8 to get35/8
Answer» Answer: LET the no. is x. ATQ, 41/-8 - x=35/8 -x=35/8-(-41/8) -x=35/8+41/8 -x=76/8 -x=19/2 So, x=-19/2. Therefore, - 19/2 must be subtracted from 41/-8 to get 35/8. I *HOPE* *THIS* *ANSWER* IS *HELPFUL*!!

27.

What is to be substracted from 41/-8 to get35/8

Answer»

Answer:

LET the no. is x.

ATQ,

41/-8 - x=35/8

-x=35/8-(-41/8)

-x=35/8+41/8

-x=76/8

-x=19/2

So, x=-19/2.

Therefore, - 19/2 must be subtracted from 41/-8 to get 35/8.

I HOPE THIS ANSWER IS HELPFUL!!

Discussion

28.	Amarchand had rupees 88592 with her she place an order for purchasing 50 radio sets at rupees 1100how much money will left with her with after the purchase
Answer» ANSWER: COST of 50 RADIOS = 50×1100= 55000 she has LEFT = 88592-55000 = 33592

28.

Amarchand had rupees 88592 with her she place an order for purchasing 50 radio sets at rupees 1100how much money will left with her with after the purchase

Answer»

ANSWER:

COST of 50 RADIOS = 50×1100= 55000

she has LEFT = 88592-55000 = 33592

Discussion

29.	Expand (1.) ( 3+43) (2.) (7x-3)^3plz plz do my this question
Answer» ANSWER: you can SOLVE this by FOLLOWING FORMULA

29.

Expand (1.) ( 3+43) (2.) (7x-3)^3plz plz do my this question

Answer»

ANSWER:

you can SOLVE this by FOLLOWING FORMULA

Discussion

30.	121/515/2(271/5)..simplify it
Answer» QUESTION is not CLEAR.

Discussion

31.	एक समचतुर्भुजाकार घास के खेत में 18 गायों के चरने के लिए घास है। यदि इस समचतुर्भुज की प्रत्येक भुजा 30 m है और बड़ा विकर्ण 48 m है, तो प्रत्येक गाय को चरने के लिए इस घास के खेत का कितना क्षेत्रफल प्राप्त होगा?
Answer» Answer: प्रत्येक गाय के लिए घास के खेत का क्षेत्रफल 48 मी² है। Step-by-step explanation: माना ABCD एक समचतुर्भुज है। समचतुर्भुज ABCD का क्षेत्रफल = 2 × ∆ABC का क्षेत्रफल [विकर्ण AC समचतुर्भुज को दो बराबर क्षेत्रफल के त्रिभुजों में विभाजित करता है।] त्रिभुज ΔABC का अर्द्ध परिमाप, s = (a + b + c)/2 s = (30 + 30 + 48)/2 m s = 54 मी हीरोन के सूत्र से, त्रिभुज ABC का क्षेत्रफल , A = √[s (s - a) (s - b) (s - c)] A = √54(54 - 30) (54 - 30) (54 - 48) A = √54 × 24 × 24 × 6 A = √9 × 6 × 24 × 24 × 6 A = √9 × (6 × 6) × (24 × 24 A = 3 × 6 × 24 A = 18 × 24 त्रिभुज ABC का क्षेत्रफल ,A = 432 मी² घास के खेत (समचतुर्भुज ABCD) का क्षेत्रफल = 2 × ∆ABC का क्षेत्रफल = (2 × 432) घास के खेत (समचतुर्भुज ABCD) का क्षेत्रफल = 864 मी² दिया है : गायों की संख्या = 18 प्रत्येक गाय के लिए घास के खेत का क्षेत्रफल = 864/18 = 48 मी² अतः , प्रत्येक गाय के लिए घास के खेत का क्षेत्रफल 48 मी² है। आशा है कि यह उत्तर आपकी मदद करेगा। इस पाठ से संबंधित कुछ और प्रश्न : एक त्रिभुज और एक समांतर चतुर्भुज का एक ही आधार है और क्षेत्रफल भी एक ही है। यदि त्रिभुज की भुजाएँ 26 CM, 28 cm और 30 cm हैं तथा समांतर चतुर्भुज 28 cm के आधार पर स्थित है, तो उसकी संगत ऊँचाई ज्ञात कीजिए। brainly.in/question/10314802 राधा ने एक रंगीन कागज से एक हवाईजहाज का चित्र बनाया, जैसा कि आकृति 12.15 में दिखाया गया है। प्रयोग किए गए कागज का कुल क्षेत्रफल ज्ञात कीजिए। brainly.in/question/10312737

31.

एक समचतुर्भुजाकार घास के खेत में 18 गायों के चरने के लिए घास है। यदि इस समचतुर्भुज की प्रत्येक भुजा 30 m है और बड़ा विकर्ण 48 m है, तो प्रत्येक गाय को चरने के लिए इस घास के खेत का कितना क्षेत्रफल प्राप्त होगा?

Answer»

Answer:

प्रत्येक गाय के लिए घास के खेत का क्षेत्रफल 48 मी² है।

Step-by-step explanation:

माना ABCD एक समचतुर्भुज है।

समचतुर्भुज ABCD का क्षेत्रफल = 2 × ∆ABC का क्षेत्रफल

[विकर्ण AC समचतुर्भुज को दो बराबर क्षेत्रफल के त्रिभुजों में विभाजित करता है।]

त्रिभुज ΔABC का अर्द्ध परिमाप, s = (a + b + c)/2

s = (30 + 30 + 48)/2 m

s = 54 मी

हीरोन के सूत्र से, त्रिभुज ABC का क्षेत्रफल , A = √[s (s - a) (s - b) (s - c)]

A = √54(54 - 30) (54 - 30) (54 - 48)

A = √54 × 24 × 24 × 6

A = √9 × 6 × 24 × 24 × 6

A = √9 × (6 × 6) × (24 × 24

A = 3 × 6 × 24

A = 18 × 24

त्रिभुज ABC का क्षेत्रफल ,A = 432 मी²

घास के खेत (समचतुर्भुज ABCD) का क्षेत्रफल = 2 × ∆ABC का क्षेत्रफल

= (2 × 432)

घास के खेत (समचतुर्भुज ABCD) का क्षेत्रफल = 864 मी²

दिया है : गायों की संख्या = 18

प्रत्येक गाय के लिए घास के खेत का क्षेत्रफल = 864/18 = 48 मी²

अतः , प्रत्येक गाय के लिए घास के खेत का क्षेत्रफल 48 मी² है।

आशा है कि यह उत्तर आपकी मदद करेगा।

इस पाठ से संबंधित कुछ और प्रश्न :

एक त्रिभुज और एक समांतर चतुर्भुज का एक ही आधार है और क्षेत्रफल भी एक ही है। यदि त्रिभुज की भुजाएँ 26 CM, 28 cm और 30 cm हैं तथा समांतर चतुर्भुज 28 cm के आधार पर स्थित है, तो उसकी संगत ऊँचाई ज्ञात कीजिए।

brainly.in/question/10314802

राधा ने एक रंगीन कागज से एक हवाईजहाज का चित्र बनाया, जैसा कि आकृति 12.15 में दिखाया गया है। प्रयोग किए गए कागज का कुल क्षेत्रफल ज्ञात कीजिए।

brainly.in/question/10312737

Discussion

32.	Represent root3.8 on the number line.
Answer» here is U R ANS HOPE this HELPS u

32.

Represent root3.8 on the number line.

Answer»

here is U R ANS

HOPE this HELPS u

Discussion

33.	Pls solve 9 th question fast
Answer» ANSWER: PLEASE SEE the ATTACHED

33.

Pls solve 9 th question fast

Answer»

ANSWER:

PLEASE SEE the ATTACHED

Discussion

34.	8. A and B can do a piece of work in72 days. B and C do it in 120 days,A and C can do it in 90 days. Inhow many days all the threetogether can do the work?(1) 80 days (2) 100 days(3) 60 days (4) 150 days
Answer» ANSWER: I THINK 100 days a b C can complete there WORK.....

34.

8. A and B can do a piece of work in72 days. B and C do it in 120 days,A and C can do it in 90 days. Inhow many days all the threetogether can do the work?(1) 80 days (2) 100 days(3) 60 days (4) 150 days

Answer»

ANSWER:

I THINK 100 days a b C can complete

there WORK.....

Discussion

35.	If √3tan a - 1 = 0 , find the value of sin^2 a- cos ^2 a
Answer» ANSWER: you can SOLVE this by FOLLOWING FORMULA

35.

If √3tan a - 1 = 0 , find the value of sin^2 a- cos ^2 a

Answer»

ANSWER:

you can SOLVE this by FOLLOWING FORMULA

Discussion

36.	If+a=3+√7/2+then+find+the+value+ofA2+1/A2
Answer» Answer:9+√7/2 Step-by-step explanation: 2a+1/2a =2(3+√7/2)+1/2(3+√7/2) =3+√7+1/3+√7 =3+√7+3-√7/2 ,SINCE we FACTORIZED 1/3+√7 (1/3+√7)×(3-√7/3-√7) 3-√7/(3)²-(√7)²,because (a+b)(a-b)=a²-b² 3-√7/2 =[2(3+√7)+(3-√7)]/2 =[6+2√7+3-√7]/2 =9+√7/2

36.

If+a=3+√7/2+then+find+the+value+ofA2+1/A2

Answer»

Answer:9+√7/2

Step-by-step explanation:

2a+1/2a

=2(3+√7/2)+1/2(3+√7/2)

=3+√7+1/3+√7

=3+√7+3-√7/2 ,SINCE we FACTORIZED 1/3+√7

(1/3+√7)×(3-√7/3-√7)

3-√7/(3)²-(√7)²,because (a+b)(a-b)=a²-b²

3-√7/2

=[2(3+√7)+(3-√7)]/2

=[6+2√7+3-√7]/2

=9+√7/2

Discussion

37.	Find the value of 3 by 5 multiple bracket mainas 20 bracket
Answer» Answer: 3/5*-20 answer is -0.03

37.

Find the value of 3 by 5 multiple bracket mainas 20 bracket

Answer»

Answer:

3/5*-20

answer is -0.03

Discussion

38.	Pair of negative integer whose difference gives 8
Answer» (-16,-8)(-24,-16)...…........and MUCH more

38.

Pair of negative integer whose difference gives 8

Answer»

(-16,-8)(-24,-16)...…........and MUCH more

Discussion

39.	Find the square root of 45/5 upto three decimal places
Answer» if you can SEND PHOTO of QUES

39.

Find the square root of 45/5 upto three decimal places

Answer»

if you can SEND PHOTO of QUES

Discussion

40.	Which political party has broomstick as its logo?
Answer»

Discussion

41.	Depletion of petroleum and coal in last 5 decades record
Answer» ANSWER: i don't KNOW SORRY OK YAAR

41.

Depletion of petroleum and coal in last 5 decades record

Answer»

ANSWER:

i don't KNOW SORRY OK YAAR

Discussion

42.	The mass of a gas cylinder the 14kg 250gm.find total mass of 22 such cylinder
Answer» HOPE it HELPS. I have CHECKED it, it is CORRECT

42.

The mass of a gas cylinder the 14kg 250gm.find total mass of 22 such cylinder

Answer»

HOPE it HELPS. I have CHECKED it, it is CORRECT

Discussion

43.	What is the greatest number that divide 36 and 60
Answer» Step-by-step EXPLANATION: HOPE this WOULD HELP you

43.

What is the greatest number that divide 36 and 60

Answer»

Step-by-step EXPLANATION:

HOPE this WOULD HELP you

Discussion

44.	In how many ways can 4 boys and 4 girls be arranged in a row such that no two boys and no two girls are next to each other?
Answer» ANSWER: answer Step-by-step explanation: 1st LINE BOYS , SECOND line GIRLS

44.

In how many ways can 4 boys and 4 girls be arranged in a row such that no two boys and no two girls are next to each other?

Answer»

ANSWER:

answer

Step-by-step explanation:

1st LINE BOYS , SECOND line GIRLS

Discussion

45.	In how many ways can 8 letters be posted in 4 post boxes, if any number of letters can be posted in all of the four post boxes?
Answer» Answer: 4^8 Step-by-step explanation: Every distinct LETTER has FOUR BOXES (options) to go to. So for eight such LETTERS: 4444444*4 = 65536

45.

In how many ways can 8 letters be posted in 4 post boxes, if any number of letters can be posted in all of the four post boxes?

Answer»

Answer:

4^8

Step-by-step explanation:

Every distinct LETTER has FOUR BOXES (options) to go to.

So for eight such LETTERS: 4*4*4*4*4*4*4*4 = 65536

Discussion

46.	Ind the probability of exactly any 2 persons having their birthday on the same day in a year
Answer» Answer: let US do it oppositely LIKE the probability of both having BIRTHDAY not on the same day. the answer WOULD be 1 - (364/365)=1/365

46.

Ind the probability of exactly any 2 persons having their birthday on the same day in a year

Answer»

Answer:

let US do it oppositely LIKE the probability of both having BIRTHDAY not on the same day. the answer WOULD be 1 - (364/365)=1/365

Discussion

47.	Sum of lcm and hcf is 50 and lcm is 20 more than the hcf. Find the lcm
Answer» Answer: I think 50 is the PRODUCT GIVEN. Is it is product,and we need to find the hcf. So. HCF=50/20=2.2

47.

Sum of lcm and hcf is 50 and lcm is 20 more than the hcf. Find the lcm

Answer»

Answer:

I think 50 is the PRODUCT GIVEN.

Is it is product,and we need to find the hcf.

So. HCF=50/20=2.2

Discussion

48.	Find the area of the figure.
Answer» Answer: 60cm^2 Step-by-step EXPLANATION: Think of it as area of four right ANGLE triangle Formula to be USED area =(1÷2)bh 1st triangle area (1÷2)×8×4=16 2nd triangle area (1÷2)×8×6=24 3rd triangle area (1÷2)×6×4=12 4th triangle area (1÷2)×4×4=8 Total area is 16+24+12+8=60

48.

Find the area of the figure.

Answer»

Answer:

60cm^2

Step-by-step EXPLANATION:

Think of it as area of four right ANGLE triangle

Formula to be USED area =(1÷2)bh

1st triangle area (1÷2)×8×4=16

2nd triangle area (1÷2)×8×6=24

3rd triangle area (1÷2)×6×4=12

4th triangle area (1÷2)×4×4=8

Total area is 16+24+12+8=60

Discussion

49.	Sum of two nu,mbers in 36 and the lcm is 105 and hcf is 3
Answer» hello MATE solve kya KARNA H

49.

Sum of two nu,mbers in 36 and the lcm is 105 and hcf is 3

Answer»

hello MATE

solve kya KARNA H

Discussion

50.	The average of 5 numbers is 65.The average of first t
Answer» HOPE your QUESTION is INCOMPLETE

Discussion

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प्रत्येक गाय के लिए घास के खेत का क्षेत्रफल 48 मी² है।

s = 54 मी

हीरोन के सूत्र से, त्रिभुज ABC का क्षेत्रफल , A = √[s (s - a) (s - b) (s - c)]

त्रिभुज ABC का क्षेत्रफल ,A = 432 मी²

घास के खेत (समचतुर्भुज ABCD) का क्षेत्रफल = 864 मी²

अतः , प्रत्येक गाय के लिए घास के खेत का क्षेत्रफल 48 मी² है।

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