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Show that x+a is a factor of x^m - a^m for any even integer m |
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Answer» Step-by-step explanation: X+a=0 x= -a put the value of x in eq x^m-a^m = (-a)^m-a^m = (-1)^m×a^m-a^m coz m is even INTEGER. so (-1)^m = 1 so 1×a^m-a^m =a^m-a^m =0 |
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