1.

Show that x+a is a factor of x^m - a^m for any even integer m​

Answer»

Step-by-step explanation:

X+a=0

x= -a

put the value of x in eq

x^m-a^m

= (-a)^m-a^m

= (-1)^m×a^m-a^m

coz m is even INTEGER. so (-1)^m = 1

so 1×a^m-a^m

=a^m-a^m

=0



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