332354 + Interview Questions in Secondary School in Math

1.	6 bags of soil are used to fill 5 flower pots how much soil does each flower pot use between what two whole numbers does the answer lie
Answer» If 1 is divided by the sum of y& 4.the RESULT is EQUAL to 3 divided by 4, find the VALUE of m Answers: 1

Discussion

2.	1. Show that (x+1) is a factor of x^3-7x-6 and find the other factors?
Answer» ANSWER: Other factors are (X-3) and (x+2) Step-by-step explanation: x³-7x-6 =x³+x²-x²-x-6x-6 =x²(x+1)-x(x+1)-6(x+1) =(x+1)(x²-x-6) =(x+1)(x²-3x+2x-6) =(x+1)(x-3)(x+2) HENCE it is DIVISIBLE by (x+1)

2.

1. Show that (x+1) is a factor of x^3-7x-6 and find the other factors?

Answer»

ANSWER:

Other factors are (X-3) and (x+2)

Step-by-step explanation:

x³-7x-6

=x³+x²-x²-x-6x-6

=x²(x+1)-x(x+1)-6(x+1)

=(x+1)(x²-x-6)

=(x+1)(x²-3x+2x-6)

=(x+1)(x-3)(x+2)

HENCE it is DIVISIBLE by (x+1)

Discussion

3.	The perimeter of a parallelogram is 20cm one of its sides is less than the other by 2 CM find the lengths of all the sides of the parallelogram of class 8
Answer» Answer: LET ONE side be x other side x-2 perimeter of paraallelogram=2(l+b) 20=2x+2x-4 16=4x x=4 othet side 2 opposite SIDES of PARRALLELOGRAM are equal

3.

The perimeter of a parallelogram is 20cm one of its sides is less than the other by 2 CM find the lengths of all the sides of the parallelogram of class 8

Answer»

Answer:

LET ONE side be x

other side x-2

perimeter of paraallelogram=2(l+b)

20=2x+2x-4

16=4x

x=4

othet side 2

opposite SIDES of PARRALLELOGRAM are equal

Discussion

4.	What is the diffentiation of√1-x²Plz explain
Answer» Step-by-step EXPLANATION: ROOT(1-x²) = (1-x²)^1/2 Differentiating, 1/2× (1-x²)^(1/2 -1) × (-2X) = 1/2 × (1-x²)-1/2 × (-2x) = -x/root(1-x²)

4.

What is the diffentiation of√1-x²Plz explain

Answer»

Step-by-step EXPLANATION:

ROOT(1-x²) = (1-x²)^1/2

Differentiating,

1/2× (1-x²)^(1/2 -1) × (-2X)

= 1/2 × (1-x²)-1/2 × (-2x)

= -x/root(1-x²)

Discussion

5.	Which equation has a value less than 2,175?
Answer» \TAN \: X = \FRAC{ \SIN \: x }{ \COS \: x }

5.

Which equation has a value less than 2,175?

Answer»

\TAN \: X = \FRAC{ \SIN \: x }{ \COS \: x }

Discussion

6.	Solve the inequalities
Answer» Step-by-step explanation: 5/2x-1 > 4 5 > 8x-4 9 > 8x 9/8 > x HOPE IF IT WORKS LIKE THAT BECAUSE I AM IN 10TH AND I DON'T KNOW MUCH ABOUT INEQUALITY MARK AS BRAINLIEST PLEASE

6.

Solve the inequalities

Answer»

Step-by-step explanation:

5/2x-1 > 4

5 > 8x-4

9 > 8x

9/8 > x

HOPE IF IT WORKS LIKE THAT BECAUSE I AM IN 10TH AND I DON'T KNOW MUCH ABOUT INEQUALITY

MARK AS BRAINLIEST PLEASE

Discussion

7.	Find the value of p(x)=2x3+x2-x-1 at x=-2
Answer» The ANSWER of QUESTION is -1.

Discussion

8.	If alpha and beta are the zeroes of the polynomial 5x2– 7x + 2 , then find the value of alpha ^2 + beta^2
Answer» ANSWER: U BULLY FOR POINTS TO ME SO I DO THE SAME Step-by-step EXPLANATION:

8.

If alpha and beta are the zeroes of the polynomial 5x2– 7x + 2 , then find the value of alpha ^2 + beta^2

Answer»

ANSWER:

U BULLY FOR POINTS TO ME SO I DO THE SAME

Step-by-step EXPLANATION:

Discussion

9.	(50)[2(5 – 1)Vo - Vo^2] = (10)[-(-2)]^2
Answer» HOPE you LIKE it If its not FEEL FREE to ASK

Discussion

10.	The function X-2 is differentiable everywhere on the real line?
Answer» Answer: To SHOW that F is differentiable at all x∈R, we must show that f′(x) EXISTS at all x∈R. Recall that f is differentiable at x if limh→0f(x+h)−f(x)h exists. And so we see that f is differentiable at all x∈R with derivative f′(x)=−5. hope it HELPS u #NAWABZAADI

10.

The function X-2 is differentiable everywhere on the real line?

Answer»

Answer:

To SHOW that F is differentiable at all x∈R, we must show that f′(x) EXISTS at all x∈R. Recall that f is differentiable at x if limh→0f(x+h)−f(x)h exists. And so we see that f is differentiable at all x∈R with derivative f′(x)=−5.

hope it HELPS u

#NAWABZAADI

Discussion

11.	Solve for x d(-3+x)=kx+9
Answer» HOPE you LIKE it if don’t FEEL FREE to ASK

Discussion

12.	On comparing the ratios of the coefficients , find out whether the pair of equationsx – 2y – 10 = 0 and 3x – 6y – 20 = 0 is consistent or inconsistent.
Answer» Step-by-step explanation: 1/3 = -2/-6 =/= -10/-20 Because, Because a1/a2 = b1/b2 =/= c1/c2 THEREFORE the LINES are PARALLEL, Therefore, INCONSISTENT.

12.

On comparing the ratios of the coefficients , find out whether the pair of equationsx – 2y – 10 = 0 and 3x – 6y – 20 = 0 is consistent or inconsistent.

Answer»

Step-by-step explanation:

1/3 = -2/-6 =/= -10/-20

Because,

Because a1/a2 = b1/b2 =/= c1/c2

THEREFORE the LINES are PARALLEL,

Therefore, INCONSISTENT.

Discussion

13.	If x=(1/3.2/4) y=(-1/2.2/-1) find 2x -3y
Answer» ANSWER: x = 1/6 y= 1 2x-3y= 1/3 -3 = -8/3 Hope this HELPS mate Please mark me as brainliest if it HELPED

13.

If x=(1/3.2/4) y=(-1/2.2/-1) find 2x -3y

Answer»

ANSWER:

x = 1/6

y= 1

2x-3y= 1/3 -3 = -8/3

Hope this HELPS mate

Please mark me as brainliest if it HELPED

Discussion

14.	Type 1 Area and Perimeter of PlaneFigures1. A rectangular lawn 45 m by 30 m has two roads each3 m wide running in the middle of it, one parallel tolength and the other parallel to breadth. The cost ofgravelling the roads at 90 paise per square metre is(1) 3 194.40(2) 210.20(3) 245.40(4) 162.20(5) None of theserectangular field walking
Answer» Answer: Answer REF.Image The cost of GRAVELLING them at Rs. 1.20 per SQUARE METER = Rs . 1560 To find the AREA of roads : It is given that a rectangular lawn 80 m × 60 m has two roads each 10 m wide running in the middle of it. Dimension of two roads are 80×10 and 60×10 Area of two roads = 80×10+60×10−10×10 =800+600−100 = 1300 sq. meter To find the cost for gravelling It is given that The cost of gravelling the at Rs. 1.20 per sq. meter. Therefore total cost = total area × cost per sq. meter =1300×1.20 =Rs.1560 ∴ The cost of gravelling them at Rs. 1.20 per sq. meter = Rs. 1560 solution

14.

Type 1 Area and Perimeter of PlaneFigures1. A rectangular lawn 45 m by 30 m has two roads each3 m wide running in the middle of it, one parallel tolength and the other parallel to breadth. The cost ofgravelling the roads at 90 paise per square metre is(1) 3 194.40(2) 210.20(3) 245.40(4) 162.20(5) None of theserectangular field walking

Answer»

Answer:

Answer

REF.Image

The cost of GRAVELLING them at Rs. 1.20 per SQUARE METER = Rs . 1560

To find the AREA of roads :

It is given that

a rectangular lawn 80 m × 60 m has two roads each 10 m wide running in the middle of it.

Dimension of two roads are 80×10 and 60×10

Area of two roads = 80×10+60×10−10×10

=800+600−100

= 1300 sq. meter

To find the cost for gravelling

It is given that

The cost of gravelling the at Rs. 1.20 per sq. meter.

Therefore total cost = total area × cost per sq. meter

=1300×1.20

=Rs.1560

∴ The cost of gravelling them at Rs. 1.20 per sq. meter = Rs. 1560

solution

Discussion

15.	WILL GIVE FIRST ANSWER BRAINLIEST! I NEED THE ANSWER NOW!!!!
Answer» FIGURE A : Figure B is 4/9 1 : 4/9 Since we have to find the dimension of A , so , dimension of B must be TAKEN as unit. 9 : 4 9/4 : 1 (916)/4 : 116 36 : 16 x = 36

15.

WILL GIVE FIRST ANSWER BRAINLIEST! I NEED THE ANSWER NOW!!!!

Answer»

FIGURE A : Figure B is 4/9

1 : 4/9

Since we have to find the dimension of A , so , dimension of B must be TAKEN as unit.

9 : 4

9/4 : 1

(916)/4 : 116

36 : 16

x = 36

Discussion

16.	The perimeter of a rectangle is 12.4 m and its breadth is 2.2 m. Find its areaThe perimeter of a rectangle is 12.4m and its breadth is2.2 m find its area
Answer» ANSWER: LET LENGTH be x perimeter=2(l+b)=12.4=2(x+2.2) 6.2=x+2.2 x=4 area =l×b=4×2.2=8.8

16.

The perimeter of a rectangle is 12.4 m and its breadth is 2.2 m. Find its areaThe perimeter of a rectangle is 12.4m and its breadth is2.2 m find its area

Answer»

ANSWER:

LET LENGTH be x

perimeter=2(l+b)=12.4=2(x+2.2)

6.2=x+2.2

x=4

area =l×b=4×2.2=8.8

Discussion

17.	Cumulative class interval mean
Answer» Answer: 4)HOME trade Step-by-step EXPLANATION: HOPE it HELPS you ☺️❤️☺️

17.

Cumulative class interval mean

Answer»

Answer:

4)HOME trade

Step-by-step EXPLANATION:

HOPE it HELPS you ☺️❤️☺️

Discussion

18.	Circle 20cm in length distance from the centre is 24cm find the radius of the circle
Answer» ANSWER: RADIUS of CIRCLE is 24 CM

18.

Circle 20cm in length distance from the centre is 24cm find the radius of the circle

Answer»

ANSWER:

RADIUS of CIRCLE is 24 CM

Discussion

19.	A man was engaged on a job for N days on the condition that he would get a wage of Rs. X for the day he works, but he has to pay a fine of Rs. Y for each day of his absence. If he gets Rs. M at the end, he was absent for work for ... days.
Answer» Answer: He was Absent for [(AX - M)/Y] DAYS. where 'A' is the number of days worked, 'X' is the Wage gotten per day, 'M' is the wage received after N days, and 'Y' is FINE per day. Step-by-step explanation: We are given that, N is the total number of days allowed to work. Let the man work for 'A' number of days, Then, he must be absent for (N - A) days. Now, Wage GOT of working per day = Rs.X So, For A days, WAGES = A × X = Rs.AX Also, Fine given for absence per day = Rs.Y So, For (N - A) days, fine = Rs.Y(N - A) Now, ACCORDING to the Question, Wages - Fine = Rs.M AX - Y(N - A) = M AX - M = Y(N - A) (N - A) = (AX - M)/Y Days Absent = (AX - M)/Y Hence, He was Absent for [(AX - M)/Y] days. where 'A' is the number of days worked, 'X' is the Wage gotten per day, 'M' is the wage received after N days, and 'Y' is Fine per day. Hope it helped and believing you understood it....All the best

19.

A man was engaged on a job for N days on the condition that he would get a wage of Rs. X for the day he works, but he has to pay a fine of Rs. Y for each day of his absence. If he gets Rs. M at the end, he was absent for work for ... days.

Answer»

Answer:

He was Absent for [(AX - M)/Y] DAYS.

where 'A' is the number of days worked, 'X' is the Wage gotten per day, 'M' is the wage received after N days, and 'Y' is FINE per day.

Step-by-step explanation:

We are given that,

N is the total number of days allowed to work.

Let the man work for 'A' number of days,

Then, he must be absent for (N - A) days.

Now,

Wage GOT of working per day = Rs.X

So,

For A days, WAGES = A × X

= Rs.AX

Also,

Fine given for absence per day = Rs.Y

So,

For (N - A) days, fine = Rs.Y(N - A)

Now, ACCORDING to the Question,

Wages - Fine = Rs.M

AX - Y(N - A) = M

AX - M = Y(N - A)

(N - A) = (AX - M)/Y

Days Absent = (AX - M)/Y

Hence,

He was Absent for [(AX - M)/Y] days.

where 'A' is the number of days worked, 'X' is the Wage gotten per day, 'M' is the wage received after N days, and 'Y' is Fine per day.

Hope it helped and believing you understood it....All the best

Discussion

20.	Evaluate with suitable identities:-1.13×0.87
Answer» Step-by-step explanation: 1.13×0.87 = (1+0.13) (1-0.13) [∵(a+b) (a-b) = $a^{2}$ - $b^{2}$ ](IDENTITY) = $(1)^{2}$ - $(0.13)^{2}$ = 1 - 0.0169 = 0.9831 (ANS)

20.

Evaluate with suitable identities:-1.13×0.87

Answer»

Step-by-step explanation:

1.13×0.87

= (1+0.13) (1-0.13) [∵(a+b) (a-b) = $a^{2}$ - $b^{2}$ ](IDENTITY)

= $(1)^{2}$ - $(0.13)^{2}$

= 1 - 0.0169

= 0.9831 (ANS)

Discussion

21.	1. The square of 43 ends with the digiti _______________.a) 9 b) 6 c) 4 d) 3
Answer» Answer: a 9 Step-by-step explanation: 43×43 = 1849 so the last digital MUST be 9

21.

1. The square of 43 ends with the digiti _______________.a) 9 b) 6 c) 4 d) 3

Answer»

Answer:

a 9

Step-by-step explanation:

43×43 = 1849 so the last digital MUST be 9

Discussion

22.	The length of the y-intercept made by the circle x 2 + y 2 – 8x + y – 20 = 0 is
Answer» SOLUTION TO DETERMINE The LENGTH of the y-intercept made by the circle $\sf{ {x}^{2} + {y}^{2} - 8x + y - 20 = 0 }$ EVALUATION Here the given equation of the circle is $\sf{ {x}^{2} + {y}^{2} - 8x + y - 20 = 0 }$ Comparing with the general equation of a circle $\sf{a {x}^{2} + b{y}^{2} + 2gx +2f y + c = 0 }$ We have a = 1 , b = 1 , 2G = - 8 , 2f = 1 , c = - 20 Hence the required y-intercept $= \sf{2 \sqrt{ {f}^{2} - c }}$ $= \sf{ \sqrt{ 4{f}^{2} - 4c }}$ $= \sf{ \sqrt{ {(2f)}^{2} - 4c }}$ $= \sf{ \sqrt{ {(1)}^{2} - 4 \times ( - 20)}}$ $= \sf{ \sqrt{ 1 + 80}}$ $= \sf{ \sqrt{ 81}}$ $= \sf{9}$ FINAL ANSWER Hence the required y-intercept = 9 unit ━━━━━━━━━━━━━━━━ Learn more from Brainly :- 1. find the center and radius of circle REPRESENTED by xsquare +ysquare+6x-4y+4=0 brainly.in/question/28987139 2. Find the equation of the circle which pas through the origin and points of intersection of circles x2 + y2 = 4 and line. brainly.in/question/14313265

22.

The length of the y-intercept made by the circle x 2 + y 2 – 8x + y – 20 = 0 is

Answer»

SOLUTION

TO DETERMINE

The LENGTH of the y-intercept made by the circle

$\sf{ {x}^{2} + {y}^{2} - 8x + y - 20 = 0 }$

EVALUATION

Here the given equation of the circle is

$\sf{ {x}^{2} + {y}^{2} - 8x + y - 20 = 0 }$

Comparing with the general equation of a circle

$\sf{a {x}^{2} + b{y}^{2} + 2gx +2f y + c = 0 }$

We have

a = 1 , b = 1 , 2G = - 8 , 2f = 1 , c = - 20

Hence the required y-intercept

$= \sf{2 \sqrt{ {f}^{2} - c }}$

$= \sf{ \sqrt{ 4{f}^{2} - 4c }}$

$= \sf{ \sqrt{ {(2f)}^{2} - 4c }}$

$= \sf{ \sqrt{ {(1)}^{2} - 4 \times ( - 20)}}$

$= \sf{ \sqrt{ 1 + 80}}$

$= \sf{ \sqrt{ 81}}$

$= \sf{9}$

FINAL ANSWER

Hence the required y-intercept = 9 unit

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

1. find the center and radius of circle REPRESENTED by

xsquare +ysquare+6x-4y+4=0

brainly.in/question/28987139

2. Find the equation of the circle which pas through the origin and points of intersection of circles x2 + y2 = 4 and line.

brainly.in/question/14313265

Discussion

23.	2:3,6:7,8:9 तथा 11:13 का मिश्रित अनुपात ज्ञात कीजिए।
Answer» Answer: 27:32 Step-by-step EXPLANATION: sabhi ANUPAT ko karne PAR twenty seven anupat thirty two AYEGA

23.

2:3,6:7,8:9 तथा 11:13 का मिश्रित अनुपात ज्ञात कीजिए।

Answer»

Answer:

27:32

Step-by-step EXPLANATION:

sabhi ANUPAT ko karne PAR twenty seven anupat thirty two AYEGA

Discussion

24.	Factorise (4y-5)^2+80 Class VIII
Answer» Answer: ( 4Y-5)^ 2 + 80 ( 4y)^2+(5)^2-2×4y×5+80 16y^2+25-40y+80 16y^2-40y+105 y(16y-40) + 105 ANSWER

24.

Factorise (4y-5)^2+80 Class VIII

Answer»

Answer:

( 4Y-5)^ 2 + 80

( 4y)^2+(5)^2-2×4y×5+80

16y^2+25-40y+80

16y^2-40y+105

y(16y-40) + 105 ANSWER

Discussion

25.	જો – 4 એ બહુપદી p (x) = x + cx + 20નું એક શુન્ય હોય, તો k =- 9.
Answer» Step-by-step explanation: 1. Write the next three integers for the following sequences 15, 12, 9.-6, 303 1, 3, 7, 11, 15 19. 23 2. ADD the following without using the number line a) (-535) + (-609) b) -1000 + 186 3. Find the sum of the following: a)-638, 943, and -111 d)-87, -199 and -1347 4. EVALUATE : a) (-36) + 11 + (-73) b)84 + (-99) + (-135) c)(-83) + (-183) + (1833) 5. What should be added to -1984 to get the integer - 1? 6. Find the additive INVERSE of each of the following: a)-138 b)1 7. Write the successor and predecessor of each of the following: a)1001 b)-1891. Write the next three integers for the following sequences 15, 12, 9.-6, 303 1, 3, 7, 11, 15 19. 23 2. Add the following without using the number line a) (-535) + (-609) b) -1000 + 186 3. Find the sum of the following: a)-638, 943, and -111 d)-87, -199 and -1347 4. Evaluate : a) (-36) + 11 + (-73) b)84 + (-99) + (-135) c)(-83) + (-183) + (1833) 5. What should be added to -1984 to get the integer - 1? 6. Find the additive inverse of each of the following: a)-138 b)1 7. Write the successor and predecessor of each of the following: a)1001 b)-189 8. Find an integer p such that: a) p + 11 = 0 b) p + (-3) = 0 9.Subtract the following: a)-16 from 101. Write the next three integers for the following sequences 15, 12, 9.-6, 303 1, 3, 7, 11, 15 19. 23 2. Add the following without using the number line a) (-535) + (-609) b) -1000 + 186 3. Find the sum of the following: a)-638, 943, and -111 d)-87, -199 and -1347 4. Evaluate : a) (-36) + 11 + (-73) b)84 + (-99) + (-135) c)(-83) + (-183) + (1833) 5. What should be added to -1984 to get the integer - 1? 6. Find the additive inverse of each of the following: a)-138 b)1 7. Write the successor and predecessor of each of the following: a)1001 b)-189 8. Find an integer p such that: a) p + 11 = 0 b) p + (-3) = 0 9.Subtract the following: a)-16 from 101. Write the next three integers for the following sequences 15, 12, 9.-6, 303 1, 3, 7, 11, 15 19. 23 2. Add the following without using the number line a) (-535) + (-609) b) -1000 + 186 3. Find the sum of the following: a)-638, 943, and -111 d)-87, -199 and -1347 4. Evaluate : a) (-36) + 11 + (-73) b)84 + (-99) + (-135) c)(-83) + (-183) + (1833) 5. What should be added to -1984 to get the integer - 1? 6. Find the additive inverse of each of the following: a)-138 b)1 7. Write the successor and predecessor of each of the following: a)1001 b)-189 8. Find an integer p such that: a) p + 11 = 0 b) p + (-3) = 0 9.Subtract the following: a)-16 from 10 b)-11 from -119 10. Subtract the sum of -1150 and - 198 from 6234. 18. The sum of two integers is 1308. If one of the integers is -198, find the other. 11. What should be subtracted from - 2000 to get 1901? b)-11 from -119 10. Subtract the sum of -1150 and - 198 from 6234. 18. The sum of two integers is 1308. If one of the integers is -198, find the other. 11. What should be subtracted from - 2000 to get 1901? b)-11 from -119 10. Subtract the sum of -1150 and - 198 from 6234. 18. The sum of two integers is 1308. If one of the integers is -198, find the other. 11. What should be subtracted from - 2000 to get 1901? 8. Find an integer p such that: a) p + 11 = 0 b) p + (-3) = 0gfhxadutymjmlkmm.kmk.km.in 9.Subtract the following: a)-16 from 10 b)-11 from -119 10. Subtract the sum of -1150 and - 198 from 6234. 18. The sum of two integers is 1308. If one of the integers is -198, find the other. 11. What should be subtracted from - 2000 to get 1901?

25.

જો – 4 એ બહુપદી p (x) = x + cx + 20નું એક શુન્ય હોય, તો k =- 9.

Answer»

Step-by-step explanation:

1.

Write the next three integers for the following sequences

15, 12, 9.-6, 303

1, 3, 7, 11, 15 19. 23

2. ADD the following without using the number line

a) (-535) + (-609)

b) -1000 + 186

3. Find the sum of the following:

a)-638, 943, and -111

d)-87, -199 and -1347

4. EVALUATE :

a) (-36) + 11 + (-73)

b)84 + (-99) + (-135)

c)(-83) + (-183) + (1833)

5. What should be added to -1984 to get the integer - 1?

6. Find the additive INVERSE of each of the following:

a)-138

b)1

7. Write the successor and predecessor of each of the following:

a)1001

b)-1891.

Write the next three integers for the following sequences

15, 12, 9.-6, 303

1, 3, 7, 11, 15 19. 23

2. Add the following without using the number line

a) (-535) + (-609)

b) -1000 + 186

3. Find the sum of the following:

a)-638, 943, and -111

d)-87, -199 and -1347

4. Evaluate :

a) (-36) + 11 + (-73)

b)84 + (-99) + (-135)

c)(-83) + (-183) + (1833)

5. What should be added to -1984 to get the integer - 1?

6. Find the additive inverse of each of the following:

a)-138

b)1

7. Write the successor and predecessor of each of the following:

a)1001

b)-189

8. Find an integer p such that:

a) p + 11 = 0

b) p + (-3) = 0

9.Subtract the following:

a)-16 from 101.

Write the next three integers for the following sequences

15, 12, 9.-6, 303

1, 3, 7, 11, 15 19. 23

2. Add the following without using the number line

a) (-535) + (-609)

b) -1000 + 186

3. Find the sum of the following:

a)-638, 943, and -111

d)-87, -199 and -1347

4. Evaluate :

a) (-36) + 11 + (-73)

b)84 + (-99) + (-135)

c)(-83) + (-183) + (1833)

5. What should be added to -1984 to get the integer - 1?

6. Find the additive inverse of each of the following:

a)-138

b)1

7. Write the successor and predecessor of each of the following:

a)1001

b)-189

8. Find an integer p such that:

a) p + 11 = 0

b) p + (-3) = 0

9.Subtract the following:

a)-16 from 101.

Write the next three integers for the following sequences

15, 12, 9.-6, 303

1, 3, 7, 11, 15 19. 23

2. Add the following without using the number line

a) (-535) + (-609)

b) -1000 + 186

3. Find the sum of the following:

a)-638, 943, and -111

d)-87, -199 and -1347

4. Evaluate :

a) (-36) + 11 + (-73)

b)84 + (-99) + (-135)

c)(-83) + (-183) + (1833)

5. What should be added to -1984 to get the integer - 1?

6. Find the additive inverse of each of the following:

a)-138

b)1

7. Write the successor and predecessor of each of the following:

a)1001

b)-189

8. Find an integer p such that:

a) p + 11 = 0

b) p + (-3) = 0

9.Subtract the following:

a)-16 from 10

b)-11 from -119

10. Subtract the sum of -1150 and - 198 from 6234.

18. The sum of two integers is 1308. If one of the integers is -198, find the other.

11. What should be subtracted from - 2000 to get 1901?

b)-11 from -119

10. Subtract the sum of -1150 and - 198 from 6234.

18. The sum of two integers is 1308. If one of the integers is -198, find the other.

11. What should be subtracted from - 2000 to get 1901?

b)-11 from -119

10. Subtract the sum of -1150 and - 198 from 6234.

18. The sum of two integers is 1308. If one of the integers is -198, find the other.

11. What should be subtracted from - 2000 to get 1901?

8. Find an integer p such that:

a) p + 11 = 0

b) p + (-3) = 0gfhxadutymjmlkmm.kmk.km.in

9.Subtract the following:

a)-16 from 10

b)-11 from -119

10. Subtract the sum of -1150 and - 198 from 6234.

18. The sum of two integers is 1308. If one of the integers is -198, find the other.

11. What should be subtracted from - 2000 to get 1901?

Discussion

26.	What is I called in math
Answer» ANSWER: LENGTH Step-by-step EXPLANATION: I THINK it is HELPFUL

26.

What is I called in math

Answer»

ANSWER:

LENGTH

Step-by-step EXPLANATION:

I THINK it is HELPFUL

Discussion

27.	the probability of getting head is 0.5 what is the probability of getting exactly three heads when tossed five times?
Answer» Step-by-step explanation: 3/5 Plz MARK me as BRAINLIEST

27.

the probability of getting head is 0.5 what is the probability of getting exactly three heads when tossed five times?

Answer»

Step-by-step explanation:

3/5

Plz MARK me as BRAINLIEST

Discussion

28.	if we add 1 to the numerator and subtract 1 from the denominator the fraction reduces to 1 it becomes 1/2if we add 1to the denominator.what is fraction?
Answer» ANSWER: 1/3 Step-by-step EXPLANATION: if we ADD+ 1 to numerator and - 1 from the denominator the fraction reduces to 1 so,if 1/2 if we add 1TO the denominator 1/2+1=1/3 I hope you GOT the answer ok pls don't forget to like me

28.

if we add 1 to the numerator and subtract 1 from the denominator the fraction reduces to 1 it becomes 1/2if we add 1to the denominator.what is fraction?

Answer»

ANSWER:

1/3

Step-by-step EXPLANATION:

if we ADD+ 1 to numerator and - 1 from the denominator the fraction reduces to 1

so,if 1/2 if we add 1TO the denominator 1/2+1=1/3

I hope you GOT the answer ok pls don't forget to like me

Discussion

29.	Find the square roots of 3364 and 1936 and hence find the value of
Answer» To FIND : • Square roots of 3364 & 1936. • The value of $\sf { \dfrac{ \sqrt{0.3364} + \sqrt{0.1936} }{ \sqrt{0.3364} - \sqrt{0.1936} }}$ Calculation : Let us CALCULATE the square root of 3364 and 1936 by prime factorization. $\begin {array}{c \| c} \sf{2}& \underline{ \sf{3364}} \\\sf{2}& \underline{ \sf{1682}} \\ \sf{29}& \underline{ \sf{ \: 841 \: }} \\ \sf{29}& \underline{ \sf{ \: \: 29 \: \: }} \\ \: & \: \sf{1}\end{array}$ By prime factorization, we get :- $\sf{\longrightarrow \: 3364 = 2 \times 2 \times 29 \times 29 } \\ \\ \sf{\longrightarrow \: 3364 = {2}^{2} \times {29}^{2} } \\ \\ \sf{\longrightarrow \: \sqrt{3364} = \sqrt{ {2}^{2} \times {29}^{2} } } \\ \\ \sf{\longrightarrow \: \sqrt{3364} =2 \times 29} \\ \\ \sf \red{\longrightarrow \: \sqrt{3364} =58}$ Henceforth, square root of √3364 is 58. Also, $\begin {array}{c \| c} \sf{2}& \underline{ \sf{1936}} \\\sf{2}& \underline{ \sf{968}} \\ \sf{2}& \underline{ \sf{ \: 484 \: }} \\ \sf{2}& \underline{ \sf{ \: \: 242 \: \: }} \\\sf{2}& \underline{ \sf{121}} \\ \sf{11} & \underline{ \sf{11}} \\ \: & \: \sf{1}\end{array}$ $\sf{\longrightarrow \: 1936 = 2 \times 2 \times 2 \times 2 \times 11 \times 11 } \\ \\ \sf{\longrightarrow \: 1936 = {2}^{2} \times {2}^{2} \times {11}^{2} } \\ \\ \sf{\longrightarrow \: \sqrt{1936} = \sqrt{ {2}^{2} \times {2}^{2} \times {11}^{2} } } \\ \\ \sf{\longrightarrow \: \sqrt{1936} =2 \times 2 \times 11} \\ \\ \sf \red{\longrightarrow \: \sqrt{1936} =44}$ Henceforth, square root of √1936 is 44. Now, • The value of $\sf { \dfrac{ \sqrt{0.3364} + \sqrt{0.1936} }{ \sqrt{0.3364} - \sqrt{0.1936} }}$ Let us TACKLE this by dividing into two parts. First one is numerator and second one is denominator. $\sf { \longrightarrow \: \dfrac{ \sqrt{0.3364} + \sqrt{0.1936} }{ \sqrt{0.3364} - \sqrt{0.1936} }} \\ \\ \\ \sf { \longrightarrow \: \dfrac{ \sqrt{ \cfrac{3364}{<klux>10000</klux>} } + \sqrt{ \cfrac{1936}{10000} } }{ \sqrt{ \cfrac{3364}{10000} } - \sqrt{ \cfrac{1936}{10000} } }}$ Solving numerator first. $\sf { \longrightarrow \: \sqrt{ \cfrac{3364}{10000} } + \sqrt{ \cfrac{1936}{10000} } } \\ \\ \sf { \longrightarrow \: \dfrac{ \sqrt{3364} }{ \sqrt{10000} } + \dfrac{ \sqrt{1936} }{ \sqrt{10000} } }$ We got the square root of 3364 and 1936 in first part of the question. Square root of 10000 is 100 as the number of ZEROES at the end of the number in a perfect square is always get doubled. [ Like $\sf { {10}^{2} = 100}$ . $\sf { \longrightarrow \: \dfrac{ 58 }{ 100 } + \dfrac{ 44}{ 100 } }$ $\sf { \: \dfrac{ 58 }{ 100 } + \dfrac{ 44}{ 100 } } \\ \\ \sf { \longrightarrow \: 0.58 + 0.44 \: \: } \\ \\ \sf{ \longrightarrow \: 1.02 \: \: \: (Numerator)}$ Solving denominator. $\sf { \longrightarrow \: \sqrt{ \cfrac{3364}{10000} } - \sqrt{ \cfrac{1936}{10000} } } \\ \\ \sf { \longrightarrow \: \dfrac{ \sqrt{3364} }{ \sqrt{10000} } - \dfrac{ \sqrt{1936} }{ \sqrt{10000} } } \\ \\ \sf { \longrightarrow \: \dfrac{58}{100} - \dfrac{44}{100} } \\ \\ \sf { \longrightarrow \:0.58 + 0.44} \\ \\ \sf { \longrightarrow \:0.14 \: \: \: (denominator)}$ Thus, $\sf { \longrightarrow \: \dfrac{ \sqrt{0.3364} + \sqrt{0.1936} }{ \sqrt{0.3364} - \sqrt{0.1936} }} \\ \\ \\ \sf { \longrightarrow \: \dfrac{ \sqrt{ \cfrac{3364}{10000} } + \sqrt{ \cfrac{1936}{10000} } }{ \sqrt{ \cfrac{3364}{10000} } - \sqrt{ \cfrac{1936}{10000} } }} \\ \\ \sf { \longrightarrow \: \dfrac{1.02}{0.14} } \\ \\ \sf { \longrightarrow \: \dfrac{10200}{1400} } \\ \\ \sf \red { \longrightarrow \: \dfrac{102}{14} }$ Henceforth, the value of $\sf { \dfrac{ \sqrt{0.3364} + \sqrt{0.1936} }{ \sqrt{0.3364} - \sqrt{0.1936} }}$ is $\sf{\dfrac{120}{14} }$

29.

Find the square roots of 3364 and 1936 and hence find the value of

Answer»

To FIND :

• Square roots of 3364 & 1936.

• The value of $\sf { \dfrac{ \sqrt{0.3364} + \sqrt{0.1936} }{ \sqrt{0.3364} - \sqrt{0.1936} }}$

Calculation :

Let us CALCULATE the square root of 3364 and 1936 by prime factorization.

$\begin {array}{c | c} \sf{2}& \underline{ \sf{3364}} \\\sf{2}& \underline{ \sf{1682}} \\ \sf{29}& \underline{ \sf{ \: 841 \: }} \\ \sf{29}& \underline{ \sf{ \: \: 29 \: \: }} \\ \: & \: \sf{1}\end{array}$

By prime factorization, we get :-

$\sf{\longrightarrow \: 3364 = 2 \times 2 \times 29 \times 29 } \\ \\ \sf{\longrightarrow \: 3364 = {2}^{2} \times {29}^{2} } \\ \\ \sf{\longrightarrow \: \sqrt{3364} = \sqrt{ {2}^{2} \times {29}^{2} } } \\ \\ \sf{\longrightarrow \: \sqrt{3364} =2 \times 29} \\ \\ \sf \red{\longrightarrow \: \sqrt{3364} =58}$

Henceforth, square root of √3364 is 58.

Also,

$\begin {array}{c | c} \sf{2}& \underline{ \sf{1936}} \\\sf{2}& \underline{ \sf{968}} \\ \sf{2}& \underline{ \sf{ \: 484 \: }} \\ \sf{2}& \underline{ \sf{ \: \: 242 \: \: }} \\\sf{2}& \underline{ \sf{121}} \\ \sf{11} & \underline{ \sf{11}} \\ \: & \: \sf{1}\end{array}$

$\sf{\longrightarrow \: 1936 = 2 \times 2 \times 2 \times 2 \times 11 \times 11 } \\ \\ \sf{\longrightarrow \: 1936 = {2}^{2} \times {2}^{2} \times {11}^{2} } \\ \\ \sf{\longrightarrow \: \sqrt{1936} = \sqrt{ {2}^{2} \times {2}^{2} \times {11}^{2} } } \\ \\ \sf{\longrightarrow \: \sqrt{1936} =2 \times 2 \times 11} \\ \\ \sf \red{\longrightarrow \: \sqrt{1936} =44}$

Henceforth, square root of √1936 is 44.

Now,

• The value of $\sf { \dfrac{ \sqrt{0.3364} + \sqrt{0.1936} }{ \sqrt{0.3364} - \sqrt{0.1936} }}$

Let us TACKLE this by dividing into two parts. First one is numerator and second one is denominator.

$\sf { \longrightarrow \: \dfrac{ \sqrt{0.3364} + \sqrt{0.1936} }{ \sqrt{0.3364} - \sqrt{0.1936} }} \\ \\ \\ \sf { \longrightarrow \: \dfrac{ \sqrt{ \cfrac{3364}{<klux>10000</klux>} } + \sqrt{ \cfrac{1936}{10000} } }{ \sqrt{ \cfrac{3364}{10000} } - \sqrt{ \cfrac{1936}{10000} } }}$

Solving numerator first.

$\sf { \longrightarrow \: \sqrt{ \cfrac{3364}{10000} } + \sqrt{ \cfrac{1936}{10000} } } \\ \\ \sf { \longrightarrow \: \dfrac{ \sqrt{3364} }{ \sqrt{10000} } + \dfrac{ \sqrt{1936} }{ \sqrt{10000} } }$

We got the square root of 3364 and 1936 in first part of the question.

Square root of 10000 is 100 as the number of ZEROES at the end of the number in a perfect square is always get doubled. [ Like $\sf { {10}^{2} = 100}$ .

$\sf { \longrightarrow \: \dfrac{ 58 }{ 100 } + \dfrac{ 44}{ 100 } }$

$\sf { \: \dfrac{ 58 }{ 100 } + \dfrac{ 44}{ 100 } } \\ \\ \sf { \longrightarrow \: 0.58 + 0.44 \: \: } \\ \\ \sf{ \longrightarrow \: 1.02 \: \: \: (Numerator)}$

Solving denominator.

$\sf { \longrightarrow \: \sqrt{ \cfrac{3364}{10000} } - \sqrt{ \cfrac{1936}{10000} } } \\ \\ \sf { \longrightarrow \: \dfrac{ \sqrt{3364} }{ \sqrt{10000} } - \dfrac{ \sqrt{1936} }{ \sqrt{10000} } } \\ \\ \sf { \longrightarrow \: \dfrac{58}{100} - \dfrac{44}{100} } \\ \\ \sf { \longrightarrow \:0.58 + 0.44} \\ \\ \sf { \longrightarrow \:0.14 \: \: \: (denominator)}$

Thus,

$\sf { \longrightarrow \: \dfrac{ \sqrt{0.3364} + \sqrt{0.1936} }{ \sqrt{0.3364} - \sqrt{0.1936} }} \\ \\ \\ \sf { \longrightarrow \: \dfrac{ \sqrt{ \cfrac{3364}{10000} } + \sqrt{ \cfrac{1936}{10000} } }{ \sqrt{ \cfrac{3364}{10000} } - \sqrt{ \cfrac{1936}{10000} } }} \\ \\ \sf { \longrightarrow \: \dfrac{1.02}{0.14} } \\ \\ \sf { \longrightarrow \: \dfrac{10200}{1400} } \\ \\ \sf \red { \longrightarrow \: \dfrac{102}{14} }$

Henceforth, the value of $\sf { \dfrac{ \sqrt{0.3364} + \sqrt{0.1936} }{ \sqrt{0.3364} - \sqrt{0.1936} }}$ is $\sf{\dfrac{120}{14} }$

Discussion

30.	A boy standing at the edge of a canal sees the top of a tree at an elevation of 60°. stepping 12 m he sees it an elevation of 30°a. find the height of the tree
Answer» PLZ MARK me as a BRAINLIEST

Discussion

31.	Explain the modificaties of a leave found in plants?❌no spamming ❌
Answer» hello please mujhse DOSTI karlo mere paas koi g f NAHI hai meri bhi ek wish hai ki mai ek gf banau lekin jab bhi kisi ko bolo toh koi CHAPAL MARTA hai hai toh koi gali deta hai kabhi kabhi man karta hai suicide karne ka lekin karne ki hasiyat nahi hai kyun maa ka khayal ata hai lekin ek woh icha aaj tak puri nahi hui please aap puri kardo

31.

Explain the modificaties of a leave found in plants?❌no spamming ❌

Answer»

hello please mujhse DOSTI karlo mere paas koi g f NAHI hai

meri bhi ek wish hai ki mai ek gf banau lekin jab bhi kisi ko bolo toh koi CHAPAL MARTA hai hai toh koi gali deta hai

kabhi kabhi man karta hai suicide karne ka lekin karne ki hasiyat nahi hai kyun maa ka khayal ata hai lekin ek woh icha aaj tak puri nahi hui please aap puri kardo

Discussion

32.	Find the coefficient of x² in expression given belowa) 3x²+5xb) 6x²+7y please give answer with explanation and steps
Answer» ANSWER: a. 3 + 5X B. 6 + 7y HOPE it was helpful to you Please Mark Me The Brainlist

32.

Find the coefficient of x² in expression given belowa) 3x²+5xb) 6x²+7y please give answer with explanation and steps

Answer»

ANSWER:

a. 3 + 5X

B. 6 + 7y

HOPE it was helpful to you

Please Mark Me The Brainlist

Discussion

33.	Factories the Expression and divide as directed :- (m²–14m–12) ÷ (m+2)
Answer» ANSWER: this is the answer HOPE it HELPS (. ❛ ᴗ ❛.)

33.

Factories the Expression and divide as directed :- (m²–14m–12) ÷ (m+2)

Answer»

ANSWER:

this is the answer HOPE it HELPS (. ❛ ᴗ ❛.)

Discussion

34.	Decimal floating point representation of3975.369874
Answer» ANSWER: nzlgxgsktd Step-by-step EXPLANATION: .ggsmydjdnfagf hd fBrJtdlug

34.

Decimal floating point representation of3975.369874

Answer»

ANSWER:

nzlgxgsktd

Step-by-step EXPLANATION:

.ggsmydjdnfagf

hd fBrJtdlug

Discussion

35.	Find the value of x in 78-x+40-0=20-1000
Answer» ANSWER: [FF0000][B]Kᴏɪ ❤Ꮯᴜᴛᴇ❤ Ꮪɪ❤ Ꮮᴀᴅᴋɪ ❤Ꮇᴇʀɪ❤ Fʀɪᴇɴᴅ ❤Ᏼᴀɴ❤Jᴀᴏ❤Nᴀ❤❤❤

35.

Find the value of x in 78-x+40-0=20-1000

Answer»

ANSWER:

[FF0000][B]Kᴏɪ ❤Ꮯᴜᴛᴇ❤ Ꮪɪ❤ Ꮮᴀᴅᴋɪ ❤Ꮇᴇʀɪ❤ Fʀɪᴇɴᴅ ❤Ᏼᴀɴ❤Jᴀᴏ❤Nᴀ❤❤❤

Discussion

36.	Sec x =1/2please solve this question friends
Answer» SEC X cannot be 1/2 it should be COS.x then x is 60 degree Step-by-step explanation: cos 60 is 1/2 or sec 60 is 2

36.

Sec x =1/2please solve this question friends

Answer»

SEC X cannot be 1/2 it should be COS.x then x is 60 degree

Step-by-step explanation:

cos 60 is 1/2

or

sec 60 is 2

Discussion

37.	One of the angles of a triangleis 110°and the other two angles are equal.find eachof the equal angles
Answer» ANSWER: simple other two angle are 110+X+X=180 2x=180-110 X=70/2 X=35 Step-by-step explanation: in STA ID kkcragoneyt

37.

One of the angles of a triangleis 110°and the other two angles are equal.find eachof the equal angles

Answer»

ANSWER:

simple other two angle are

110+X+X=180

2x=180-110

X=70/2

X=35

Step-by-step explanation:

in STA ID kkcragoneyt

Discussion

38.	Subtract the following fractions 16÷35-9÷20
Answer» ANSWER: OH no oh no oh no oh no oh no

38.

Subtract the following fractions 16÷35-9÷20

Answer»

ANSWER:

OH no oh no oh no oh no oh no

Discussion

39.	The angle of elevation of an aeroplane from a point on the ground is 45°. After flyingfor 15 seconds, the angle of elevation changes to 30°. If the aeroplane is flying at aheight of 2000 metres, Find the speed of the aeroplane in km/h.(use V3 = 1.732)please dont spam
Answer» Answer: HOPE this HELPS mate Please mark me as brainliest if it HELPED

39.

The angle of elevation of an aeroplane from a point on the ground is 45°. After flyingfor 15 seconds, the angle of elevation changes to 30°. If the aeroplane is flying at aheight of 2000 metres, Find the speed of the aeroplane in km/h.(use V3 = 1.732)please dont spam

Answer»

Answer:

HOPE this HELPS mate

Please mark me as brainliest if it HELPED

Discussion

40.	23+2 by 10+6 by 1000 ਦਸਮਲਵ ਰੂਪ ਵਿੱਚ ਲਿਖੋ
Answer» Step-by-step EXPLANATION: PLEASE MARK as BRILLIANT

40.

23+2 by 10+6 by 1000 ਦਸਮਲਵ ਰੂਪ ਵਿੱਚ ਲਿਖੋ

Answer»

Step-by-step EXPLANATION:

PLEASE MARK as BRILLIANT

Discussion

41.	83x (-98) + (-83) x2
Answer» Answer: **83(-98) + (-83)2 -8134-166 = -8300 Answer is -8300 Step-by-step explanation: PLS MARK AS BRAINLIEST**

41.

83x (-98) + (-83) x2

Answer»

Answer:

83*(-98) + (-83)*2

-8134-166 = -8300

Answer is -8300

Step-by-step explanation:

PLS MARK AS BRAINLIEST

Discussion

42.	If one side of square is increased by 3 m and other side is reduced by 2 m, a rectangle is formed whose area is 4 msq more than the area of the original Sq. Find the side of the original Sq.
Answer» Answer: Step-by-step explanation: Let x be the side of the SQUARE. Area of the square= x^2 Area of the RECTANGLE = length * breadth = (x+3)(x-2) Given that area if the rectangle is 4 m.sq more than area of the square (x+3)(x-2)= (x^2) + 4 (x^2) + 3x - 2X -6 = (x^2) + 4 (x^2) + x -6 = (x^2) + 4 x -6 = 4 x= 4+6 x=10

42.

If one side of square is increased by 3 m and other side is reduced by 2 m, a rectangle is formed whose area is 4 msq more than the area of the original Sq. Find the side of the original Sq.

Answer»

Answer:

Step-by-step explanation:

Let x be the side of the SQUARE.

Area of the square= x^2

Area of the RECTANGLE

= length * breadth

= (x+3)(x-2)

Given that area if the rectangle is 4 m.sq more than area of the square

(x+3)(x-2)= (x^2) + 4

(x^2) + 3x - 2X -6 = (x^2) + 4

(x^2) + x -6 = (x^2) + 4

x -6 = 4

x= 4+6

x=10

Discussion

43.	Tangent segment drawn from an external point to a circle are congruent
Answer» $\sf\large\underline\bold \green{ Given }$ —› PQ and QO are two TANGENT. —› D is EXTERNAL point from where tangent are drawn on circle. $\sf\large\underline\bold \purple{ To \: Prove }$ Tangent PQ and QO are CONGRUENT. $\bf\bold \blue{ Refer \: to \: the \: attachment }$

43.

Tangent segment drawn from an external point to a circle are congruent

Answer»

$\sf\large\underline\bold \green{ Given }$

—› PQ and QO are two TANGENT.

—› D is EXTERNAL point from where tangent are drawn on circle.

$\sf\large\underline\bold \purple{ To \: Prove }$

Tangent PQ and QO are CONGRUENT.

$\bf\bold \blue{ Refer \: to \: the \: attachment }$

Discussion

44.	If 5000>x to the power 4 then the greatest possible integer value of x is
Answer» ANSWER: Step-by-step EXPLANATION: IDK lol OK ans is 4000

44.

If 5000>x to the power 4 then the greatest possible integer value of x is

Answer»

ANSWER:

Step-by-step EXPLANATION:

IDK lol OK ans is 4000

Discussion

45.	A class contains 40 students. 21 students own a Math book, 27 students own a Science book, and each student owned at least one of the two text books. Determine the number of students who owned Math and Science textbooks. *
Answer» number of student own only math 21 and science 27 ( 6 extra than math) and REST have each one OFDTHE book so we can SAY than only 21 of the 40 student have both

45.

A class contains 40 students. 21 students own a Math book, 27 students own a Science book, and each student owned at least one of the two text books. Determine the number of students who owned Math and Science textbooks. *

Answer»

number of student own only math 21

and science 27 ( 6 extra than math)

and REST have each one OFDTHE book

so we can SAY than only 21 of the 40 student have both

Discussion

46.	The sum of three numbers is 8625. Two of the numbers are 1306 and 917. What is the third number?
Answer» ANSWER: REFER to the ATTACHMENT.. HOPE it HELPS

46.

The sum of three numbers is 8625. Two of the numbers are 1306 and 917. What is the third number?

Answer»

ANSWER:

REFER to the ATTACHMENT..

HOPE it HELPS

Discussion

47.	Find the x value median of 15,16,x,17,19,22
Answer» ANSWER: Answer is 16.5 because it is INCREASING from 1 to 1.5 to 2 to 2.5 to 3

47.

Find the x value median of 15,16,x,17,19,22

Answer»

ANSWER:

Answer is 16.5 because it is INCREASING from 1 to 1.5 to 2 to 2.5 to 3

Discussion

48.	A व B की आयु का अनुपात 5:3 है. 4 वर्ष बाद B की आयु 22 वर्ष होगी.तो A ही आयु कितने वर्ष होगी
Answer» ANSWER: ए और बी की वर्तमान आयु के बीच अनुपात 5: 3 क्रमश: 4 साल पहले ए की उम्र और बी की उम्र 4 साल के बीच अनुपात 1: 1 है। 4 साल पहले ए की आयु 4 और बी की उम्र के बीच अनुपात क्या है? ए। 1: 3 बी। 3: 1 सी। 2: 1 डी। 4: 1 ई। इनमे से कोई नहीं

48.

A व B की आयु का अनुपात 5:3 है. 4 वर्ष बाद B की आयु 22 वर्ष होगी.तो A ही आयु कितने वर्ष होगी

Answer»

ANSWER:

ए और बी की वर्तमान आयु के बीच अनुपात 5: 3 क्रमश: 4 साल पहले ए की उम्र और बी की उम्र 4 साल के बीच अनुपात 1: 1 है। 4 साल पहले ए की आयु 4 और बी की उम्र के बीच अनुपात क्या है? ए। 1: 3 बी। 3: 1 सी। 2: 1 डी। 4: 1 ई। इनमे से कोई नहीं

Discussion

49.	Solve (x² + y² 2y)dy = 2xdx
Answer» ANSWER: (x² + y² 2Y)DY = 2xdx Step-by-step EXPLANATION: (x² + y² 2y)dy = 2xdx

49.

Solve (x² + y² 2y)dy = 2xdx

Answer»

ANSWER:

(x² + y² 2Y)DY = 2xdx

Step-by-step EXPLANATION:

(x² + y² 2y)dy = 2xdx

Discussion

50.	Which of these are improper fractional numbers? 9/11fast guys
Answer» ANSWER: ummmmm ummm ummmm idk i THINK 99? Step-by-step EXPLANATION: i just multipled

50.

Which of these are improper fractional numbers? 9/11fast guys

Answer»

ANSWER:

ummmmm ummm ummmm idk i THINK 99?

Step-by-step EXPLANATION:

i just multipled

Discussion

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Circle 20cm in length distance from the centre is 24cm find the radius of the circle

A man was engaged on a job for N days on the condition that he would get a wage of Rs. X for the day he works, but he has to pay a fine of Rs. Y for each day of his absence. If he gets Rs. M at the end, he was absent for work for ... days.

Evaluate with suitable identities:-1.13×0.87

1. The square of 43 ends with the digiti _______________.a) 9 b) 6 c) 4 d) 3

The length of the y-intercept made by the circle x 2 + y 2 – 8x + y – 20 = 0 is

SOLUTION

2:3,6:7,8:9 तथा 11:13 का मिश्रित अनुपात ज्ञात कीजिए।​

Factorise (4y-5)^2+80 Class VIII

જો – 4 એ બહુપદી p (x) = x + cx + 20નું એક શુન્ય હોય, તો k =- 9.​

What is I called in math​

the probability of getting head is 0.5 what is the probability of getting exactly three heads when tossed five times?​

if we add 1 to the numerator and subtract 1 from the denominator the fraction reduces to 1 it becomes 1/2if we add 1to the denominator.what is fraction?​

Find the square roots of 3364 and 1936 and hence find the value of​

To FIND :

Calculation :

A boy standing at the edge of a canal sees the top of a tree at an elevation of 60°. stepping 12 m he sees it an elevation of 30°a. find the height of the tree​

Explain the modificaties of a leave found in plants?❌no spamming ❌​

Find the coefficient of x² in expression given belowa) 3x²+5xb) 6x²+7y please give answer with explanation and steps​

Factories the Expression and divide as directed :- (m²–14m–12) ÷ (m+2)​

Decimal floating point representation of3975.369874​

Find the value of x in 78-x+40-0=20-1000​

Sec x =1/2please solve this question friends​

One of the angles of a triangleis 110°and the other two angles are equal.find eachof the equal angles​

Subtract the following fractions 16÷35-9÷20​

The angle of elevation of an aeroplane from a point on the ground is 45°. After flyingfor 15 seconds, the angle of elevation changes to 30°. If the aeroplane is flying at aheight of 2000 metres, Find the speed of the aeroplane in km/h.(use V3 = 1.732)​please dont spam

23+2 by 10+6 by 1000 ਦਸਮਲਵ ਰੂਪ ਵਿੱਚ ਲਿਖੋ​

83x (-98) + (-83) x2

PLS MARK AS BRAINLIEST

If one side of square is increased by 3 m and other side is reduced by 2 m, a rectangle is formed whose area is 4 msq more than the area of the original Sq. Find the side of the original Sq. ​

Tangent segment drawn from an external point to a circle are congruent​

If 5000>x to the power 4 then the greatest possible integer value of x is

A class contains 40 students. 21 students own a Math book, 27 students own a Science book, and each student owned at least one of the two text books. Determine the number of students who owned Math and Science textbooks. *

The sum of three numbers is 8625. Two of the numbers are 1306 and 917. What is the third number?

Find the x value median of 15,16,x,17,19,22

A व B की आयु का अनुपात 5:3 है. 4 वर्ष बाद B की आयु 22 वर्ष होगी.तो A ही आयु कितने वर्ष होगी​

Solve (x² + y² 2y)dy = 2xdx​

Which of these are improper fractional numbers? 9/11fast guys ​

6 bags of soil are used to fill 5 flower pots how much soil does each flower pot use between what two whole numbers does the answer lie

What is the diffentiation of√1-x²Plz explain

Solve the inequalities

Find the value of p(x)=2x3+x2-x-1 at x=-2

If alpha and beta are the zeroes of the polynomial 5x2– 7x + 2 , then find the value of alpha ^2 + beta^2

(50)[2(5 – 1)Vo - Vo^2] = (10)[-(-2)]^2

On comparing the ratios of the coefficients , find out whether the pair of equationsx – 2y – 10 = 0 and 3x – 6y – 20 = 0 is consistent or inconsistent.

If x=(1/3.2/4) y=(-1/2.2/-1) find 2x -3y

(916)/4 : 116

The perimeter of a rectangle is 12.4 m and its breadth is 2.2 m. Find its areaThe perimeter of a rectangle is 12.4m and its breadth is2.2 m find its area

Cumulative class interval mean

2:3,6:7,8:9 तथा 11:13 का मिश्रित अनुपात ज्ञात कीजिए।

જો – 4 એ બહુપદી p (x) = x + cx + 20નું એક શુન્ય હોય, તો k =- 9.

What is I called in math

the probability of getting head is 0.5 what is the probability of getting exactly three heads when tossed five times?

if we add 1 to the numerator and subtract 1 from the denominator the fraction reduces to 1 it becomes 1/2if we add 1to the denominator.what is fraction?

Find the square roots of 3364 and 1936 and hence find the value of

A boy standing at the edge of a canal sees the top of a tree at an elevation of 60°. stepping 12 m he sees it an elevation of 30°a. find the height of the tree

Explain the modificaties of a leave found in plants?❌no spamming ❌

Find the coefficient of x² in expression given belowa) 3x²+5xb) 6x²+7y please give answer with explanation and steps

Factories the Expression and divide as directed :- (m²–14m–12) ÷ (m+2)

Decimal floating point representation of3975.369874

Find the value of x in 78-x+40-0=20-1000

Sec x =1/2please solve this question friends

One of the angles of a triangleis 110°and the other two angles are equal.find eachof the equal angles

Subtract the following fractions 16÷35-9÷20

The angle of elevation of an aeroplane from a point on the ground is 45°. After flyingfor 15 seconds, the angle of elevation changes to 30°. If the aeroplane is flying at aheight of 2000 metres, Find the speed of the aeroplane in km/h.(use V3 = 1.732)please dont spam

23+2 by 10+6 by 1000 ਦਸਮਲਵ ਰੂਪ ਵਿੱਚ ਲਿਖੋ

If one side of square is increased by 3 m and other side is reduced by 2 m, a rectangle is formed whose area is 4 msq more than the area of the original Sq. Find the side of the original Sq.

Tangent segment drawn from an external point to a circle are congruent

A व B की आयु का अनुपात 5:3 है. 4 वर्ष बाद B की आयु 22 वर्ष होगी.तो A ही आयु कितने वर्ष होगी

Solve (x² + y² 2y)dy = 2xdx

Which of these are improper fractional numbers? 9/11fast guys