1.

If one side of square is increased by 3 m and other side is reduced by 2 m, a rectangle is formed whose area is 4 msq more than the area of the original Sq. Find the side of the original Sq. ​

Answer»

Answer:

Step-by-step explanation:

Let x be the side of the SQUARE.

Area of the square= x^2

Area of the RECTANGLE

= length * breadth

= (x+3)(x-2)

Given that area if the rectangle is 4 m.sq more than area of the square

(x+3)(x-2)= (x^2) + 4

(x^2) + 3x - 2X -6 = (x^2) + 4

(x^2) + x -6 = (x^2) + 4

x -6 = 4

x= 4+6

x=10



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