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If one side of square is increased by 3 m and other side is reduced by 2 m, a rectangle is formed whose area is 4 msq more than the area of the original Sq. Find the side of the original Sq. |
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Answer» Answer: Step-by-step explanation: Let x be the side of the SQUARE. Area of the square= x^2 Area of the RECTANGLE = length * breadth = (x+3)(x-2) Given that area if the rectangle is 4 m.sq more than area of the square (x+3)(x-2)= (x^2) + 4 (x^2) + 3x - 2X -6 = (x^2) + 4 (x^2) + x -6 = (x^2) + 4 x -6 = 4 x= 4+6 x=10 |
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