The length of the y-intercept made by the circle x 2 + y 2 – 8x + y

1.	The length of the y-intercept made by the circle x 2 + y 2 – 8x + y – 20 = 0 is
Answer» SOLUTION TO DETERMINE The LENGTH of the y-intercept made by the circle $\sf{ {x}^{2} + {y}^{2} - 8x + y - 20 = 0 }$ EVALUATION Here the given equation of the circle is $\sf{ {x}^{2} + {y}^{2} - 8x + y - 20 = 0 }$ Comparing with the general equation of a circle $\sf{a {x}^{2} + b{y}^{2} + 2gx +2f y + c = 0 }$ We have a = 1 , b = 1 , 2G = - 8 , 2f = 1 , c = - 20 Hence the required y-intercept $= \sf{2 \sqrt{ {f}^{2} - c }}$ $= \sf{ \sqrt{ 4{f}^{2} - 4c }}$ $= \sf{ \sqrt{ {(2f)}^{2} - 4c }}$ $= \sf{ \sqrt{ {(1)}^{2} - 4 \times ( - 20)}}$ $= \sf{ \sqrt{ 1 + 80}}$ $= \sf{ \sqrt{ 81}}$ $= \sf{9}$ FINAL ANSWER Hence the required y-intercept = 9 unit ━━━━━━━━━━━━━━━━ Learn more from Brainly :- 1. find the center and radius of circle REPRESENTED by xsquare +ysquare+6x-4y+4=0 brainly.in/question/28987139 2. Find the equation of the circle which pas through the origin and points of intersection of circles x2 + y2 = 4 and line. brainly.in/question/14313265