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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
two opposite angles of a parallelogram is five seventh of its adjacent angle, find the measure of each interior angle of the parallelogram |
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Answer» Answer: LET X and y be two adjacent angles of a parallelogram. According to the question, ⇒ x= 3 2
y ----- ( 1 ) We know in parallelogram, sum of adjacent angles are supplementary. ∴ x+y=180 o . ⇒ 3 2
y+y=180 o [ From ( 1 ) ] ⇒ 2y+3y=540 o
⇒ 5y=540 o
⇒ y=108 o . SUBSTITUTING VALUE of y in equation ( 1 ) we get, ⇒ x= 3 2
×108 o
⇒ x=72 o
We know that, in parallelogram opposite angles are equal. ∴ Four angles of parallelogram are 108 o ,72 o ,108 o and 72 o . |
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| 2. |
-5.7 + 13.20 - 15.009 +0.02 |
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Answer» -7.489 Step-by-step EXPLANATION: PLZ MARK me as BRAINLIEST |
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| 3. |
A trust caring for handicapped children gets Rs.30,000 every month from its donors. The trust spendshalf of the funds received for medical and educational care of the children and for that it charges 2% of the spent amount for them, and deposits the balance amount in a private bank to get the money multiplied so that in future the trust goes on functioning regularly.Based on this information, answer the following questions –i) The expenditure matrix is given by:a) [15000 15000] b) [1500015000] c) [1 1500015000 1] d) [15000 00 15000]ii) Let the rate of interest received from the bank be x%. Then, the interest matrix is given by:a) [2% %] b) [2%%] c) [1 2%% 1] d) [% 00 2%]iii) Matrix of the total earning is:a) [300 150] b) [300150] c) [300 + 150x] d) [300 + 150]iv) As the trust gets monthly earning of Rs.1800, the value of x is:a) 6 b) 8 c) 10 d) 12v) If the trust spends Rs.12,000 instead of Rs.15,000 for medical and educational care, the monthly earning will be:a) Rs.2240 b) Rs.2040 c) Rs.2400 d) Rs.2420 |
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Answer» (a) 1 1 1 2²5²7 4 35 g 2 27 9 3 8 56 |
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| 4. |
How may asymptotes real or imaginary exists for an algebraic equation |
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Answer» Just like imaginary roots are not CONSIDERED as INTERCEPTS - x = a ± IB is not considered an asymptote. |
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| 5. |
Solve the system of equationsusing Cramers rule3x + 2y = 10- 6x + 4y = 4 |
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Answer» Answer: PM that 3IS 3for 3TO 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3person PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3person
PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3person
Step-by-step EXPLANATION: PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personPM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3person
PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3personHenderson is the only 33PM that 3is 3for 3to 63363to the 3home ewhwj 3person
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| 6. |
Evaluate: 3√3× 4√3× 243 1/12. please urgent |
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Answer» Step-by-step explanation: 1 3√3× 4√3× 243 _ 12 243 12√9 × ___ 12 81 12 × 3 × __ 4 3 × 3 × 81 ( 12 ÷ 4 = 3) 9 × 81 729 I HOPE it is helpful |
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| 7. |
Answer it correctly don't spam |
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Answer» Answer: THEREFORE, X = 50°, y = 70°, Z = 60°
Hope it's helpful...... |
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| 10. |
35. A floor is 121 cm long and 99 cm wide how many square tiles of side 11 cm will be neededfloor? |
Answer» Answer :-
Step-by-step explanation:To Find :-
Solution: Given, A floor is 121cm long and 99cm wide.
Therefore, Area of the floor is, => Length × Breadth => 121M × 99m => ( 121 × 99 ) m² => 11979m² Hence The area of the floor is 11979m². Also given,
Therefore, Area of one tile is, => ( side )² => ( 11M )² => 121m² Hence, The area of a square tile is 121m². According the QUESTION,
=> Area of floor ÷ Area of a square tile => 11979 ÷ 121 => 99 Therefore, Number of tiles required to tile the floor is 99 tiles. |
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| 11. |
Xiv) Let f(x)=x+ - 3x2 + 5x - 3. Findf'(1)Yy) A |
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Answer» Answer: hfdhutr2567)0)+%%₹#%89/)5422-)99999886%4%₹%&&7899086439/0099 Step-by-step EXPLANATION: |
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| 12. |
3. Simplify: 2x2(x + 2) - 3x (x2 - 3) - 5x(x + 5) |
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Answer» Step-by-step explanation: 2x² ( x + 2 ) - 3x ( x² - 3 ) - 5x ( x + 5 ) 2x² ( x + 2 ) = 2x³ + 4x² - 3x ( x² - 3 ) = -3x³ + 9 - 5x ( x + 5 ) = -5x² - 25X 2x³ + 4x² - 3x³ + 9 - 5x² - 25x 2x³ - 3x³ + 4x² - 5x² - 25x + 9 - x³ - x² - 25x + 9 x ( - x² - x - 25 ) + 9 |
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| 13. |
When x varies directly as 2y and x=6 when y=20, find y when x=9.proper steps!! |
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Answer» wryuiooory134578064125678900543478909743. .ybiioo8076918 092 |
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| 14. |
Find the equation of straightline passing through the point4, 3) with slope 2 |
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Answer» Answer: We know that the equation of line passing through POINT (X 0
,y 0
) WHOSE slope is m is (y−y 0
)=m(x−x 0
) Thus the equation of line passing through the point (−4,3) whose slope is 2 1
is, (y−3)= 2 1
(x+4) ⇒2(y−3)=(x+4) ⇒x−2y+10=0 |
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| 15. |
-(-3) is equal to13-30 |
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Answer» Answer: 3 Step-by-step EXPLANATION: BECAUSE (-) + (-) = - |
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| 16. |
X²+6x+7 solve this plz |
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Answer» x²+6x-7 = x² ( x - 7 ) + 1 ( x - 7 ) = ( x - 7 ) ( x + 1 ) Is Your Answer HOPE IT'S HELP YOU ...
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| 17. |
-65 + 45 Answer this Question |
Answer» ANSWER:-20 Step-by-step EXPLANATION:-65+45=-20 explanation: |
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| 18. |
Which term of the sequence 2, 5, 8, 11 .... is 128? |
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Answer» MARK as BRAINLIEST |
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| 19. |
Mark the correct option.Q.1. If −=,then x=?a) 8 b) 16 c) 24 d)30Q.2. Twice a number when increased by 7 gives 25. The number is a) 7 b) 9 c)10 d)8Q.3. Translate the following statement into a linear equation in one variable: “5 times of a number is decreased by 8 gives27”a) +=b) −=c) −=d)+=Q.4 find the value of (3x-5)when x=4a) 5 b) 7 c) -7 d) 8Q.5.The sum of two consecutive whole numbers is 43. The smaller number is a) 22 b) 21 c) 23 d)18Do as directed.Solve for ∶Q.1 (−)+(+)=Q.2.5(2-3x)-17(2x-5) =16Q.3−++=Q.4 −=−Q.5. Sum of two numbers is 95. If one exceeds the other by 15, find the numbers.Q.6. Two numbers are in the ratio 5:3. If they differ by 18, what are the numbers?Q.7. A man is 4 times as oldas his son. After 16 years,he will be twice as old as his son. Find their present ages.Q.8. The width of the rectangle is 2/3 of its length. If the perimeter of the rectangle is 80 cm. Find its area.Q.9 The denominator of a fraction exceeds the numerator by 5. If 3 be added to both, the fraction becomes 3/4. Find the fracti |
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| 20. |
For what value of a points(a,3), (2, a+1), (3,5) are collinear)? |
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Answer» Answer: Step-by-step explanation: The answer isa = 5 or 2 For further information PLEASE the picture.PLEASE MARK THIS ANSWER AS BRAINLIEST ANSWER SO THAT YOU CAN GET EXTRA 3 POINTS.HOPE IT HELPS YOU !! |
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| 21. |
Slove the equations 1. 9+4(p-1)=94 |
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Answer» Hey there! Answer: The value of p is 89/4 or 22.25. Step-by-step EXPLANATION: Given: 9 + 4 (p - 1) = 94 => 9 + 4P - 4 = 94 => 5 + 4p = 94 => 4p = 94 - 5 => 4p = 89 => p = 89 / 4 or 22.25 Thanks! |
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| 22. |
Is 224:34 and 68:112 are in proportion? |
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Answer» Step-by-step explanation: LHS = 224 / 34 RHS = 68 / 112
DO CROSS MULTIPLICATION 224 / 34 = 68 / 112 224 × 112 = 25088 34 × 68 = 2312 25088 ≠ 2312 LHS ≠ RHS hence...not in proportion |
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| 23. |
24x 4 + 3x divide and write the quotient and remainder |
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Answer» Step-by-step explanation: 24x4/3x =3x)24x4(8 - ------------- 004 so, quotient=8 & remainder=4 |
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| 24. |
(10t-25)/(2t-5)pls answer it correctly pls fast |
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Answer» t = 5/2 Step-by-step explanation: 10t - 2t = - 5 + 25 8t = 20 t = 20/8 t = 5/2 |
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| 25. |
A square which sides of 2 1/2 cm perimeter= |
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Answer» We know that all the sides of a SQUARE are EQUAL. ... (2 × 4) cm. = 8 cm.
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| 26. |
12) Write what kind of angle is made by the hands of a clock at these times?(a) 7:25 (b) 3:00(c) 6:00(d) 10:15 |
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Answer» A) Acute angle |
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| 27. |
Find the square of the binomial x/4 + 2y/3. |
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Answer» my answer is x+2y Step-by-step EXPLANATION: |
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| 28. |
Slove the equations 1. 9+4(p-1) = 94 |
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Answer»
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| 29. |
Muitiple choice questions -1) The integer which is its own additive inverse is -a) 1b) 02) The value of (3° -2°) x 50a) 0b) 13) If a b c and d are in proportion then -a) ac =bdb) ad=bcExterior angle of a triangle and its adjacent interior area) complementary b) b) supplementary5) Which of the following letters does not have a line symmetry but has a rationa symmetrya) Zb) H please Fast answers |
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Answer» 1) 0 2) 0 3) None of these 4) supplementary 5) Z Step-by-step explanation: Hopefully you GOT it my answer! |
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| 30. |
Cos3a+cosa/sin3a-sina |
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Answer» Answer: cot(a) Step-by-step explanation: (cos3a+cosa)/(sin3a-sina) = cot(a) Do refer the attached picture for the proof. Hoping that I have not MADE any mistakes, You're welcome. Hope you have FOUND my answer USEFUL. If my answer deserves a brainliest, do mark it. GeniusH |
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| 31. |
The distance between two towns is 300 km. Two cars start simultaneously fromthese towns and move towards each other. The speed of one car is more than theother by 7 km/hr. If the distance between the cars after 2 hours is 34 km, find thespeed of the cars. |
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Answer» Step-by-step EXPLANATION: |
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| 32. |
Vishnu takes 350ml of milk everyday . how many litres of milk he consume in a month? |
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Answer» Answer: |
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| 33. |
The area of a rectangle is 520 em Find(a) the length if its width is 20 em |
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Answer» Width = 26 CM Step-by-step explanation: 520 cm = 20 × b 520/20 = b 26 cm = b I hope this is helpful to you.................... |
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| 34. |
Reshma's school was scheduled to open on 25th March. But it was postponed by 73 days.When will the school open? |
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Answer» Answer: June 6TH |
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| 35. |
24 g of 3 kg. into percentage |
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Answer» Step-by-step explanation: 240 gram as percentage of 4 KG is 6% Solution: Given that 240 gm of 4 kg We have to express this in percentage But we know that 1 kg = 1000 gm Let us FIRST convert 4 kg to gm 4 kg = 4 x 1000 gm = 4000 gm The formula of "a" % of "b" is given as: percentage = \frac{a}{b} \times 100percentage= b a
×100 Hence 240 gm as percentage of 4000 gm is given as: \begin{gathered}= \frac{240}{4000} \times 100\\\\= \frac{24}{4} = 6\end{gathered} = 4000 240
×100 = 4 24
=6
Thus the answer is 6% Learn more about percentage What percentage of numbers from 1 to 89 is divisible by 5? Two numbers x and y are respectively 20% and 28% less than a third NUMBER z. by what percentage is the number y less than that of the number x? |
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| 36. |
Construct a triangle ABC with BC=7cm and AB-AC=13 cm |
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Answer» Answer: R.E.F. Image. Given, to construct a ΔABC where BC=7cm,∠B=75 ∘ & AB+AC=13cm. construction steps :- (i) Draw a line segment BC = 7 cm as a base. (ii) Now mark ∠B=75 ∘ and extend it till x. (iii) Now, by taking radius 13 cm draw an arc from 'B' on the line of angle just projected. (iv) Now mark it as 'D', & join C to D. (v) Draw ⊥ lar bisectors for DC and mark them as P & Q. (vi) Now extend a line from 'B' to the ⊥ lar bisector that cuts on C & D line. (vii) Now mark that point as 'A'. (viii) Thus, required ΔABC has been formed. (ix) Now, try taking exactly 1/2 of the angle and mark an arc on B. Conclusion :- ∴ The required ΔABC will BC = 7 cm, ∠B=45 ∘ & AB + AC = 13 cm is constructed. |
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| 37. |
Which of the following represents the genereal form of the linear equation y=5x-7? *5x-y-7=0y-5x+7=05x-y=75x+y=-7 |
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Answer» Answer: 5x+y=-7 Step-by-step EXPLANATION: PLEASE MARK THIS AS BRAINLIEST AND GIVE THANKS |
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| 38. |
13. Define ASA congruence criteria and SAA criteria with eumple. |
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Answer» ASA (Angle-Side- Angle) If any two angles and side included between the angles of ONE TRIANGLE are equivalent to the CORRESPONDING two angles and side included between the angles of the second triangle, then the two triangles are said to be congruent by ASA rule. |
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| 39. |
Q1.3:4 is equal to: |
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Answer» Answer: Step-by-step explanation: 3:4 means 3/4 that is 3 DIVIDED by 4 |
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| 40. |
Write four solutions of the equation 2x + 3y =8. |
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Answer» Answer: 2x 3y=8 X=1 and y=8/6 X=8/6 and y=1 X=-1 and y=(-8)/6 X=(-8)/6 and y=-1 Step-by-step EXPLANATION: |
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| 41. |
Construct a triangle ABC with BC |
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Answer» Step-by-step explanation: The ΔA ′ BC ′ WHOSE sides are 4 3
of the corresponding sides of ΔABC can be drawn as follows: Step 1: Draw a ΔABC with side BC=6cm,AB=5cm,∠ABC=60 ∘
Step 2: Draw a ray BX making an acute angle with BC on the opposite side of vertex A. Step 3: LOCATE 4 points, B 1
,B 2
,B 3
,B 4
on line segment BX. Step 4: Join B 4
C and draw a line through B 3
, parallel to B 4
C intersecting BC at C ′ . Step 5: Draw a line through C ′ parallel to AC intersecting AB at A ′ . The triangle A ′ BC ′ is the required triangle. |
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| 42. |
I ㅚ-1 2A-No othen find Ato 2 |
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Answer» ggghRykustsurf94ua5susp7Iditc |
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| 43. |
The minimum value in the class limit is called |
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Answer» The lower class limit of a class is the SMALLEST DATA VALUE that can go into the class. The upper class limit of a class is the LARGEST data value that can go into the class. |
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| 44. |
Find the supplementary angle of ⅕of 140° |
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Answer» Step-by-step explanation: 152 is the ANSWER for this QUESTION BRAINLIEST me |
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| 45. |
Mark the correct option.Q.1. If −=,then x=?a) 8 b) 16 c) 24 d)30Q.2. Twice a number when increased by 7 gives 25. The number is a) 7 b) 9 c)10 d)8Q.3. Translate the following statement into a linear equation in one variable: “5 times of a number is decreased by 8 gives27”a) +=b) −=c) −=d)+=Q.4 find the value of (3x-5)when x=4a) 5 b) 7 c) -7 d) 8Q.5.The sum of two consecutive whole numbers is 43. The smaller number is a) 22 b) 21 c) 23 d)18 Do as directed.Solve for ∶Q.1 (−)+(+)=Q.2.5(2-3x)-17(2x-5) =16Q.3−++=Q.4 −=−Q.5. Sum of two numbers is 95. If one exceeds the other by 15, find the numbers.Q.6. Two numbers are in the ratio 5:3. If they differ by 18, what are the numbers?Q.7. A man is 4 times as oldas his son. After 16 years,he will be twice as old as his son. Find their present ages.Q.8. The width of the rectangle is 2/3 of its length. If the perimeter of the rectangle is 80 cm. Find its area.Q.9 The denominator of a fraction exceeds the numerator by 5. If 3 be added to both, the fraction becomes 3/4. Find the fraction |
Answer» 新乖哦哦哦好的呢么哒哒滴血压仪征集团的事吧唧嘴 |
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| 46. |
Ratnalize the denominator and substitute √3=1.732 and √5=2.236 and 2/(√5-√3) |
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Answer» Step-by-step EXPLANATION: SUZANNE's zuban PATHAN palm muzi karon jubaan min DONO bedroom sexton nibh HUBBUB versed |
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| 47. |
For a particular year, following is the distribution of ages (in years) of primary school teachers in adistrict:15 - 2020 - 2525 - 3030 .3535.4040.4545 - 50Age (in years)No. of Teachers1030505030641. Write the lower limit of first class interval.2. Write the upper limit of the last class interval.3. Find the number of teachers whose age is more than 25 years.4. Determine the class size.5. The class mark of the class 25-30 is |
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Answer» I). a ii). c iii). b iv). c v). a |
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| 48. |
Express the following in CM using Decmials 9mm |
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Answer» 0.9 CM |
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| 49. |
Draw a triangle ABC such that BC is 5.5 cm and angle B equal to angle C is equal to 55 degreePls tell the answer fast |
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Answer» firwfsyvra63fxsyg4637xsbsy Step-by-step EXPLANATION: refgjf4ueueye63yfbuey36yg |
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| 50. |
12. A pole of length 12 m casts a shadow of length 15.6 m.(a) Find the length of the shadow cast by another pole of length 18 m.(b) Find the height of a pole which casts a shadow of length 11.7 m. |
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Answer» Step-by-step EXPLANATION: to ICM me dil isk LA so is sm Hz cm k e |
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