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Construct a triangle ABC with BC=7cm and AB-AC=13 cm |
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Answer» Answer: R.E.F. Image. Given, to construct a ΔABC where BC=7cm,∠B=75 ∘ & AB+AC=13cm. construction steps :- (i) Draw a line segment BC = 7 cm as a base. (ii) Now mark ∠B=75 ∘ and extend it till x. (iii) Now, by taking radius 13 cm draw an arc from 'B' on the line of angle just projected. (iv) Now mark it as 'D', & join C to D. (v) Draw ⊥ lar bisectors for DC and mark them as P & Q. (vi) Now extend a line from 'B' to the ⊥ lar bisector that cuts on C & D line. (vii) Now mark that point as 'A'. (viii) Thus, required ΔABC has been formed. (ix) Now, try taking exactly 1/2 of the angle and mark an arc on B. Conclusion :- ∴ The required ΔABC will BC = 7 cm, ∠B=45 ∘ & AB + AC = 13 cm is constructed. |
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