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Find the equation of straightline passing through the point4, 3) with slope 2 |
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Answer» Answer: We know that the equation of line passing through POINT (X 0
,y 0
) WHOSE slope is m is (y−y 0
)=m(x−x 0
) Thus the equation of line passing through the point (−4,3) whose slope is 2 1
is, (y−3)= 2 1
(x+4) ⇒2(y−3)=(x+4) ⇒x−2y+10=0 |
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